Trouble with insertion of C string into linked list - c

I am writing a program to read a file and then store the data into a linked List.
linkedList.h
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdbool.h>
struct linked_list
{
char *stock_name;
double stock_price;
struct linked_list *next;
};
typedef struct linked_list NODE;
NODE* insert(NODE *head, double stock_price, char *stock_name);
void printList(NODE *head);
linkedList.c
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdbool.h>
#include"linkedList.h"
void printList(NODE *head)
{
NODE *this = head;
while(this != NULL)
{
printf("stock name:%s , stock price:%lf\n", this->stock_name, this->stock_price);
this = this->next;
}
}
NODE* insert(NODE *head, double stock_price, char *stock_name)
{
NODE *newNode = malloc(sizeof(NODE));
if(head == NULL)
{
newNode->stock_price = stock_price;
newNode->stock_name = stock_name;
head = newNode;
}
else
{
newNode->stock_price = stock_price;
newNode->stock_name = stock_name;
newNode->next = head;
head = newNode;
}
return head;
}
main.c
#include <stdio.h>
#include <stdbool.h>
#include <string.h>
#include "linkedList.h"
NODE *head;
bool headNode = true;
void insertIntoLinkedList(char *stock_name, double stock_price);
int main ( int argc, char *argv[] )
{
head = malloc(sizeof(NODE));
double stock_price;
char stock_name[100];
int stock_name_counter = 0;
**..then I read the file..**
stock_name[stock_name_counter] = '\0'; //to end my C string
stock_name_counter = 0; //this is used for reading char
insertIntoLinkedList(stock_name, stock_price); //I double checked here,the name and price is correct
**......**
printList(head); //**Not the output I want**
fclose( file );
void insertIntoLinkedList(char *m_stock_name, double m_stock_price)
{
if(headNode == true)
{
head = insert(NULL, m_stock_price, m_stock_name);
headNode = false; //this is used to insert data to my linked list for the first time
}
else
{
head = insert(head, m_stock_price, m_stock_name);
}
}
Here is the problem: if the file contains:
YAHOO 120
GOOGLE 10
APPLE 199
my printList() gave me this:
APPLE 120
APPLE 10
APPLE 199
I have been trying to debug for hours and still cannot figure why the name is not stored in my linked list properly(but the price is store properly..)...any help will be appreciate :)

The address of stock_name in main is always constant through out the program and you store that address to newNode->stock_name and so you will always get the last stored string in stock_name.
Modification
NODE* insert(NODE *head, double stock_price, char *stock_name)
{
NODE *newNode = malloc(sizeof(NODE));
newNode->stock_name = malloc(strlen(stock_name)+1);
if(head == NULL)
{
newNode->stock_price = stock_price;
strcpy(newNode->stock_name, stock_name);
head = newNode;
}
else
{
newNode->stock_price = stock_price;
strcpy(newNode->stock_name, stock_name);
newNode->next = head;
head = newNode;
}
return head;
}
Don't forget to free the allocated memory.

You need to make a copy of the string stored in stock_name when you call insert. As is, all the nodes point to the same buffer, and every time you read a new line, you overwrite the buffer. In the end, this means that all of the nodes have the text APPLE because that's the last content that's read into the shared buffer. If you either copy the buffer's contents (instead of just the pointer to the buffer) or allocate a new buffer every time you read from the file, this will be fixed.

Your basic problem is that C does not have a "String" type. A string is simple an array of characters, and an array "decays" to a pointer when used as an argument to a function. Based on the way you're using it, your insert() function should do a second malloc() to allocate storage for the string and use strdup() or similar to store it.
Your other problem is that you've got a logic flaw in the insert() function. You aren't initializing newNode->next if head is NULL. You should be doing newNode->next = head either way. If it's NULL, good. Your list tail will then not be pointing at an indeterminate place.

