I have a simple form in a a view and I am trying to access the $this=>passedArgs but it is coming back empty.
I am actualy trying to use the cakeDC search plugin which uses the $this=>passedArgs. It must be something simple I have not done to get the results from the form submit.
find view
<?php
echo $this->Form->create('Member', array(
'url' => array_merge(array('action' => 'find'), $this->params['pass'])
));
echo $this->Form->input('name', array('div' => false));
echo $this->Form->submit(__('Search'), array('div' => false));
echo $this->Form->end();
?>
Controller
public function find() {
debug($this->passedArgs);
exit;
}
I have tried $this->request->params
array(
'plugin' => null,
'controller' => 'members',
'action' => 'find',
'named' => array(),
'pass' => array(),
'isAjax' => false
)
I have add method get to the form.
This question has been asked before but their solution of having lower cases in the public $uses = array('order', 'product'); when it should be public $uses = array('Order', 'Product'); did not work.
Cakephp version 2.3.5
Thanks for any help
Update:
I have set my form to method get and this is the url:
http://localhost/loyalty/members/find?name=searchtext
I have removed the plugin and I still do not get anything $this->passedArgs, but I now get data for $this->request->data['name']. Once I put public $components = array('Search.Prg'); I get noting again for $this->request->data['name'].
I have tried again $this->Prg->parsedParams() with the Search plugin and I just get array()
The documentation is pretty clear on that.
You cannot just debug something that has not been set yet.
So including the plugin itself (and its component) is not enough.
From the readme/documenation:
public function find() {
$this->Prg->commonProcess();
$this->paginate['conditions'] = $this->ModelName->parseCriteria($this->passedArgs);
$this->set('...', $this->paginate());
}
Note the commonProcess() call which then only makes passedArgs contain what you need.
Related
I have two form on a single page: login form and register form. When I submit the register form, it validates both: form fields that are in login and registeration. How can I handle it if both form have the same model (user model)
Register form
<?php echo $this->Form->create('User', array('url' => array('controller' => 'users', 'action' => 'add'))); ?>
<?php echo $this->Form->input('username', array('label' => false, 'div' => false, 'class' => 'reg_input'));?>
<?php echo $this->Form->input('email', array('label' => false, 'div' => false, 'class' => 'reg_input'));?>
<?php echo $this->Form->input('password', array('label' => false, 'div' => false, 'class' => 'reg_input'));?>
<?php echo $this->Form->input('confirm_password', array('type' => 'password', 'label' => false, 'div' => false, 'class' => 'reg_input'));?>
<?php echo $this->Form->submit(__('Submit', true), array ('class' => 'reg_button', 'div' => false));
echo $this->Form->end();?>
and Login form is below
<?php echo $this->Form->create('User', array('controller' => 'users', 'action' => 'login'))?>
<?php echo $this->Form->input('User.username',array('label'=>false,'div'=>false, 'class' => 'reg_input'));?>
<?php echo $this->Form->input('User.password',array('label'=>false,'div'=>false, 'class' => 'reg_input'));?>
<?php echo $this->Form->submit(__('Log in', true), array ('class' => 'reg_button', 'div' => false)); ?>
<?php echo $this->Form->end();?>
When I submit registration form it validates both forms, I want to validate only the registration form.
How can I handle that?
I've come up with a "solution" (I find the approach dirty, but it works) for a different question (very similar to this). That other question worked with elements and views, though. I'll post the entire solution here to see if it helps someone (though I rather someone else comes with a different approach).
So, first: change the creation names for the two forms.
//for the registration
<?php echo $this->Form->create('Registration',
array('url' => array('controller' => 'users', 'action' => 'add'))); ?>
//for the login
<?php echo $this->Form->create('Login',
array('controller' => 'users', 'action' => 'login'))?>
The forms should work, look and post to the same actions, so no harm done.
Second step: I don't have your action code, so I'm going to explain what needs to be done in general
public function login() {
if ($this->request->is('post')) {
//we need to change the request->data indexes to make everything work
if (isset($this->request->data['Login'] /*that's the name we gave to the form*/)) {
$this->request->data['User'] = $this->request->data['Login'];
unset($this->request->data['Login']); //clean everything up so all work as it is working now
$this->set('formName', 'Login'); //we need to pass a reference to the view for validation display
} //if there's no 'Login' index, we can assume the request came the normal way
//your code that should work normally
}
}
Same thing for the registration (only need to change 'Login' to 'Registration').
