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I just started getting a weird printf output, has anyone ever seen this? Any idea what it could be caused by?
http://imgur.com/4Mt6xdi
Edit
Here's the code. I'm new to c so if anything (even if it's not causing the error) looks wrong or uncommon please tell me.
printf(f2,"%8.31f\t%8.31f\n",x[0],x[2]);
fprintf(f2,"%8.31f\t%8.31f\n",x[1],x[2]);
In the code you write:
if (x[0]*oldx<0)
{
printf(f2,"%8.31f\t%8.31f\n",x[0],x[2]);
fprintf(f2,"%8.31f\t%8.31f\n",x[1],x[2]);
}
where f2 is a pointer to FILE, which shall not be passed as the first parameter of printf. Just remove it.
At least one problem is on lines 96-97:
printf(f2,"%8.31f\t%8.31f\n",x[0],x[2]);
fprintf(f2,"%8.31f\t%8.31f\n",x[1],x[2]);
The first line should call fprintf, not printf.
Any compiler should give you at least a warning for calling printf with a FILE* as the first argument. Did you see such a warning? If so, why did you ignore it?
Compiling with additional warnings enabled should show you a number of other problems. Fix those before doing anything else.
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I have experienced a strange problem when using assert in my program.
The program does not terminate even when I add a line of codeassert(false).
But the assert works when I write several lines of sample code. Anybody know why it happened?
If you have:
#define NDEBUG
this turns all assert's into nop's.
If you have differing behaviour, depending on the amount of code, then I guess you don't have NDEBUG defined and I would guess the compiler is simply compiling out the redundant code.
More details about environment are required, however, you give a definitive answer.
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I know it is not recommended to post code as an image, since I am getting a formatting error when trying to post code on here. Anyway, I am trying to write a simple C program to count number of words, characters, newlines using do while loop. However, the output is not as expected. Please help!
Instead of a do-while, you should try using while. Since your code starts off by checking whether a is any of your if cases, it goes to the else case, and increments the New line variable. If possible, could you share the output screen.
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thanks for your help.
I'm trying to similate a simplified version of ARM, and I have a very weird error in c http://pastebin.com/3XRdngty .
I don't understant why in the function executer_code(),
the for doesn't work ...
I mean it should be looping untill the variable "i" is equal to the variable nombre_instruction, but it turns out that the variable "nombre_instruction" is the right value the first time it goes in the for, but the second time it doesn't go in the for because its value changed to 0, I search on the internet if someone has the same kind of error, and i didn't find anything.I reread my code but still I cannot figure out why it does this, 3 hours has passed already.
And thank you again for you help :)
This is taken from your code:
char *compar;
if(i==0){
sprintf(&compar,"%c%c%c%c",code[0],code[1],code[2],code[3]);
}
The problem here is that you declare compar as a pointer to char, but it is uninitialized. So, it has an undefined value. When you fill it with sprintf, you just write somewhere in the memory, and apparently, you write over the variable nombre_instruction.
Solution:
char compar[200];
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So lets say I have received a message that resembles the following
"L2N5*8R10!11T0A1K3Y14#4W7O6O9C12R13"
and I am expected to sort out the characters in accordance to the numbers succeeding them and change the characters that are not letters into a space. I have no problem doing the sorting out part, I am only having a trouble while trying to write a function that will change those characters into space.
The out put should be something like this
TALK NOW OR CRY
but I am getting
TALK#NOW*OR!CRY
Can anyone help me figure out what my function should look like so that I can be able to change the characters into space??
Unless you show your code, we'll only be able to guess!!
However, as a general suggestion, I would recommended, you should check each entry against isalpha(). In case you got a return value of 0, replace the entry with a .
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#include<stdio.h>
void main(){
if(printf("Hello World")){
}
}
this is editted which i copied from the compiler ...
Try this its truly working and print as Hello World
You have to remember that a function call is an expression, and that in C you can have any expression as the condition for an if statement.
Not sure what the problem is here.
printf() is just a function. It returns a value (an int that says how many characters were printed).
So when used as the controlling expression in an if, of course it's called ("evaluated") since the if needs to know the return value.
Calling printf() has the usual side-effect of generating output.
I've tried running this and got following Build messages
However, printf() returns the number of characters it has printed , Unless you put printf("") as condition, it will evaluate to be true. ;)
printf("Hello World") is an expression not statement, so you don't need semi-colon there.