Disable warning/error for default warnings - c

We want to start using -Wall -Werror on a large project.
Due to the size, this change has to be phased, and we want to start with the most important warnings first.
The best way to do it seems to be using -Wall -Werror, with exceptions for specific warnings. The exceptional warnings are those which we have a lot of (so fixing them all is hard and risky), and we don't consider them very dangerous.
I'm not saying we don't want to fix all these warnings - just not on the first phase.
I know two ways to exclude a warning from -Werror - the best is -Wno-error=xxx, and if it doesn't work - -Wno-xxx (of course, we prefer to see the warning and ignore it, rather than hide it).
My problem is with warnings which are enabled by default, and don't have a -Wxxx flag related to them. I couldn't find any way to alllow them when -Werror is used.
I'm specifically concerned about two specific warnings. Here's a program that exhibits them and the compiler output:
#include <stdio.h>
void f(int *p) { printf("%p\n", p); }
int main(int argc, char *argv[]) {
const int *p = NULL;
const unsigned int *q = NULL;
f(p); /* Line 7: p is const, f expects non const */
if (p == q) { /* Line 8: p is signed, q is unsigned */
printf("Both NULL\n");
}
return 0;
}
% gcc warn.c
warn.c: In function 'main':
warn.c:7: warning: passing argument 1 of 'f' discards qualifiers from pointer target type
warn.c:8: warning: comparison of distinct pointer types lacks a cast
I know the best solution is to fix these warnings, but it's much easier said than done. In order for this change to be successful, we have to do this phased, and can't do too many changes at once.
Any suggestions?
Thanks.

What about phasing on a compilation unit/module/library basis instead of per warning? Is triggering a subtarget compilation an option (a good-enough build system in place)?

It might be folly, but ...
Why not a simple grep ?
something like
gcc teste.c 2>&1 | grep -v 'comparison of distinct' | grep -v 'some_other_string'
You probably want to hide these greps in a script, and call the script from your makefile instead of gcc

According to https://gcc.gnu.org/bugzilla/show_bug.cgi?id=43245 it will be "-Wdiscarded-qualifiers", but since the bug-fixed entry is from May 1, 2014, the gcc compiler you are using might not support it.

Related

"control reaches end of non-void function" produces error instead of warning

I'm trying to compile a large project (https://github.com/ESCOMP/CTSM). I would like to compile it as-is, without editing the code, if possible (it is known to build successfully on many platforms).
I'm using gcc (SUSE Linux) 11.2.1. and I get
In function ncmp : /run/media/dominic/hdbtrfs/dominic/git/ESCOMP/CTSM/cime/src/share/timing/gptl.c:4069:1: error: control reaches end of non-void function [-Werror=return-type]
from the following function. I believe that earlier versions of gcc only gives a warning rather than an error in this instance.
/*
** ncmp: compares values of memory adresses pointed to by a pointer. for use with qsort
*/
static int ncmp( const void *pa, const void *pb )
{
static const char *thisfunc = "GPTLsetoption";
const char** x = (const char**)pa;
const char** y = (const char**)pb;
if( *x > *y )
return 1;
if( *x < *y )
return -1;
if( *x == *y )
GPTLerror("%s: shared memory address between timers\n", thisfunc);
}
I expect this can be fixed by inserting a spurious return statement at the end of the function, but since I am interested to try to build an unmodified version of the code (I'm not currently a contributor on the project, so can't push changes upstream) I'm wondering if there's a workaround to convert this error to a warning using compiler flags?
As requested here is the gcc call that is genertaed by the makefile:
mpicc -c -I/run/media/dominic/hdbtrfs/dominic/git/ESCOMP
/CTSM/cime/src/share/timing -std=gnu99 -O -DCESMCOUPLED
-DFORTRANUNDERSCORE -DNO_R16 -DCPRGNU -DCESMCOUPLED
-DFORTRANUNDERSCORE -DNO_R16 -DCPRGNU -DNUOPC_INTERFACE
-DHAVE_MPI /run/media/dominic/hdbtrfs/dominic/git/ESCOMP
/CTSM/cime/src/share/timing/gptl.c
I'm wondering if there's a workaround to convert this error to a warning using compiler flags?
I would expect the -Wno-error option to have that effect. It should also be possible to narrow the scope of that to the specific diagnostic you report, but beware: there is no way with command-line options alone to narrow the effect to this particular instance of the issue.
Addendum
The question having been edited to show that the diagnostic category is return-type, I can say that one would use -Wno-error=return-type to make all diagnostics of this type warnings instead of errors.
-Werror elevates all warnings to errors. You can turn reverse this for specific warnings with -Wno-error=WarningName, such as -Wno-error=return-type, as is clearly documented in the GCC documentation for warning options:
This switch [-Werror=] takes a negative form, to be used to negate -Werror for specific warnings; for example -Wno-error=switch makes -Wswitch warnings not be errors, even when -Werror is in effect.

