I want to replace the normal behaviour of Validation.ErrorTemplate.
I want to put a background border object (filled with red color) behind my own UserControl
and then apply a simple color animation to blink it.
I tried this in my implicit control style:
<Style TargetType="{x:Type local:myControl}">
<Setter Property="Validation.ErrorTemplate">
<Setter.Value>
<ControlTemplate>
<Border Name="ErrorBorder" CornerRadius"5" Background="Red">
<AdornedElementPlaceholder />
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="Validation.HasError" Value="True">
<Setter Property="ToolTip" Value="{Binding
RelativeSource={RelativeSource Self},
Path=(Validation.Errors)[0].ErrorContent}" />
</Trigger>
</Style.Triggers>
</Style>
Unfortunately the border object entirely overlays the control UI.
The other question is: where is the right place to put a DoubleAnimation applied on Opacity to make my Background blinking? Wich property/event should I trigger? Should I use style or simply place it in the Border.Triggers?
Thank you
I'm pretty sure this isn't possible, adorners are always drawn on top of the adorned element.
See the Adorners Overview on MSDN
"An Adorner is a custom FrameworkElement that is bound to a UIElement. Adorners are rendered in an AdornerLayer, which is a rendering surface that is always on top of the adorned element or a collection of adorned elements"
You could probably get the same effect by adorning with a normal border that just borders the adorned element instead of trying to stick it behind the adorned element.
Related
i am new in WPF. My project have one Grid Control that grid control border is Red color and I have a one button. when i click the button grid border color will be changed to green.
How can i changed to border color using control template with DataTemplate trigger. My Goal is border color will be change using template(don't change programmatically)
Screenshot will be attached.enter image description here
You can create a property called for example IsColorChanged and bind to your DataTrigger and when button is clicked set this boolean typed property to true on the code side then DataTrigger will set to background property of your border to the green.
<Grid>
<Border BorderThickness="2" CornerRadius="4">
<Border.Style>
<Style TargetType="{x:Type Border}">
<Style.Triggers>
<DataTrigger Binding="{Binding IsColorChanged}" Value="True">
<Setter Property="Background" Value="Green"/>
</DataTrigger>
</Style.Triggers>
</Style>
</Border.Style>
</Border>
</Grid>
Suppose I have n number of rectangles.
I want them to behave such that when I click on any rectangle it should be filled white and all other should be filled with black color.
I know that I can create a style. But while creating style I can tell the trigger that fill the rectangle with black color but how can I say that fill all the remaining rectangles with white color.
Can anyone suggest me?
I want just a small hint.
Don't make rectangles work like RadioButtons, make RadioButtons look like rectangles.I would suggest to use RadioButton instead and change template to make it look like rectangle. Then you can trigger change of background based on RadioButton.IsChecked property. This way RadioButton will take care of tick/untick operation and trigger background change in other RadioButtons in the same group.
<Style TargetType="{x:Type RadioButton}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type RadioButton}">
<Border BorderBrush="Black" BorderThickness="1" Background="Black" x:Name="PART_Border">
<ContentPresenter/>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="IsChecked" Value="True">
<Setter TargetName="PART_Border" Property="Background" Value="White"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
and use your RadioButton like this:
<RadioButton>
<RadioButton.Content>
<!-- content to be displayer inside border -->
</RadioButton.Content>
</RadioButton>
You've answered the question yourself. Take two radio buttons and try editing the template. Basically when you'll have the close look at the template you will find an ellipse with a dot whose visibility gets toggled off on mouse click
Instead of having the ellipse you can have a rectangle/border with some thickness and set its background color on mouse click
The idea is when mouse howler above TextBlock, new Image is appear and it possible to click on it. When mouse leave the TextBlock - Image should disappear.
Meanwhile I came to this, but still unable to continue:
<Style x:Key="HoverHighlightTextStyle" TargetType="TextBlock">
<Setter Property="FontSize" Value="16"/>
<Setter Property="FontWeight" Value="Normal"/>
<Setter Property="Margin" Value="3,0,3,0"/>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
</Trigger>
</Style.Triggers>
</Style>
Expected result
I suggest you to follow the below steps.
Create a stackpanel (orientation is set to horizontal) or any other appropriate control and add text box and image controls inside it.
Hide the borders of text box and the image controls so that only the stackpanel border is visible.
When the mouseover event fired, set the image control to be appeared.
When the mouseleave event fired, set the image control to be disappeared.
I haven't tested this. But this might help you to get an idea.
I find solution based on sa_ddam213 answer:
<TextBlock x:Name="txtblkSelectedItem" Text="My Textblock">
<TextBlock.ToolTip>
<ToolTip PlacementTarget="{Binding ElementName=txtblkSelectedItem}" Placement="Right" HorizontalOffset="-20">
<Image Source="http://stackoverflow.com/users/flair/1849109.png" Width="10" Height="10"/>
</ToolTip>
</TextBlock.ToolTip>
The idea, is positioning tooltip inside textblock can be achived by using ToolTip
Placement="Right" HorizontalOffset="-20"
properties
My problem:
I haven't been able to figure out how I inside the 'Setter.Value' field of a setter for a property A in a style targeting a particular control can do a binding to a property B of that particualr control. More specifically I want to use the Foreground brush value on a graphical element inside the visual tree of the Content property of a Button. this will ensure that the graphical element always has the foreground color set for this button control.
