I'm doing cast from a pointer then it keeps me runing this warning (assignment makes pointer from integer without a cast).
here's the code:
#include<stdio.h>
#include<stdbool.h>
typedef int TipoChave;
typedef struct TipoRegistro {
TipoChave Chave;
/*outros componentes*/
} TipoRegistro;
typedef struct TipoPagina* TipoApontador;
typedef struct TipoPagina {
int registros;
TipoRegistro *r;
TipoApontador *p;
} TipoPagina;
TipoApontador NovaSubArvore(int ordem){
TipoApontador A;
A=malloc(sizeof(TipoPagina));
int i;
A->registros=0;
A->r=malloc((2*ordem)*sizeof(TipoRegistro));
A->p=malloc((2*ordem+1)*sizeof(TipoPagina));
for (i=0;i<(2*ordem+1);i++){
A->p[i]=NULL;
if(i!=2*ordem){
A->r[i].Chave=0;
}
}
return (A);
}
on main I call:
TipoApontador Raiz;
then:
Raiz=NovaSubArvore(ordem); //Warning happens here
if I do:
if (Raiz!=NULL)
free(Raiz);
it runs a invallid free (strange, because if Raiz is NULL the free shouldn't had run.
Can anyone help me with that problem, please? I think that this warning is the problem that keeps me from "freeing" too.
EDIT: OK problem about waring solved. But if I do the free 2 times it runs a invalid free (I have a function that does a free somethings, other-times not. If I do the free the "if(Raiz!=NULL)" should block the other free from runing. but it isn't.
One problem is the calls to malloc() and the fact that you've not declared malloc() by including <stdlib.h>.
By default, functions are assumed to return an int in pre-C99 code — in C99 code, you're supposed to declare a function before using it.
You need to compile with more warning options. If you use GCC, I recommend:
gcc -O3 -g -std=c99 -Wall -Wextra -Wmissing-prototypes -Wstrict-prototypes \
-Wold-style-definition ...
This pretty much ensures that you don't have undeclared functions (such as malloc()) used. Depending on the version of GCC you use, you may get more or less warnings enabled by default. In general, newer versions are fussier, though it isn't quite that simple.
The other problem appears to be that you have a source file (name not given in the question) containing type definitions and function definitions such as:
typedef struct TipoPagina* TipoApontador;
typedef struct TipoPagina { ... } TipoPagina;
TipoApontador NovaSubArvore(int ordem) { ... }
Within this file the types are known. In your main code, you have:
TipoApontador Raiz;
...
Raiz = NovaSubArvore(ordem); //Warning happens here
The type name TipoApontador must be known in this file, but it appears that your code does not include a declaration for NovaSubArvore().
For types and functions that are going to be used in multiple source files, there should be a header defining the types and declaring the functions. The header should be used in both the source file that defines the functions and in the source files that use the types and functions.
For example, the header might be tipopagina.h:
#ifndef TIPOPAGINA_H_INCLUDED
#define TIPOPAGINA_H_INCLUDED
typedef int TipoChave;
typedef struct TipoRegistro {
TipoChave Chave;
/*outros componentes*/
} TipoRegistro;
typedef struct TipoPagina* TipoApontador;
typedef struct TipoPagina {
int registros;
TipoRegistro *r;
TipoApontador *p;
} TipoPagina;
extern TipoApontador NovaSubArvore(int ordem);
#endif /* TIPOPAGINA_H_INCLUDED */
The header guards are important; they avoid problems with redefining types (though C11 has more flexibility than either C99 or C89 in handling redefinitions of typedefs). The use of extern before the function name is not strictly necessary, though I prefer to see it — if only for symmetry with the extern that must be present before any variables that are declared in the header (if there are any — global variables should be avoided whenever possible).
Then the implementation file tipopagina.c might start:
#include "tipopagina.h"
#include <stdlib.h>
TipoApontador NovaSubArvore(int ordem)
{
TipoApontador A = malloc(sizeof(TipoPagina));
...
return (A);
}
There's a good reason for putting the tipopagina.h header first; it ensures that the header can be used on its own (which is important).
The main code also includes tipopagina.h, and because the function NovaSubArvore() is declared in the header, you avoid the compiler warning.
The code looks okay but if I put main before NovaSubArvore is defined then I see the exact same error:
int main()
{
TipoApontador Raiz;
int ordem = 10 ;
Raiz=NovaSubArvore(ordem);
}
TipoApontador NovaSubArvore(int ordem){
/// Rest of the function
}
so in this case the return type will default to int. In K&R C i f you leave off the type it will default to int.
