#echo off
set /p UserInput= What file would you like to hide?
cd %UserInput%
So I want to make a batch file that when run asks the user for a file, which it will hide in a maze of random folders. Let me explain.
Let's say I type C:\Program Files\Steam\butts.exe
It'd make a new directory in C:\Program Files\Steam
This is where I'm stuck. How do I have it find C:\Program Files\Steam from C:\Program Files\Steam\butts.exe?
Hah! The quickest and hacksiest way would be just to add a \.. to the end. For instance, on my desktop I have a file called weather.xml. If I do this:
dir c:\users\me\Desktop\weather.xml\..
... I end up with a directory listing of my Desktop. :)
So you can accomplish what you need with
cd %UserInput%\..
Otherwise, you could pass the path to a for loop or call :label to a subroutine to end up with %%~dpX. See the last couple of pages of help for and help call for details.
If you want to be even hacksier, instead of requiring the user to enter the path\to\file to set %UserInput%, you can use powershell to launch a File... Open sort of file chooser. See this answer for details.
Try this:
#echo off&setlocal
for %%i in ("C:\Program Files\Steam\butts.exe") do set "steampath=%%~dpi"
:: remove last backslash
echo %steampath:~0,-1%
You can use this batch
#echo off
set /p UserInput=What file would you like to hide?
for %%i in ("%UserInput%") do set path="%%~dpi"
cd %path%
Related
I've noticed that any time I open up the command prompt, I tend to have to navigate to my git directory. So I'm trying to set up a simple macro to take me there. I've made a folder called C:\Macros and modified my %PATH% variable to point there. And I've added a file called gotoGit.bat.
Inside that batch file, I'm simply doing this :
#ECHO off
:: Check if a path is provided...
SET pathvar=%1
IF "%pathvar%"=="" (SET pathvar=some\default\dir)
:: Navigate...
CD /D C:\git\%pathvar%
But when I call it from the command line, I'm not navigating anywhere.
C:\Users\You> gotoGit
C:\Users\You>
Toggling ECHO on I can see that it is executing and creating the correct path, but it's not navigating me to C:\git\some\default\dir. The cd is only modifying the working directory inside the script, not my command line directory.
I'd like for it to navigate me to the right place :
C:\Users\You> gotoGit
C:\git\some\default\dir>
Any help is greatly appreciated.
Add the "cmd" term at the end example:
ECHO off
:: Check if a path is provided...
SET pathvar=%1
IF "%pathvar%"=="" (SET pathvar=some/default/dir)
:: Navigate...
CD /D C:/git/%pathvar%
cmd
It will open a command prompt with the directory you specified!
(If you are already in cmd it will just change the directory)
Based on the comments on the question, this suggestion ended up working for me.
#ECHO off
:: Check if a path is provided...
SET pathvar=%1
IF "%pathvar%"=="" (SET pathvar=some\default\dir)
:: Navigate...
CMD /K CD /D C:\git\%pathvar%
Is there a batch command that can read a root directory without the entire path?
I want a batch file to tell me if its in D:\ or E:\.
I tried to use:
set mypath=%cd%
#echo %mypath%
Pause
But it just says the exact place it is in rather than just the root.
Here's a few options for you which provide the root directory of the scripts current directory:
Using PushD/Popd
PushD\&Call Set "RootDir=%%CD%%"&PopD
Echo(%RootDir%
Pause
Using a For loop
For %%A In (%CD%) Do Set "RootDir=%%~dA\"
Echo(%RootDir%
Pause
Using variable expansion
Set "RootDir=%CD:~,3%"
Echo(%RootDir%
Pause
Edit
After reading your question again, I decided to add a fourth example. This one unlike the other three provides the root directory of the batch files location.
Set "RootDir=%~d0\"
Echo(%RootDir%
Pause
the directory where the batch file is located could be different from the current directory cmd.exe operates in.
TO get the batch file root path use:
for %%a in ("%0") do echo %%~da
To ger the current directory use
echo "%cd:~0,3%"
And let us not forget the &REM trick.