Related

Unable to make push function for linked-list

After many hours of searching in google and stackoverflow, finally I couldn't release an obvious way to make push function for linked-list.
I wanna make push function which adds new node with new value at the end of a particular linked-list. My last effort to do this is shown below but it doesn't work.
Where I made mistake and how I can fix it?
#include <stdio.h>
#include <stdlib.h>
struct node{
int value;
struct node *next;
};
typedef struct node node_t;
void push(node_t *h, int val){
//copy value head
node_t *copy;
copy = h;
//reach to last node
while(copy->next != NULL)
copy = h->next;
//make new node and value "val"
copy->next = malloc(sizeof(node_t));
copy->next->next = NULL;
copy->next->value = val;
}
int main(){
node_t h;
h.next = NULL;
push(&h, 100);
push(&h, 200);
push(&h, 300);
printf("%d", h.next->value);
return EXIT_SUCCESS;
}
Additional information:
It was compiled properly but it wasn't ran.
I use TDM-GCC and C language not C++.
This loop is wrong,
//reach to last node
while(copy->next != NULL)
copy = h->next;
You are assigning h->next again and again. It will be an infinite loop when h->next is not NULL and h->next->next is not NULL.
The loop should be:
//reach to last node
while(copy->next != NULL)
copy = copy->next;

Fail to push head on Linked List

I tried to create a program to add elements to a linked list. The elements consist of name and age. But it fails to add without giving me any error. Could you please show me my mistake?
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#define MAX 9999
struct data {
char name[MAX];
int age;
struct data *next;
};
void pushHead(struct data **head, struct data **tail, char name[], int age) {
struct data *node = (struct data *)malloc(sizeof(struct data));
strcpy(node->name, name);
node->age = age;
if (*head == NULL) {
node = *head;
node = *tail;
node->next = NULL;
} else {
node->next = *head;
*head = node;
}
}
void view(struct data *head) {
struct data *curr = head;
if (curr == NULL)
printf("No Data\n");
else {
while (curr != NULL) {
printf("%s(%d)\n", curr->name, curr->age);
curr = curr->next;
}
}
}
int main(int argc, char const *argv[]) {
struct data *head = NULL;
struct data *tail = NULL;
pushHead(&head, &tail, "Felix", 19);
view(head);
return 0;
}
Output : No Output
My code is working when I put the head on global scope (by changing all the functions to work globally), but when I try to put the head in main scope it doesn't work.
In pushHead(), you are doing:
node = *head;
node = *tail;
this end up assigning NULL to node pointer because *head and *tail both are NULL. Note that this is a memory leak as your program loose the memory reference which the node pointer is holding. Instead, you should do
*head = node;
*tail = node;
Some suggestions:
For storing name in the list node, you are taking buffer of size
9999 (MAX macro) which is (IMO) very large. I believe, a buffer
of size 256 is more than enough for this purpose. Or, you can also
have buffer of exact size required for storing name by allocating
the memory dynamically to it. For this , you have to take a char *
member instead of char array for name and allocate memory to it
dynamically based on size of name parameter of pushHead() and in
this case, you need to make sure to free it explicitly when deleting
the list nodes.
When using strcpy() to copy string, make sure that destination
buffer is large enough to contain the source string to avoid
overflows.
Follow good programming practice. Always check malloc return and
ensure to free the allocated memory once you are done with it.
Do not cast the malloc return.
To include standard library header files use <>, i.e. #include "stdio.h" -> #include <stdio.h>, check this.

