Not having to have an exact input in Batch - batch-file

So basicly, is there any way to make it so a Batch file doesnt need an exact answer to do an action. For example:
if %c%=images goto :images
The above means that I must type in the exact word, images, and if I add any more words it wont go to the :images label. How would I make it to go to a label using just a word from a sentence that you input.
For example if it asks me:
Where would you like to go?
And I say:
The image section please.
Then it takes me to the image section without the need for just saying image.
Is this possible?

You could use find.
echo %c% | find /i "image" >NUL && goto images
That'll also provide case-insensitive matching. Furthermore, you can similarly use findstr to match based on a regular expression if you need finer tuning of your match.
If you're curious about how the | and && above do their magic, see command redirection for more info.

There's a similar question here: Batch file: Find if substring is in string (not in a file)
The accepted answer could work in your case:
if /i "%c:image=%" neq "%c%" goto images
This technique uses string substitution to replace the word image with nothing (strip the word from the string you're searching), then compare it to the original string. If they're different, then the substring was found.

Related

Batch: How do I replace a specific part of text in a variable, without changing everything else?

So I'm trying to make a search engine that, when you input a search string, replaces the spaces with a "+", and it'd be helpful if someone pointed out which commands I can use to achieve that.
So far I haven't found anyone that has the same question, which is why I'm posting it here. I've found someone with a way to detect spaces in a variable:
if not "%VAR%"=="%VAR: =%"
but no way to replace them.
Any hints?
P.S.: Please, do not recommend me PowerShell or other scripting languages/methods like I saw some people do, I have my reason for using batch and I'm going to stick to it.
So let me explain how substitution works.
set "var=This is a line with spaces"
set "var=%var: =+%"
echo %var%
in the second set we set var to %var% again, but we use substitution of spaces. Everything after : up to = is the search function and everything after = up to the % is the replace function. So %var: =+% means find all the space and replace with + Hence the outcome of the above code will be:
This+is+a+line+with+spaces
Obviously the variable can be manipulated multiple times:
set "var=This is a line with spaces"
set "var=%var: =+%"
set "var=%var:spaces=pluses%
echo %var%
you can also use the substitution to do comparisons without doing substitution using set:
set "var=This is a line with spaces"
if /i "%var: =+%"=="This+is+a+line+with+spaces" echo Matched!
I suggest you read the help by running set /? from cmdline.

inverted question mark and findstr

I can't seem to write certain characters (inverted question marks, fancy single quote marks, ampersands) to a text file, and then to search that file for those characters. For example the following findstr doesn't find the upside down question mark item in .txt:
#echo off
echo "Cato Event - GO Beyond GDP. What Really Drives the Economy¿">c:\test.txt
findstr /I /N /C:"Cato Event - GO Beyond GDP. What Really Drives the Economy¿" c:\test.txt
pause
::chcp 1254
I've tried with various chcp commands also to no avail.
Any help appreciated.
That is a known issue with FINDSTR - Some characters provided on the command line with ANSI byte codes > 127 are transformed into a different character by FINDSTR, prior to doing the search, which causes the search to fail.
The solution is to put the search string(s) in a file and use the /L and /G options.
See the section titled "Character limits for command line parameters - Extended ASCII transformation" at What are the undocumented features and limitations of the Windows FINDSTR command?
The only other option (assuming you want to stick with native batch commands) is to use FIND instead. It has much less functionality, but it does not have the character translation issue, and I believe it should work for your simple literal search.
find /I /N "Cato Event - GO Beyond GDP. What Really Drives the Economy¿" c:\test.txt
The line numbers at the beginning of each matching line will look like [123] instead of 123:.

