My tables combined look something like:
Seller_ID |From |To |Depart_Date |Arrival_Date
-------------------------------------------------------------------------------------
Paul |office |client_23 |10/20/2015 3:30:00 PM |10/21/2015 7:54:00 AM
Paul |client_23 |client_ 88fe |10/21/2015 11:55:00 AM |10/22/2015 8:11:00 PM
Paul |client_88fe |client_avr4 |10/23/2015 3:57:00 PM |10/26/2015 11:27:00 AM
Paul |client_avr4 |home |10/26/2015 5:28:00 PM |10/28/2015 3:39:00 PM
I do not have a indicator like first visit, second visit, third visit...
First visit always has 'From' = office and last visit always has 'To' = home.
Only way to make the sequence is either go backwards by Dates (or by From-To ??)
My desired outcome would be :
|Seller_ID |from |office_departure |client1 |clt1_arrival |clt1_departure |client2 |clt2_arrival |clt2_departure |client3 |clt3_arrival |clt3_departure |home_arrival
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
|Paul |office |10/20/2015 3:30:00PM |client_23 |10/21/2015 7:54:00 AM|10/21/2015 11:55:00 AM |client_ 88fe|10/22/2015 8:11:00 PM |10/23/2015 3:57:00 PM |client_avr4 |10/26/2015 11:27:00 AM |10/26/2015 5:28:00 PM |10/26/2015 5:28:00 PM
Any help is apreciated!
thanks in advance.
If your case is just one trip per seller, or that you have another field not shown here that you can use in group by, you can use something like this:
select
Seller_ID,
max(case when RN = 1 then [From] end),
max(case when RN = 1 then [Depart_Date] end),
max(case when RN = 1 then [Arrival_Date] end),
max(case when RN = 2 then [From] end),
max(case when RN = 2 then [Depart_Date] end),
max(case when RN = 2 then [Arrival_Date] end)
from (
select
row_number() over (partition by Seller_ID
order by Depart_Date asc) as RN,
*
from Table1
) X
group by Seller_ID
Result:
Seller_ID
Paul office October, 20 2015 15:30:00 October, 21 2015 07:54:00 client_23 October, 21 2015 11:55:00 October, 22 2015 20:11:00
Example in SQL Fiddle
If you don't have any field for tracking the number of trip, you can use running total in order of departure date for statement case when [From] = 'office' then 1 else 0 end partitioned by Seller_ID, that will then assign trip number for the rows.
I am running SQL Server 2014 and I have the following T-SQL query:
USE MYDATABASE
SELECT *
FROM RESERVATIONLIST
WHERE [MTH] IN ('JANUARY 2015','FEBRUARY 2015')
RESERVATIONLIST mentioned in the code above is a view. The query gives me the following output (extract):
ID NAME DOA DOD Nights Spent MTH
--------------------------------------------------------------------
251 AH 2015-01-12 2015-01-15 3 JANUARY 2015
258 JV 2015-01-28 2015-02-03 4 JANUARY 2015
258 JV 2015-01-28 2015-02-03 2 FEBRUARY 2015
The above output consist of around 12,000 records.
I need to modify my query so that it eliminates all duplicate ID and give me the following results:
ID NAME DOA DOD Nights Spent MTH
--------------------------------------------------------------------
251 AH 2015-01-12 2015-01-15 3 JANUARY 2015
258 JV 2015-01-28 2015-02-03 4 JANUARY 2015
I tried something like this, but it's not working:
USE MYDATABASE
SELECT *
FROM RESERVATIONLIST
WHERE [MTH] IN ('JANUARY 2015', 'FEBRUARY 2015')
GROUP BY [ID]
HAVING COUNT ([MTH]) > 1
Following query will return one row per ID :
SELECT * FROM
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY ID ORDER BY (SELECT NULL)) rn FROM RESERVATIONLIST
WHERE [MTH] IN ('JANUARY 2015','FEBRUARY 2015')
) T
WHERE rn = 1
Note : this will return a random row from multiple rows having same ID. IF you want to select some specific row then you have to define it in order by. For e.g. :
SELECT * FROM
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY ID ORDER BY DOA DESC) rn FROM RESERVATIONLIST
WHERE [MTH] IN ('JANUARY 2015','FEBRUARY 2015')
) T
WHERE rn = 1
definitely, it will return the row having max(DOA).
