String pattern:
1#5,7;2#;3#4
These are three sets of values separated by semicolon.
Digit before # goes in one column, digits after # (separated by comma) go in another column (so the second set in this case only has one value)
How can I do this?
This is what I found on the net:
DECLARE #S VARCHAR(MAX) = '1,100,12345|2,345,433|3,23423,123|4,33,55'
DECLARE #x xml = '<r><c>' +
REPLACE(REPLACE(#S, ',','</c><c>'),'|','</c></r><r><c>') +
'</c></r>'
SELECT x.value('c[1]','int') AS seq,
x.value('c[2]','int') AS invoice,
x.value('c[3]','int') AS amount
FROM #x.nodes('/r') x(x)
This however has fixed no. of figures after every delimiter. And it also uses only 2 delimiters.
Related
I have a simple string; for example,'01023201580001'.
I would like to replace the last two characters of this string; '01', with '00'.
I could extract the last two characters from this string as RIGHT(columname,2) and then use
REPLACE([columname], RIGHT([columname], 2), '00') as newColumnString
But in the result, it replaces the first two characters as well?
Expected result: 01023201580000
Result I get: 00023201580000
What am I doing wrong?
The second argument to the replace() function defines a pattern to match. The function will look for all instances of that pattern in the target string (first argument) and replace them with the replacement text (third argument).
If you know you only need to change the last two characters, you can take the value excluding those characters and then append the characters you want:
select left(columname, len(columname) - 2) + '00';
If you are doing this for an entire column and some of the rows might not end with '01', you can filter those out:
update MyTable
set columname = left(columname, len(columname) - 2) + '00'
where columname like '%01';
You could also use stuff() in a similar way.
In SQL server, you can use substring like so:
DECLARE #s NVARCHAR(20) = N'01023201580001';
DECLARE #ReplaceWith NVARCHAR(20) = N'00';
SELECT SUBSTRING(#s, 0, LEN(#s) - 1) + #ReplaceWith;
Output: 01023201580000
In SQL server, I have VARCHAR values.
I need a view that automatically reformats data.
Data that is stored in the following form:
hawthorn104freddy#hawthorn.com
scotland2samantha#gmail.com3
birmingham76roger#outlook.co.uk1905student
Needs to be reformatted into the following:
hawthorn 104freddy#hawthorn.com0000
scotland 002samantha#gmail.com 0003
birmingham076roger#outlook.co.uk1905student
Reformatting
Numeric values within the strings are padded with zeros to the length of the longest number
All other characters are padded with space characters to line up the numbers.
Does anyone know how this is done?
Note: Bear in mind that a string may contain any combination of words and numbers.
You should split your values to 4 columns (to find maximum length in each column), then add leading/trailing zeros/spaces, then concat it.
Here is code to split values, hope you will have no problems with adding zeros and spaces:
declare #v varchar(255) = 'hawthorg104freddy#hawthorn.com50'
select
FirstPart = left(#v, patindex('%[a-z][0-9]%', #v)),
SecondPart = substring(#v, patindex('%[0-9]%', #v), patindex('%[0-9][a-z]%', #v) - patindex('%[a-z][0-9]%', #v)),
ThirdPart = substring(#v, patindex('%[0-9][a-z]%', #v) + 1, len(#v) - patindex('%[0-9][a-z]%', #v) - patindex('%[0-9][a-z]%', reverse(#v))),
Fourthpart = right(#v, patindex('%[0-9][a-z]%', reverse(#v)))
Notes:
patindex('%[a-z][0-9]%', #v) - Last letter in hawthorn (nickname?)
patindex('%[0-9][a-z]%', #v) - Last digit in first number (104)
patindex('%[0-9][a-z]%', reverse(#v)) - Length of the last number
You can also use CLR and RegEx to split values to groups:
https://github.com/zzzprojects/Eval-SQL.NET/wiki/SQL-Server-Regex-%7C-Use-regular-expression-to-search,-replace-and-split-text-in-SQL
You can use PATINDEX
declare #str varchar(100)='hawthorn104freddy#hawthorn.com'
SELECT SUBSTRING(#str,0,PATINDEX('%[0-9]%',#str)),
SUBSTRING(#str,PATINDEX('%[0-9]%',#str),LEN(#str)-LEN(SUBSTRING(#str,0,PATINDEX('%[0-9]%',#str))))
I have a database that has multiple columns populated with various numeric fields. While trying to populate from a CSV, I must have mucked up assigning delimited fields. The end result is a column containing It's Correct information, but also contains the next column over's data- seperated by a comma.