Clang parameter -Wno-conditional-type-mismatch and GCC

The following simple C example program correctly emits a compile warning:
#include <stdio.h>
int main(int argc, char *argv[])
{
int *p = NULL;
int q = 1;
if(1 == 2 ? p : q) { printf("Info\n"); }
return(0);
}
The warning emitted is "warning: pointer/integer type mismatch in conditional expression".
In clang, the parameter "-Wno-conditional-type-mismatch" works in such a way that no warnings appear for the example code.
In GCC, I was looking for a similar option. The best I could find was the parameter "-fcond-mismatch", which would allow the example code. From the man page:
Allow conditional expressions with mismatched types in the second and third arguments. The
value of such an expression is void. This option is not supported for C++.
But when using this option, GCC keeps complaining:
# gcc -fcond-mismatch -c example.c
example.c: In function 'main':
example.c:8:17: warning: pointer/integer type mismatch in conditional expression
8 | if(1 == 2 ? p : q) { printf("Info\n"); }
Using GCC 10.3.0, would there be a GCC option or compiler flag to suppress the warning, in a similar way as clang does?
I don't think there is any such flag. GCC's manual says, under -Werror=, "The warning message for each controllable warning includes the option that controls the warning."
Since this message does not mention such an option, this suggests it is not controllable.

Why does GCC 9.1.0 sometimes complain about this use of strncpy()?

