Twice Inner Join on same table with Aggregate function - sql-server

being a novice sql user:
I have a simple table storing some records over night daily. table:
Table: T1
+----+-----+----+-----------+------------+
| Id | A | AB | Value | Date |
+----+-----+----+-----------+------------+
| 1 | abc | I | -48936.08 | 2013-06-24 |
| 2 | def | A | 431266.19 | 2013-06-24 |
| 3 | xyz | I | -13523.90 | 2013-06-24 |
| 4 | abc | A | 13523.90 | 2013-06-23 |
| 5 | xyz | I | -13523.90 | 2013-06-23 |
| 6 | def | A | 13523.90 | 2013-06-22 |
| 7 | def | I | -13523.90 | 2013-06-22 |
+----+-----+----+-----------+------------+
I would like to get all values of columns A,AB, Value for the latest Date on Column A filtered on AB = I
basically the result should look like:
+----+-----+----+-----------+------------+
| Id | A | AB | Value | Date |
+----+-----+----+-----------+------------+
| 1 | abc | I | -48936.08 | 2013-06-24 |
| 3 | xyz | I | -13523.90 | 2013-06-24 |
| 7 | def | I | -13523.90 | 2013-06-22 |
+----+-----+----+-----------+------------+
I have tried to use inner join twice on the same table but failed to come up with correct result.
any help would be appreciated.
thanks :)

This will work with sqlserver 2005+
;WITH a as
(
SELECT id, A,AB, Value, Date
, row_number() over (partition by A order by Date desc) rn
FROM t1
WHERE AB = 'I'
)
SELECT id, A,AB, Value, Date
FROM a WHERE rn = 1

; WITH x AS (
SELECT id
, a
, ab
, "value"
, "date"
, Row_Number() OVER (PARTITION BY a ORDER BY "date" DESC) As row_num
FROM your_table
WHERE ab = 'I'
)
SELECT *
FROM x
WHERE row_num = 1

Related

Results of join listed in rows vs additional columns?

I have 2 tables, with the same exact fields and fields names. i am trying to inner join them but im having some difficulty determining how i can get my results in my desired format.
I know i can do select a.customer, a.id, a.date, a.line, a.product, b.customer, b.id, b.date, b.line, b.product but instead of having my A data and B data on the same row, id like for them to be on seperate rows.
I have 2 tables, with the same exact fields and fields names, i am trying to inner join them so that unique line becomes a row.
Table A:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 845689 | 789 | 1/25/22 | 1 | 45587 |
TABLE B:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
| 587435 | 157 | 2/12/22 | 3 | 25896 |
DESIRED RESULTS:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
my query:
select a.customer, a.id, a.date, a.line, a.product
from data1 a
inner join data2 b
on a.date = b.date
and a.customer = b.customer

SQL SELECT and INSERT/UPDATE, PIVOT?

I need to take data from a table that looks like this:
name | server | instance | version | user
----------|----------|------------|----------|--------- -
package_a | x | 1 | 1 | AB
package_b | x | 1 | 1 | TL
package_a | x | 2 | 4 | SK
package_a | y | 1 | 2 | MD
package_c | y | 1 | 4 | SK
package_b | y | 2 | 1 | SK
package_a | y | 2 | 1 | TL
package_b | x | 2 | 3 | TL
package_c | x | 2 | 1 | TL
and I need to put it in a table like that:
name | v_x_1 | u_x_1 | v_x_2 | u_x_2 | v_y_1 | u_y_1 | v_y_2 | u_y_2
----------|-------|-------|-------|-------|-------|-------|-------|-------
package_a | 1 | AB | 4 | SK | 2 | MD | 1 | TL
package_b | 1 | TL | 3 | TL | NULL | NULL | 1 | SK
package_c | NULL | NULL | 1 | TL | 4 | SK | NULL | NULL
I already tried INSERT with (SUB)SELECT, tried to INSERT package names first using DISTINCT and UPDATE afterwards, played around with PIVOT and stuff like that.
But I'm rather new to SQL and programming in general, so I couldn't come up with a solution. Since I not only have a version number in the source table but also nvarchar columns, It seems like PIVOT won't be the way to go, right?
You can use PIVOT on a sub query that uses UNION to separate the user and version values.
insert into YourNewTable (name, [v_x_1],[u_x_1],[v_x_2],[u_x_2],[v_y_1],[u_y_1],[v_y_2],[u_y_2])
select *
from (
select name, cast([version] as varchar(30)) as value, concat('v_',[server],'_',instance) as title from YourTable
union all
select name, [user] as value, concat('u_',[server],'_',instance) as title from YourTable
) q
pivot (max(value) FOR title IN (
[v_x_1],[u_x_1],[v_x_2],[u_x_2],[v_y_1],[u_y_1],[v_y_2],[u_y_2]
)
) pvt;

