transpose non-square matrix in C - c

Question

everyone I am trying to work on the transpose matrix
here is my code so far.
void Transpose(int mt[][10], int m, int n)
{
int c,d,temp;
for (c = 0; c < m; c++)
{
for (d = c+1; d < n; d++)
{
temp = mt[c][d];
mt[c][d]=mt[d][c];
mt[d][c] = temp;
}
}
}
void print(int pose[][10], int m, int o)
{
int i,j;
for(i = 0; i < m; i++)
{
for(j = 0; j < o; j++)
{
printf("%d\n",pose[j][i]);
}
}
}
int main()
{
/*The body of your source code will go here */
int a[4][5] = {{1,2,3,4,5},{6,7,8,9,10},{10,9,8,7,6},{5,4,3,2,1}};
printf("ARRAY: %d",a[][5]);
Transpose();
return (0);
}
Here is my function for print and transpose a matrix, but now I am trying to pass the array into the function from my main. I just wondering how I declare the array that in the main can pass to the function. Thanks

Answer 1

Your declaration of Transpose does not match your use of it. Since it is declared as:
void Transpose(int mt[][10], int m, int n) {...}
It should be invoked by
Transpose(a, 4, 5);
Also, what is the 10 for? And, the statement
printf("ARRAY: %d", a[][5]);
is unlikely to work.
You should choose better names for your variables. Instead of m and n, use nRows and nColumns. Use row and column instead of i and j.

Answer 2

You can use the following code to do it.
#include<stdio.h>
// Print Matrix
void printArr(int *A, int row,int col)
{
int i,j;
for(i=0;i<row;i++)
{
printf("\n");
for(j=0;j<col;j++)
printf("%d\t",*(A+(col*i)+j));
}
}
//Find the Transpose(TA) of Matrix(A)
void Transpose(int *A,int *TA,int row,int col)
{
int i,j;
for(i=0;i<row;i++)
for(j=0;j<col;j++)
*(TA+(j*row)+i)=*(A+(col*i)+j);
}
// Start of Main
int main()
{
int A[4][5]={{1,2,3,4,5},{6,7,8,9,10},{10,9,8,7,6},{5,4,3,2,1}};
int *TA=malloc(sizeof(int)*4*5); // Allocate Memory for TA
int i,j;
printf("Matrix A:");
printArr(A,4,5); //Print Array A
Transpose(A,TA,4,5); //Call Transpose
printf("\nTranspose Matrix A:");
printArr(TA,5,4); // Print Array TA
return 0;
}
Output:
Matrix A:
1 2 3 4 5
6 7 8 9 10
10 9 8 7 6
5 4 3 2 1
Transpose Matrix A:
1 6 10 5
2 7 9 4
3 8 8 3
4 9 7 2
5 10 6 1

Answer 3

The C programming language does not remember the lengths of arrays like other programming languages do. That makes working with multidimensional arrays difficult.
To pass a multidimensional array as a parameter in C, you either have to know the dimensions of the array at compile time:
#define HEIGHT 10
#define WIDTH 13
void function_prototype(int M[HEIGHT][WIDTH]) {
access M normally with M[y][x]
}
or you have to pass a single dimensional array and the lengths as parameters:
void function_prototype(int* M, int height, int width) {
access M as M[y * width + x]
}
It's troublesome, but that's the price you pay for having extremely fast array access.