Error in admin console:
Unable to access the selected application
Exception in AppMerge flows' progression
Exception in AppMerge flows' progression
VALIDATION PROBLEMS WERE FOUND problem: cvc-attribute.4: The value '6' does not equal the fixed value '5' of attribute 'version':<null>
VALIDATION PROBLEMS WERE FOUND problem: cvc-attribute.4: The value '6' does not equal the fixed value '5' of attribute 'version':<null>
Application.xml:
<?xml version="1.0" encoding="UTF-8"?>
<application xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:application="http://java.sun.com/xml/ns/javaee/application_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/application_6.xsd" id="Application_ID" version="6">
<display-name>weblogic-ear</display-name>
<module>
<web>
<web-uri>weblogic-web.war</web-uri>
<context-root>/view</context-root>
</web>
</module>
<module>
<ejb>weblogic-service.jar</ejb>
</module>
</application>
weblogic-application.xml:
<?xml version="1.0" encoding="UTF-8"?>
<wls:weblogic-application xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-application"
xmlns:javaee="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.oracle.com/weblogic/weblogic-application http://xmlns.oracle.com/weblogic/weblogic-application/1.2/weblogic-application.xsd">
<!-- server-version: 10.3.4 -->
<wls:application-param>
<wls:param-name>webapp.encoding.default</wls:param-name>
<wls:param-value>UTF-8</wls:param-value>
</wls:application-param>
web.xml:
<?xml version="1.0"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>weblogic-web</display-name>
<!--
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
-->
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.faces</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
</web-app>
weblogic.xml:
<?xml version="1.0" encoding="UTF-8"?>
<weblogic-web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.bea.com/ns/weblogic/weblogic-web-app http://www.bea.com/ns/weblogic/weblogic-web-app/1.0/weblogic-web-app.xsd"
xmlns="http://www.bea.com/ns/weblogic/weblogic-web-app">
<jsp-descriptor>
<keepgenerated>true</keepgenerated>
<debug>true</debug>
</jsp-descriptor>
<context-root>/view</context-root>
<fast-swap>
<enabled>false</enabled>
</fast-swap>
</weblogic-web-app>
Help will be appreciated.
Namespace in following claims EE 5, but schema location and version refer to EE 6:
<application xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:application="http://java.sun.com/xml/ns/javaee/application_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/application_6.xsd" id="Application_ID" version="6">
WebLogic 11G is not Java EE 6 application server, it is implementation of Java EE 5.
If application does not use concepts available only in Java EE 6, then version 5 should be used consistently, and deploying to WebLogic 11G is fine.
On the other hand, if features available only in Java EE 6 (EJB 3.1 for example) are in use, version 6 and compatible container should be used. For example Weblogic 12 is tested to be compatible.
Change the Namespace Java version in both web.xml and application.xml
for weblogic 12c use version="6" and for weblogic 10 use version="1.4"
Related
How do I map a servlet to a cron url? This question results from the comment to the answer in the following post: Use Cron jobs with Appengine Endpoints API
In my project the cron job is called as shown in the log in Google App Engine and the url https://[url-commented-out].appspot.com/_ah/api/stocksApi/v1/stocks executes properly when tested in the web browser and returns the proper value.
But I am getting the error 405: HTTP method GET not supported by this URL, when I try to run it in GAE. I've read https://cloud.google.com/appengine/docs/java/config/cron My code in cron.xml file is:
<?xml version="1.0" encoding="UTF-8"?>
<cronentries>
<cron>
<url>/_ah/api/stocksApi/v1/stocks</url>
<description>Backend Process Stocks</description>
<schedule>every 1 minutes from 11:10 to 11:30</schedule>
<timezone>America/New_York</timezone>
</cron>
</cronentries>
My web.xml is:
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" version="2.5">
<servlet>
<servlet-name>SystemServiceServlet</servlet-name>
<servlet-class>com.google.api.server.spi.SystemServiceServlet</servlet-class>
<init-param>
<param-name>services</param-name>
<param-value>
[package].StocksEndpoint</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/spi/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/api/*</url-pattern>
</servlet-mapping>
<security-constraint>
<web-resource-collection>
<web-resource-name>cron</web-resource-name>
<url-pattern>/_ah/api/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>admin</role-name>
</auth-constraint>
</security-constraint>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<filter>
<filter-name>ObjectifyFilter</filter-name>
<filter-class>com.googlecode.objectify.ObjectifyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>ObjectifyFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
I am using Android Studio and have added a backend module by following HelloEndpoints and I have a StocksEndpoint.java
file with a getStocks(); method that returns stocks.