You are trying to do a GROUP BY statement which IMHO is the right way to go. You should formulate all columns that are a constant, and roll-up the others. Depending on the value of DOD and DOA I can see two solutions:
SELECT ID,NAME,DOA,DOD,SUM([Nights Spent]) as Nights,
min(MTH) as firstRes, max(MTH) as lastRes
FROM RESERVATIONLIST
GROUP BY ID,NAME,DOA,DOD
OR
SELECT ID,NAME,min(DOA) as firstDOA,max(DOD) as lastDOD,SUM([Nights Spent]) as Nights,
min(MTH) as firstRes, max(MTH) as lastRes
FROM RESERVATIONLIST
GROUP BY ID,NAME
I have the below data, and I performed a ROW_NUMBER(partition by ID order by YEAR) function based on year which's ranking my data as below.
I want to bring in name for every id based on their latest year. I want to bring in NULL data if that's the only data available and bring in latest NON NULL data for every other record. But rownumber only lets me bring in recent name which could be NULL. How do I query below data to bring in most recent NON NULL name?
ID year name rownum
10 2011 abc 1
10 2010 abc 2
11 2011 ghi 1
11 2010 ghi 1
13 2010 NULL 1
13 2009 jkl 2
14 2014 NULL 1
14 2014 mno 2
15 2015 NULL 1
I want to bring in names jkl, mno for ID's 13 and 14 and not NULLS in my final result. Any suggestion on how to achieve that?
The output I desire is below - I want to display data for ROW NUM=1
10 2011 abc
11 2011 ghi
13 2009 jkl
14 2014 mno
15 2015 NULL
Sort non-null rows ahead of null rows:
select ID, year, name
from (select *,
row_number() over (partition by ID
order by case when name is null then 1 else 0 end, year desc) as RN
from #t) _
where rn = 1
See also SQL Server equivalent to Oracle's NULLS FIRST?, SQL Server ORDER BY date and nulls last &
I have 2 tables with the following datas in them:-
Company
CompanyId CompanyName
1 Company1
2 Company2
3 Company3
Employees
EmployeeId EmployeeName CompanyId StartDate
1 Employee1 1 12/21/2011
2 Employee2 1 01/20/2012
3 Employee3 2 03/23/2012
4 Employee4 2 07/15/2012
5 Employee5 2 01/20/2013
6 Employee6 3 12/17/2013
Now i want to check, How many people were recruited in the team in the specified month and year? I have the storage table as follows:-
RecruiterIndicator
CompanyId Year Month EmployeeRecruited
1 2011 12 1
1 2012 1 1
2 2012 3 1
2 2012 7 1
2 2013 1 1
3 2013 12 1
This should be a merge stored procedure that should update the data if it is present for the same month year and company and insert if that is not present? The loop would start from a particular date that can be an parameter and it would loop through the current month.
Please help me with this
Thanks
Vishal
SELECT YEAR(StartDate) AS [Year], MONTH(StartDate) AS [Month], COUNT(*) EmpTotal
FROM Employees
GROUP BY YEAR(StartDate), MONTH(StartDate)
If you want to see the Total Employees by company as well you can do something like this
SELECT YEAR(StartDate) AS [Year], MONTH(StartDate) AS [Month]
,C.CompanyName , COUNT(E.EmployeeId) EmpTotal
FROM Employees E INNER JOIN Company C
ON E.CompanyId = C.CompanyId
GROUP BY YEAR(StartDate), MONTH(StartDate) ,C.CompanyName
I have a query that pulls out month/year totals for customers, and add the ntile ranking. If I were to be able to pull out the max subtotal for ntile 1, 2, 3, 4, and 5, I would ALMOST get what I'm after, but I do not know how to proceed.
For example, the result I want would look something like:
Month Year CustomerCode SubTotal ntile
1 2012 CCC 131.45 1
1 2012 CCC 342.95 2
1 2012 ELITE 643.92 3
1 2012 CCC 1454.05 4
1 2012 CCC 12971.78 5
2 2012 CCC 135.99 1
2 2012 CCI 370.47 2
2 2012 NOC 766.84 3
2 2012 ELITE 1428.26 4
2 2012 VBC 5073.20 5
3 2012 CCC 119.02 1
3 2012 CCC 323.78 2
3 2012 HUCC 759.66 3
3 2012 ELITE 1402.95 4
3 2012 CCC 7964.20 5
EXCEPT - I would expect ranking to be different customers like for month 2, but my base query isn't giving me that result - and I obviously don't know how to get it in T-SQL on SQL SERVER 2005 - in fact I'm not sure what I'm getting.