Now, the actions should behave normally, since it has no idea we changed the form names on the view (we made sure of that changing the indexes in the action). But, if there are validation errors, the view will check for them in
$this->validationErrors['Model_with_errors']
And that 'Model_with_errors' (in this case 'User') won't be displayed in the respective forms because we've changed the names. So we need to also tweak the view. Oh! I'm assuming these both forms are in a view called index.ctp, for example, but if they are on separate files (if you're using an element or similar) I recommend add the lines of code for all the files
//preferably in the first line of the view/element (index.ctp in this example)
if (!empty($this->validationErrors['User']) && isset($formName)) {
$this->validationErrors[$formName] = $this->validationErrors['User'];
}
With that, we copy the model validation of the User to the fake-named form, and only that one. Note that if you have a third form in that view for the same model, and you use the typical $this->form->create('User'), then the validation errors will show for that one too unless you change the form name for that third one.
Doing that should work and only validate the form with the correct name.
I find this a messy approach because it involves controller-view changes. I think everything should be done by the controller, and the view shouldn't even blink about validation issues... The problem with that is that the render function of Controller.php needs to be replaced... It can be done in the AppController, but for every updgrade of Cakephp, you'll have to be careful of copying the new render function of Controller.php to the one replacing it in AppController. The advantage of that approach, though, is that the "feature" would be available for every form without having to worry about changing the views.
Well, it's just not that maintainable anyway, so better to leave it alone if it's just for this one case... If anyone is interested on how to handle this just in the controller side, though, comment and I'll post it.
You can duplicate your model and change his name and define $useTable as the same table name.
Example :
class Registration extends AppModel {
public $useTable = 'users';
You define the action in form->create like Nunser for your login form
<?php
echo $this->Form->create('User',array(
'url' => array(
'controller' => 'Users',
'action' => 'login',
'user' => true
),
'inputDefaults' => array(
'div' => false,
'label' => false
),
'novalidate'=>true,
));
?>
and your registration form
<?php
echo $this->Form->create('Registration',array(
'url' => array(
'controller' => 'Users',
'action' => 'validation_registration',
'user' => false
),
'inputDefaults' => array(
'div' => false,
'label' => false
),
'novalidate'=>true,
));
?>
In your controller define a method for registration validation and the most important define the render
public function validation_registration(){
$this->loadModel('Registration');
if($this->request->is('post')){
if($this->Registration->save($this->request->data)){
--- code ---
}else{
--- code ---
}
}
$this->render('user_login');
}
Sorry for my english ! Have a nice day ! :D
The create method on your login form is missing the 'url' key for creating the action attribute. I tried to re-create this once I fixed this and could not. Maybe that will fix it?
I am trying to work with HABTM association between Profiles and Qualifications tables.
Model: Profile.php
App::uses('AppModel', 'Model');
class Profile extends AppModel {
public $hasAndBelongsToMany = array(
'Qualification' => array(
'className' => 'Qualification',
'joinTable' => 'profile_qualifications',
'foreignKey' => 'profile_id',
'associationForeignKey' => 'qualification_id',
'unique' => 'keepExisting'
)
);
}
Model: Qualification.php
App::uses('AppModel', 'Model');
class Qualification extends AppModel {
public $hasAndBelongsToMany = array(
'Profile' => array(
'className' => 'Profile',
'joinTable' => 'profile_qualifications',
'foreignKey' => 'qualification_id',
'associationForeignKey' => 'profile_id',
'unique' => 'keepExisting',
)
);
}
Controller: ProfilesController.php
App::uses('AppController', 'Controller');
class ProfilesController extends AppController {
public function edit() {
$this->Profile->id = $this->Auth->user('profile_id');
if ($this->request->is('post') || $this->request->is('put')) {
if ($this->Profile->save($this->request->data)) {
$this->Session->setFlash(__('The profile has been saved'));
$this->redirect(array('action' => 'view'));
} else {
$this->Session->setFlash(__('The profile could not be saved. Please, try again.'));
}
} else {
$this->request->data = $this->Profile->read(null, $this->Auth->user('profile_id'));
}
$salutations = $this->Profile->Salutation->find('list', array('fields' => array('Salutation.id', 'Salutation.abbr_name')));
$qualifications = $this->Profile->Qualification->find('list', array('fields' => array('Qualification.id', 'Qualification.abbr_name')));
$this->set(compact('salutations', 'qualifications'));
}
}
Vew: edit.ctp
<div class="profiles form">
<?php echo $this->Form->create('Profile'); ?>
<fieldset>
<legend><?php echo __('My Profile'); ?></legend>
<?php
echo $this->Form->input('salutation_id');
echo $this->Form->input('first_name');
echo $this->Form->input('middle_name');
echo $this->Form->input('last_name');
echo $this->Form->input('qualification'); /* gives drop down not multi select */
echo $this->Form->input('bio');
echo $this->Form->input('email');
echo $this->Form->input('mobile');
echo $this->Form->input('phone');
?>
</fieldset>
<?php echo $this->Form->end(__('Submit')); ?>
</div>
The edit view thus generated contains drop down to select a single value at a time for Qualifications attribute.
