Batch Extract path and filename from a variable - batch-file

Question

How can I extract path and filename from a variable?
Setlocal EnableDelayedExpansion
set file=C:\Users\l72rugschiri\Desktop\fs.cfg
I want to do that without using any function or any GOTO.
is it possible?

Answer 1

#ECHO OFF
SETLOCAL
set file=C:\Users\l72rugschiri\Desktop\fs.cfg
FOR %%i IN ("%file%") DO (
ECHO filedrive=%%~di
ECHO filepath=%%~pi
ECHO filename=%%~ni
ECHO fileextension=%%~xi
)
Not really sure what you mean by no "function"
Obviously, change ECHO to SET to set the variables rather thon ECHOing them...
See for documentation for a full list.
ceztko's test case (for reference)
#ECHO OFF
SETLOCAL
set file="C:\Users\ l72rugschiri\Desktop\fs.cfg"
FOR /F "delims=" %%i IN ("%file%") DO (
ECHO filedrive=%%~di
ECHO filepath=%%~pi
ECHO filename=%%~ni
ECHO fileextension=%%~xi
)
Comment : please see comments.

Answer 2

You can only extract path and filename from (1) a parameter of the BAT itself %1, or (2) the parameter of a CALL %1 or (3) a local FOR variable %%a.
in HELP CALL or HELP FOR you may find more detailed information:
%~1 - expands %1 removing any surrounding quotes (")
%~f1 - expands %1 to a fully qualified path name
%~d1 - expands %1 to a drive letter only
%~p1 - expands %1 to a path only
%~n1 - expands %1 to a file name only
%~x1 - expands %1 to a file extension only
%~s1 - expanded path contains short names only
%~a1 - expands %1 to file attributes
%~t1 - expands %1 to date/time of file
%~z1 - expands %1 to size of file
And then try the following:
Either pass the string to be parsed as a parameter to a CALL
call :setfile ..\Desktop\fs.cfg
echo %file% = %filepath% + %filename%
goto :eof
:setfile
set file=%~f1
set filepath=%~dp1
set filename=%~nx1
goto :eof
or the equivalent, pass the filename as a local FOR variable
for %%a in (..\Desktop\fs.cfg) do (
set file=%%~fa
set filepath=%%~dpa
set filename=%%~nxa
)
echo %file% = %filepath% + %filename%

Answer 3

All of this works for me:
#Echo Off
Echo Directory = %~dp0
Echo Object Name With Quotations=%0
Echo Object Name Without Quotes=%~0
Echo Bat File Drive = %~d0
Echo Full File Name = %~n0%~x0
Echo File Name Without Extension = %~n0
Echo File Extension = %~x0
Pause>Nul
Output:
Directory = D:\Users\Thejordster135\Desktop\Code\BAT\
Object Name With Quotations="D:\Users\Thejordster135\Desktop\Code\BAT\Path_V2.bat"
Object Name Without Quotes=D:\Users\Thejordster135\Desktop\Code\BAT\Path_V2.bat
Bat File Drive = D:
Full File Name = Path.bat
File Name Without Extension = Path
File Extension = .bat

Answer 4

if you want infos from the actual running batchfile,
try this :
#echo off
set myNameFull=%0
echo myNameFull %myNameFull%
set myNameShort=%~n0
echo myNameShort %myNameShort%
set myNameLong=%~nx0
echo myNameLong %myNameLong%
set myPath=%~dp0
echo myPath %myPath%
set myLogfileWpath=%myPath%%myNameShort%.log
echo myLogfileWpath %myLogfileWpath%
more samples?
C:> HELP CALL
%0 = parameter 0 = batchfile
%1 = parameter 1 - 1st par. passed to batchfile... so you can try that stuff (e.g. "~dp") between 1st (e.g. "%") and last (e.g. "1") also for parameters

Answer 5

Late answer, I know, but for me the following script is quite useful - and it answers the question too, hitting two flys with one flag ;-)
The following script expands SendTo in the file explorer's context menu:
#echo off
cls
if "%~dp1"=="" goto Install
REM change drive, then cd to path given and run shell there
%~d1
cd "%~dp1"
cmd /k
goto End
:Install
rem No arguments: Copies itself into SendTo folder
copy "%0" "%appdata%\Microsoft\Windows\SendTo\A - Open in CMD shell.cmd"
:End
If you run this script without any parameters by double-clicking on it, it will copy itself to the SendTo folder and renaming it to "A - Open in CMD shell.cmd". Afterwards it is available in the "SentTo" context menu.
Then, right-click on any file or folder in Windows explorer and select "SendTo > A - Open in CMD shell.cmd"
The script will change drive and path to the path containing the file or folder you have selected and open a command shell with that path - useful for Visual Studio Code, because then you can just type "code ." to run it in the context of your project.
How does it work?
%0 - full path of the batch script
%~d1 - the drive contained in the first argument (e.g. "C:")
%~dp1 - the path contained in the first argument
cmd /k - opens a command shell which stays open
Not used here, but %~n1 is the file name of the first argument.
I hope this is helpful for someone.