That looks OK to me. Are you sure the given definitions of TipoApontador and NovaSubArvore are the ones being referenced in main? Ways you might not be using those defintions are (for example):
Including a different header file than the one you've pasted from (if those live in a .h file)
Including another header file that also defines a type or function with that name, although I would expect a warning in this case
TipoApontadore or NovaSubArvore are actually undeclared in main, and the compiler is assigning default types. (This seems the most likely to me. If this is the case, you should expect a warning to this effect.)
Of course, this is not an exhaustive list, but those things have happened to me before.
EDIT: Also, are you turning on all warnings from the compiler? For example, if you're using gcc, are you using the -Wall option?
ok.... I think that it can't be done something like that:
free (Raiz)
if (Raiz!=NULL)
free(Raiz);
This will get invalid free anyway.
The rest of the problem it's solved by some answers there. I've accepted the most complete. But thanks everyone for trying to help!
Related
Short version: I would like to declare a function in the same statement that calls it. The syntax I'm looking for is something of this sort:
// foo is undeclared in this file, and implemented in another file
int main() {
void* p = (cast_to_function_that_receivs_ints_and_returns_pointer)foo(1,2);
}
Long version:
The following code creates an obvious implicit declaration warning and undefined reference error, because of the call to foo:
// a.c
int main() {
void* p = foo(1,2);
}
I add the following file to the compilation to solve the undefined reference:
// b.c
void* foo(int a, int b) {
return (void*)0xbadcafe;
}
I would now like to solve the implicit declaration. The usual solution is to modify a.c to either #include a declaration to foo or declare it itself, something like:
// a.c
void* foo(int a, int b);
int main() {
void* p = foo(1,2);
}
But I would rather not declare foo, instead modifying the line that calls foo, similar to function pointers syntax, or to the example I posted in the "short versions". Is it even possible?
Assume I am proficient in C and that I have a valid motivation - I would like to "override" the behavior of foo by recompiling with -Dfoo=bar.
So if I understand correctly, your motivation is that you have existing code that looks like
p = bar(1,2);
and you would like to define macros so that it calls foo(1,2) instead. But you don't want to modify the source file to include a declaration of foo - you want to do everything by means of command-line macro definitions. Have I got that right?
Since you've tagged this gcc, perhaps you are willing to consider non-standard gcc extensions to the C language. If so, you can do it with gcc statement expressions, also supported by clang and icc. Define bar to expand to an expression containing a block which declares foo and whose value is a pointer to foo. That is:
#define bar ({ extern void *foo(int, int); foo; })
Or from the command line:
gcc -D'bar=({ extern void *foo(int, int); foo; })' call_bar.c
Try it on godbolt.
This has
A variant would be to define a macro bar(a,b) with two arguments, where the corresponding statement expression actually calls foo:
gcc -D'bar(a,b)=({ extern void *foo(int, int); foo((a), (b)); })' call_bar.c
but this will fail if the original code tries to call p = (bar)(a,b) or tries to take the address of bar.
I'm not aware of any way to get this exact effect in standard C. But a different approach would be to create a header file containing the declaration of foo, and then using -include to "inject" it at the top of the source file:
gcc -include declare_foo.h -Dbar=foo call_bar.c
This isn't technically what you asked for, because at some level it does involve declaring foo "beforehand", but it may still help solve your problem. In this case everything is standard C, but we have moved the "non-portability" from the code to the build process.
On the other hand, if the desired replacement for bar is something simple enough to put in a macro, like the constant return in your example, then you can cut out the middleman foo and just define a macro:
gcc -D'bar(a,b)=((void *)0xbadcafe)' call_bar.c
There's no way around the declaration requirement. You must define a symbol for the compiler to work with. Some compilers allow you to use a pragma or other non-standard feature to create the mapping between the symbol and physical/virtual address.
Compile your mock_foo.c file and link the object file to the program instead of foo.c.
Another approach is only ever call through a macro definition:
#ifdef MOCK_FOO
#define (FOO(a, b) mock_foo(a, b))
#else
#define (FOO(a, b) foo(a, b)
#endif
Otherwise, you have to understand how the compiler/linker and OS/loader work, to correctly hook functions to call mocks. There's a reason tooling for quality mock frameworks cost so much money. They are very complex.
