I'm trying to count Holiday bookings (B.ID) for dates 2 days either side of today.
It works but my results are separated as I have to introduce the end date of
the holiday too, which varies for each start date (holidays have different durations).
The separates out my counts. What I need is one count for each date. Is there a way of working round this? I kinda just want to exclude the vwReturnDate from the group by but have to put it there as I've used it in my count.
In English I want - For each [date] count the number of [B.id] where [B.Depart] <= [date] and [vwReturnDate] > [date]
DECLARE #startDate DATE
DECLARE #endDate DATE
SET #startDate = Getdate()-2
SET #endDate = Getdate()+2;
WITH dates(Date) AS
( SELECT #startdate as Date
UNION ALL
SELECT DATEADD(d,1,[Date])
FROM dates
WHERE DATE < #enddate )
SELECT
[Date] as 'Calendar Date',
--CONVERT(VARCHAR(10), [Date],103) AS 'Date'
-- ,CONVERT(CHAR(2), [Date], 113) AS 'Day'
-- ,CONVERT(CHAR(4), [Date], 100) AS 'Month'
-- ,CONVERT(CHAR(4), [Date], 120) AS 'Year',
Case when B.Depart <= [date] AND vwR.ReturnDate >=[date] then count (B.ID) end AS 'Number of holidays live on date'
FROM [dates]
left join Booking B on B.depart=[Date]
inner join Quote Q on Q.ID=B.QuoteID
inner join vwReturnDate vwR on vwR.ID=B.ID
Group by [date], B.depart, vwR.ReturnDate
order by [date]
OPTION (MAXRECURSION 0)
GO
Related
I am trying to create a 12 month grid view of all questions that were submitting for each month in that 12 month period.
SELECT
YEAR(h.metaInsert) [Year],
MONTH(h.metaInsert) [Month],
DATENAME(MONTH,h.metaInsert) [Month Name],
COUNT(1) [Total Documents]
FROM
Document_Count_History AS h
WHERE
YEAR(h.metaInsert) = 2017
GROUP BY
YEAR(h.metaInsert), MONTH(h.metaInsert), DATENAME(MONTH, h.metaInsert)
ORDER BY
1, 2
This returns the data perfectly for the months that have it, but I get no data returned for those with 0 records for that specific month.
My goal is to see all 12 months along with the count of documents. If there are no documents, it will simply be a 0 for that month but it will be included in the result set.
How can I take what I have and apply the missing months?
You could use something like this to generate the sequence of months for your query:
declare #StartDate date = '20170101'
,#NumberOfYears int = 1;
;with Months as (
select top (12*#NumberOfYears)
[Month] = dateadd(Month, row_number() over (order by number) -1, #StartDate)
, NextMonth = dateadd(Month, row_number() over (order by number), #StartDate)
from master.dbo.spt_values
)
select
year(m.Month) [Year],
Month(m.Month) [Month],
datename(Month,m.Month) [Month Name],
count(h.*) [Total Documents]
from Months as m
left join Document_Count_History AS h
on h.metaInsert >= m.Month
and h.metaInsert < m.NextMonth
--where h.metaInsert >= '20170101'
group by m.Month
order by m.Month
Although you may want to consider adding a Calendar table, or Date Dimension.
Calendar and Numbers table references:
Generate a set or sequence without loops - 1 - Aaron Bertrand
The "Numbers" or "Tally" Table: What it is and how it replaces a loop - Jeff Moden
Creating a Date Table/Dimension in SQL Server 2008 - David Stein
Calendar Tables - Why You Need One - David Stein
Creating a date dimension or calendar table in SQL Server - Aaron Bertrand
An example months table:
create table dbo.Months(
MonthStart date not null primary key
, NextMonthStart date not null
, [Year] smallint not null
, [Month] tinyint not null
, [MonthName] varchar(16) not null
);
declare #StartDate date = '20100101'
,#NumberOfYears int = 30;
insert dbo.Months(MonthStart,NextMonthStart,[Year],[Month])
select top (12*#NumberOfYears)
[MonthStart] = dateadd(month, row_number() over (order by number) -1, #StartDate)
, NextMonthStart = dateadd(month, row_number() over (order by number), #StartDate)
, [year] = year(dateadd(month, row_number() over (order by number) -1, #StartDate))
, [Month] = Month(dateadd(month, row_number() over (order by number) -1, #StartDate))
, MonthName = datename(Month,dateadd(month, row_number() over (order by number) -1, #StartDate))
from master.dbo.spt_values;
and your query would simplify to:
select
m.[Year],
m.[Month],
m.[MonthName],
count(h.*) [Total Documents]
from Months as m
left join Document_Count_History AS h
on h.metaInsert >= m.MonthStart
and h.metaInsert < m.NextMonthStart
where m.Year = 2017
group by m.Month, m.Year, m.MonthName
order by m.MonthStart
You need a date dimension. Specifically, you need a table that has all the values for months. Then, you can do a left-join on the table that gets the totals, and pull out a sum value.