I want to know how can I generate a view with multi value selection box for qualifications ?
Moreover, what is the mistake in my code right now ?
First time poster, long time user.
I stumbled across this question today, and ended up using the subsequent solution which indeed does work quite nicely. However, I left myself wondering "why wouldn't CakePHP pickup on the HABTM relationship properly?" Especially considering (at least in my case) that the majority of the files had been baked in the cake console.
If we dive a little deeper into the issue, we discover that the problem is actually quite simple. A closer look at this snippet in the PostsController.php reveals how Cake builds in the HABTM relationship to the function, and uses $this->set() in order to pass it to the view (IMPORTANT: using lower-case plural versions "salutations"):
$salutations = $this->Profile->Salutation->find('list', array('fields' => array('Salutation.id', 'Salutation.abbr_name')));
$qualifications = $this->Profile->Qualification->find('list', array('fields' => array('Qualification.id', 'Qualification.abbr_name')));
$this->set(compact('salutations', 'qualifications'));
According to the Cake Cook Book, in order to take advantage of this HABTM in the front end when using the form helper is to specify the variable in singular form & title case (ie: "Salutation")
Snippet from the cook book:
Assuming that User hasAndBelongsToMany Group. In your controller, set a camelCase plural variable (group -> groups in this case, or ExtraFunkyModel -> extraFunkyModels) with the select options. In the controller action you would put the following:
$this->set('groups', $this->User->Group->find('list'));
And in the view a multiple select can be created with this simple code:
echo $this->Form->input('Group');
Should solve your issue without any necessary field tweaking.
Cheers!
Bake on.
Perhaps you need further configuration of your input:
echo $this->Form->input('Qualification',array(
'label' => 'Qualifications',
'type' => 'select',
'multiple' => true, // or 'checkbox' if you want a set of checkboxes
'options' => $qualifications,
'selected' => $html->value('Qualification.Qualification'),
));
I've used this blog post whenever I've come up against HABTM associations. It seems to me that a set of checkboxes maybe desired by default over a select input - maybe someone with greater CakePHP insight can chime in here?
Change
echo $this->Form->input('qualification');
to
echo $this->Form->input('qualification', array(
'multiple' => true
));
The CakePHP manual has more information on the form helper input options.
I can't seem to get my edit class to work. My validation works fine and when I use debug($this->data) after hitting the edit button all the displayed data is perfect, but not updating the tables.
Here is my edit class.
public function edit($id = null) {
if($this->request->is('get')) {
$this->request->data = $this->Bookmark->read(null, $id);
} else {
if($this->Bookmark->saveAll($this->request->data)) {
$this->Session->setFlash('The bookmark has been saved!');
$this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash('The bookmark could not be saved. Please, try again.');
}
}
}
Here is the view.
<?php
echo $this->Form->create('Bookmark', array(
'action' => 'edit',
'inputDefaults' => array(
'class' => 'input-text'
)
));
echo $this->Form->inputs(array(
'legend' => false,
'fieldset' => true,
'Bookmark.title',
'Url.url',
'Bookmark.id' => array('type' => 'hidden'),
'Url.id' => array('type' => 'hidden')
));
echo $this->Form->button('Edit');
echo $this->Form->end();
?>
I have updated my edit class, but that still didn't fix my error. What fixed it was the two hidden fields I added to the view.
'Bookmark.id' => array('type' => 'hidden'),
'Url.id' => array('type' => 'hidden')
Not really sure why, but I looked at some other edit views online and tried this and it now works.