How to make changes in an array through a function

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define SIZE 10
// A hashtable is a mixture of a linked list and array
typedef struct node NODE;
struct node{
int value;
NODE* next;
};
int hash(int);
void insert(int,NODE **);
int main(){
NODE* hashtable[SIZE];
insert(12,&hashtable[SIZE]);
printf("%d\n",hashtable[5]->value);
}
int hash(int data){
return data%7;
}
void insert(int value,NODE **table){
int loc = hash(value);
NODE* temp = malloc(sizeof(NODE));
temp->next = NULL;
temp->value = value;
*table[loc] = *temp;
printf("%d\n",table[loc]->value);
}
The above code prints :
12 and
27475674 (A random number probably the location.)
how do I get it to print 12 and 12 i.e. how to make a change in the array. I want to fill array[5] with the location of a node created to store a value.
The expression *table[loc] is equal to *(table[loc]) which might not be what you want, since then you will dereference an uninitialized pointer.
Then the assignment copies the contents of *temp into some seemingly random memory.
You then discard the memory you just allocated leading to a memory leak.
There's also no attempt to make a linked list of the hash-bucket.
Try instead to initially create the hashtable array in the main function with initialization to make all pointers to NULL:
NODE* hashtable[SIZE] = { NULL }; // Will initialize all elements to NULL
Then when inserting the node, actually link it into the bucket-list:
temp->next = table[loc];
table[loc] = temp;
This is just a simple change which I have made to your program which will tell you what you are actually doing wrong.
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define SIZE 10
// A hashtable is a mixture of a linked list and array
typedef struct node NODE;
struct node {
int value;
NODE* next;
};
NODE *hashtable[SIZE] = { NULL };
int hash(int);
int insert(int); //, NODE **);
int main(void)
{
int loc = insert(12); //, &hashtable[SIZE]);
if (loc < SIZE) {
if (hashtable[loc]) {
printf("%d\n", hashtable[loc]->value);
} else {
printf("err: invalid pointer received\n");
}
}
return 0;
}
int hash(int data)
{
return data%7;
}
int insert(int value) //, NODE *table[])
{
int loc = hash(value);
printf("loc = %d\n", loc);
if (loc < SIZE) {
NODE *temp = (NODE *) malloc(sizeof(NODE));
temp->value = value;
temp->next = NULL;
hashtable[loc] = temp;
printf("%d\n", hashtable[loc]->value);
}
return loc;
}
Here I have declared the hashtable globally just to make sure that, the value which you are trying to update is visible to both the functions. And that's the problem in your code. Whatever new address you are allocating for temp is having address 'x', however you are trying to access invalid address from your main function. I just wanted to give you hint. Hope this helps you. Enjoy!

Trying to add a node into a linked list

I've been trying to add a new node into a linked list of profiles (for ex. facebook profiles), and I'm getting a runtime error while launching. This is what I got :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdlib.h>
typedef struct friend {
char *name;
int age;
char gender;
struct friend* next;
} friend;
void node_add(friend* new);
int main(int argc, char *argv[]) {
friend amit;
friend *new;
amit.name = "amit";
amit.age = 16;
amit.gender = 'm';
node_add(new);
new->name = "amit";
printf ("name: %s\n", new->name);
system("PAUSE");
return 0;
}
void node_add(friend* new) {
new = (friend* )malloc(sizeof(friend));
friend* head = new;
new -> next = head;
}
I'm trying now to create a delete node function. I tried to find which node does the user wants to delete, and then delete it by doing
delete -> next = delete -> next -> next
The problem is, I need to get for the first node in the list.
Here is what I wrote:
void node_delete(friend* delete) {
friend *temp;
char name[256];
int i = 0, j = 0;
printf ("Please enter the friend's name you want to delete: \n");
fgets (name, 256, stdin);
fgets (name, 256, stdin);
while (0 == (strcmp(temp -> next -> name, delete -> next -> name))) {
temp = friend -> next;
}
temp -> next = temp -> next -> next;
free (delete);
}
Edit:
It seems my test was a mite too quick, because there is in fact a pretty serious problem with this code, but it's subtle:
In main() you are never actually pointing new at anything. It's just a garbled pointer out into memory space, which might sometimes work, and most of the time, is just terrible.
friend *new; // here's your problem; change this to:
friend *new = malloc(sizeof(friend));
Also, never cast the results of malloc.
Reedit:
How a very simple linked list implementation might look:
typedef struct _node node;
struct _node {
void *payload;
node *next;
};
node *create_node () {
node *retval = malloc(sizeof(node));
retval->payload = NULL;
retval->next = NULL;
return retval;
}
node *add_node (node *target) {
if (target->next)
return;
node *next = create_node();
node->next = next;
}
node *node_search (node *haystack, void *needle) {
while (haystack) {
if (!compare(needle, haystack->payload)) {
return haystack;
} else {
haystack = haystack->next;
}
}
return NULL;
}
Implementation of deletion and insertion are left as an exercise to the reader.
Of course, you alloc memory and assign it to local variable.
If you want to change pointer, pass pointer with one more asterix.
And, by the way, do not name anything like friend or new. Its keywords in C++,
and it create not needed problems.
You should have friend *head global.
And in the
void node_add(friend* new)
{
new = (friend* )malloc(sizeof(friend));
new->next = head;
head = new;
}
You should use a double-pointer.
void node_add(friend **new) {
*new = malloc(sizeof(friend));
/* etc */
}
The issue is in the following line:
amit.name = "amit";
You should be a malloc and doing a strcpy()

How to implement a linked list in C?