Selecting grouped rows after first two rows SQL Server

This is a bit of a tricky question/situation and my search fu failed me.
Lets say i have the following data
| UID | SharedID | Type | Date |
|-----|----------|------|-----------|
| 1 | 1 | foo | 2/4/2016 |
| 2 | 1 | foo | 2/5/2016 |
| 3 | 1 | foo | 2/8/2016 |
| 4 | 1 | foo | 2/11/2016 |
| 5 | 2 | bar | 1/11/2016 |
| 6 | 2 | bar | 2/11/2016 |
| 7 | 3 | baz | 2/1/2016 |
| 8 | 3 | baz | 2/3/2016 |
| 9 | 3 | baz | 2/11/2016 |
And I would like to ommit a variable number of leading rows (most recent date in this case) and lets say that number is 2 in this example. The resulting table would be something like this:
| UID | SharedID | Type | Date |
|-----|----------|------|-----------|
| 1 | 1 | foo | 2/4/2016 |
| 2 | 1 | foo | 2/5/2016 |
| 7 | 3 | baz | 2/1/2016 |
Is this possible in SQL? Essentially I want to filter on an unknown number of rows which uses the date column as the order by. The goal is to get the oldest types and get a list of UID's in the process.
Sure, it's possible. Use a ROW_NUMBER function to assign a value to each row, partitioning by the SharedID column so that the count restarts every time that ID changes, and select those rows with a value greater than your limit.
WITH cteNumberedRows AS (
SELECT UID, SharedID, Type, Date,
ROW_NUMBER() OVER(PARTITION BY SharedID ORDER BY Date DESC) AS RowNum
FROM YourTable
)
SELECT UID, SharedID, Type, Date
FROM cteNumberedRows
WHERE RowNum > 2;
Not sure if I understand what you mean but something like this?
SELECT * FROM MyTable t1 JOIN MyTable T2 ON t2.id NOT IN (
SELECT TOP 2 UID FROM myTable
WHERE SharedID = t1.sharedID
ORDER BY [Date] DESC
)

SQL Server : update sequence number across multiple groups

I would like to update a table:
| id | type_id | created_at | sequence |
|----|---------|------------|----------|
| 1 | 1 | 2010-04-26 | NULL |
| 2 | 1 | 2010-04-27 | NULL |
| 3 | 2 | 2010-04-28 | NULL |
| 4 | 3 | 2010-04-28 | NULL |
To this (note that created_at is used for ordering, and sequence is "grouped" by type_id):
| id | type_id | created_at | sequence |
|----|---------|------------|----------|
| 1 | 1 | 2010-04-26 | 1 |
| 2 | 1 | 2010-04-27 | 2 |
| 3 | 2 | 2010-04-28 | 1 |
| 4 | 3 | 2010-04-28 | 1 |
Same question has been raised but for SQL Server.
Link
Thanks.
You can use ROW_NUMBER() to get sequence number per type_id slice. Use a CTE to make UPDATE operation simpler:
;WITH ToUpdate AS (
SELECT id, type_id, created_at, sequence,
ROW_NUMBER() OVER (PARTITION BY type_id ORDER BY created_at) AS newSeq
FROM mytable
)
UPDATE ToUpdate
SET sequence = newSeq
Demo here

how to check date records with in fdate and tdate range in sql server

Hi friends i have small doubt in sql server
here i want data based on condition
same id and status is equal to s then that date value be
how to write query in sql server
Table :emp
id |status |date(mm-dd-yy) |fdate(mm-dd-yy) |tdate(mm-dd-yy)
1 | S |03-16-11 | |
1 | b | | 03-15-11 |03-18-11
1 | s |03-17-11 | |
1 | b | | 04-20-12 |04-30-12
1 | S |04-20-12 | |
1 | s |04-10-12 | |
1 | s |10-01-14 | |
1 | b | |10-02-14 |10-25-14
2 | s |01-18-12 | |
2 | b | |01-18-12 |01-28-12
2 | b | |03-10-13 |03-24-13
2 | s |03-16-13 | |
2 | s |03-10-13 | |
2 | s |03-23-13 | |
2 | b | |04-20-13 |04-27-13
2 | s |07-01-14 | |
the table (status = s, id, date) compare it with status = b, same id number and date ( Date value from status s) with the date range of fdate and tdate .
if that data with in range then Billing yes other wise billing no
output like
id |status |date(mm-dd-yy) |fdate(mm-dd-yy) |tdate(mm-dd-yy) |Billing
1 | S |03-16-11 | | |yes
1 | s |03-17-11 | | |yes
1 | S |04-20-12 | | |yes
1 | s |04-10-12 | | |no
1 | s |10-01-14 | | |no
2 | s |01-18-12 | | |yes
2 | s |03-16-13 | | |yes
2 | s |03-10-13 | | |yes
2 | s |03-23-13 | | |yes
2 | s |07-01-14 | | |no
i tried query like below
select *
from ( select * from emp a where status ='s') a
inner join (select * from emp b where status='b') b
on a.pn=b.pn
where a.date<=b.date1 and a.date>=b.date2
its not give exactely result.
please tell me how to write query in sql server .
Try
select a.Id,
a.status,
a.date,
a.fdate,
a.tdate,
max(IsNull(case when a.date between b.fDate and b.tDate
then 'yes'
else 'no'
end, 'no')) Billing
from emp a
left join emp b
on a.Id=b.Id
where a.status ='s'
and b.status = 'b'
group by a.Id,
a.status,
a.date,
a.fdate,
a.tdate
Some questions/comments:
What are the fields: pn, date1 and date2?
date1 in your query is, I guess, bigger than date2

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