So instead of Column UPC1 containing "958634", it contains "958634,95877456". The "95877456" is supposed to be in the UPC2 column, instead UPC2 is NULL.
Is there a way for me to split on the comma and send the data to UPC2 while keeping UPC1 data before the comma in tact?
Thanks.
You can do this with string functions. To query the values and verify the logic, try this:
SELECT
LEFT(UPC1, CHARINDEX(',', UPC1) - 1),
SUBSTRING(UPC1, CHARINDEX(',', UPC1) + 1, 1000)
FROM myTable;
If the result is what you want, turn it into an update:
UPDATE myTable SET
UPC1 = LEFT(UPC1, CHARINDEX(',', UPC1) - 1),
UPC2 = SUBSTRING(UPC1, CHARINDEX(',', UPC1) + 1, 1000);
The expression for UPC1 takes the left side of UPC1 up to one character before the comma.
The expression for UPC2 takes the remainder of the UPC1 string starting one character after the comma.
The third argument to SUBSTRING needs some explaining. It's the number of characters you want to include after the starting position of the string (which in this case is one character after the comma's location). If you specify a value that's longer than the string SUBSTRING will just return to the end of the string. Using 1000 here is a lot easier than calculating the exact number of characters you need to get to the end.
I have a table with details of family members staying in a particular locality. Since these are government data, it has lot mistakes. Like in one column 'houseno', there a 2 values 'Ti 303' and '303' which are same house numbers.
In the end, I want Ti 303 to be updated with '303'. (As these are family members living in same house)
Similarly 'P-101' and 'P/101' are same houseno's and I want it to be converted to either 'P-101' or 'P/101'. I tried difference, substring etc but of now use to me. Please help!
You just need to strip out the characters to compare the content?
CREATE FUNCTION dbo.FN_GetNumberPart (#strMixedString VARCHAR(200))
RETURNS VARCHAR(200)
AS
BEGIN
DECLARE #NumberPart INT
-- Get the next non numeric character position
SET #NumberPart = PATINDEX('%[^0-9]%', #strMixedString)
-- While there are non numeric characters remaining
WHILE #NumberPart > 0
BEGIN
-- Remove the non numeric character from the string
SET #strMixedString = STUFF(#strMixedString, #NumberPart , 1, '' )
-- Get the next non numeric character position
SET #NumberPart = PATINDEX('%[^0-9]%', #strMixedString)
END
-- Spit out the cleansed string
RETURN ISNULL(#strMixedString,0)
END
GO
SELECT dbo.FN_GetNumberPart(HouseNo)
from TblAddresses
You should use the REPLACE command. For the two examples give you could hard code it as follows:
select REPLACE('Ti 303','Ti ','')
select REPLACE('P-101','P-','P/')
You would use REPLACE in your UPDATE command and not as a SELECT obviously.
If you have a list of strings to replace in a column with an update then you could put these into a table. Then use this in your REPLACE command for the string pattern to be replaced.
I have data in a column which contains values for various fields from an application and all these fields are concatenated into one field on the database side and separated with commas.
If the field in the application is blank, then the value between the two commas will just be blank.
I need a select statement to select each of the individual fields if they are populated. I would like to specify each field as a variable which I will declare at the top of the statement.
An example of the string in the database field is:
,"FIELD1","FIELD2","FIELD3",FIELD4,FIELD5,FIELD6,,,,"FIELD10",FIELD11,FIELD12,FIELD13
As you can see, fields 7-9 were blank in this example so they are blank in the string.
I just need a way to selectively select the field I need using the commas as my marker. The string always starts with a comma so field1 always comes after the first comma.
I hope this makes sense!
Try this:
DECLARE #STRING VARCHAR(255) = ',"FIELD1","FIELD2","FIELD3",FIELD4,FIELD5,FIELD6,,,,"FIELD10",FIELD11,FIELD12,FIELD13'
DECLARE #FieldToReturn INT = 12 -- Pick which field you want
SET #STRING = RIGHT(#STRING, LEN(#STRING) - 1) + ',' -- Strip leading comma & add comma to the end
WHILE #FieldToReturn > 1
BEGIN
SET #STRING = SUBSTRING(#STRING,PATINDEX('%,%',#STRING), LEN(#STRING))
SET #FieldToReturn = #FieldToReturn - 1
SET #STRING = RIGHT(#STRING, LEN(#STRING) - 1)
END
SELECT SUBSTRING(#STRING,0,PATINDEX('%,%', #STRING))
If it the field is not populated, this will return a blank.
Edit: I know that I could have put all of the string manipulation in one line within the WHILE, but chose not to for readability...to me that is more important that the possibility of a teeny tiny bit of overhead in this example