I am creating a linked list as in the previous question I asked. I have found that the best way to develop the linked list is to have the head and tail in another structure. My products struct will be nested inside this structure. And I should be passing the list to the function for adding and deleting. I find this concept confusing.
I have implemented the initialize, add, and clean_up. However, I am not sure that I have done that correctly.
When I add a product to the list I declare some memory using calloc. But I am thinking shouldn't I be declaring the memory for the product instead. I am really confused about this adding.
Many thanks for any suggestions,
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define PRODUCT_NAME_LEN 128
typedef struct product_data
{
int product_code;
char product_name[PRODUCT_NAME_LEN];
int product_cost;
struct product_data_t *next;
}product_data_t;
typedef struct list
{
product_data_t *head;
product_data_t *tail;
}list_t;
void add(list_t *list, int code, char name[], int cost);
void initialize(list_t *list);
void clean_up(list_t *list);
int main(void)
{
list_t *list = NULL;
initialize(list);
add(list, 10, "Dell Inspiron", 1500);
clean_up(list);
getchar();
return 0;
}
void add(list_t *list, int code, char name[], int cost)
{
// Allocate memory for the new product
list = calloc(1, sizeof(list_t));
if(!list)
{
fprintf(stderr, "Cannot allocated memory");
exit(1);
}
if(list)
{
// First item to add to the list
list->head->product_code = code;
list->head->product_cost = cost;
strncpy(list->head->product_name, name, sizeof(list->head->product_name));
// Terminate the string
list->head->product_name[127] = '/0';
}
}
// Initialize linked list
void initialize(list_t *list)
{
// Set list node to null
list = NULL;
list = NULL;
}
// Release all resources
void clean_up(list_t *list)
{
list_t *temp = NULL;
while(list)
{
temp = list->head;
list->head = list->head->next;
free(temp);
}
list = NULL;
list = NULL;
temp = NULL;
}
============================== Edited ============================
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define PRODUCT_NAME_LEN 64
// typedef struct product_data product_data_t;
typedef struct product_data
{
int product_code;
char product_name[PRODUCT_NAME_LEN];
int product_cost;
}product_data_t;
typedef struct list
{
struct list *head;
struct list *tail;
struct list *next;
struct list *current_node;
product_data_t *data;
}list_t;
void add(list_t *list, int code, char name[], int cost);
int main(void)
{
list_t *list = NULL;
list = initialize(list);
add(list, 1001, "Dell Inspiron 2.66", 1299);
add(list, 1002, "Macbook Pro 2.66", 1499);
clean_up(list);
getchar();
return 0;
}
void add(list_t *list, int code, char name[], int cost)
{
/* Allocate memory for the new product */
product_data_t *product = (product_data_t*) calloc(1, sizeof(*product));
if(!product)
{
fprintf(stderr, "Cannot allocate memory.");
exit(1);
}
/* This is the first item in the list */
product->product_code = code;
product->product_cost = cost;
strncpy(product->product_name, name, sizeof(product->product_name));
product->product_name[PRODUCT_NAME_LEN - 1] = '\0';
if(!list->head)
{
/* Assign the address of the product. */
list = (list_t*) product;
/* Set the head and tail to this product */
list->head = (list_t*) product;
list->tail = (list_t*) product;
}
else
{
/* Append to the tail of the list. */
list->tail->next = (list_t*) product;
list->tail = (list_t*) product;
}
/* Assign the address of the product to the data on the list. */
list->data = (list_t*) product;
}
If you are looking to better understand the basics of linked lists, take a look at the following document:
http://cslibrary.stanford.edu/103/LinkedListBasics.pdf
Arguably you want your list data structure to be external to the data that it stores.
Say you have:
struct Whatever
{
int x_;
}
Then your list structure would look like this:
struct Whatever_Node
{
Whatever_Node* next_
Whatever* data_
}
Ryan Oberoi commented similarly, but w/o example.
In your case the head and tail could simply point to the beginning and end of a linked-list. With a singly linked-list, only the head is really needed. At it's most basic, a linked-list can be made by using just a struct like:
typedef struct listnode
{
//some data
struct listnode *next;
}listnodeT;
listnodeT *list;
listnodeT *current_node;
list = (listnodeT*)malloc(sizeof(listnodeT));
