How to get choices of each item in a table in cakephp? - cakephp

Question

This is my choices table
id | question_id | content
1 1 bee
2 1 fly
3 1 dog
4 2 cat
5 2 bat
6 2 wasp
and this is my questions table
id | content
1 question1
2 item2
This is what i did.With this I could display the question with its choices..what I want to do now, is to paginate it,more like 1 question per page.How to do this?Your help will be greatly appreciated.Thanks
$options['fields'] = array('questions.id','questions.content');
$options['joins'] = array(
array(
'table' => 'generated_exam_items',
'alias' => 'GenExamItems',
'type' => 'inner',
'conditions' => array(
'GenExamItems.generated_examination_id' => 25
)
),
array(
'table' => 'questions',
'alias' => 'Questions',
'type' => 'inner',
'conditions' => array(
'Questions.id = GenExamItems.questions_id'
)
),
);
$options['conditions']=array('GenExamItems.generated_examination_id' => 25,'Question.id=GenExamItems.questions_id');
$question_detail = $this->Question->find('all',$options);
$this->set('questions',$question_detail);
Someone please help me.!!I dont how to do it and im stuck in this for almos a week..

Answer 1

you can get using relation ship with each other model
as here i am just adding skeleton code you need to verify it to you actual code with real classname
In Question model write this relation
class Question extends AppModel {
public $hasMany = array(
'Choice' => array(
'className' => 'Choice',
)
);
And in Choice model you can define like
class Choice extends AppModel {
public $belongsTo = 'Question';
}
And in controller if you want to fetch for speacific Question with its choices you can write query like below
$question_detail = $this->Question->find('first', array(
'conditions' => array('Question.id' => $question_id)
));
let me know if i can help you more

Answer 2

Let's assume you have the correct associations on both models.
I'll show the code for just one question in the view.
If you use the automagic way cake provides (read the "Creating form elements" part)
In your controller, you have to get the choices
$this->set('choices', $this->Question->Choice->find('list',
array('conditions'=>
array('question_id'=>$your_question_id))));
And in your view, you have to do
echo $this->Form->input('choice_id', array('type'=>'radio'));
That should automatically display the choices as radios (not really sure what type of input you wanted)
If by some reason the automagic way doesn't work (be sure to check your model's associations if that happens), then you can pass the array of choices (get them as showed before on the controller) and pass it as a parameter
echo $this->Form->input('choice_id', array('type'=>'radio',
'options'=>$choices));
Note: If the radio labels are showing the ids instead of the content, you'll have to change the displayField of choices.

Answer 3

This what i did.It returns the question and corresponding choices.I hope I will be able to someone with this.Thank you.
public function take($id=null) {
$this->request->params['named']['page'] = (isset($this->request->params['page'])) ? $this->request->params['page'] : 1;
$options['fields'] = array('questions.id','questions.content');
$options['joins'] = array(
array(
'table' => 'generated_exam_items',
'alias' => 'GenExamItems',
'type' => 'inner',
'conditions' => array(
'GenExamItems.generated_examination_id' => 40
)
),
array(
'table' => 'questions',
'alias' => 'Questions',
'type' => 'inner',
'conditions' => array(
'Questions.id = GenExamItems.questions_id'
)
),
);
//$options['contains']='Choice';
$options['conditions']=array('Question.id = GenExamItems.questions_id');
$options['order']=array('rand(Question.id)');
$options['limit']=1;
$this->paginate=$options;
$data = $this->paginate('Question');
$this->set('questions',$data);
}