I would like to filter consecutive dates from my holiday table if any of the consecutive date is yesterday. Below is my code to get consecutive dates with row numbers.
SELECT
RW = ROW_NUMBER() OVER( PARTITION BY GRP ORDER BY HolidayDate),
HolidayDate
FROM
(SELECT
HolidayDate,
DATEDIFF(Day, '1900-01-01', HolidayDate) - ROW_NUMBER() OVER (ORDER BY HolidayDate) AS GRP,
HolidayType
FROM
Holiday) A
ORDER BY
HolidayDate
For example, yesterday's date is 03/14/2017. I need to get data from the Holiday table if there are any consecutive holidays involving this date.
Output should be null if there is no match else it should display dates as below
03/12/2017
03/13/2017
03/14/2017
Well, you are almost there!
Define "yesterday" as a parameter, since it is easy to find.
CREATE TABLE Holiday(
HolidayDate SMALLDATETIME PRIMARY KEY,
HolidayType VARCHAR(20)
);
INSERT INTO Holiday VALUES
('2016-12-25', 'A'), ('2016-12-26', 'A'), ('2017-01-01', 'A'),
('2017-04-12', 'A'), ('2017-04-13', 'A'), ('2017-04-14', 'A');
DECLARE #yesterday SMALLDATETIME;
SET #yesterday = '2017-04-13'; -- belongs to a group of consecutive holidays
-- SET #yesterday = '2017-01-01'; -- isolated holiday
-- SET #yesterday = '2017-02-10'; -- not a holiday
; WITH groups as
(
SELECT
HolidayDate,
DATEDIFF(Day, '1900-01-01', HolidayDate)
- ROW_NUMBER() OVER (ORDER BY HolidayDate) AS GRP,
HolidayType
FROM Holiday
),
consecutive as (
SELECT GRP FROM groups GROUP BY GRP HAVING COUNT(*) > 1
)
SELECT DISTINCT g2.HolidayDate, g2.HolidayType
FROM consecutive c
JOIN groups g1 ON c.GRP = g1.GRP
JOIN groups g2 ON g1.GRP = g2.GRP
WHERE g1.HolidayDate = #yesterday;
I am fairly new to SSIS, and now I have this requirement to exclude weekends in order to do a performance management. Now I have created a calendar and marked the weekends; what I am trying to do, using SSIS, is get the start and end date of every status and count how many weekends are there. I am kind of struggling to know which component to use to achieve this task.
So I have mainly two tables:
1- Table Calendar
2- Table History-Log
Calendar has the following columns:
1- ID
2- date
3- year
4- month
5- day of week
6- isweekend
History-Log has the following:
1- ID
2- Status
3- startdate
4- enddate
Your help is really appreciated.
I'm not an SSIS user, so apologies if this answer does not help, but if I wanted to get the result you describe, based on some test data:
DECLARE #Calendar TABLE (
ID INT,
[Date] DATETIME,
[Year] INT,
[Month] INT,
[DayOfWeek] VARCHAR(10),
IsWeekend BIT
)
DECLARE #HistoryLog TABLE (
ID INT,
[Status] INT,
StartDate DATETIME,
EndDate DATETIME
)
DECLARE #StartDate DATE = '20100101', #NumberOfYears INT = 10
DECLARE #CutoffDate DATE = DATEADD(YEAR, #NumberOfYears, #StartDate);
INSERT INTO #Calendar
SELECT ROW_NUMBER() OVER (ORDER BY d) AS ID,
d AS [Date],
DATEPART(YEAR,d) AS [Year],
DATEPART(MONTH,d) AS [Month],
DATENAME(WEEKDAY,d) AS [DayOfWeek],
CASE WHEN DATENAME(WEEKDAY,d) IN ('Saturday','Sunday') THEN 1 ELSE 0 END AS IsWeekend
FROM
(
SELECT d = DATEADD(DAY, rn - 1, #StartDate)
FROM
(
SELECT TOP (DATEDIFF(DAY, #StartDate, #CutoffDate))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
ORDER BY s1.[object_id]
) AS x
) AS y;
INSERT INTO #HistoryLog
SELECT 1, 3, '2016-01-05', '2016-01-20'
UNION
SELECT 2, 7, '2016-01-08', '2016-01-25'
UNION
SELECT 3, 4, '2016-01-01', '2016-02-03'
UNION
SELECT 4, 3, '2016-02-09', '2016-02-10'
I would use a query like this to return all of the HistoryLog records with a count of the number of weekend days between their StartDate and EndDate:
SELECT h.ID,
h.[Status],
h.StartDate,
h.EndDate,
COUNT(c.ID) AS WeekendDays
FROM #HistoryLog h
LEFT JOIN #Calendar c ON c.[Date] >= h.StartDate AND c.[Date] <= h.EndDate AND c.IsWeekend = 1
GROUP BY h.ID, h.[Status], h.StartDate, h.EndDate
ORDER BY 1