#ECHO OFF
set "root=%cd:\="&rem %
echo %root%
im a beginner in batch script,and im trying to do a script that ask for a file path,then create a folder(in the current folder)and I want the created folder name to be like "sav-DATE-TIME"(for example,right now the folder would be named: sav-2015-12-07-18-55-00) and then copy the file given by the user filepath in the created folder.So far I did this:
#ECHO OFF
SET /P pathh=Enter the path
SET foldname=sav%DATE%%TIME%
mkdir %foldname%
cd %foldname%
xcopy /s/e %pathh% %cd%
pause
However when I run this,no matter how I enter the path with " or ' or nothing around the path,it always says that the path is incorrect,and also it create a folder with random number(74,56,21...)as the folder name and I dont understand why it wont work properly,wich mean creating the folder with name as said at the begining of question and also saying the path is always incorrect.
thank you!
You need to use quotes when the variables are expanded (used). The first set of quotes below is only to ensure that you don't have any trailing white space chars. Try this:
#ECHO OFF
SET /P pathh=Enter the path
SET "foldname=sav-%DATE%-%TIME:~0,8%
SET "foldname=%foldname::=-%
echo foldname=%foldname%
rem mkdir "%foldname%"
rem cd "%foldname%"
rem xcopy /s/e "%pathh%" "%cd%"
pause
Remove the rem's when it looks good
set foldname=%date:~-4%-%date:~3,2%-%date:~0,2%:%time:~0,2%:%time:~3,2%,%time:~6,2% this should give you 2015-12-09-10:56,17
Then mkdir %foldname%
So I have the batch file below.
#ECHO OFF
FOR %%I IN (.) DO SET FolderName=%%~nxI
MKDIR "C:\%FolderName%"
for %%i in (%*) do (
move "%%~i" "C:\%FolderName%"
)
So when I drag and drop multiple files into the batch file, it will take the name of the folder that holds the files that I drag and drop and make a new folder at C:\ with the same name and then move the files into the new folder at C:\
Example: The folder that holds the files that I want to move is name Shop. Then the folder Shop is located at
...\ground\bell\tower\Shop
Using the batch file will make a new folder name Shop at C:\
Example
C:\Shop
The batch files works when I drag and drop about 100 files at once. The problem is that when I drag and drop 300 files at once, it returns the Error that says "The filename or extension is too long". I am able to move the files manually so I know that it can not be cause by a filename being too long.
Then I made a new batch file thinking maybe it is a problem with the move command or my for loop. So I wrote the batch file below.
#echo off
FOR %%I IN (.) DO SET FolderName=%%~nxI
MKDIR "C:\%FolderName%"
MOVE "%cd%\*.*" "C:\%FolderName%"
Now the second batch file above works just about the same as the first batch file. Just that with the second batch file, I only need to drag and drop one file from the folder that I want to move and it will move all the files in the first folder to a new folder at C:\ even if the first folder had 1000 files.
My question is why does the first batch file fail if I drag and drop too many files at once. Using the second batch file work, so it can not be because of the move command or is it? Since I am moving all the files from one folder to the other, the second batch file fits my need and was wondering if there will be any problems with the second batch file or a better way of doing this.
When you Drag-n-Drop Files on you Bat File, your Bat is actually called as if you would have called it in your command prompt. So if you drag three files on your Bat i.e.
Testfile.txt
Testfile.md
Testfile.jpg
Then actually your Bat is called like this:
C:\MyBatch.BAT Testfile.txt Testfile.md Testfile.jpg
If you call more it is obviously something like:
C:\MyBatch.BAT Testfile.txt Testfile.md Testfile.jpg Testfile01.txt Testfile01.md Testfile01.jpg Testfile02.txt Testfile02.md Testfile02.jpg Testfile03.txt Testfile03.md Testfile03.jpg Testfile04.txt Testfile04.md Testfile04.jpg Testfile05.txt Testfile05.md Testfile05.jpg etc...
Ah, can you read the rest of the line? Ok, this is not as long as 1000 Files but get the point what the difference is in your scripts. Your command line buffer will not be able to capture that much input.
Actually the size of how many characters you can enter in you command prompt varies a bit from system to system, but there was something like 8k in winXP, i reckon it is still the same.
http://support.microsoft.com/kb/830473 <-- that could help more concerning max.