You can cast a function as you call it:
void *p = ((void *(*)(int, int))foo)(1, 2);
It's ugly, I don't see a valid reason for it, but you can.
Files: A(main), B
I have learned that B's function can't be use in A without
funcntion definitions.
But my code ran normally with A, B files without function definitions
This is my code:
B.c
void a()
{
printf("hi");
}
A.c
#include <stdio.h>
void main()
{
a();
}
What is it? I'm confused.
ㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡ
addendum...
sorry for my bad question.
my code works well with error.
but i couldn't see error.
but i have more question for difference between
'void a();'
'extern void a();'
Once upon a time, C did not require prior declaration of all functions. Many compilers still let you get away with this.
In file A.c, when you called
a();
where a was a function the compiler has never seen before, the compiler assumed that the declaration
extern int a();
was in scope. That is, the compiler assumed that a was a function taking unspecified arguments and returning int.
Or, that used to be the rule. That rule is no longer in C, so yes, you are supposed to explicitly declare all your functions before you call them. Most of today's compilers will warn you when they apply the old rule, and many aren't willing to apply the rule at all, or at least, not unless you use a non-default option flag requesting them to. But it sounds like your compiler is still willing to apply the rule without warning or error. That's great if you're compiling a bunch of very old code, but it's not so great if you're trying to learn modern C.
Now, in this case you have the additional problem that the actual definition of function a in file B.c defines it as returning void, not int, so theoretically that's wrong, too. But, in practice, the error of misdeclaring (or mis-calling) void- versus int-returning functions is an innocuous one, that doesn't cause any real problems. (It's still wrong, though, and worth avoiding.)
I think you know this, but a correct setup would either be to have file A.c look like this:
#include <stdio.h>
extern void a(void);
int main()
{
a();
}
or else to create the file B.h containing
extern void a(void);
and then to have file A.c look like this:
#include <stdio.h>
#include "B.h"
int main()
{
a();
}
(Note that I have also changed void main() to int main(), for correctness. If you're using an old compiler, as it sounds like you are, you may also have to add the line return 0; at the end of main().)
Addendum. You had also asked about that extern keyword. It has to do with the distinction between declarations and definitions. But this distinction plays out slightly differently for functions, versus global variables.
Declarations explain what type something has. Definitions explain what type something has, and they additionally allocate memory for the something, and supply its initial value.
These are declarations:
extern int i;
int f(int);
extern int f2(int, double);
These are definitions:
int i;
int i2 = 2;
int f(int x) { return 2 * x; }
int f2(int n, double x) { return n * x; }
The keyword extern explicitly says, "This is a declaration, the definition is somewhere else." For global variables, this makes a big difference. But for functions, when you say int f(int);, the compiler can tell, when it finds a , instead of a {, that this is a declaration (not a definition), so the keyword extern is optional in function declarations.
(Also, functions are always global in C; there are no local functions.)
See also section 4.2 and section 4.3 of these course notes.
I just found a quirk in C that I find really confusing. In C it's possible to use a pointer to a struct before it has been declared. This is a very useful feature that makes sense because the declaration is irrelevant when you're just dealing with a pointer to it. I just found one corner case where this is (surprisingly) not true, though, and I can't really explain why. To me it looks like a mistake in the language design.
Take this code:
#include <stdio.h>
#include <stdlib.h>
typedef void (*a)(struct lol* etc);
void a2(struct lol* etc) {
}
int main(void) {
return 0;
}
Gives:
foo.c:6:26: warning: ‘struct lol’ declared inside parameter list [enabled by default]
foo.c:6:26: warning: its scope is only this definition or declaration, which is probably not what you want [enabled by default]
foo.c:8:16: warning: ‘struct lol’ declared inside parameter list [enabled by default]
To remove this problem we can simply do this:
#include <stdio.h>
#include <stdlib.h>
struct lol* wut;
typedef void (*a)(struct lol* etc);
void a2(struct lol* etc) {
}
int main(void) {
return 0;
}
The unexplainable problem is now gone for an unexplainable reason. Why?
Note that this question is about the behavior of language C (or possible the compiler behavior of gcc and clang) and not the specific example I pasted.
EDIT:
I won't accept "the order of declaration is important" as an answer unless you also explain why C would warn about using a struct pointer for the first time in a function argument list but allow it in any other context. Why would that possibly be a problem?