This is a 40-line MCVE (Minimal, Complete, Verifiable Example) — or something close to minimal — cut down from a 1675 line source file that originally included 32 headers (and most of those included multiple other headers — compiling it with gcc -H lists 464 headers from the project and the system, many of them several times). That file is working code that previously compiled without warnings (GCC 8.3.0), but not with GCC 9.1.0. All structure, function, type, variable names have been changed.
pf31.c
#include <string.h>
enum { SERVERNAME_LEN = 128 };
typedef struct ServerQueue
{
char server_name[SERVERNAME_LEN + 1];
struct ServerQueue *next;
} ServerQueue;
extern int function_under_test(char *servername);
#ifdef SUPPRESS_BUG
extern int function_using_name(char *name);
#endif /* SUPPRESS_BUG */
extern int GetServerQueue(const char *servername, ServerQueue *queue);
int
function_under_test(char *servername)
{
ServerQueue queue;
char name[SERVERNAME_LEN + 1];
if (GetServerQueue(servername, &queue) != 0)
return -1;
char *name_in_queue = queue.server_name;
if (name_in_queue)
strncpy(name, name_in_queue, SERVERNAME_LEN);
else
strncpy(name, servername, SERVERNAME_LEN);
name[SERVERNAME_LEN] = '\0';
#ifdef SUPPRESS_BUG
return function_using_name(name);
#else
return 0;
#endif /* SUPPRESS_BUG */
}
Compilation
When compiled using GCC 9.1.0 (on a Mac running macOS 10.14.5 Mojave, or on a Linux VM running RedHat 5.x — don't ask!), with the option -DSUPPRESS_BUG I get no error, but with the option -USUPPRESS_BUG, I get an error:
$ gcc -std=c11 -O3 -g -Wall -Wextra -Werror -DSUPPRESS_BUG -c pf31.c
$ gcc -std=c11 -O3 -g -Wall -Wextra -Werror -USUPPRESS_BUG -c pf31.c
In file included from /usr/include/string.h:417,
from pf31.c:1:
pf31.c: In function ‘function_under_test’:
pf31.c:30:9: error: ‘__builtin_strncpy’ output may be truncated copying 128 bytes from a string of length 128 [-Werror=stringop-truncation]
30 | strncpy(name, name_in_queue, SERVERNAME_LEN);
| ^~~~~~~
cc1: all warnings being treated as errors
$
When I compile using GCC 8.3.0, I get no errors reported.
Question
Two sides of one question:
Why does GCC 9.1.0 complain about the use of strncpy() when the code is compiled with -USUPPRESS_BUG?
Why doesn't it complain when the code is compiled with -DSUPPRESS_BUG?
Corollary: is there a way to work around this unwanted warning that works with older GCC versions as well as 9.1.0. I've not yet found one. There's also a strong element of "I don't think it should be necessary, because this is using strncpy() to limit the amount of data copied, which is what it is designed for".
Another variant
I have another non-erroring variant, changing the signature of the function_under_test() — here's a set of diffs:
11c11
< extern int function_under_test(char *servername);
---
> extern int function_under_test(char *servername, ServerQueue *queue);
20c20
< function_under_test(char *servername)
---
> function_under_test(char *servername, ServerQueue *queue)
22d21
< ServerQueue queue;
25c24
< if (GetServerQueue(servername, &queue) != 0)
---
> if (GetServerQueue(servername, queue) != 0)
27c26
< char *name_in_queue = queue.server_name;
---
> char *name_in_queue = queue->server_name;
This compiles cleanly regardless of whether SUPPRESS_BUG is defined or not.
As you can guess from the SUPPRESS_BUG terminology, I'm tending towards the view that this is bug in GCC, but I'm kinda cautious about claiming it is one just yet.
More about the the original code: the function itself was 540 lines long; the strncpy() block occurs about 170 lines into the function; the variable corresponding to name was used further down the function in a number of function call, some of which take name as an argument and supply a return value for the function. This corresponds more to the -DSUPPRESS_BUG code, except that in the 'real code', the bug is not suppressed.
This is a GCC bug tracked as PR88780. According to Martin's comment, this warning did not exist prior to GCC 8.
GCC is shipped with this known bug, as it is not deemed release-critical.
To be honest, I am not 100% sure it is the bug. The point is, there are known false-positives. If you feel like helping the GCC project, you can find the most appropriate bug among strncpy / Wstringop-truncation bugs and post your example there. It would be more helpful if you minimized it further (say, with creduce); minimizing the compile string is also appreciated (that would be rather trivial, I guess).
Several compilation warnings related to strncpy were found in GCC 9.0 and reported here and here.
One of them is the error mentioned in the question which seems to occur in the file string_fortified.h:
/usr/include/bits/string_fortified.h:106:10: warning: ‘__builtin_strncpy’ output may be truncated copying 16 bytes from a string of length 16 [-Wstringop-truncation]
106 | return __builtin___strncpy_chk (__dest, __src, __len, __bos (__dest));
| ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The response to this was given on April 15, 2019 was:
Thank you for the report, however as GCC 9 still under development. We do not see the above errors in the current stable GCC 7.4 or GCC 8.3. We appreciate the advanced notice, and will accept PRs to fix issues against GCC 9, but for now our target compiler is gcc stable.
So I believe the errors are probably a result of versions 9 and 9.1 being not stable versions. Hopefully they will be eliminated when these versions become stable.

How should I handle a value that is never used?