And since the length of your command prompt is so "short" you have to find different methods for longer file trails - as you did - you could also overcome this, if you output the files you want to copy in a text file and then use that as input for your copy bat.
dir /b >filelist.txt
so now that you have this file list, then you just read the text file line by line:
for /f "delims=" %%i in (filelist.txt) do echo D|xcopy "C:\FolderName\%%i" "c:\temp\%%i" /i /z /y
so this will actually read your file list.txt and will (for each filename in list) press D key and pipes it to the XCopy command.
So piping a filelist to your command is a much better way, where actually in your case, if you really want the whole dir and not just a selection, copying directories is faster than copying file by file.
Hope you Question is answered.
If I am not mistaken, you are trying to create a folder with the parent folder as name. So before you ask again the same question in another post, I will code what you are seeking.
#echo off
setlocal
set "destination=c:\destination"
for %%i in (%~1) do set "parent=%%~pi" &goto:next
:next
for %%i in ("%parent:~0,-1%") do set "parent=%%~nxi"
for %%i in (%*) do (
echo:
if not exist %destination%\%parent%\nul ( mkdir "%destination%\%parent%" )
move "%%~i" "%destination%%parent%"
)
In addition, a command with many arguments is not a problem in the previous code.
For example: Write a batch file with the following code
#echo off
setlocal
set "destination=c:\destination"
for %%i in (%~1) do set "parent=%%~pi" &goto:next
:next
for %%i in ("%parent:~0,-1%") do set "parent=%%~nxi"
for %%i in (%*) do (
echo:
if not exist %destination%\%parent%\nul (echo mkdir "%destination%\%parent%")
echo move "%%~i" "%destination%%parent%"
)
call it test-move.bat and put the following long command-line of 250 parameters in cmd:
test-move.bat TestFile001.txt TestFile002.txt TestFile003.txt TestFile004.txt TestFile005.txt TestFile006.txt TestFile007.txt TestFile008.txt TestFile009.txt TestFile010.txt TestFile011.txt TestFile012.txt TestFile013.txt TestFile014.txt TestFile015.txt TestFile016.txt TestFile017.txt TestFile018.txt TestFile019.txt TestFile020.txt TestFile021.txt TestFile022.txt TestFile023.txt TestFile024.txt TestFile025.txt TestFile026.txt TestFile027.txt TestFile028.txt TestFile029.txt TestFile030.txt TestFile031.txt TestFile032.txt TestFile033.txt TestFile034.txt TestFile035.txt TestFile036.txt TestFile037.txt TestFile038.txt TestFile039.txt TestFile040.txt TestFile041.txt TestFile042.txt TestFile043.txt TestFile044.txt TestFile045.txt TestFile046.txt TestFile047.txt TestFile048.txt TestFile049.txt TestFile050.txt TestFile051.txt TestFile052.txt TestFile053.txt TestFile054.txt TestFile055.txt TestFile056.txt TestFile057.txt TestFile058.txt TestFile059.txt TestFile060.txt TestFile061.txt TestFile062.txt TestFile063.txt TestFile064.txt TestFile065.txt TestFile066.txt TestFile067.txt TestFile068.txt TestFile069.txt TestFile070.txt TestFile071.txt TestFile072.txt TestFile073.txt TestFile074.txt TestFile075.txt TestFile076.txt TestFile077.txt TestFile078.txt TestFile079.txt TestFile080.txt TestFile081.txt TestFile082.txt TestFile083.txt TestFile084.txt TestFile085.txt TestFile086.txt TestFile087.txt TestFile088.txt TestFile089.txt TestFile090.txt TestFile091.txt TestFile092.txt TestFile093.txt TestFile094.txt TestFile095.txt TestFile096.txt TestFile097.txt TestFile098.txt TestFile099.txt TestFile100.txt TestFile101.txt TestFile102.txt TestFile103.txt TestFile104.txt TestFile105.txt TestFile106.txt TestFile107.txt TestFile108.txt TestFile109.txt TestFile110.txt TestFile111.txt TestFile112.txt TestFile113.txt TestFile114.txt TestFile115.txt TestFile116.txt TestFile117.txt TestFile118.txt TestFile119.txt TestFile120.txt TestFile121.txt TestFile122.txt TestFile123.txt TestFile124.txt TestFile125.txt