current_node = list;
and as long as list is always pointing to the beginning of the list and the last item has next set to NULL, you're fine and can use current_node to traverse the list. But sometimes to make traversing the list easier and to store any other data about the list, a head and tail token are used, and wrapped into their own structure, like you have done. So then your add and initialize functions would be something like (minus error detection)
// Initialize linked list
void initialize(list_t *list)
{
list->head = NULL;
list->tail = NULL;
}
void add(list_t *list, int code, char name[], int cost)
{
// set up the new node
product_data_t *node = (product_data_t*)malloc(sizeof(product_data_t));
node->code = code;
node->cost = cost;
strncpy(node->product_name, name, sizeof(node->product_name));
node->next = NULL;
if(list->head == NULL){ // if this is the first node, gotta point head to it
list->head = node;
list->tail = node; // for the first node, head and tail point to the same node
}else{
tail->next = node; // append the node
tail = node; // point the tail at the end
}
}
In this case, since it's a singly linked-list, the tail is only really useful for appending items to the list. To insert an item, you'll have to traverse the list starting at the head. Where the tail really comes in handy is with a doubly-linked list, it allows you to traverse the list starting at either end. You can traverse this list like
// return a pointer to element with product code
product_data_t* seek(list_t *list, int code){
product_data_t* iter = list->head;
while(iter != NULL)
if(iter->code == code)
return iter;
iter = iter->next;
}
return NULL; // element with code doesn't exist
}
Often times, the head and tail are fully constructed nodes themselves used as a sentinel to denote the beginning and end of a list. They don't store data themselves (well rather, their data represent a sentinel token), they are just place holders for the front and back. This can make it easier to code some algorithms dealing with linked lists at the expense of having to have two extra elements. Overall, linked lists are flexible data structures with several ways to implement them.
oh yeah, and nik is right, playing with linked-lists are a great way to get good with pointers and indirection. And they are also a great way to practice recursion too! After you have gotten good with linked-list, try building a tree next and use recursion to walk the tree.
I am not writing the code here but you need to do the following:
Create and object of list, this will remain global for the length of program.
Malloc the size of product _ data _ t.
For first element (head is NULL), point head to the malloced' address.
To add next element, move to the end of list and then add the pointer of malloced address to next of last element. (The next of the last element will always be NULL, so thats how you traverse to end.)
Forget tail for a while.
If you are learning C pointer theory this is a good exercise.
Otherwise, it feels like too much indirection for code that is not generic (as in a library).
Instead of allocating a static 128 byte character string, you might want to do some more pointer practice and use an allocated exact length string that you clean up at exit.
Academically, kungfucraigs' structure looks more generic then the one you have defined.
You're calloc'ing space for your list_t struct, just pointers to list head and tail, which isn't what you want to do.
When you add to a linked list, allocate space for an actual node in the list, which is your product_data_t struct.
You're allocating the wrong chunk of memory. Instead of allocating memory for each list element, you're allocating for the list head and tail.
For simplicity, get rid of the separate structure for the head and tail. Make them global variables (the same scope they're in now) and change them to be listhead and listtail. This will make the code much more readable (you won't be needlessly going through a separate structure) and you won't make the mistake of allocating for the wrong struct.
You don't need a tail pointer unless you're going to make a doubly linked list. Its not a major element to add once you create a linked list, but not necessary either.
In memory your items are linked by pointers in the list structure
item1 -> item2
Why not make the list structure part of your item?
