I'm new to CakePHP and have a question about this controller:
function showmy($userid) {
return $this->Voucher->find('all', array('conditions' => array('Voucher.user_id' => $userid)));
}
public function index() {
$this->Voucher->recursive = 0;
$userid = $this->Session->read('Auth.User.id');
$this->set('vouchers', $this->showmy($userid ));
}
I want all the Voucher with user_id by the loged in user.
It works, but i get many errors like :
Warning (2): array_filter() expects parameter 1 to be array, null given [CORE\Cake\View\Helper\PaginatorHelper.php, line 419]
Maybe someone with more experienced could give me some advice!
Thanks,
Julius
I think you need to use PaginatorComponent::paginate() to be able to use the PaginatorHelper in your view. More info in the manual.
You must declare $paginate array in you controller for the pagination
public $paginate = array(
'limit' => 25,
'order' => array(
'Post.title' => 'asc'
)
);
paginate => array
public function index() {
$this->Voucher->recursive = 0;
$userid = $this->Session->read('Auth.User.id');
$this->Paginator->settings = array(
array('conditions' => array('Voucher.user_id' => $userid))
);
$this->set('vouchers', $this->Paginator->paginate('Voucher'));
}
Related
I created a custom find type, and am trying to paginate the results, but the paginator seems to be ignoring the findType setting. Can someone tell me what I'm doing wrong?
(CakePHP 2.X)
In my Controller:
public function list($username=null) {
$this->Paginator->settings = array(
'Question' => array(
'findType' => 'unanswered',
'conditions' => array('Question.private' => 0),
);
$data = $this->Paginator->paginate('Question');
$this->set('data', $data);
);
Custom find type setup in my Model:
public $findMethods = array('unanswered' => true);
protected function _findUnanswered($state, $query, $results = array()) {
if ($state == 'before') {
$query['order'] = array('Question.created DESC');
$query['conditions'] = array_merge($query['conditions'], array('Question.date_answered' => ''));
return $query;
$this->log($query);
} elseif ($state == 'after') {
return $results;
}
}
Edit
I can paginate the query if I remove $this->Paginate->settings, and replace it with this:
$this->paginate = array('unanswered');
However, I want to add some additional conditions., this doesn't work:
$this->paginate = array('unanswered' => 'conditions' => array('Question.user_id' => $id, 'limit' => 4)) );
Is this possible?
findType was added to the paginator component in CakePHP 2.3, I was on 2.0
http://api.cakephp.org/2.3/class-PaginatorComponent.html
I read the documentation regarding file downloads, however I can't seem to get this to work.
I have read through questions here as well, and have had no luck.
My function looks as follows:
public function generate($id) {
$this->layout = 'ajax';
$this->Magazine->recursive = 2;
$DistributionLists = $this->Magazine->DistributionList->find('all',
array(
'conditions' => array(
'Magazine.id' => $id
),
'order' => array(
'DistributionList.priority ASC'
)
)
);
$this->set('magazine',$DistributionLists[0]['Magazine']['magazine_name']);
$this->set(compact('DistributionLists'));
}
public function download() {
$this->viewClass = 'Media';
$params = array(
'id' => "Magazine Distribution List.doc",
'name' => "Magazine Distribution List",
'download' => true,
'extension' => 'doc',
'path' => APP . "tmp" . DS
);
$this->set($params);
unlink(APP."tmp".DS);
$this->redirect(array('action'=>'index'));
}
public function afterFilter() {
parent::afterFilter();
if($this->action == 'generate') {
$this->redirect(array('action'=>'download'));
}
}
The reason I have an afterFilter function is because the word document that needs to be downloaded is created in the view file.
Does anyone know why this doesn't work?
You have to remove the call to the redirect method in your download method because it prevents your view from getting "rendered" due to the redirect.