My next option is to pull a DataTable in C# and do some gymnastics to get there, but there has to be an easier way :)
My base query is
SELECT
i.DateOrdered
,LTRIM(STR(DATEPART(MONTH,i.DateOrdered))) AS [Month]
,LTRIM(STR(YEAR(i.Dateordered))) AS [Year]
,c.CustomerCode
,SUM(i.Jobprice) AS Subtotal
,NTILE(5) OVER(ORDER BY SUM(i.JobPrice)) AS [ntile]
FROM Invoices i
JOIN
Customers c
ON i.CustomerID = c.ID
WHERE i.DateOrdered >= '1/1/2012'
AND i.DateOrdered <= '9/30/2012'
GROUP BY YEAR(i.DateOrdered), MONTH(i.DateOrdered), i.DateOrdered, c.CustomerCode
ORDER BY LTRIM(STR(DATEPART(MONTH,i.DateOrdered))),
TRIM(STR(YEAR(i.Dateordered))),
SUM(i.JobPrice), c.CustomerCode ASC
I'd really appreciate help getting this right.
Thanks in advance
Cliff
If I read you correctly, what you are after is
For each month in the range,
Show 5 customers who have the greatest SUMs in that month
And against each customer, show the corresponding SUM.
In that case, this SQL Fiddle creates a sample table and runs the query that gives you the output described above. If you wanted to see what's in the created tables, just do simple SELECTs on the right panel.
The query is:
; WITH G as -- grouped by month and customer
(
SELECT DATEADD(D,1-DAY(i.DateOrdered),i.DateOrdered) [Month],
c.CustomerCode,
SUM(i.Jobprice) Subtotal
FROM Invoices i
JOIN Customers c ON i.CustomerID = c.ID
WHERE i.DateOrdered >= '1/1/2012' AND i.DateOrdered <= '9/30/2012'
GROUP BY DATEADD(D,1-DAY(i.DateOrdered),i.DateOrdered), c.CustomerCode
)
SELECT MONTH([Month]) [Month],
YEAR([Month]) [Year],
CustomerCode,
SubTotal,
Rnk [Rank]
FROM
(
SELECT *, RANK() OVER (partition by [Month] order by Subtotal desc) Rnk
FROM G
) X
WHERE Rnk <= 5
ORDER BY Month, Rnk
To explain, the first part (WITH block) is just a fancy way of writing a subquery, that GROUPs the data by month and Customer. The expression DATEADD(D,1-DAY(i.DateOrdered),i.DateOrdered) turns every date into the FIRST day of that month, so that the data can be easily grouped by month. The next subquery written in traditional form adds a RANK column within each month by the subtotal, which is finally SELECTed to give the top 5*.
Note that RANK allows for equal rankings, which may end up showing 6 customers for a month, if 3 of them are ranked equally at position 4. If that is not what you want, then you can change the word RANK to ROW_NUMBER which will randomly tie-break between equal Subtotals.
The query needs to be modified to only get the month and year dateparts. The issue you are having with the same customer showing multiple times in the same month is due to the inclusion of i.DateOrdered in the select and group by clauses.
The following query should give you what you need. Also, I suspect it is a typo on the next to last line of the query, but tsql doesn't have a TRIM() function only LTRIM and RTRIM.
SELECT
LTRIM(STR(DATEPART(MONTH,i.DateOrdered))) AS [Month]
,LTRIM(STR(YEAR(i.Dateordered))) AS [Year]
,c.CustomerCode
,SUM(i.Jobprice) AS Subtotal
,NTILE(5) OVER(ORDER BY SUM(i.JobPrice)) AS [ntile]
FROM Invoices i
JOIN
Customers c
ON i.CustomerID = c.ID
WHERE i.DateOrdered >= '1/1/2012'
AND i.DateOrdered <= '9/30/2012'
GROUP BY YEAR(i.DateOrdered), MONTH(i.DateOrdered), c.CustomerCode
ORDER BY LTRIM(STR(DATEPART(MONTH,i.DateOrdered))),
LTRIM(STR(YEAR(i.Dateordered))),
SUM(i.JobPrice), c.CustomerCode ASC
This gives these results
Month Year CustomerCode Subtotal ntile
1 2012 ELITE 643.92 2
1 2012 CCC 14900.23 5
2 2012 CCC 135.99 1
2 2012 CCI 370.47 1
2 2012 NOC 766.84 3
2 2012 ELITE 1428.26 4
2 2012 VBC 5073.20 4
3 2012 HUCC 759.66 2
3 2012 ELITE 1402.95 3
3 2012 CCC 8407.00 5
Try this:
declare #tab table
(
[month] int,
[year] int,
CustomerCode varchar(20),
SubTotal float
)
insert into #tab
select
1,2012,'ccc',131.45 union all
select
1,2012,'ccc',343.45 union all
select
1,2012,'ELITE',643.92 union all
select
2,2012,'ccc',131.45 union all
select
2,2012,'ccc',343.45 union all
select
2,2012,'ELITE',643.92 union all
select
3,2012,'ccc',131.45 union all
select
3,2012,'ccc',343.45 union all
select
3,2012,'ELITE',643.92
;with cte as
(
select NTILE(3) OVER(partition by [month] ORDER BY [month]) AS [ntile],* from #tab
)
select * from cte
Even in your base query you need to add partition by, so that you will get correct output.
