Elegant way to determine EOF? - c

I am reading from a text file, iterating with a while(!feof) loop,
but whenever I use this condition the loop iterates an extra time.
I solved the problem with this 'patchy' code
while (stop == FALSE)
{
...
terminator = fgetc(input);
if (terminator == EOF)
stop = TRUE;
else
fseek(input, -1, SEEK_CUR);
}
But it looks and feels very bad.

You can take advantage of the fact that an assignment gets evaluated as the value being assigned, in this case to the character being read:
while((terminator = fgetc(input))!= EOF) {
// ...
}

Here is an idiomatic example (source):
fp = fopen("datafile.txt", "r"); // error check this!
// this while-statement assigns into c, and then checks against EOF:
while((c = fgetc(fp)) != EOF) {
/* ... */
}
fclose(fp);

Similarly you ca read line-by-line:
char buf[MAXLINE];
// ...
while((fgets(buf,MAXLINE,stdin)) != NULL) {
do_something(buf);
}
Since fgets copies the detected newline character, you can detect
end of line by checking the second to last buffer element. You can use
realloc to resize the buffer (be sure you keep a pointer to the beginning of the buffer, but pass buf+n, to the next fgets, where n is the number of read characters). From the standard regarding fgets:
Reads characters from stream and stores them as a C string into str until (num-1) characters have been read or either a newline or the end-of-file is reached, whichever happens first. A newline character makes fgets stop reading, but it is considered a valid character by the function and included in the string copied to str.
Alternatively, you could read the whole file in one go using fread() (see example following the link).

Related

How can I skip an entire comment line by using fgets even after the set maximum nr of chars

I'm reading lines from a file and I might have a comment anywhere throughout it of any size.
while (fgets(line, 100, myFile))
{
// skip and print comment
if (line[0] == '#') printf("Comment is = %s", line);
else {...}
}
The code is doing what is supposed to until it gets a comment which is over 100 characters. In that case it will not detect the # anymore and it won't skip it. How can I solve this?
You could introduce a state variable to tell the program that you are on comment
mode. Like this:
// mode == 0 --> normal
// mode == 1 --> comment, remove/ignore comments
int mode = 0;
char line[100];
while(fgets(line, sizeof line, myFile))
{
char *newline = strchr(line, '\n');
if(mode == 1)
{
if(newline)
mode = 0; // restore normal mode
continue; // ignore read characters
}
char *comment = strchr(line, '#');
if(comment)
{
*comment = '\0';
if(newline == NULL)
mode = 1; // set comment mode
}
// process your line without the comment
}
If a comment is found, strchr returns a pointer to that location. Setting it
to '\0' allows you to process the line without a comment. If the comment is
larger than line can hold, then the newline character is not found. In that case
you have to skip the next read bytes of fgets, until you find a newline.
That's when the mode variable comes in handy, you set it to 1 so the next
iterations can ignore the line if a newline is not found.
fgets itself will tell you when it did not read the entire line:
The fgets() function reads bytes from the stream into the array pointed to by s, until n−1 bytes are read, or a newline character is read and transferred to s, or an end-of-file condition is encountered. The string is then terminated with a null byte.
(https://docs.oracle.com/cd/E36784_01/html/E36874/fgets-3c.html)
So if your just-read line starts with # but does not end with \n (and fgets does not indicate EOF), read and skip all next 'lines' until you either find the end of the current 'line' indicated by a terminating \n, or you encounter an EOF condition.
If you want to store the comment for later display (as you are doing), use malloc and realloc to create and enlarge memory for the comment itself. Do not forget to free it after you're done.

How to discard the rest of a line in C

I'm trying to write a function that removes the rest of a line in C. I'm passing in a char array and a file pointer (which the char array was read from). The array is only supposed to have 80 chars in it, and if there isn't a newline in the array, read (and discard) characters in the file until you reach it (newline). Here's what I have so far, but it doesn't seem to be working, and I'm not sure what I'm doing wrong. Any help would be greatly appreciated! Here's the given information about what the function should do:
discardRest - if the fgets didn't read a newline than an entire line hasn't been read. This function takes as input the most recently read line and the pointer to the file being read. discardRest looks for the newline character in the input line. If newline character is not in the line, the function reads (and discards) characters from the file until the newline is read. This will cause the file pointer to be positioned to the beginning of the next line in the input file.
And here's the code:
void discardRest(char line[], FILE* file)
{
bool newlineFound = FALSE;
int i;
for(i = 0; i < sizeof(line); i++)
{
if(line[i] == '\n') newlineFound = TRUE;
}
if(!newlineFound)
{
int c = getc(file);
while(c != '\n')
{
c = getc(file);
}
}
}
Your way is much too difficult, besides sizeof always giving the size of its operand, which is a pointer and not the array it points to which you think it is.
fgets has thefollowing contract:
return NULL: Some kind of error, do not use the buffer, its content might be indeterminate.
otherwise the buffer contains a 0-terminated string, with the last non-0 being the retained '\n' if the buffer and the file were both large enough.
Thus, this should work:
So, use strlen() to get the buffer length.
Determine if a whole line was read (length && [length-1] == '\n').
As appropriate:
remove the newline character and return.
discard the rest of the line like you tried.

