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I really don't understands this code:
#include <stdio.h>
int main (int argument c, char *argument v[])
{
return 0;
}
What does this code mean? How does it converts to other formation of coding?
This is (almost) the simplest C/C++ program. (It works for both languages.) It does nothing other than return 0, which signifies successful execution.
It should read
int main(int argc, char **argv)
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Hi I was wondering if there is an alternative of str.substring() in string.h. If not, what is an efficient alternative?
Assuming that we all agree that using c++ it is safer and more professional to use the standard library tools.
That said, if we're talking about C and not C++, this should be one of the ways to extract a substring with the "string.h" library:
#include <stdio.h>
#include <string.h>
int main() {
char test[] = "abcdef";
char subtext[3];
memcpy(subtext, &test[1], 2); //Result: "bc"
subtext[2] = '\0';
printf("%s", subtext);
return 0;
}
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Can I make a float number in a C program always round up
You can use the ceil() function. For example:
#include <stdio.h>
#include <math.h>
int main () {
float val1 = 1.6;
printf ("Round up to %.1lf\n", ceil(val1));
return(0);
}
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I just started programming and have a question. I have a example input from command line: "number:10" which is "number:" followed by a number. I want to check if the character after "number:" is a number:
int main(int argc, char **argv)
{
if(isdigit(*argv[2]+7)){
printf("correct");
}
return 0;
}
It doesn't work. How can I read only the number in the input string?
*argv[2] is 'n'. *(argv[2]+7) is correct
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I was trying to explain to my friend something about C coding and he asked me why his code (with "scanf") didn't work.
#include
int main() {
char x=scanf("%c",&x);
printf("%c\n",x);
return 0;
}
and this one yes
#include <stdio.h>
int main()
{
int k;
char x=getchar
printf("%c\n",x);
return 0;
}
When scanf completes, x contains the character that was read. However, that value is immediately overwritten when x is assigned the return value of scanf, which is the number of items successfully matched or EOF in the event of an error.
If you call scanf without assigning the return value to x you should get the expected result.
For example, this should work.
char x;
scanf("%c",&x);
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#include <stdio.h>
int main()
{
int var=0;
for(; var++; printf("%d",var));
printf("%d", var);
}
Please explain to me this C code. How is the output 1?
You might be confused because of the wrong code indentation. Your code is:
for(; var++; printf("%d",var))
;
printf("%d", var);
So you always get the output of the second printf. As var is initialized to 0 and var++ (the for-condition) is always executed, you end up with var==1.