What I try to achive:
I'm working on a WPF-application where I have three button controls:
DefaultButton
SpecialButton
ExtendedSpecialButton
The DefaultButton is where I define the style of buttons in the application through a style with a ControlTemplate.
The SpecialButton introduces a new property not supposed to be used for general buttons. This property will be represented by one visual state that I define through a style setter. Else from that it shall be identical in apperance to the DefaultButton.
I define the style of this SpecialButton by basing it on the style of the DefaultButton. In this style there is no ControlTemplate only a MultiTrigger-response on the basis of a couple of property conditions setting av a couple of visual properties:
<Style x:Key="SpecialButtonStyle" TargetType="{x:Type MyControls:SpecialButton}" BasedOn="{StaticResource DefaultButtonStyle}">
<Style.Triggers>
<MultiTrigger>
<MultiTrigger.Conditions>
<Condition Property="IsActive" Value="false"/>
<Condition Property="IsMouseOver" Value="false"/>
</MultiTrigger.Conditions>
<Setter Property="BorderBrush" Value="{DynamicResource ButtonDisabledBorder}" />
<Setter Property="Background" Value="{DynamicResource ButtonDisabledBg}" />
</MultiTrigger>
</Style.Triggers>
</Style>
All this worked great.
The next step is also no problem:
I wanted to base the ExtendedSpecialButton on the SpecialButton and set a default shape content inside the button.
<Style x:Key="ExtendedSpecialButtonStyle" TargetType="{x:Type MyControls:ExtendedSpecialButton}" BasedOn="{StaticResource SpecialButtonStyle}">
<Setter Property="Content">
<Setter.Value>
<Rectangle Fill="Black" Height="5" Width="15"></Rectangle>
</Setter.Value>
</Setter>
</Style>
The original style of DefaultButton is still present - the added visual state responding to the IsActiveProperty of the SpecialButton is still with us - and the ExtendedSpecialButton also inherited the visual behaviour created by the MultiTrigger of the SpecialButton.
I also successfully displayed a graphical element that this ExtendedSpecialButton should have.
However I wanted the fill of this graphical element to use the Foreground color. This foreground color is originally styled in the DefaultButton and works just fine for the two first buttons.
The code below is how I currently thought such a binding should be done. But this does not work:
<Style x:Key="ExtendedSpecialButtonStyle" TargetType="{x:Type MyControls:ExtendedSpecialButton}" BasedOn="{StaticResource SpecialButtonStyle}">
<Setter Property="Content">
<Setter.Value>
<Rectangle Fill="{Binding RelativeSource={RelativeSource TemplatedParent}}" Height="6" Width="20"></Rectangle>
</Setter.Value>
</Setter>
</Style>
Does anyone know what I could do to set up the binding so that it does what I intended it to do?
I am attempting to create a LinkLabel control for WPF. Essentially, I'm going to create the LinkLabel from a TextBlock and handle MouseEnter, MouseLeave, and MouseLeftButtonUp events. In the back end I have a base class that has properties that you would expect to see with a LinkLabel. With most other clickable controls in WPF, there is a default MouseEnter animation where the control becomes Ice Blue. I would like to duplicate this behavior when the mouse cursor enters over the TextBlock. I'm not sure if I'm needing to derive from ButtonBase or something along those lines. I have a I am able to change the cursor to a hand, and handle the event for when the "LinkLabel" is clicked. If accessing this seemingly default color changing animations, then I just may have to resort to a simple foreground color swap without the smooth transition. If anyone has created a custom WPF LinkLabel before or has any advice into the matter your input would be much appreciated.
You can create the equivalent of WinForms' LinkLabel right now using a combination of TextBlock and HyperLink:
<TextBlock>Here is a <Hyperlink NavigateUri="http://example.com">link</Hyperlink></TextBlock>
You won't get the "ice blue" mouse-over effect, but you will get the hand cursor. I'm sure you can introduce your mouse-over effects using a simple style trigger.
The "NavigateUri" property works in navigation-style applications where the hyperlink is inside a Frame control. In a standard WPF application you'll want to handle the Hyperlink's Click event instead and use Process.Start to kick off a web browser with the correct URL.
I just created a style for a button and apply a style to a button whenever you want LinkLabel look. Click event of button is used to perform a function when the text is clicked.
<Style x:Key="LinkLabelButtonStyle" TargetType="Button">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Foreground" Value="CornflowerBlue"></Setter>
</Trigger>
</Style.Triggers>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Border Background="Transparent">
<ContentPresenter/>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Setter Property="ContentTemplate">
<Setter.Value>
<DataTemplate>
<TextBlock TextDecorations="Underline" Text="{TemplateBinding Content}"></TextBlock>
</DataTemplate>
</Setter.Value>
</Setter>
<Setter Property="Foreground" Value="DarkBlue"></Setter>
<Setter Property="MinWidth" Value="90"></Setter>
<Setter Property="HorizontalAlignment" Value="Left"></Setter>
<Setter Property="Padding" Value="5"></Setter>
<Setter Property="Margin" Value="5"></Setter>
<Setter Property="Cursor" Value="Hand"></Setter>
</Style>
You can place above style in the Window.Resources so you can use it in entire window.
Then apply the style to a button whenever you want LinkLabel look.
<Button Name="LinkLabelLookALikeButton" Content="Text goes here" Style="{StaticResource LinkLabelButtonStyle}" Click="Event_Goes_Here">
</Button>
Hope this helps!