array not being read properly - c

Question

I have a 2D array. I am iterating all the 8 rows and 10 columns and reading the values using a for loop. Here is the our array and the output:
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 2 1 1 1 0 0 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 1 2 1 2 2 1 2 1 2 1 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
empty row board[3][3] = 0 empty row board[3][4] = 1
empty row board[4][3] = 0 empty row board[4][4] = 2
empty row board[5][3] = 0 empty row board[5][4] = 1
empty row board[6][3] = 0 empty row board[6][4] = 2
empty row board[7][3] = 0 empty row board[7][4] = 2
empty row board[8][3] = 0 empty row board[8][4] = 1
empty row board[9][3] = 0 empty row board[9][4] = 2
empty row board[10][3] = 0 empty row board[10][4] = 1
empty row board[11][3] = 0 empty row board[11][4] = 2
empty row board[12][3] = 0 empty row board[12][4] = 1
The actual array is surrounded by buffer of zeros (atleast 3 on each side). When we try to read row =3, it doesn't read the elements but rather reads them as all zeros. We have printed below the array the elements of row 3 and elements of row+1, which is 4. It can read all elements from row 4 but nothing from row 3. WHY? Please Help!!!
#Mat
Posted Code:
We are trying to find if the row is empty or not.
int emptyRow(int row){
int i, counter;
counter = 0;
for(i=3; i<=num_col+2; i++) {
printf ("empty row board[%d][%d] = %d ", i, row, board[i][row]);
printf ("empty row board[%d][%d] = %d\n", i, row+1, board[i][row+1]);
if(board[i][row] == 1 || board[i][row] == 2 || board[i][row] == 3)
counter++;
}
return counter; /* Counter = 0 means its empty*/
}
The row being passed is 3, the counter counts the number of elements in the row, num_col is the number of columns.
The functions returns counter = 0 which means row 3 is empty.
We are reading the input from a file and printing it. This code is part of an AI we are working on, so cannot post all of the code since it is complicated. Print board is posted below:
Row 3 is our boundary condition, so we dont care whats above row 3 but we need to read in row 3 properly
void print_board(){
int i;
int j;
for(i=0;i< 16; i++){
for(j=0;j<16;j++){
printf("%d ", board[j][i]);
}
printf("\n");
}
}

Answer 1

Assuming the displayed output is from a call to print_board(), and the debugging output shown is from a call to emptyRow(3), then the only explanation that makes sense is that board was modified between those two calls. Check your software to make sure that the board contains the values you expect it to at each stage leading up to the call to emptyRow(3).

Answer 2

Use these lines,
printf ("empty row board[%d][%d] = %d ", i, row, board[row][i]);
printf ("empty row board[%d][%d] = %d\n", i, row+1, board[row+1][i]);
if(board[row][i] == 1 || board[row][i] == 2 || board[row][i] == 3)
This should work as expected. See previous answers re row/col mix up.
This assumes the board array is in fact 16 x 16 in size, and num_col+2 evaluates to 12.
I would use gdb to run the program and then you can use print board[3], print board[4], etc to see what the program sees.

Answer 3

Row and column interchanged up in the code of printing the first set of whole array as matrix
Use
void print_board(){
int i;
int j;
for(i=0;i< 16; i++){
for(j=0;j<16;j++){
printf("%d ", board[i][j]);
}
printf("\n");
}
}