I'm writing automated test cases for a mobile website, somehow the back button appears in the DOM, but is only clickable after mouseover. AndroidDriver is able to find the Element, but it's not clickable. I am not sure why, but it's working fine with the FirefoxDriver. I guess AndroidDriver can't deal with mouseover since there is no mouse ;-)
So I figured out that I use AdvancedUserInteractions, but that is not working:
underlying driver does not implement advanced user interactions yet
It works fine with the FirefoxDriver, so are there any alternative for AndroidDriver?
WebElement BackButton = driver.findElement(By.xpath("//img[contains(#class,'left menu Stuff__landscapeOnly')]"));
actions.moveToElement(Zurueck).build().perform();
//Back.click();
jsLib.callEmbeddedSelenium(driver,"triggerMouseEventAt", Zurueck,"click", "0,0");
How to deal with mouseover using AndroidDriver?
For Ruby, I used..
include Selenium::WebDriver::DriverExtensions::HasTouchScreen
#driver.touch.single_tap(element).perform
Related
I'm about to try to create a walkthrough for a web app created using React. I'm trying to think of the best way to do it, and have been thinking of using things like Material UI's modal component. I'm thinking I should also include some kind of arrow component that points the user to whichever element (button, link, etc) on my page I want them to click next. Also I will want to create a backdrop to fade the screen except for whichever element I want the users attention to be drawn to.
I feel like this must have been done many times before, but I can't find anything from searching. Obviously whenever I Google "react walkthrough/guide/intro" I just get suggestions for teaching basic React.
(NB: I'm not looking to do one of those intro sliders, as I want to provide a more detailed step-by-step)
The keyword your need to search for is 'tour'. Searching on google for 'react tour', I found 2 libraries for you:
React Joyride: https://github.com/gilbarbara/react-joyride | Live Demo
reactour: https://github.com/elrumordelaluz/reactour | Live Demo
Both seem to have similar features:
Instruction modal that explains about an element on the page.
The modal is positioned next to the highlighted element.
The window will scroll down to the highlighted element if it's outside of the viewport.
The element is highlighted to bring more attention while the rest of the page is in the backdrop.
There are steppers on the modal to indicate which step you're on.
I'm building a React Native app which has a screen containing a list of several items the user can see. I wrapped up the elements by using a ScrollView component and it works fine as shown below:
However, I'd like to have the vertical scrollbar always visible just to let the user know he can see more items than the ones shown in the first place. I've read the ScrollView documentation but it seems that there is not an option to make it happen.
Does anyone know if there is a way to achieve that or perhaps a workaround to make it intuitive to the user that there is a scroll on the list?
Try this ,Its working for me
persistentScrollbar={true}
https://facebook.github.io/react-native/docs/scrollview#flashscrollindicators
The closest thing to showing the scroll indicator constantly that is available in React Native is flashing the indicator. You can obtain a reference to the scrollview and call the flashScrollIndicators() method. There is no known way to disable hiding the indicator without writing native code. If you want to go down that path, you could try something like this for iOS.
Using angular and material design, I notice that, when you focus an input and then click outside (on nothing particular):
on desktop, the focus is removed from the input
on mobile (android), the focus stays
This is really annoying on mobile, because having an md-autocomplete that is focused, the virtual keyboard slides up and take half of the available height. And there is no way to hide it, except to click on another field or a button!
I really can't understand why the mobile shouldn't behave like the desktop. Is there no way to loose the focus when the user clicks outside or select an element?
app = angular.module('App', ['ngMaterial'])
.config(function( $mdGestureProvider ) {
$mdGestureProvider.skipClickHijack();
});
I know this is already years old question, but in case anyone is the same problem. The $mdGestureProvider.skipClickHijack() worked for me.
I have an off panel menu working perfectly on a site. The user can open and close it using both a navicon or sliding it with the finger.
Right now I have a very nice navicon icon that transitions from Menu Icon to X Icon when is clicked (and opens the menu) and the other way around when is clicked again and the menu closes. Buuut if the user slides the menu open or closed instead of using the navicon, the transition is not triggered, which might lead to confusions on the UX (i.e. the menu being closed, and the navicon showing an X instead of the regular 3 horizontal lines icon).
So, the navicon has right now the following code to trigger the transition:
ng-click="open = !open" ng-class="{'open-mob':open}">
I thought that a nice and easy way to fix this, would be to trigger this "open = !open" every time that the menu is open or closed, as the js from the off panel adds the class slidRight to the main section when the menu is open, and removes it when it is closed.
Being so, is there some straight way to check if the class is there using AngularJS?
Something like if class = slidRight -> "open = !open".
Thanks!!
for those (including me) who could not get their head around Angular's documentation, here is an example which worked for me:
angular.element(myElement).hasClass('my-class');
angular.element(myElement).addClass('new-class');
angular.element(myElement).removeClass('old-class');
hope this help someone ...
Angular uses jqLite's .hasClass() natively.
Read here on the angular docs for more info.
http://docs.angularjs.org/api/angular.element
https://docs.angularjs.org/api/ng/function/angular.element
I've wasted too much time on this and am begging, begging, I tell you, the stackoverflow community for help!
I'm a new jqGrid user, and have my grid working as I want it to, but at the moment, cannot get a row to highlight in IE 7 as the mouse is hovered over it. Our shop is currently running IE7, so changing browsers/versions is not a possibility. Hover works great in Firefox, does not work in IE7.
I have googled endlessly for "jqgrid ie7 hover", "jquery ie7 hover", and any iteration of "ie7" and "hover", and "css" and all that.
I have tried so many variations of DOCTYPE declarations it ain't funny. I've tried reverse engineering the http://www.trirand.com/blog/jqgrid/jqgrid.html demo pages until my fingers are aching. Yes, the hover works on the demo pages. No it ain't working on my own page. I have tried manually passing in the ui hover CSS classes directly with different attributes and the !important flag just to see if I get anything. Nothing.
Now here is what does happen when I hover over a jqGrid row with IE7: The bottom and right borders of the table cells will change color, but the background color does not. So, I know the hover highlighting is working for the cell borders, but not for the cells or row itself.
As a diagnostic aid, I slapped in a javascript alert() to bang when I hovered over the table. It works at the table level, but does not ever fire if I set it to fire if I hover over a row or cell. I used the IE Developer Toolbar DOM parser to verify I'm calling it right. I'm wondering if jqGrid takes over that functionality, though.
Anyhow, folks, the short version is: Why can't I get row highlighting to work in IE7?
Help me Obi Wan Kenobi, you're my only hope!
I'll answer my own question. The problem was a conflict with a separate .css file. My page uses the 960 Grid System for layout control. One of the items used as part of the grid system is a "reset.css" which was conflicting with the jqGrid hover display in my app. I commented out the call to reset.css and the problem went away. Fwiw, I did not see any other adverse affects to the grid system by leaving out reset.css.