To understand why the compiler complains, you need to know two things about C "struct"s:
they are created (as a declared, but not yet defined, type) as soon as you name them, so the very first occurrence of struct lol creates a declaration
they obey the same "declaration scope" rules as ordinary variables
(struct lol { declares and then begins defining the structure, it's struct lol; or struct lol * or something else that does not have the open-brace that stops after the "declare" step.)
A struct type that is declared but not yet defined is an instance of what C calls an "incomplete type". You are allowed to use pointers to incomplete types, as long as you do not attempt to follow the pointer:
struct lol *global_p;
void f(void) {
use0(global_p); /* this is OK */
use1(*global_p); /* this is an error */
use2(global_p->field); /* and so is this */
}
You have to complete the type in order to "follow the pointer", in other words.
In any case, though, consider function declarations with ordinary int parameters:
int imin2(int a, int b); /* returns a or b, whichever is smaller */
int isum2(int a, int b); /* returns a + b */
Variables named a and b here are declared inside the parentheses, but those declarations need to get out of the way so that the the next function declaration does not complain about them being re-declared.
The same thing happens with struct tag-names:
void gronk(struct sttag *p);
The struct sttag declares a structure, and then the declaration is swept away, just like the ones for a and b. But that creates a big problem: the tag is gone and now you can't name the structure type ever again! If you write:
struct sttag { int field1; char *field2; };
that defines a new and different struct sttag, just like:
void somefunc(int x) { int y; ... }
int x, y;
defines a new and different x and y at the file-level scope, different from the ones in somefunc.
Fortunately, if you declare (or even define) the struct before you write the function declaration, the prototype-level declaration "refers back" to the outer-scope declaration:
struct sttag;
void gronk(struct sttag *p);
Now both struct sttags are "the same" struct sttag, so when you complete struct sttag later, you're completing the one inside the prototype for gronk too.
Re the question edit: it would certainly have been possible to define the action of struct, union, and enum tags differently, making them "bubble out" of prototypes to their enclosing scopes. That would make the issue go away. But it wasn't defined that way. Since it was the ANSI C89 committee that invented (or stole, really, from then-C++) prototypes, you can blame it on them. :-)
The compiler is warning you about a forward declaration of struct lol. C allows you to do this:
struct lol; /* forward declaration, the size and members of
struct lol are unknown */
This is most used when defining self-referencing structs, but it is also useful when defining private structs that are never defined in the header. Because of this latter use case, it is allowed to declare functions that receive or return pointers to incomplete structs:
void foo(struct lol *x);
However, just using an undeclared struct in a function declaration, as you did, will be interpreted as a local incomplete declaration of struct lol whose scope is constrainted to the function. This interpretation is mandated by the C standard, but it is not useful (there is no way to construct the struct lol to pass to the function) and is almost certainly not what the programmer intended, so the compiler warns.
This is because, in the first example, the struct is previously undefined and so the compiler tries to treat this first reference to that struct as a definition.
In general, C is a language where the order of your declarations matters. Everything you use should be properly declared in advance in some capacity, so that the compiler can reason about it when it's referenced in other context.
This is not a bug or a mistake in the design of the language. Rather, it's a choice that I believe was made to simplify the implementations of the first C compilers. Forward declarations allow a compiler to translate the source code serially in one pass (as long as some information such as sizes and offsets is known). If this weren't the case, the compiler would have be able to go back and forth in the program whenever it meets an unrecognized identifier, requiring its code emission loop to be much more complex.
I see this same warning before. My fix is to include the proper header file which contains the definition of the struct.
In addition to other answers, I would like to post a code example, which makes the problem more obvious. Please consider the following:
int testFunc(struct SomeStruct {int a; int b;} param1) // gcc: warning ...
{
return param1.a + param1.b;
}
int main(void)
{
struct SomeStruct params; // gcc: error: storage size of 'params' isn't known
params.a = 25;
params.b = 15;
return testFunc(params);
}
As you can see, the function declaration of testFunc is considered a valid C code (tested with GCC 12, Clang 15 and MSVC 19.32). However, you can't really use it because SomeStruct is only valid within the scope of the function, which is what compiler warns you about.
I've stumbled on this myself when working on my own C parser as the allowance of such syntax makes parser development easier as you can reuse the same implementation to parse struct declaration inside function parameter lists. It is surprising, however, that such bizarre syntax is still considered valid nowadays (as of C17) and instead of error you just get a warning.