Try following this page: http://book.cakephp.org/2.0/en/models/saving-your-data.html
In Cake 2.0.x you should be using $this->request->data, though that's not likely the problem. You'll also see they're not setting the id manually, but allowing the form to do that fom them.
If you try it as the book suggests, and it's still not working, post your new attempt as an Edit to this question.
Each time this happend to me was because of validation error. Check for validation errors like so
echo debug( $this->ModelName->invalidFields() );
After migrating a fully functional Cake 1.3 application to the recently released 2.0 version Authentication has ceased to work.
I've changed the calling of the AuthComponent and the structure of the login action according to the updated 2.0 manual, to no avail. The strange thing is the user is actually validated by $this->Auth->login() as it reaches the part of the login function where the user is redirect to the url set by $this->Auth->redirect(). After that redirect however, $this->Auth->user() returns empty (as well as AuthComponent::user()) and the user isn't logged in by the Auth component.
Cake doesn't throw any error during the process, the flash messages for 'auth' remain empty.
Users are stored in a simple database table containing id, username, email, password and timestamp columns. The passwords are hashed and I've added some users using the new Cake 2.0 methods.
This is the code of AppController.php:
<?php
class AppController extends Controller {
public $helpers = array('Session', 'Html', 'Time', 'Form', 'Text');
public $components = array('Session', 'RequestHandler', 'Auth');
public function beforeFilter() {
$this->Auth->loginAction = array('controller' => 'users', 'action' => 'login');
$this->Auth->loginRedirect = array('controller' => 'maps', 'action' => 'index');
$this->Auth->logoutRedirect = array('controller' => 'maps', 'action' => 'index');
}
}
?>
UserController.php:
<?php
class UsersController extends AppController {
public $name = 'Users';
function beforeFilter() {
parent::beforeFilter();
}
function login() {
if ($this->request->is('post')) {
if ($this->Auth->login()) {
return $this->redirect($this->Auth->redirect());
}
}
}
function logout() {
$this->redirect($this->Auth->logout());
}
}
?>
User.php model. I've disabled form validation for the time being after I solve this problem:
<?php
class User extends AppModel {
public $name = 'User';
}
?>
The login view:
<?php
echo $this->Form->create('User');
echo $this->Form->input('username', array('label' => 'Username', 'before' => '<p class="input" id="username">', 'after' => '</p>', 'between' => '<br />', 'div' => false));
echo $this->Form->input('password', array('label' => 'Password', 'before' => '<p class="input" id="password">', 'after' => '</p>', 'between' => '<br />', 'div' => false));
echo $this->Form->end('Login');
?>
I also tried to setting some of the Auth features in the $components variable in the AppController, which didn't work as well:
public $components = array(
'Auth'=> array(
'loginAction' => array(
'controller' => 'users',
'action' => 'login',
),
'loginRedirect' => array(
'controller' => 'maps',
'action' => 'index',
),
'authenticate' => array(
'Form' => array(
'fields' => array('username', 'password')
)
)
)
);
What's causing the problem here? Routing maybe? I've commented out all routes except:
require CAKE . 'Config' . DS . 'routes.php';
UPDATE:
After adding some debug statements in the login method in the UsersController I now know $this->Auth->user() is actually populated with the correct user after the call to $this->Auth->login(). After the redirect to another controller the login session is lost completely, however. So I still don't know what's going wrong here.
UPDATE 2
I've restarted the process of migrating by taking my working 1.3 application and running the migration console script on it like I did the last time.
This time I noticed the script stopped because of two errors relating to custom components. Component classes should extend Component now, instead of the 1.3 default: Object.
After fixing these component errors I ran the migration script again (something I neglected to do during the first migration attempt) and implemented the new AuthCompenent call. So far everything seems to be working correctly. Not sure what's different now and what went wrong the first time, as Cake didn't output any error messages.
UPDATE 3
It's getting weirder. I thought I solved it, but after transferring my code to another development machine Auth suddenly stops working. It's working on my main setup, but while testing on another it fails again following the same scenario. I've cleared the cache to be sure, but it still isn't working. Cake doesn't generate any error output.
UPDATE 4
It appears to be a Session problem on my machine. I've just set the Session to be stored in a cookie and suddenly Auth starts working again. Not sure why the default Session isn't working and I don't know where to start debugging in that case.
Only cookie sessions appear to work, defining a database session has the same result as a regular session; Auth stops working.