Reading from stdin and storing \n and whitespace

I've been trying to use scanf to get input from stdin but it truncates the string after seeing whitespace or after hitting return.
What I'm trying to get is a way to read keyboard input that stores in the buffer linebreaks as well as whitespace. And ending when ctrl-D is pressed.
Should I try using fgets? I figured that wouldn't be optimal either since fgets returns after reading in a \n
There is no ready-made function to read everyting from stdin, but creating your own is fortunately easy. Untested code snippet, with some explanation in comments, which can read arbitrarily large amount of chars from stdin:
size_t size = 0; // how many chars have actually been read
size_t reserved = 10; // how much space is allocated
char *buf = malloc(reserved);
int ch;
if (buf == NULL) exit(1); // out of memory
// read one char at a time from stdin, until EOF.
// let stdio to handle input buffering
while ( (ch = getchar()) != EOF) {
buf[size] = (char)ch;
++size;
// make buffer larger if needed, must have room for '\0' below!
// size is always doubled,
// so reallocation is going to happen limited number of times
if (size == reserved) {
reserved *= 2;
buf = realloc(buf, reserved);
if (buf == NULL) exit(1); // out of memory
}
}
// add terminating NUL character to end the string,
// maybe useless with binary data but won't hurt there either
buf[size] = 0;
// now buf contains size chars, everything from stdin until eof,
// optionally shrink the allocation to contain just input and '\0'
buf = realloc(buf, size+1);
scanf() splits the input at whitespace boundaries, so it's not suitable in your case. Indeed fgets() is the better choice. What you need to do is keep reading after fgets() returns; each call will read a line of input. You can keep reading until fgets() returns NULL, which means that nothing more can be read.
You can also use fgetc() instead if you prefer getting input character by character. It will return EOF when nothing more can be read.
If you want to read all input, regardless of whether it is whitespace or not, try fread.
Read like this
char ch,line[20];
int i=0; //define a counter
//read a character assign it to ch,
//check whether the character is End of file or not and
//also check counter value to avoid overflow.
while((ch=getchar())!=EOF && i < 19 )
{
line[i]=ch;
i++;
}
line[i]='\0';

