How to pass parameter to Laravel DB::transaction() - database

Question

From the laravel documentation: Database Transaction.
It says that:
DB::transaction(function() {
DB::table('users')->update(array('votes' => 1));
DB::table('posts')->delete();
});
Here, 1 is explicitly entered to update the users...
I tried this using a variable,
$id = 3;
DB::transaction(function() {
DB::table('users')->where('id','=',$id)->get();
});
It throws an error:
Undefined variable: id
I also tried to place to $id as a parameter like this:
$id = 3;
DB::transaction(function($id) {
DB::table('users')->where('id', '=', $id)->get();
});
Still, an error:
Object of class Illuminate\Database\MySqlConnection could not be converted to string
Have I done anything wrong? Please advise. Thanks...

Answer 1

The use keyword is what you need:
$id = 3;
DB::transaction(function($id) use ($id) {
DB::table('users')->where('id', '=', $id)->get();
});
For PHP 7 (untested, edited as requested by the answer below):
$id = 3;
DB::transaction(function() use ($id) {
DB::table('users')->where('id', '=', $id)->get();
});

Answer 2

In PHP 7 the syntax has changed:
$id = 3;
DB::transaction(function () use ($id) {
DB::table('users')->where('id', '=', $id)->get();
});

Answer 3

To answer #CaptainHypertext question of
If you alter $id inside the closure, will it affect the $id outside?
This method worked for me:
$id = 3;
$transactionResult = DB::transaction(function($id) use ($id) {
$request_id = DB::table('requests')->insertGetId([
'company_id' => $company->$id,
]);
return $request_id ;
});
echo($transactionResult);