I would like to start cmd.exe from batch file and execute command, but:
If I use start cmd.exe /k e.g. „net use“ – it executes command behind /k. - and it gives me default path - i would like to change it.
But how to run cmd.exe with another path as it is set and execute command behind /k?
I start cmd.exe - i have - c:\users\xxxx
What do i have to if i would like to chande it? E.g. c:\tools\Script\...
How to write batch like this?
Use the start /d parameter, e.g.
start "" /d"c:\documents and settings" cmd /k
see start /? for more help.
Try using
cd "pathname"
to get to the correct Path.
For Example:
cd c:\tools\Script
you can also show all folders by using the command
dir
Furthermore the cmd.exe is automatically used if you try to execute a .bat file I believe.
But for changing the normal path used you can edit the settings as shown in this picture:
For more funcitons you could look here: http://www.computerhope.com/overview.htm
Related
This might be very basic but I cannot find the answer in the internet.
I have a cmd/bat file with 3 basics lines to set the working directory as the one of the current folder.Once I run it, I get the CMD window, and I type specific commands (example : "start notepad").
%~d1
cd "%~p1"
call cmd
What should I write within the cmd. or bat. file so the "start notepad" will be already launched as command?
Thank you very much
There are a couple of ways you can achieve this.
You can open notepad directly with the start command and then run cmd, like this:
#echo off
%~d1
cd "%~p1"
start "" notepad
call cmd
You can also include the notepad start command directly in the cmd call, like this:
#echo off
%~d1
cd "%~p1"
call cmd /k start "" notepad
Note that there is a "" after start because start considers the first set of quotes that it encounters to be the window's title.
Try this:
#echo off
Command.Com
When you'll open this batch file it will open up CMD where you can start typing commands like start notepad etc...I think this was what you was looking for?
I need a batch file which will do the following:
1. Open CMD and navigate to a location C:/Users/...../program.exe
2. Run the program.exe with an additional command to point it to a config file:
e.g. "program.exe C:/Users/..../configFile.bgi"
How can I do this?
I tried this but with no luck:
start "C:\Users\Ben\Desktop\BGInfo\bginfo.exe C:\Users\Ben\Desktop\BGInfo\dc_bginfo.bgi"
pause
Update
I've used the solution provided by Ganesh (below) and came up with this:
cd C:\Users\Ben\Desktop\BGInfo\
bginfo.exe C:\Users\Ben\Desktop\BGInfo\dc_bginfo.bgi
I've tested it on a local machine (changing the directories) but on the server (with the directory above) it does not work...
The folder directory with batch file:
The error
in batch file abc.bat
cd c:\user\ben_dchost\documents\
executible.exe -flag1 -flag2 -flag3
I am assuming that your executible.exe is present in c:\user\ben_dchost\documents\
I am also assuming that the parameters it takes are -flag1 -flag2 -flag3
Edited:
For the command you say you want to execute, do:
cd C:\Users\Ben\Desktop\BGInfo\
bginfo.exe dc_bginfo.bgi
pause
Hope this helps
You can use
start "" "%USERPROFILE%\Desktop\BGInfo\bginfo.exe" "%USERPROFILE%\Desktop\BGInfo\dc_bginfo.bgi"
or
start "" /D "%USERPROFILE%\Desktop\BGInfo" bginfo.exe dc_bginfo.bgi
or
"%USERPROFILE%\Desktop\BGInfo\bginfo.exe" "%USERPROFILE%\Desktop\BGInfo\dc_bginfo.bgi"
or
cd /D "%USERPROFILE%\Desktop\BGInfo"
bginfo.exe dc_bginfo.bgi
Help on commands start and cd is output by executing in a command prompt window help start or start /? and help cd or cd /?.
But I do not understand why you need a batch file at all for starting the application with the additional parameter. Create a shortcut (*.lnk) on your desktop for this application. Then right click on the shortcut, left click on Properties and append after a space character "%USERPROFILE%\Desktop\BGInfo\dc_bginfo.bgi" as parameter.
Found another solution for the same. It will be more helpful.
START C:\"Program Files (x86)"\Test\"Test Automation"\finger.exe ConfigFile="C:\Users\PCName\Desktop\Automation\Documents\Validation_ZoneWise_Default.finger.Config"
finger.exe is a parent program that is calling config solution.
Note: if your path folder name consists of spaces, then do not forget to add "".
I want to write a batch file that will do following things in given order:
Open cmd
Run cmd command cd c:\Program files\IIS Express
Run cmd command iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
Open Internet Explorer 8 with URL= http://localhost:8088/default.aspx
Note: The cmd window should not be closed after executing the commands.
I tried start cmd.exe /k "cd\ & cd ProgramFiles\IIS Express", but it is not solving my purpose.
So, make an actual batch file: open up notepad, type the commands you want to run, and save as a .bat file. Then double click the .bat file to run it.