Then you allocate a product item, and the list structure is within it.
typedef struct product_data
{
int product_code;
char product_name[PRODUCT_NAME_LEN];
int product_cost;
struct list_t list; // contains the pointers to other product data in the list
}product_data_t;
I think u first need to Imagin back-end. Code are nothing to important. Go here and visualize back-end basic c code of all insertion.
1) Insertion at beginning Visit and scroll to get every instruction execution on back- end
And u need front and imagin Go here
Back end imagin
And All other possible insertion here.
And important thing u can use this way.
struct Node{
int data;//data field
struct Node*next;//pointer field
};
struct Node*head,*tail; // try this way
or short cut
struct Node{
int data;//data field
struct Node*next;//pointer field
}*head,*tail; //global root pointer
And << Click >> To visualize other linked list problem.
Thanks.
A demo for Singly Linked List. If you prefer, try to check Circular Linked List and Doubly Linked List.
#include <stdio.h>
#include <stdlib.h>
typedef struct node {
int val;
struct node * next;
} node_t;
// Iterating over a list
void
print_list(node_t *head)
{
node_t *current = head;
while(current != NULL)
{
printf("%d\n", current->val);
current = current->next;
}
}
// Adding an item to the end of the list
void
push_end(node_t *head, int val)
{
node_t *current = head;
while (current->next != NULL)
{
current = current->next;
}
current->next = malloc(sizeof(node_t));
current->next->val = val;
current->next->next = NULL;
}
// Adding an item to the head of the list
void
push_head(node_t **head, int val)
{
node_t *new_node = NULL;
new_node = malloc(sizeof(node_t));
new_node->val = val;
new_node->next = *head;
*head = new_node;
}
// Removing the head item of the list
int
pop_head(node_t **head)
{
int retval = -1;
node_t *next_node = NULL;
if (*head == NULL) {
return -1;
}
next_node = (*head)->next;
retval = (*head)->val;
free(*head);
*head = next_node;
return retval;
}
// Removing the last item of the list
int
pop_last(node_t *head)
{
int retval = 0;
node_t *current = NULL;
if (head->next == NULL) {
retval = head->val;
free(head);
return retval;
}
/* get to the second to last node in the list */
current = head;
while (current->next->next != NULL) {
current = current->next;
}
/* now current points to the second to last item of the list.
so let's remove current->next */
retval = current->next->val;
free(current->next);
current->next = NULL;
return retval;
}
// Removing a specific item
int
remove_by_index(node_t **head, int n)
{
int i = 0;
int retval = -1;
node_t *current = *head;
node_t *temp_node = NULL;
if (n == 0) {
return pop_head(head);
}
for (i = 0; i < n - 1; i++) {
if (current->next == NULL) {
return -1;
}
current = current->next;
}
temp_node = current->next;
retval = temp_node->val;
current->next = temp_node->next;
free(temp_node);
return retval;
}
int
main(int argc, const char *argv[])
{
int i;
node_t * testnode;
for (i = 0; i < argc; i++)
{
push_head(&testnode, atoi(argv[i]));
}
print_list(testnode);
return 0;
}
// http://www.learn-c.org/en/Linked_lists
// https://www.geeksforgeeks.org/data-structures/linked-list/
The linked list implementation inspired by the implementation used in the Linux kernel:
// for 'offsetof', see: https://stackoverflow.com/q/6433339/5447906.
#include <stddef.h>
// See: https://stackoverflow.com/q/10269685/5447906.
#define CONTAINER_OF(ptr, type, member) \
( (type *) ((char *)(ptr) - offsetof(type, member)) )
// The macro can't be used for list head.
#define LIST_DATA(ptr, type, member) \
CONTAINER_OF(ptr, type, member);
// The struct is used for both: list head and list nodes.
typedef struct list_node
{
struct list_node *prev, *next;
}
list_node;
// List heads must be initialized by this function.
// Using the function for list nodes is not required.
static inline void list_head_init(list_node *node)
{
node->prev = node->next = node;
}
// The helper function, mustn't be used directly.
static inline void list_add_helper(list_node *prev, list_node *next, list_node *nnew)
{
next->prev = nnew;
nnew->next = next;
nnew->prev = prev;
prev->next = nnew;
}
// 'node' must be a list head or a part of a list.
// 'nnew' must not be a list head or a part of a list. It may
// be uninitialized or contain any data (even garbage).
static inline void list_add_after(list_node *node, list_node *nnew)
