Find specific word in column - sql-server

Question

I am using SQL Server 2008.
My tables are :
Location
------------------------
Id | LocationName
------------------------
1 | Bodakdev
2 | Thaltej Road
3 | Andheri East
4 | Noida Sector 2
Company
--------------------------------------------------------------------------
CId | Address | LocationId
--------------------------------------------------------------------------
11 | 301, GNFC Infotower, Bodakdev, | NULL
12 | 307/308,Arundeep Complex | NULL
13 | 7 Krishana Dyeing Compund, Nagardas rd., Andheri | NULL
14 | B-23 ,Ground Floor,Sector 2 | NULL
--------------------------------------------------------------------------
Currently LocationId in the Company table are null. If Address contains any location name then update LocationId.
For example, Address of CID - 11 contains Bodakdev then update LocationId 1, second example, Address of CID - 13 contains Andheri word then update LocationId 3.
Required output :
CId | Address | LocationId
--------------------------------------------------------------------------
11 | 301, GNFC Infotower, Bodakdev, | 1
12 | 307/308,Arundeep Complex | NULL
13 | 7 Krishana Dyeing Compund, Nagardas rd., Andheri | 3
14 | B-23 ,Ground Floor,Sector 2 | 4
--------------------------------------------------------------------------
I have tried using below query
SELECT
(LEN(Address) - LEN(REPLACE(Address, LocationName, '')) ) / LEN(LocationName)
if Address contains Location Name then it will return number of occurrences otherwise it return 0.
But it will not give correct output. How can I do this? Thanks. Any suggestion would be appreciated.

Answer 1

Try following Query :
1.STEP1 : make one function which can split the sting by any character and return the output in table format .
CREATE FUNCTION [dbo].[fnSplit](
#sInputList VARCHAR(8000) -- List of delimited items
, #sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
) RETURNS #List TABLE (item VARCHAR(8000))
BEGIN
DECLARE #sItem VARCHAR(8000)
WHILE CHARINDEX(#sDelimiter,#sInputList,0) <> 0
BEGIN
SELECT
#sItem=RTRIM(LTRIM(SUBSTRING(#sInputList,1,CHARINDEX(#sDelimiter,#sInputList,0)-1))),
#sInputList=RTRIM(LTRIM(SUBSTRING(#sInputList,CHARINDEX(#sDelimiter,#sInputList,0)+LEN(#sDelimiter),LEN(#sInputList))))
IF LEN(#sItem) > 0
INSERT INTO #List SELECT #sItem
END
IF LEN(#sInputList) > 0
INSERT INTO #List SELECT #sInputList -- Put the last item in
RETURN
END
2.STEP2 : use following query to get your desire output .
DECLARE #LOCATION AS TABLE (ID INT ,NAME VARCHAR(MAX))
DECLARE #COMPANY AS TABLE (CID INT , ADDRESS VARCHAR(MAX) , LOCATIONID INT)
INSERT INTO #LOCATION VALUES(1,'Bodakdev')
INSERT INTO #LOCATION VALUES(2,'Thaltej Road')
INSERT INTO #LOCATION VALUES(3,'Andheri East')
INSERT INTO #LOCATION VALUES(4,'Noida Sector 2')
INSERT INTO #COMPANY VALUES(11,'301, GNFC Infotower, Bodakdev,' , NULL)
INSERT INTO #COMPANY VALUES(12,'307/308,Arundeep Complex' , NULL)
INSERT INTO #COMPANY VALUES(11,'7 Krishana Dyeing Compund, Nagardas rd., Andheri' , NULL)
INSERT INTO #COMPANY VALUES(11,'B-23 ,Ground Floor,Sector 2' , NULL)
UPDATE #Company
SET
LOCATIONID = B.ID
FROM #COMPANY AS A , #LOCATION AS B
WHERE
1 = CASE WHEN
(
SELECT COUNT(*)
FROM FNSPLIT(B.NAME , ' ')
WHERE A.ADDRESS LIKE '%' + ITEM + '%'
) > 0 THEN 1 ELSE 0 END
This is the one way to do it . we can do it using full text searching also.