I currently have this in my Model (Referer Model):
public function getReferers($type = 'today') {
if ($type == 'this_month') {
return $this->_getThisMonthsReferers();
} elseif ($type == 'today') {
return $this->_getTodaysPageReferers();
}
}
private function _getThisMonthsReferers() {
$today = new DateTime();
return $this->Visitor->find('all', array(
'fields' => array(
'Referer.url',
'COUNT(UserRequest.visitor_id) as request_count',
'COUNT(DISTINCT(Visitor.id)) as visitor_count',
'COUNT(UserRequest.visitor_id) / COUNT(DISTINCT(Visitor.id)) as pages_per_visit',
'COUNT(DISTINCT(Visitor.id)) / COUNT(UserRequest.visitor_id) * 100 as percent_new_visit'
),
'joins' => array(
array(
'table' => 'user_requests',
'alias' => 'UserRequest',
'type' => 'RIGHT',
'conditions' => array(
'UserRequest.visitor_id = Visitor.id'
)
)
),
'conditions' => array(
'Visitor.site_id' => $this->Site->id,
'MONTH(UserRequest.created)' => $today->format('m'),
'YEAR(UserRequest.created)' => $today->format('Y')
),
'group' => array(
'url'
)
));
}
The thing is that I how I would paginate this. It will be so easy if just copy my code out of the model and to the controller. The thing is I want the keep the query in my Model.
How is this supposed to be done in CakePHP?
A custom find type is one method. You can find more information here: http://book.cakephp.org/2.0/en/core-libraries/components/pagination.html#custom-query-pagination
To turn your _getThisMonthsReferers into a custom find, follow this http://book.cakephp.org/2.0/en/models/retrieving-your-data.html#creating-custom-find-types
For example:
// model
protected function _findThisMonthsReferers($state, $query, $results = array()) {
if ($state === 'before') {
$query['fields'] = ....
$query['joins'] = ....
return $query;
}
return $results;
}
// controller
public $paginate = array('findType' => 'thisMonthsReferers')
EDIT:
I think it should be :
public $paginate = array('thisMonthsReferers');
However the Solution I used derived from this answer is adding this to the method I am using
$this->paginate = array('thisMonthsReferers');
Since I don't want i used in all my actions. Then paginating the Model like this.
$this->paginate('Visitor);
Instead of returning the results of the find, just return it's array of options:
return array(
'fields' => array(
//...etc
Then use those options to paginate in the controller. More details on this answer of this similar question: Paginate from within a model in CakePHP
It still keeps the model fat (with any logic that might alter the conditions, joins, fields...etc), and the controller skinny, which just uses the returned array as paginate options.
in my controller I have this
public function station_users($id=null){
$users = $this->User->find('all',array('conditions'=>array('test_id'=>$this->params['named']['test_id'])));
$this->set('users', $users);
$this->render("station_users",'ajax');
}
I am getting all the users for a certain test id but now my sort doesnt work. how can I add pagination.
I tried
$this->User->recursive = 0;
$this->set('users', $this->paginate());
and that didnt work
thanks
Before calling $this->paginate(), you need to configure your pagination, with something like this:
$this->paginate = array
(
'User' => array
(
'recursive' => 0,
'conditions' => array
(
'test_id' => $this->params['named']['test_id'],
),
)
);
$users = $this->paginate('User');
The Cookbook is your friend, use it whenever possible.
I want to test a function with this header:
public function includeNumComments($posts){
Where $post is an array of data.
I wonder how can i test the method passing it an array of posts.
I have tried things like this, but it doesn't work:
$result = $this->testAction("/comments/includeNumComments/", array('data' => $posts));
$result = $this->testAction("/comments/includeNumComments/", array($posts));
Thanks
Here's the correct case, it worked for me. Hope it helps:
public function testAddUser() {
$data = array(
'User' => array(
'id' => 12,
'username' => 'testname1',
'password' => 'Pass#123!',
'email' => 'test#example.com'
)
);
$result = $this->testAction(
'/users/add',
array('data' => $data, 'method' => 'post')
);
debug($result);
}
That's not really using testAction then, because you can't pass an array via HTTP. There'd be no way to do this via a form or link on a website.
You can just test it as a normal function:
$result = $this->CommentsController->includeNumComments($posts);