Try something like this for a start:
c:\
cd c:\Program files\IIS Express
start iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
start http://localhost:8088/default.aspx
pause
I think the correct syntax is:
cmd /k "cd c:\<folder name>"
This fixes some issues with Blorgbeard's answer (but is untested):
#echo off
cd /d "c:\Program files\IIS Express"
start "" iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
timeout 10
start http://localhost:8088/default.aspx
pause
cmd /c "command" syntax works well. Also, if you want to include an executable that contains a space in the path, you will need two sets of quotes.
cmd /c ""path to executable""
and if your executable needs a file input with a space in the path a another set
cmd /c ""path to executable" -f "path to file""
#echo off
title Command Executer
color 1b
echo Command Executer by: YourNameHere
echo #################################
: execute
echo Please Type A Command Here:
set /p cmd=Command:
%cmd%
goto execute
start cmd /k "your cmd command1"
start cmd /k "your cmd command2"
It works in Windows server2012 while I use these command in one batch file.
cmd /k cd c:\
is the right answer
I was trying to run a couple of batch files parallely at startup, if a condition was true.
For this I made a parent batch file which should have checked for the condition and invoke the other child batch files if the condition was true.
I tried to achieve it via START but it gave me an empty black command prompt running in the directory of children batch files, instead of running the children batch files themselves
The thing which worked for me was by using a combination of START and CALL
As an example
condition ...
start call "C:\Users\Amd\conn\wsl_setup - conn1.bat"
start call "C:\Users\Amd\conn\wsl_setup - conn2.bat"
start call "C:\Users\Amd\conn\wsl_setup - conn3.bat"
I know DOS and cmd prompt DOES NOT LIKE spaces in folder names. Your code starts with
cd c:\Program files\IIS Express
and it's trying to go to c:\Program in stead of C:\"Program Files"
Change the folder name and *.exe name. Hope this helps
I'd like a .bat file which is stored on the desktop to perform 2 simple tasks:
1. Start cmd.exe
2. Change directory to c:\executionsdktest_10.2.2
I have:
#echo off
start cmd.exe \k
cdsdad c:\ExecutionSDKTest_10.2.2
But when I double click the .bat file, this starts cmd.exe but cd to c:\users\qestester\desktop. ANy ideas?
You can use
cmd /k "cd /d c:\ExecutionSDKTest_10.2.2"
And you wouldn't need a batch file for that. This can be put in a normal shortcut.
And if you have a normal shortcut you can just specify its working directory and run cmd directly without any arguments.
This worked for me:
start cmd.exe #cmd /k "cd /d C:\Users\Michael && node test.js"
What I needed ... was from a localhost page served in PHP, open a terminal, change directory, and start a node script. Achieved like this:
pclose(popen("start /B ". $cmd, "r"));
.. where $cmd is the first string above.
start cmd.exe /k "C: && cd \ExecutionSDKTest_10.2.2"
I wanted to:
open a command prompt
change directory (go to another directory)
run a command from there
solution that worked for me:
#echo off
d:
cd\Path\to\wherever
my command
Notes:
the d: after #echo off tells that the path is on the D drive. Write a c instead of the d and You will be on drive C.
third line starts with the mandatory cd, after which starts the path, with a preceding \.
my command can be anything you want, and can contain more that one word (or only one). I used it to run jupyter notebook.
I know it seems this has been asked before, but I need a batch to open another batch in a new window. I've tried:
start abc.bat
cmd abc.bat
run abc.bat
and others. They've all opened in the same window or just opened Command Prompt in new window, ignoring my batch. Is there a batch command to open a batch file in a new window?
Is this what your after?
start "New Window" cmd /c test.cmd
It's a little bit strange that start abc.bat doesn't work but I assume this is because you are running this in the middle of another batch. You probably need call:
22:22:38.85 c:\help call
Calls one batch program from another.
CALL [drive:][path]filename [batch-parameters]
Giving you start call abc.bat or call start abc.bat depending on what the exact problem is.
To simply do it is just
start cmd /c "exampleexample.bat"
This could also work with spaces;
start cmd /c "example example.bat"
And directories.
start cmd /c "C:\NAME\Example\Hi there\example example.bat"
I created my universal batch with this and this works flawlessly.
start abc.bat works for me. What is the problem in your case? You could also try start cmd /c abc.bat.
I found something that works:
call "C:\FILEPATH HERE\abc"
Demo:
#echo off
call "C:\Users\USERNAME HERE\Desktop\abc"
This should work <3
Unfortunatly, I know of no such method (I encounter the same thing). However, try killing the old window when you start the batch
abc.bat:
abd.bat
stop
abd.bat:
#echo off
#echo It works!
If you are going to run it in a different command prompt, type start C:\abc.bat or whatever the directory of abc.bat is, or if you want to open it in the same command prompt, type call "C:\abc.bat" again, wherever the directory is. It should work
Either:
call "C:\abc.bat"
or
start C:\abc.bat