Using FINDSTR to search for a pattern and assign it to a variable

I have the following entry in the file Build.aip. I need to write a batch file that searches for "PackageFileName and prints the value assigned for that in the file. In this case, I need to print MyPackageName on the console:
<ROW BuildKey="DefaultBuild" BuildName="DefaultBuild" BuildOrder="1" BuildType="0" PackageFolder="C:\Build\Build.aip" PackageFileName="MyPackageName" Languages="en" InstallationType="4">
May you please give me some examples how I can do that? I seen in some forums that this can be done using FINDSTR.
Thanks in advance.
findstr "PackageFileName" Build.aip
If you want to make it case insensitive, add the /i argument.
For more details, type findstr /?
Updated for an example to use the for statement
FOR /F "token=2" %i in (`FINDSTR "PackageFileName" Build.aip`) do SET var=%i
A couple things to keep in mind here:
This version is based on Windows 8.1; it may work differently in different versions of Windows.
The token=2 is an example assuming that the word you are looking for is the second word in the line
If PackageFileName appears more than once in Build.aip, this code will break.
The findstring command is surrounded by back-ticks, not single quotes.
I haven't tested it; the SET may not actually survive the for loop. So test!
If you use it in a batch file, you must double all the % signs.

Storing multi-word strings to a file

I've recently been trying to make a program to simply store text to a file for later viewing, storing it as a .rar file for security against those who don't understand how to extract the text from the .rar (i.e. the less "techy" people)...
I have, however, encountered an error in the program that results in the <word> not expected at this time followed by the .exe closing when I input add/<word> <word>... (i.e. any multi-word string with spaces in between the words [add/<word>, however, does function properly]).
Is there a special rule that must be followed for storing multi-word strings to a .rar or a file in general (I do, however, know that there is a rule for creating/renaming folders/directories)?
The Program Segment:
:command
cls
set /p journal=<journal.rar
echo %journal%
echo.
set /p command=What would you like to do?
cls
if %command%==exit exit
if %command%==help goto help
if %command%==delete echo START; > journal.rar
if %command:~0,4%==add/ echo "%journal%""%command:~4%;" > journal.rar
if %command:~0,5%==edit/ echo %journal:%command:~5%=%;" > journal.rar
goto command
Excuse me. Your question is not clear. There are several confusing points in it, like "followed by the .exe closing" (which .exe is closing?), and the fact that your question is NOT related to .rar files in any way, nor to "storing multi-word strings". However, I can see the following points in it:
When a variable value is expanded with percent signs this way: %command% you must be aware that the variable is first expanded and then the resulting line is parsed. This mean that the value of the variable may introduce errors in the line. For example, in this line: if %command%==exit exit, if the value of command variable is add/one two three, then the line that is parsed is this: if add/one two three==exit exit that, of course, issue an error! (type if /? for further details).
The way to avoid this problem is enclosing both the variable and the comparison value in quotes; this way, if the value have several words with spaces, the whole value is grouped in the IF command for comparison purposes: if "%command%" == "exit" exit. This must be done in every IF command that use the value of the variable.
In the following line:
if %command:~0,5%==edit/ echo %journal:%command:~5%=%;" > journal.rar
you must be aware that the line is parsed from left to right; this means that you can not nest a %variable% expansion inside another one. The way to solve this problem is first complete a %normal% variable expansion, and then a !delayed! variable expansion that will take the previous expanded value. To do that, insert this line at beginning of your program:
setlocal EnableDelayedExpansion
and change previous line by this one:
if "%command:~0,5%" == "edit/" echo !journal:%command:~5%=!;" > journal.rar
For further details, type set /? and carefully read the sections about "delayed expansion".
Here is a sample that can accept multiple words:
set "command="
set /p "command=What would you like to do? "
cls
if /i "%command%"=="have lunch" goto :food