Lookout for typos and DOUBLE CHECK your line numbers! I concat all my source files before compiling, so the line numbers from the source I am working in are meaningless. I have to take extra time to open up the concatted payload and examine it. So usually I don't and I just assume I know what line I am looking at from the console output message.
Example:
GCC Says:
EXAMPLE.C11:27:1: error: 'struct THIS_STRUCT_IS_OK' declared inside
parameter list [-Werror] ){
#include <stdio.h> //:for: printf(...)
struct THIS_STRUCT_IS_OKAY{
int whatever;
};
int LookingAtThisFunction(
struct THIS_STRUCT_IS_OKAY* arg
){
//: (Because you are not checking line numbers, you )
//: (assume you are looking here. But you are not. )
//: (Maybe you are concatenating all of your source )
//: (files together before compiling and line numbers )
//: (don't correspond to the original source and you )
//: (didn't examine your concatted source code payload?)
return( arg -> whatever );
}
//:You are not looking here because this is later in the
//:file, so the compiler would be complaining about the
//:FIRST usage of the struct, not the second one, you assume.
//:And you would be correct, if there wasn't a typo.
void WhereYouAreNotLooking(
struct THIS_STRUCT_IS_OK* arg
){
LookingAtThisFunction( arg );
}
int main( void ){
}
In summary: If you know what the error message means. And you swear to god
the compiler is broken because you already checked that...
1. Look for typos.
2. Make sure you are really looking at the correct line number.
I get that this is kinda stupid. But it had been scratching my head for
half an hour. So hopefully it helps someone who's already looked at the
obvious solutions.
I have a C project that is designed to be portable to various (PC and embedded) platforms.
Application code will use various calls that will have platform-specific implementations, but share a common (generic) API to aid in portability. I'm trying to settle on the most appropriate way to declare the function prototypes and structures.
Here's what I've come up with so far:
main.c:
#include "generic.h"
int main (int argc, char *argv[]) {
int ret;
gen_t *data;
ret = foo(data);
...
}
generic.h: (platform-agnostic include)
typedef struct impl_t gen_t;
int foo (gen_t *data);
impl.h: (platform-specific declaration)
#include "generic.h"
typedef struct impl_t {
/* ... */
} gen_t;
impl.c: (platform-specific implementation)
int foo (gen_t *data) {
...
}
Build:
gcc -c -fPIC -o platform.o impl.c
gcc -o app main.c platform.o
Now, this appears to work... in that it compiles OK. However, I don't usually tag my structures since they're never accessed outside of the typedef'd alias. It's a small nit-pick, but I'm wondering if there's a way to achieve the same effect with anonymous structs?
I'm also asking for posterity, since I searched for a while and the closest answer I found was this: (Link)
In my case, that wouldn't be the right approach, as the application specifically shouldn't ever include the implementation headers directly -- the whole point is to decouple the program from the platform.
I see a couple of other less-than-ideal ways to resolve this, for example:
generic.h:
#ifdef PLATFORM_X
#include "platform_x/impl.h"
#endif
/* or */
int foo (struct impl_t *data);
Neither of these seems particularly appealing, and definitely not my style. While I don't want to swim upstream, I also don't want conflicting style when there might be a nicer way to implement exactly what I had in mind. So I think the typedef solution is on the right track, and it's just the struct tag baggage I'm left with.
Thoughts?
Your current technique is correct. Trying to use an anonymous (untagged) struct defeats what you're trying to do — you'd have to expose the details of definition of the struct everywhere, which means you no longer have an opaque data type.
In a comment, user3629249 said:
The order of the header file inclusions means there is a forward reference to the struct by the generic.h file; that is, before the struct is defined, it is used. It is unlikely this would compile.
This observation is incorrect for the headers shown in the question; it is accurate for the sample main() code (which I hadn't noticed until adding this response).
The key point is that the interface functions shown take or return pointers to the type gen_t, which in turn maps to a struct impl_t pointer. As long as the client code does not need to allocate space for the structure, or dereference a pointer to a structure to access a member of the structure, the client code does not need to know the details of the structure. It is sufficient to have the structure type declared as existing. You could use either of these to declare the existence of struct impl_t:
struct impl_t;
typedef struct impl_t gen_t;
The latter also introduces the alias gen_t for the type struct impl_t. See also Which part of the C standard allows this code to compile? and Does the C standard consider that there are one or two struct uperms entry types in this header?
