Splitting a Character string in C programming - c

Question

I need to split a string and need to store in two seperate variables. The string contains a tab space. so it need to be seperated from the tab space
EG: the string looks like this
Sony <TAB> A Hindi channel.
I need to store Sony in one variable say char a[6]; and A Hindi Channel in another Variable say char b[20];
How can do this?

Answer 1

Tokenize string for a lot of programming language: link
In your case < tab > is a special character and it can be indicated as '\t'.
If you are using C programming language
#include<string.h>
#include<stdio.h>
#include<stdlib.h>
int main(void) {
char *a[5];
const char *s="Sony\tA Hindi channel.";
int n=0, nn;
char *ds=strdup(s);
a[n]=strtok(ds, "\t");
while(a[n] && n<4) a[++n]=strtok(NULL, "\t");
// a[n] holds each token separated with tab
free(ds);
return 0;
}
For C++ without using boost library:
#include <string>
#include <sstream>
#include <vector>
#include <iterator>
#include <iostream>
#include <algorithm>
int main() {
std::string s = "Sony\tA Hindi channel.";
std::vector<std::string> v;
std::istringstream buf(s);
for(std::string token; getline(buf, token, '\t'); )
v.push_back(token);
// elements of v vector holds each token
}
Using C++ and boost: How to tokenize a string in C++
#include <iostream>
#include <string>
#include <boost/foreach.hpp>
#include <boost/tokenizer.hpp>
using namespace std;
using namespace boost;
int main(int, char**) {
string text = "Sony\tA Hindi channel.";
char_separator<char> sep("\t");
tokenizer< char_separator<char> > tokens(text, sep);
BOOST_FOREACH (const string& t, tokens) {
cout << t << "." << endl;
}
}

Answer 2

Probably the strtok function is that you are looking

Answer 3

My C is old but something like that should work:
#include <stdio.h>
int getTabPosition (char str [])
{
int i = 0;
//While we didn t get out of the string
while (i < strlen(str))
{
//Check if we get TAB
if (str[i] == '\t')
//return it s position
return i;
i = i + 1;
}
//If we get out of the string, return the error
return -1;
}
int main () {
int n = 0;
//Source
char str [50] = "";
//First string of the output
char out1 [50] = "";
//Second string of the output
char out2 [50] = "";
scanf(str, "%s");
n = getTabPosition(str);
if (n == -1)
return -1;
//Copy the first part of the string
strncpy(str, out1, n);
//Copy from the end of out1 in str to the end of str
//str[n + 1] to skip the tab
memcpy(str[n+1], out2, strlen(str) - n);
fprintf(stdout, "Original: %s\nout1=%s\nout2=%s", str, out1, out2);
return 0;
}
Untested, but the principe is there