First add a servlet mapping for your cron to web.xml:
<!-- stock servlet -->
<servlet>
<servlet-name>StockServlet</servlet-name>
<servlet-class>YOUR.PACKAGE.HERE.StockServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>StockServlet</servlet-name>
<url-pattern>/cron/stocks</url-pattern>
</servlet-mapping>
make sure to update the servlet class for your servlet!
Then finally put the new cron url in your cron.xml:
<cron>
<url>/cron/stocks</url>
<description>Backend Process Stocks</description>
<schedule>every 1 minutes from 11:10 to 11:30</schedule>
<timezone>America/New_York</timezone>
</cron>
Unfortunately urls under /_ah/api are restricted and cannot be called from within your App.
There are a couple of ways to go around this but the most accepted option is usually to use a regular servlet to serve Cron requests rather connecting to the endpoint.
I successfully deployed a Vaadin application, but when calling it I see ERROR : NOT_FOUND
I suppose that my default page is not found,because the default page is selected wrong.
Question:
How can I point (I suppose in my web.xml) to my default page?
My web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>GoogleAppVaadin701Project</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
Vaadin eclipse plugin does not create web.xml which works for vaadin application. In the book of vaadin you can find section about web.xml - https://vaadin.com/book/vaadin7/-/page/application.environment.html
following is basic servlet definition and mapping based on the book which works fine. Just change the UI parameter to point to your UI implementation
<servlet>
<servlet-name>myservlet</servlet-name>
<servlet-class>
com.vaadin.server.GAEVaadinServlet
</servlet-class>
<init-param>
<param-name>UI</param-name>
<param-value>com.example.higoogle.HigoogleUI</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>myservlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
I'm pretty sure this questions is very easy.
I built a app with google app engine. I use JPA and JAX-RS with Jersey.
my web.xml looks like this:
<?xml version="1.0" encoding="utf-8" standalone="no"?><web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>Jersey Web Application</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.rest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey Web Application</servlet-name>
<url-pattern>/resources/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>SystemServiceServlet</servlet-name>
<servlet-class>com.google.api.server.spi.SystemServiceServlet</servlet-class>
<init-param>
<param-name>services</param-name>
<param-value/>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>SystemServiceServlet</servlet-name>
<url-pattern>/_ah/spi/*</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
My index.html is in war/WEB-INF/index.html. What do i need to do to display it ?
index.html should go directly under war as in war/index.html.
keep your file in war folder itself,
Don't keep inside WEB-INF.
Once you have taken it out,
You just need to give localhost:8888/ it will display the welcome-file ie index.html
you can keep other Jsp's inside WEB-INF, it will just be invisible for direct URL access.
I'm migrating an existing app from Tomcat to GAE. When testing locally, the xhtml pages are loaded as static pages. All processing is bypassed including my filter. However, if I reference a page that doesn't exist, my security filter forwards the request to the login.xhtml and the JSF/facelet renders fine.
Any idea why the xhtml pages are getting processed?
Other integrations: eclipse Helios, gae 1.6.5, maven (eclipse/m2), moharra 2.0.9, richfaces 4.2.0, spring 3.1.1
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<!-- https://community.jboss.org/wiki/HowToUseRichFaces40WithGoogleAppEngine -->
<context-param>
<param-name>com.sun.faces.enableThreading</param-name>
<param-value>false</param-value>
</context-param>
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Production</param-value>
</context-param>
<context-param>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>client</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
</listener>
<filter>
<filter-name>SecurityFilter</filter-name>
<filter-class>com.xyz.web.filter.SecurityFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>SecurityFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>Resource Servlet</servlet-name>
<servlet-class>org.richfaces.webapp.ResourceServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Resource Servlet</servlet-name>
<url-pattern>/org.richfaces.resources/*</url-pattern>
</servlet-mapping>
</web-app>
Update:
It works if I add the following mapping and refer to the page with .jsf extension. Referring to the .xhtml directly, still loads the source. Is it typical configuration to refer to .jsf extension for a .xhtml? If so, how do you configure the app so the source isn't available when accessed via .xhtml?
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
If I correctly understand your needs, you should add
<static-files>
<exclude path="/**.xhtml" />
</static-files>
in appengine-web.xml
If you skip this, your web browser will get reply from "static file server", not from JSF.
I tried Struts 2 in Google App Engine following example from http://www.mkyong.com/google-app-engine/google-app-engine-struts-2-example
It works perfectly but I can't accessed Development Console which is supposed to be accessed in http://localhost:8888/_ah/admin
Is it about the filter? How to fixed it?
Below is the content of web.xml
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>com.mkyong.listener.Struts2ListenerOnGAE</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
Yes, the <url-pattern>/*</url-pattern> maps everything to Struts filter.
I solved it by appending the code below to struts.xml
<constant name="struts.action.excludePattern" value="/_ah/admin"/>