Largest value in array [closed] - c

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I've been asked to write a program that accepts a list of numbers until a non-numeric is encountered (up to 30 numbers), putting the numbers into an array, and keeping track of how many numbers were inserted. Then it should scan through the array to find the largest number, and print the largest.
This is what I've come up with:
#include<stdio.h>
int main()
{
const int INPUT = 30 ;
int size [INPUT];
int i, big;
printf("Type integer numbers, followed by q to quit: ");
while (scanf("%d", &size[INPUT]) != 'q')
{
for(i=0;i<size;i++)
scanf("%d",&INPUT[i]);
big = INPUT[0];
for(i=1;i<size;i++)
{
if(big<INPUT[i])
big=INPUT[i];
}
printf("The largest number is %d",big);
return 0;
}

Answer 1

Besides the problems, I listed in the comments. You seems to be comfused by the varaible names~ Anyway, I made some code for you.
#include<stdio.h>
int main()
{
const int MAX_INPUT = 30 ;
int input[MAX_INPUT];
int size=0, big;
printf("Type integer numbers, followed by q to quit: ");
while(size < MAX_INPUT){
if(scanf("%d", &input[size]) != 1){
break;
}
++size;
}
if(size ==0){
return 0;
}
big = input[size-1];
while( size-- > 0)
{
if(big<input[size]){
big=input[size];
}
}
printf("The largest number is %d\n",big);
return 0;
}
Tested with GCC 4.1.2 and Linux.

Answer 2

Return value of scanf:
Upon successful completion, these functions return the
number of successfully matched and assigned input items
further, you are mixing the size and input, you actually want the size to be a constant and input to be an array:
const int SIZE = 30 ;
int input[SIZE];
So the while loop should look like:
while (scanf("%d", &input[some_index]) == 1)
and of course this is wrong:
scanf("%d",&INPUT[i]); // should be ==> &input[i]