TestFile126.txt TestFile127.txt TestFile128.txt TestFile129.txt TestFile130.txt TestFile131.txt TestFile132.txt TestFile133.txt TestFile134.txt TestFile135.txt TestFile136.txt TestFile137.txt TestFile138.txt TestFile139.txt TestFile140.txt TestFile141.txt TestFile142.txt TestFile143.txt TestFile144.txt TestFile145.txt TestFile146.txt TestFile147.txt TestFile148.txt TestFile149.txt TestFile150.txt TestFile151.txt TestFile152.txt TestFile153.txt TestFile154.txt TestFile155.txt TestFile156.txt TestFile157.txt TestFile158.txt TestFile159.txt TestFile160.txt TestFile161.txt TestFile162.txt TestFile163.txt TestFile164.txt TestFile165.txt TestFile166.txt TestFile167.txt TestFile168.txt TestFile169.txt TestFile170.txt TestFile171.txt TestFile172.txt TestFile173.txt TestFile174.txt TestFile175.txt TestFile176.txt TestFile177.txt TestFile178.txt TestFile179.txt TestFile180.txt TestFile181.txt TestFile182.txt TestFile183.txt TestFile184.txt TestFile185.txt TestFile186.txt TestFile187.txt TestFile188.txt TestFile189.txt TestFile190.txt TestFile191.txt TestFile192.txt TestFile193.txt TestFile194.txt TestFile195.txt TestFile196.txt TestFile197.txt TestFile198.txt TestFile199.txt TestFile200.txt TestFile201.txt TestFile202.txt TestFile203.txt TestFile204.txt TestFile205.txt TestFile206.txt TestFile207.txt TestFile208.txt TestFile209.txt TestFile210.txt TestFile211.txt TestFile212.txt TestFile213.txt TestFile214.txt TestFile215.txt TestFile216.txt TestFile217.txt TestFile218.txt TestFile219.txt TestFile220.txt TestFile221.txt TestFile222.txt TestFile223.txt TestFile224.txt TestFile225.txt TestFile226.txt TestFile227.txt TestFile228.txt TestFile229.txt TestFile230.txt TestFile231.txt TestFile232.txt TestFile233.txt TestFile234.txt TestFile235.txt TestFile236.txt TestFile237.txt TestFile238.txt TestFile239.txt TestFile240.txt TestFile241.txt TestFile242.txt TestFile243.txt TestFile244.txt TestFile245.txt TestFile246.txt TestFile247.txt TestFile248.txt TestFile249.txt TestFile250.txt
I have a good command over cmd commands, but this may require a variable or a loop which is where I fail in batch commands. Please help if you can!
-- Have about 100 subdirectories each has 1-20 HTML files in it. There are about 100 HTML files in the root directory too.
-- Need to replace all HTML files in the above directories with the same HTML source (copy over existing file and keep the name the same). Basically trying to replace all existing files with a redirect script to a new server for direct bookmarked people. We are running a plain webserver without access to server-side redirects so trying to do this just by renaming the files (locked down corp environment).
Seems pretty simple. I can't get it to work with wildcards by copying the same file over to replace. I only get the first file replaced, but the rest of the files will fail. Any one with any advice?
This should do it from the command prompt. Replace % with %% for use in a batch file.
for /r "c:\base\folder" %a in (*.html) do copy /y "d:\redirect.html" "%a"
Without knowing more precisely how you want to update the file content I suggest the following rough approach.
To re-create your example, I had to create some folders. Run this command to do that:
for /l %i in (1,1,20) do mkdir fold%i
I then used this script to create some example files:
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do call :makefiles %%i
goto :EOF
:makefiles
set /a number+=1
touch %1\file%number%.txt
echo %number% >%1\file%number%.txt
I then used this script to append the text changed to the file. Not sure if that is what you wanted - probably you need something more sophisticated.
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do #for %%f in ("%%i\*.txt") do call :changetext %%f
goto :EOF
:changetext
echo changing file contents to ^"changed^" for file: %1
echo changed>>%1