I don't always use all return values, and sometimes I must handle return values. For instance:
$ make
gcc -pedantic -std=c99 -Wall -O3 -ledit -g -DVERSION=\"v0.160425-2-gc443\" -c -o main.o main.c
main.c: In function ‘int_handler’:
main.c:532:5: warning: ignoring return value of ‘write’, declared with attribute warn_unused_result [-Wunused-result]
write(fileno(stdin), s, sizeof s - 1);
^
gcc -o shell main.o errors.c util.c pipeline.c -ledit
What should I do to avoid the warning? Is there a good way to "use" a variable like writing it to /dev/null so that the compiler won't complain? My own idea is this, which deals with the problem without ignoring the error and I can commit my code without warnings and deal with this later:
void int_handler(int signum) {
if (write(fileno(stdin), s, sizeof s - 1)) {
} else {}
}
Typically to suppress this warning, you can do:
(void)write(fileno(stdin), s, sizeof s - 1);
But the reason for the warning is because write() is declared with an attribute in the header (<unistd.h>) which leads to the warning.
This (attribute) is not done for every function but selectively. For example, printf()'s return is typically ignored.
Since, you would want to check the results of IO operation, it's done for write().
So, if you really want to ignore the result, you can use the (void)func(...); to suppress this.
First of all, in case of file handling functions in production-quality code, you should almost certainly handle all return values.
Otherwise, the standard way to ignore a variable or a function result, is to cast it to (void).
It is a bad idea to not take in account the return value of a call to write, as an I/O may fail it is important to take care of such an event. If you really want to remove the warning, you should explicitly ignore the return value:
(void)write(...);
The prototype for write in the header file unistd.h has been declared as follows
extern ssize_t write (int __fd, const void *__buf, size_t __n) __wur
and __wur has been defined as (in cdefs.h)
# if __USE_FORTIFY_LEVEL > 0
# define __wur __attribute_warn_unused_result__
# endif
#else
# define __attribute_warn_unused_result__ /* empty */
So when you are compiling with fortify switch on, wur gets defined as
__attribute_warn_unused_result. This attribute essentially tells the compiler to throw out warning if return value of function is not used.
You can redirect your stdout and stderr to /dev/null
gcc -c file.c > /dev/null 2>&1
and get rid of the warning (though even error is redirected to null) or you can redirect to file as
gcc -c warn.c > xx 2>&1
Hope this helps . And like said above, always check the value of "write", the error will automatically vanish
:)

gcc -Wall -Wuninitialized is not throwing warning for uninitialized variable

gcc version - gcc (Ubuntu 4.8.4-2ubuntu1~14.04.1) 4.8.4
Compiling below code with -Wall -Wuninitialized is throwing warning as expected
warning: ‘test’ is used uninitialized in this function [-Wuninitialized]
#include<stdio.h>
#include<stdlib.h>
void check (int test )
{
printf("%d",test);
}
int
main()
{
int test;
check(test);
return 0;
}
But compiling below code with -Wall -Wuninitialized is not throwing warning
#include<stdio.h>
#include<stdlib.h>
void check (int test )
{
printf("%d",test);
}
int
main()
{
int test;
int condition = 0;
if(condition == 27)
test = 10;
check(test);
return 0;
}
Shouldn't it throw warning?. is it anyway related to compiler optimization?
What an user understands as a false positive may be different for the particular
user. Some users are interested in cases that are hidden because of
actions of the optimizers combined with the current environment.
However, many users aren't, since that case is hidden because it
cannot arise in the compiled code. The canonical example is (MM05):
int x;
if (f ())
x = 3;
return x;
where 'f' always return non-zero for the current environment, and
thus, it may be optimised away. Here, a group of users would like to
get an uninitialized warning since 'f' may return zero when compiled
elsewhere. Yet, other group of users would consider spurious a warning
about a situation that cannot arise in the executable being compiled.
https://gcc.gnu.org/wiki/Better_Uninitialized_Warnings#Proposal
EDIT: MMO5 is already fixed
https://gcc.gnu.org/wiki/Better_Uninitialized_Warnings#MM05
Yes, gcc is not warning you because the code is optimized away. Some people think this is the right thing, because it might be that way by a compile time configuration value. Others think it's the wrong thing, because it hides possible mistakes.
You are not the first to notice this problem with GCC. There's a whole proposal about it.
clang with -Wall detects the problem and even suggests a fix.
$ make
cc -Wall -g test.c -o test
test.c:15:7: warning: variable 'test' is used uninitialized whenever 'if' condition is false
[-Wsometimes-uninitialized]
if(condition == 27)
^~~~~~~~~~~~~~~
test.c:18:10: note: uninitialized use occurs here
check(test);
^~~~
test.c:15:4: note: remove the 'if' if its condition is always true
if(condition == 27)
^~~~~~~~~~~~~~~~~~~
test.c:12:12: note: initialize the variable 'test' to silence this warning
int test;
^
= 0
1 warning generated.

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