I can't see how to solve this problem without double ranking:
You need to get the largest sums per customer & month.
You then need, for every month, to retrieve the top five of the found sums.
Here's how I would approach this:
;
WITH MaxSubtotals AS (
SELECT DISTINCT
CustomerID,
MonthDate = DATEADD(MONTH, DATEDIFF(MONTH, 0, DateOrdered), 0),
Subtotal = MAX(SUM(JobPrice)) OVER (
PARTITION BY Customer, DATEADD(MONTH, DATEDIFF(MONTH, 0, DateOrdered), 0)
ORDER BY SUM(JobPrice)
)
FROM Invoices
GROUP BY
CustomerID,
DateOrdered
),
TotalsRanked AS (
SELECT
CustomerID,
MonthDate,
Subtotal,
Ranking = ROW_NUMBER() OVER (PARTITION BY MonthDate ORDER BY Subtotal DESC)
FROM MaxDailyTotals
)
SELECT
Month = MONTH(i.MonthDate),
Year = YEAR(i.MonthDate),
c.CustomerCode,
i.Subtotal,
i.Ranking
FROM TotalsRanked i
INNER JOIN Customers ON i.CustomerID = c.ID
WHERE i.Ranking <= 5
;
The first CTE, MaxSubtotals, determines the maximum subtotals per customer & month. Involving DISTINCT and a window aggregating function, it is essentially a "shortcut" for the following two-step query:
SELECT
CustomerID,
MonthDate,
Subtotal = MAX(Subtotal)
FROM (
SELECT
CustomerID,
MonthDate = DATEADD(MONTH, DATEDIFF(MONTH, 0, DateOrdered), 0),
Subtotal = SUM(JobPrice)
FROM Invoices
GROUP BY
CustomerID,
DateOrdered
) s
GROUP BY
CustomerID,
MonthDate
The other CTE, TotalsRanked, simply adds ranking numbers for the found susbtotals, partitioning by customer and month. As a final step, you only need to limit the rows to those that have rankings not greater than 5 (or whatever you might choose another time).
Note that using ROW_NUMBER() to rank the rows in this case guarantees that you'll get no more than 5 rows with the Ranking <= 5 filter. If there were two or more rows with the same subtotal, the would get distinct rankings, and in the end you might end up with an output like this:
Month Year CustomerCode Subtotal Ranking
----- ---- ------------ -------- -------
1 2012 CCC 1500.00 1
1 2012 ELITE 1400.00 2
1 2012 NOC 900.00 3
1 2012 VBC 700.00 4
1 2012 HUCC 700.00 5
-- 1 2012 ABC 690.00 6 -- not returned
-- 1 2012 ... ... ...
Even though there might be other customers with Subtotals of 700.00 for the same month, they wouldn't be returned, because they would be assigned rankings after 5.
You could use RANK() instead of ROW_NUMBER() to account for that. But note that you might end up with more than 5 rows per month then, with an output like this:
Month Year CustomerCode Subtotal Ranking
----- ---- ------------ -------- -------
1 2012 CCC 1500.00 1
1 2012 ELITE 1400.00 2
1 2012 NOC 900.00 3
1 2012 VBC 700.00 4
1 2012 HUCC 700.00 4
1 2012 ABC 700.00 4
-- 1 2012 DEF 690.00 7 -- not returned
-- 1 2012 ... ... ...
Customers with subtotals less than 700.00 wouldn't make it to the output because they would have rankings starting with 7, which would correspond to the ranking of the first under-700.00 sum if ranked by ROW_NUMBER().
And there's another option, DENSE_RANK(). You might want to use it if you want up to 5 distinct sums per month in your output. With DENSE_RANK() your output might contain even more rows per month than it would have with RANK(), but the number of distinct subtotals would be exactly 5 (or fewer if the original dataset can't provide you with 5). That is, your output might then look like this:
Month Year CustomerCode Subtotal Ranking
----- ---- ------------ -------- -------
1 2012 CCC 1500.00 1
1 2012 ELITE 1400.00 2
1 2012 NOC 900.00 3
1 2012 VBC 700.00 4
1 2012 HUCC 700.00 4
1 2012 ABC 700.00 4
1 2012 DEF 650.00 5
1 2012 GHI 650.00 5
1 2012 JKL 650.00 5
-- 1 2012 MNO 600.00 5 -- not returned
-- 1 2012 ... ... ...
Like RANK(), the DENSE_RANK() function assigns same rankings to identical values, but, unlike RANK(), it doesn't produce gaps in the ranking sequence.
References:
OVER Clause (Transact-SQL)
Ranking Functions (Transact-SQL)