I am working with a WPF application.I have two text boxes and a button in my first window.Based on some DB operations i need to open the copy of the first window(if possible open like a new tab) provided both windows can be accessed simultaneously.I used
var MainWindow = new MainWindow();
MainWindow.ShowDialog();
and
var MainWindow = new MainWindow();
MainWindow.Show();
both of them doesnt meet my expectations.Can anyone help me.
When you use ShowDialog(), it opens a single modal dialog that is expected to be closed when complete.
If you want to open multiple windows and not block form control, try using Show() instead.
var window = new MainWindow();
window.Show();
I would advise you to read all of the relating pages on MSDN so that you can learn how everything works.
For the Show method:
Opens a window and returns without waiting for the newly opened window to close.
For the ShowDialog method:
Opens a window and returns only when the newly opened window is closed.
From the Remarks section of the Window.Show Method page:
When the Window class is instantiated, it is not visible by default. Show shows a window and returns immediately, without waiting for the window to be closed. Consequently, the opened window does not prevent users from interacting with other windows in the application. This type of window is called a modeless window. Common examples of modeless windows are properties windows, toolboxes, and palettes. To restrict a user to interacting with a specific window, the window must be opened by calling ShowDialog.
Calling Show achieves the same end result as setting Visibility property of the Window object to Visible. However, there is a difference between the two from a timing perspective.
Therefore, for your solution, I would recommend that you use the Show method instead.
Related
I have this problem:
In a C# WPF application:
I open a new Window (showOnTaskBar=true, noresize, centered);
From this opened window I open another one that is above the other opened window. The new window is without blue top bar and
showOnTaskbar=false, showDialog();
Everything is ok but if I change the focus, I mean, for example, I open Firefox or another program and then I want to go back to my
opened windows I saw just the first opened window (from step 1) the
other modal window comes up only with ALT+TAB.
So, is there a way to keep both windows always displayed ?
Code to open the second window (from the first normally opened window in step 1):
Form2 form2 = new Form2();
formA2.ShowInTaskbar = false;
form2.ShowDialog();
Thank you,
Adrian
If as I think you have said you are opening the second window from the first, I'm pretty sure you want to try setting the owner of the dialog like this:
form2.Owner = Window.GetWindow(this);
See WPF: How do I set the Owner Window of a Dialog shown by a UserControl?
Hope this helps,
Jay
ı'am opening a new window in a another window ,but when window1.show()' method is called,
window1 is down in the taskbar with caller window and they is grouping in that task bar,
I click the window1 but not showed the screen,is is still in the task bar...
Why might something like that ?
Unless you specify in Windows 7 that you do not wish to regroup the windows under the same icon, it is not possible per say. The only way I can think of would be to create a new application with that windows instead of opening the window itself., but that would be far fecthed.
Why do you need this ?
I have a WPF application that has several modal window used for various purposes. This is easily accomplished by using the ShowDialog function. However, in my application I have a timer to measure idle time (i.e. no mouse moves or key strokes) that will cause the user to be logged off. Is there a way (when this timer fires) to find and close all open modal windows without tracking each explicitly?
Update
I would also like to close any MessageBox.Show instances. Is this possible?
Thanks,
Matt
Have you tried to iterate the Application.Current.Windows collection, and close all these that are not the Application.Current.MainWindow?
Jogy
Is there a way (when this timer fires) to find and close all open modal windows without tracking each explicitly?
You could use ComponentDispatcher.IsThreadModal to check to see if you're UI thread is in a modal state. If it is, the Application.Current.Windows property will give you the list of opened Windows.
If you only have a single MainWindow, you could close any others (as they'd be your modal dialogs), but if you have multiple windows, you'd have to check each one.
Unfortunately, there's no direct API to determine whether a specific Window is modal - but there is a private variable in the Window class you could use to do this. For example, the following method uses reflection to determine whether a Window is modal:
public static bool IsModal(Window window)
{
Type type = typeof(Window);
var field = type.GetField("_showingAsDialog", BindingFlags.Instance | BindingFlags.NonPublic);
return field.GetValue(window);
}
This is, unfortunately, subject to change (since it's using undocumented private members).
I have a problem with my Application ending unexpectedly when a modal dialog, spawned from the main program window, closes normally. No unhandled exceptions are being thrown and none of the Closing or Closed events are fired on the Main application window.
Essentially I have a main/shell window, which is started in the Application code using ShellWindow.Show(). Through a menu the user can spawn a custom open dialog, this is a new window created and then shown using ShowDialog (the windows owner is set to that of the shell window).
When the dialog is closed (internally, by a command invoking _modalDialogWindow.Close()) the application closes, whereas I would only have expected the modal dialog to have closed.
Debugging the code indicates that the ShellWindow is dumped from memory, as the next executed line of code after _modalDialogWindow.Close() is it falling out of Application.Run() in the static program code.
If anyone has any ideas I am willing to try anything.
It appears that, due to the MVVM/Ioc way I am designing the application window close events are being propagated further than they should. I don't understand this!
However, setting the Application.ShutDownMode to Explicit prevents the app from closing prematurely and I now have the desired behaviour.
Incidentally, turning on all the exceptions as suggested by declyclone didn't yield any exceptions that are thrown internally when then window is closed.
Don't create any windows before you create your application, or they won't get registered properly. They won't show up in Application.Current.Windows or Application.Current.MainWindow. Then when you create your dialog window, your application will think that it is both the MainWindow and the only window.
Example of what not to do:
public partial class App : Application, ISingleInstanceApp
{
MyWindow win = new MyWindow(); //BAD! this is called inside new App(), but before the actual App constructor.
[STAThread]
public static void Main()
{
if (SingleInstance<App>.InitializeAsFirstInstance(Unique))
{
var application = new App();
application.InitializeComponent();
application.Run();
// Allow single instance code to perform cleanup operations
SingleInstance<App>.Cleanup();
}
}
I had this problem too, your answer helped me figure out why.
I'm setting up a program that has three different windows. I'm just using ..
Window1 win1 = new Window1();
win1.show();
...for each of the extra windows. The problem is that each window opens up a new tab on the taskbar. Is there anyway that I can still have my three windows with only one related item on the taskbar?
If possible, I would not like to make them all child forms and have to sit inside of another box.
Thank you
Set the ShowInTaskbar to false
<Window ShowInTaskbar="False" ... />
If you want to make the windows related together, like when you click one of them it brings them all, set the Owner before showing the window (assuming this is your main window)
Window1 w = new Window1();
w.Owner = this;
Set the "secondary" windows' ShowInTaskbar property to false. Also it wouldn't hurt to set their Owner property to App.Current.MainWindow, so that the all the windows close (and hence the application exits) when the main window is closed.