Understanding fgetc program

I'm reading a book about c programming and don't understand a shown example. Or more precisely I don't understand why it works because I would think it shouldn't.
The code is simple, it reads the content of a text file and outputs it in output area. As far as I understand it, I would think that the
ch = fgetc(stream);
ought to be inside the while loop, because it only reads one int a time? and needs to read the next int after the current one has been outputted. Well, it turns out that this code indeed works fine so I hope someone could explain my fallacy to me. Thanks!
#include <stdio.h>
int main(int argc, char *argv[]) {
FILE *stream;
char filename[67];
int ch;
printf("Please enter the filename?\n");
gets(filename);
if((stream = fopen(filename, "r")) == NULL) {
printf("Error opening the file\n");
exit(1);
}
ch = fgetc(stream);
while (!feof(stream)) {
putchar(ch);
ch = fgetc(stream);
}
fclose(stream);
}
I think you are confuse because of feof():
Doc: int feof ( FILE * stream );
Checks whether the end-of-File indicator associated with stream is
set, returning a value different from zero if it is.
This indicator is generally set by a previous operation on the stream
that attempted to read at or past the end-of-file.
ch = fgetc(stream); <---"Read current symbol from file"
while (!feof(stream)) { <---"Check EOF read/returned by last fgetc() call"
putchar(ch); <---"Output lasts read symbol, that was not EOF"
ch = fgetc(stream); <---"Read next symbols from file"
}
<-- control reach here when EOF found
A much better way is to write your loop like:
while((ch = fgetc(stream))!= EOF){ <--" Read while EOF not found"
putchar(ch); <-- "inside loop print a symbol that is not EOF"
}
Additionally, Note: int fgetc ( FILE * stream );
Returns the character currently pointed by the internal file position
indicator of the specified stream. The internal file position
indicator is then advanced to the next character.
If the stream is at the end-of-file when called, the function returns
EOF and sets the end-of-file indicator for the stream (feof).
If a read error occurs, the function returns EOF and sets the error
indicator for the stream (ferror).
If the fgetc outside while is removed, like this:
while (!feof(stream)) {
putchar(ch);
ch = fgetc(stream);
}
ch will be un-initialized the first time putchar(ch) is called.
By the way, don't use gets, because it may cause buffer overflow. Use fgets or gets_s instead. gets is removed in C11.
The code you have provided has 'ch =fgetc(stream);' before the While loop and also
'ch = fgetc(stream);' within the body of the loop.
It would be logical that the statement within the loop is retrieving the ch from the stream one at a time as you correctly state.
It is inside and outside as you see. The one outside is responsible for reading the first character (which may be already the end of file, then the while wouldn't be entered anyway and nothing is printed), then it enters the loop, puts the character and reads the next one.. as long as the read character is not the end of file, the loop continues.
This is because of second fgetc which is getting call upto while (!feof(stream)).
fgetc() reads a char(byte) and return that byte,The reading of byte value depends on where the read pointer is available.
Once fgetc() successfully read one byte the read file pointer moves to the next byte .so if you read the file the next byte will be the output and it will continue upto it find the end of the file where it return EOF.
Actually this part here:
while (!feof(stream)) {
putchar(ch);
ch = fgetc(stream);
}
is pretty unsafe and you should avoid checking EOF like that (here why).
The way you should read a file using fgetc is like so:
int ch;
while ((ch = fgetc(stream)) != EOF)
{
printf("%c", ch)
}
This is non functional code. Last character from file is never outputted. fgetc will read last character and pointer will be at end of file. So, when while is checked, !feof will return false, and read character will not be outputed.
feofis not preventing reading after end of file: for empty files fgetc will be called before feof!
Unless there is some benefit in console handling, two better options exist:
Using feof:
while (!feof(stream)) {
ch=fgetc(stream);
putchar(ch);
}
Without using feof - because fgetc returns EOF when there are no more characters:
while ((ch=fgetc(stream))!=EOF) putchar(ch);

understanding ungetc use in a simple getword

I've come across such an example of getword.
I understand all the checks and etc. but I have a problem with ungetc.
When the c does satisfy if ((!isalpha(c)) || c == EOF)and also doesn't satisfy while (isalnum(c)) -> it isn't a letter, nor a number - ungetc rejects that char.
Let's suppose it is '\n'.
Then it gets to return word however it can't be returned since it is not saved in any array. What happens then?
while (isalnum(c)) {
if (cur >= size) {
size += buf;
word = realloc(word, sizeof(char) * size);
}
word[cur] = c;
cur++;
c = fgetc(fp);
}
if ((!isalpha(c)) || c == EOF) {
ungetc(c, fp);
}
return word;
EDIT
#Mark Byers - thanks, but that c was rejected for a purpose, and will not satisfy the condition again and again in an infinite loop?
The terminal condition, just before the line you don't understand, is not good. It should probably be:
int c;
...
if (!isalpha(c) && c != EOF)
ungetc(c, fp);
This means that if the last character read was a real character (not EOF) and wasn't an alphabetic character, push it back for reprocessing by whatever next uses the input stream fp. That is, suppose you read a blank; the blank will terminate the loop and the blank will be pushed back so that the next getc(fp) will read the blank again (as would fscanf() or fread() or any other read operation on the file stream fp). If, instead of blank, you got EOF, then there is no attempt to push back the EOF in my revised code; in the original code, the EOF would be pushed back.
Note that c must be an int rather than a char.
ungetc pushes the characters onto the stream so that the next read will return that character again.
ungetc(c, fp); /* Push the character c onto the stream. */
/* ...etc... */
c = fgetc(fp); /* Reads the same value again. */
This can sometimes be convenient if you are reading characters to find out when the current token is complete, but aren't yet ready to read the next token.
OK. Now I understand why that case with eg. '\n' was troubling me. I'm just dumb and forgot about the section in main() referring to getword. Of course before calling getword there are a couple of tests (another ungetc there) and it fputs that characters not satisying isalnum
It emerges from this that while loop in getword always starts with at least one isalnum positive, and the check at then end is just for following characters.

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