Try it with use_trans_sid enabled in /Config/core.php:
Configure::write('Session', array(
//'defaults' => 'php'
'defaults' => 'cake',
'cookie' => 'CAKEPHP2',
'ini' => array('session.use_trans_sid' => true)
));
Did you try also to configure the Authentication handler ?
public $components = array(
'Auth'=> array(
'authenticate' => array('Form')
)
);
I'm working with CakePHP and trying to understand the best ways to make my application consistent and logical.
Now I'm trying to working with Model data validation and handling validation errors in the view, I have a doubt on how should I do if I like to insert some link inside the returned error, for example for a forgotten password.
Is it good to use (if it's possibile) HtmlHelper inside the Model to return consistent links inside my application, or should I think about another way?
<?php
App::import('Helper', 'Html');
class User extends AppModel {
var $name = 'User';
var $validate = array (
'email' => array (
'checkEmail' => array (
'rule' => array('email', true),
'message' => 'Email not valid message.'
),
'checkUnique' => array (
'rule' => 'isUnique',
'message' => 'This email is allready in the db, if you forgot the password, '.(string)$this->Html->link('click here', array('controller' => 'users', 'action' => 'password-recover')).'.'
)
)
// the rest of the code...
This doesn't work because it seems I can't chain the message string with HTML string.
Does exist e smartest way to do that, or should I simply insert the html string without the HtmlHelper?
If you really want HTML in your validation messages CakePHP provides a way to do this, no breaking Cake, no writing a lot of code.
In your $validation just use whatever HTML you would like to have presented to the user.
In your view when you create your FormHelper::input($fieldName, array $options) pass the following array to $options:
$options = array('error' => array(
'attributes' => array('escape' => false)
))
See this page to learn more about the $options['error'] ...options.
Alternatively, if you want all inputs with no HTML escaping you can pass $options['inputDefaults'] when you create the form.
this is a difficult topic because
you might need to break MVC
validation is as in your case usually in $validate and cannot contain dynamic stuff
for 1)
you can also use Router::url() with manual HTML
you can use BBcode or pseudo-markup and translate this into real links in the view/element of the flashmessage
for 2)
use __construct() and $this->validate to use dynamic elements if needed
In PHP, properties of a class (such as $validate) have to be initialized with constant values.
<?php
class User extends AppModel {
public $validate = array(
'email' => array(
'checkUnique' => array(
'rule' => array('isUnique'),
'message' => 'This email address has already been claimed, possibly by you. If this is your email address, use the reset password facility to regain access to your account'
),
),
);
public function beforeValidate($options = array()) {
$this->validate['email']['checkUnique']['message'] = String::insert(
$this->validate['email']['checkUnique']['message'],
array('link' => Router::url(array('action' => 'password-recover')))
);
return true;
}
You are making it hard on yourself. The helpers are not accessible in the model and controller. And for good reason: the M and C shouldn't be concerned with the V.
There are ways to do exactly as you want (but involves considerably more code). Since you ask for the smartest way: What's wrong with just echo the reset password link in the view, after the login form? Just echo 'Forgot your password? '.$this->Html->link('Click here', array('controller' => 'users', 'action' => 'password-recover'));
I don't agree on breaking the MVC logic. I also tried all the array('escape' => false) possible ways (in Form->input, in Form->error and even in the model) and none of them worked with me! (cakephp 2.0)
"Anh Pham" answer is the easiest and simplest way. In addition to that, I returned empty error message from model validation ('errorMessage' => false ; doesn't work in cakePhp 2.0).
Because I wanted to pass a variable to the view to build the link there (MVC), in the controller I check if the field is invalidated:
$invlaidFields = array_keys($this->Model->validationErrors();
if ( in_array('myField', $invalidFields) ){
...
}
In the view, I check if the field was invalidated, I then echo my error message giving it class error-message so it looks the same as the rest error messages.
if ($this->Form->('myFields')) { ... echo '<span class="error-message">error message'. $this->Html->link(...).'</span>'; }
Hope it helps somebody out there.
P.S. It's always a good practice to mention what cakePHP version you are using...
To cakephp2 you can use the following:
//model validation
'company' => array('notempty' => array('rule' => array('notempty'),'message' => "select one company o send email to contact",),)
//front
<?php if ($this->Form->isFieldError('Register.company')): ?>
<span class="text-danger"><?php echo $this->Form->error('Register.company', null, array('escape'=>false)); ?></span>
<?php endif; ?>