The original main() program in the question was:
int main (int argc, char *argv[]) {
int ret;
gen_t data;
ret = foo(&data);
…
}
This code cannot be compiled with gen_t as an opaque (non-pointer) type. It would work OK with:
typedef struct impl_t *gen_t;
It would not compile with:
typedef struct impl_t gen_t;
because the compiler must know how big the structure is to allocate the correct space for data, but the compiler cannot know that size by definition of what an opaque type is. (See Is it a good idea to typedef pointers? for typedefing pointers to structures.)
Thus, the main() code should be more like:
#include "generic.h"
int main(int argc, char **argv)
{
gen_t *data = bar(argc, argv);
int ret = foo(data);
...
}
where (for this example) bar() is defined as extern gen_t *bar(int argc, char **argv);, so it returns a pointer to the opaque type gen_t.
Opinion is split over whether it is better to always use struct tagname or to use a typedef for the name. The Linux kernel is one substantial body of code that does not use the typedef mechanism; all structures are explicitly struct tagname. On the other hand, C++ does away with the need for the explicit typedef; writing:
struct impl_t;
in a C++ program means that the name impl_t is now the name of a type. Since opaque structure types require a tag (or you end up using void * for everything, which is bad for a whole legion of reasons, but the primary reason is that you lose all type safety using void *; remember, typedef introduces an alias for an underlying type, not a new distinct type), the way I code in C simulates C++:
typedef struct Generic Generic;
I avoid using the _t suffix on my types because POSIX reserves the _t for the implementation to use* (see also What does a type followed by _t represent?). You may be lucky and get away with it. I've worked on code bases where types like dec_t and loc_t were defined by the code base (which was not part of the implementation — where 'the implementation' means the C compiler and its supporting code, or the C library and its supporting code), and both those types caused pain for decades because some of the systems where the code was ported defined those types, as is the system's prerogative. One of the names I managed to get rid of; the other I didn't. 'Twas painful! If you must use _t (it is a convenient way to indicate that something is a type), I recommend using a distinctive prefix too: pqr_typename_t for some project pqr, for example.
* See the bottom line of the second table in The Name Space in the POSIX standard.
I wrote the following code:
struct DVDARRAY
{
int length;
pDVD* dvds;
};
typedef struct DVDARRAY DVDARRAY_t;
//...
int main()
{
int i;
char c;
DVDARRAY_t* dvds;
poDAOproperties props;
props = get_dao_properties();
dvds = (DVDARRAY_t*) DVDDAO_read_raw_filter(props, "id = 1");
printf("title->: %s", dvds->dvds[0]->title);
}
and in another file the following is defined:
DVDARRAY_t* DVDDAO_read_raw_filter(poDAOproperties properties, char* filter)
{
DVDARRAY_t *dvds;
// ...some code...
dvds = malloc(sizeof(DVDARRAY_t));
// ...some code...
return dvds;
}
Now my question: when I try to compile these files I get the following warning:
src/main.c: In Funktion »main«:
src/main.c:80:9: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
Line 80 of main.c is exactly that line:
dvds = (DVDARRAY_t*) DVDDAO_read_raw_filter(props, "id = 1");
What can I do?
You do not list the file names above so I will just call them main.c and dvd.c.
In main.c, you make a call to the otherwise undeclared function DVDDAO_read_raw_filter. This tells the compiler to assume that the function exists, has an unknown (but fixed) set of arguments, and has a return value of type int.
In dvd.c you define the function DVDDAO_read_raw_filter with fixed (and known) arguments, returning type DVDARRAY_t*. (Presumably you have to repeat the definition of DVDARRAY_t first.)
Note that main.c believes something untrue about DVDDAO_read_raw_filter, namely, that it has return type int. This is causing your compile-time diagnostic. By luck (you can decide for yourself whether this is good or bad luck :-) ) the program runs successfully in spite of this incorrect belief.
To fix the problem, tell main.c about the function before calling it, i.e., declare it. You can also get a more explicit warning from gcc by adding -Wimplicit-function-declaration to your compile-time flags.
In general, it's a good idea to put struct definitions, typedefs, and function declarations into a header file (e.g., dvd.h) and then #include that header in the various C source files that make use of the definitions and declarations. That way the compiler can compare the function declarations against the function definitions, and you need not repeat the contents of structs and the names of typedefs in multiple .c files.
If you are just trying to make things work...
unsigned char *temp;
int number;
temp = someArr[y][x].charAtThisLoc;
number = (int)(size_t)temp;
other solutions didn't work for me.