{
list_add_helper(node, node->next, nnew);
}
// 'node' must be a list head or a part of a list.
// 'nnew' must not be a list head or a part of a list. It may
// be uninitialized or contain any data (even garbage).
static inline void list_add_before(list_node *node, list_node *nnew)
{
list_add_helper(node->prev, node, nnew);
}
// 'node' must be part of a list.
static inline list_node *list_del(list_node *node)
{
node->prev->next = node->next;
node->next->prev = node->prev;
return node->prev;
}
Example of usage:
#include <stdio.h>
// The struct must contain 'list_node' to be able to be inserted to a list
typedef struct
{
int data;
list_node node;
}
my_struct;
// Convert 'list_node *' to 'my_struct*' that contains this 'list_node'
static inline my_struct* get_my_struct(list_node *node_ptr)
{
return LIST_DATA(node_ptr, my_struct, node);
}
void print_my_list(list_node *head)
{
printf("list: {");
for (list_node *cur = head->next; cur != head; cur = cur->next)
{
my_struct *my = get_my_struct(cur);
printf(" %d", my->data);
}
printf(" }\n");
}
// Print 'cmd' and run it. Note: newline is not printed.
#define TRACE(cmd) \
(printf("%s -> ", #cmd), (cmd))
int main()
{
// The head of the list and the list itself. It doesn't contain any data.
list_node head;
list_head_init(&head);
// The list's nodes, contain 'int' data in 'data' member of 'my_struct'
my_struct el1 = {1};
my_struct el2 = {2};
my_struct el3 = {3};
print_my_list(&head); // print initial state of the list (that is an empty list)
// Run commands and print their result.
TRACE( list_add_after (&head , &el1.node) ); print_my_list(&head);
TRACE( list_add_after (&head , &el2.node) ); print_my_list(&head);
TRACE( list_add_before(&el1.node, &el3.node) ); print_my_list(&head);
TRACE( list_del (head.prev) ); print_my_list(&head);
TRACE( list_add_before(&head , &el1.node) ); print_my_list(&head);
TRACE( list_del (&el3.node) ); print_my_list(&head);
return 0;
}
The result of execution of the code above:
list: { }
list_add_after (&head , &el1.node) -> list: { 1 }
list_add_after (&head , &el2.node) -> list: { 2 1 }
list_add_before(&el1.node, &el3.node) -> list: { 2 3 1 }
list_del (head.prev) -> list: { 2 3 }
list_add_before(&head , &el1.node) -> list: { 2 3 1 }
list_del (&el3.node) -> list: { 2 1 }
http://coliru.stacked-crooked.com/a/6e852a996fb42dc2
Of course in real life you will most probably use malloc for list elements.
In C language, we need to define a Node to store an integer data and a pointer to the next value.
struct Node{
int data;
struct Node *next;
};
To add a new node, we have a function add which has data as an int parameter. At first we create a new Node n. If the program does not create n then we print an error message and return with value -1. If we create the n then we set the data of n to have the data of the parameter and the next will contain the root as it has the top of the stack. After that, we set the root to reference the new node n.
#include <stdio.h>
struct node
{
int data;
struct node* next;
};
int main()
{
//create pointer node for every new element
struct node* head = NULL;
struct node* second = NULL;
struct node* third = NULL;
//initialize every new pointer with same structure memory
head = malloc(sizeof(struct node));
second = malloc(sizeof(struct node));
third = malloc(sizeof(struct node));
head->data = 18;
head->next = second;
second->data = 20;
second->next = third;
third->data = 31;
third->next = NULL;
//print the linked list just increment by address
for (int i = 0; i < 3; ++i)
{
printf("%d\n",head->data++);
return 0;
}
}
This is a simple way to understand how does pointer work with the pointer. Here you need to just create pointer increment with new node so we can make it as an automatic.
Go STL route. Declaring linked lists should be agnostic of the data. If you really have to write it yourself, take a look at how it is implemented in STL or Boost.
You shouldn't even keep the *next pointer with your data structure. This allows you to use your product data structure in a various number of data structures - trees, arrays and queues.
Hope this info helps in your design decision.
Edit:
Since the post is tagged C, you have equivalent implementations using void* pointers that follow the basic design principle. For an example, check out:
Documentation | list.c | list.h

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