If you wanted to know the number of weekends, rather than the number of weekend days, we'd need to slightly amend this logic (and define how a range containing only one weekend day - or one starting on a Sunday and ending on a Saturday inclusive - should be handled). Assuming you just want to know how many distinct weekends are at least partially within the date range, you could do:
SELECT h.ID,
h.[Status],
h.StartDate,
h.EndDate,
COUNT(weekends.ID) AS Weekends
FROM #HistoryLog h
LEFT JOIN
(
SELECT c.ID,
c.[Date] AS SatDate,
DATEADD(DAY,1,c.[Date]) AS SunDate
FROM #Calendar c
WHERE c.[DayOfWeek] = 'Saturday'
) weekends ON h.StartDate BETWEEN weekends.SatDate AND weekends.SunDate
OR h.EndDate BETWEEN weekends.SatDate AND weekends.SunDate
OR (h.StartDate <= weekends.SatDate AND h.EndDate >= weekends.SunDate)
GROUP BY h.ID, h.[Status], h.StartDate, h.EndDate
How can I find the latest date in a column but constrain it between 2 dates
SELECT [Weight]
FROM [weighinevent] w
WHERE [Date] = (SELECT MAX([Date]) WHERE [Date] BETWEEN #StartDate AND #EndDate AND w.[userid] = #userid )
This is what I have. Is that correct?
No, it is not correct. Subqueries need to define the table too from which they are selecting. But you can order by the date and take only the first record
SELECT top 1 Weight
FROM weighinevent
WHERE Date BETWEEN #StartDate AND #EndDate
AND userid = #userid
ORDER BY Date DESC
Lets say I have following query:
SELECT top (5) CAST(Created AS DATE) as DateField,
Count(id) as Counted
FROM Table
GROUP BY CAST(Created AS DATE)
order by DateField desc
Lets say it will return following data set
DateField Counted
2016-01-18 34
2016-01-17 99
2016-01-14 1
2015-12-28 1
2015-12-27 6
But when I have Counted = 0 for certain Date I would like to get that in result set. So for example it should look like following
DateField Counted
2016-01-18 34
2016-01-17 99
2016-01-16 0
2016-01-15 0
2016-01-14 1
Thank you!
Expanding upon KM's answer, you need a date table which is like a numbers table.
There are many examples on the web but here's a simple one.
CREATE TABLE DateList (
DateValue DATE,
CONSTRAINT PK_DateList PRIMARY KEY CLUSTERED (DateValue)
)
GO
-- Insert dates from 01/01/2015 and 12/31/2015
DECLARE #StartDate DATE = '01/01/2015'
DECLARE #EndDatePlus1 DATE = '01/01/2016'
DECLARE #CurrentDate DATE = #StartDate
WHILE #EndDatePlus1 > #CurrentDate
BEGIN
INSERT INTO DateList VALUES (#CurrentDate)
SET #CurrentDate = DATEADD(dd,1,#CurrentDate)
END
Now you have a table
then you can rewrite your query as follows:
SELECT top (5) DateValue, isnull(Count(id),0) as Counted
FROM DateList
LEFT OUTER JOIN Table
on DateValue = CAST(Created AS DATE)
GROUP BY DateValue
order by DateValue desc
Two notes:
You'll need a where clause to specify your range.
A join on a cast isn't ideal. The type in your date table should match the type in your regular table.
One more solution as a single query:
;WITH dates AS
(
SELECT CAST(DATEADD(DAY, ROW_NUMBER() OVER (ORDER BY [object_id]) - 1, '2016-01-14') as date) 'date'
FROM sys.all_objects
)
SELECT TOP 5
[date] AS 'DateField',
SUM(CASE WHEN Created IS NULL THEN 0 ELSE 1 END) AS 'Counted'
FROM dates
LEFT JOIN Table ON [date]=CAST(Created as date)
GROUP BY [date]
ORDER BY [date]
For a more edgy solution, you could use a recursive common table expression to create the date list. PLEASE NOTE: do not use recursive common table expressions in your day job! They are dangerous because it is easy to create one that never terminates.
DECLARE #StartDate date = '1/1/2016';
DECLARE #EndDate date = '1/15/2016';
WITH DateList(DateValue)
AS
(
SELECT DATEADD(DAY, 1, #StartDate)
UNION ALL
SELECT DATEADD(DAY, 1, DateValue)
FROM DateList
WHERE DateList.DateValue < #EndDate
)
SELECT DateValue, isnull(Count(id),0) as Counted
FROM DateList
LEFT OUTER JOIN [Table]
ON DateValue = CAST(Created AS DATE)
GROUP BY DateValue
ORDER BY DateValue DESC