How to get a the directory path from a variable in a cmd batch file

Within my batch file I have a variable that contains a file path:
SET VAR1=C:\Folder1\Folder2\File.txt
I would like to extract on the directory structure and retreive:
C:\Folder1\Folder2\
I have read threads like this where I need to use %~dp0 where 0 I believe is passed as a parameter. I have tried %~dpVAR1 but that doesn't work. How can I get the output I'm looking for, but with a variable containing the file path?
Also, to make matters difficult, I have to perform all of this within an IF condition which means that once the variable is declared, I will need to refer to it with ! instead of % (I have declared setlocal enableextensions enabledelayedexpansion at the beginning of my script to allow for this).
Any help is much appreciated!
Thanks!
Andrew
You are attempting to use parameter expansion syntax on an environment variable - that cannot work. But it is relatively easy to do what you want.
Using a CALL (relatively slow):
(...
call :getPath "!var!" var
...
)
exit /b
:getPath
set "%2=%~dp1"
exit /b
Using FOR, assuming the variable does not contain any wildcards (fast)
(...
for %%F in ("!var!") do set "var=%%~dpF"
...
)
Using FOR, if the variable may contain wildcards (also fast)
(...
for /f "delims=" %%F in ("!var!") do set "var=%%~dpF"
...
)
Note 1: If the variable does not contain the full path, then all the solutions will attempt to resolve the name into an absolute path and will return the full absolute path. For example, if var contains foobar\test.txt, then the solutions will include the full path to the current directory, even if the file is not found. Something like c:\pathToCurrentDirectory\foobar\.
Note 2: All solutions above will remove all quotes from the path.
Note 3: A path could include the ! character, which will cause problems when expanding %~dp1 or %%~dpF because you have delayed expansion enabled. The delayed expansion will corrupt both ^ and ! if the value contains !. There is a solution that involves protecting both ! and ^. Here is a demonstration applied to the last solution above. The protection requires normal expansion, and since you are within a code block, it requires at least one CALL. It could be done without a subroutine, but it is easier with a subroutine. The subroutine assumes the variable is named var.
(...
call :getPath
...
)
exit /b
:getPath
set "var=!var:"=!"
set "var=!var:^=^^^^!"
set "var=%var:!=^^^!%" !
for /f "delims=" %%F in ("!var!") do set "var=%%~dpF" !
exit /b
I do believe (once again) many questions are on the same topic (string constraints, or splitting strings).
Instead of giving you the whole code, I'm going to give you a template and explain why %~dpVAR! didn't work.
Firstly, why %~dpVAR! did't work.
Before I get into modifiers, let's discuss parameters. You may know that batch files can parse parameters to each other. These parameters can be called by using a single percent sign (%) in front of the numbers 0-9. As far as I'm aware (someone might have made a way for more to be parsed), only 9 parameters can be parsed. You may think that is wrong (there's 10 parameters right?). Parameters 1-9 are parsed to the batch file (or function within one), %0 is the file path of the batch file (or function name). If you look, %~dp0 shares some (not really) resemblance to %0. This will be discussed below.
Secondly, the term %~dp0 has modifiers in it. Modifiers are things that modify variables (only in the case of parameters and those declared in for loops, you know the ones with double percent signs like %%i) and parameters. The modifier d expands the parameter to a drive letter only while p expands the parameter to a path only. You may think that these would contradict themselves, but parameters can be combined to create extremely wacky formats.
So, as you can see, you attempt at replacing 0 with your variable name failed because it's not specified for those sort of things.
Now, on to the template.
You can constrain variables (and put them into other variables) like this:
set variable=!variable:~offset,amount!
Don't worry if that seems confusing, I'm about to explain the components.
Firstly, notice that there is no /a switch. This is because this is not a mathematical function (don't really know why I added this). So, before I explain it, here's an example of what it would do to a variable name numbers that has the value of 0123456789.
set numbers=!numbers:~5,1!
By using that line of code, numbers would now equal 5. This is because it is recreating the variable with a smaller version of the original value (gee this is hard to explain). As you can see, there is a 5 where offset was on the template above. This is because it is skipping the first 5 characters and setting the variable as the next amount, or 1 character (I really hope you're getting this).
So basically, it sets a variable as a shorter value of a different (or the same) variable determined by the offset and the amount of characters to contain in it.
I really hope this helps because I probably wouldn't understand a word of this.
Can someone redirect this poor guy to a link explaining this better (I tried, ok!)?
Complete example of extracting paths from variable:
#echo off
set /p Fullpath="Specify full path: "
call :getPath %Fullpath% filename folder
echo %filename%
echo %folder%
pause
exit /b
:getPath
set "%2=%~nx1"
set "%3=%~dp1"
exit /b
Would this work:
SET VAR1=C:\Folder1\Folder2\File.txt
echo %var1%
Where Echo is the name of your exe.
%CD% may work as well: Echo %CD%

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