a=Array.new
a=[1,2,3,4,5]
puts a
then output will be 1,2,3,4,5, but I want to display a[1] to a[0]
(2,3,4,5,1).
Are there any built-in methods for display in the above order?
Thanks in advance.
I'm afraid there's no built in method to display it in the order you want - you would have to customize/implement your own toString (or similar) method/utility to achieve an arbitrary display of array elements
Related
I'm trying to write a cell formula which can essentially create a single playlist of songs.
Currently the songs are grouped by decade, but I'd like to be able to see a single list of everything that has been ticked.
I tried an array formula, but it only returned the first ticked song. Plus not sure how to make the array formula include the adjacent lists.
I tried a FILTER function, it works for one list of songs, but I don't know how to get it to append the other lists on the end.
Could I use a QUERY function? Not sure how though.
Many thanks!
try:
={"LIST"; FILTER({C:C; F:F}; {B:B; E:E}=TRUE)}
awesome question! You were super close in your filter example, one more filter in your array would've done it :)
Example Image:
Example Formula:
={"LIST"; FILTER(C:C, B:B=TRUE); FILTER(F:F, E:E=TRUE)}
I need to get all possible subdomains from the domain name, such as:
www.abc.xyz.com, and I have an array (www.abc.xyz.com,abc.xyz.com,xyz.com,com). Now I want to explode this array into:
www.abc.xyz.com
abc.xyz.com
xyz.com
but I do not want the last element: com
Note that the size of the array can vary.
How can I achieve this? Thanks in advance for all the help!!
Scala has a nice function for this. It is called as dropRight:
arr.dropRight(n)
This will drop all the last "n" elements. It also handles exceptional cases. E.g. if your array length < n then it will simply return empty array.
https://www.scala-lang.org/api/current/scala/Array.html
If I have an array with elements linked to xassets with names like "card1", "card2", etc up to "card100" is there a quicker way to write these elements in the array format without having to write out all 100?
Also if this has been answered already please let me know or link to it. About 2 days into trying to teach myself to program.
Not exactly sure what you're asking but you may want to look at loops - Swift Loops. You can add items to an array in a for loop from 1 to 100.
Is this what you are looking for ?
let cards = Array(1...100).map({"card\($0)"})
I have an array with several objects {id:x , name:y} retrieved from a Java Enum and I need to order them alphabetically, but one of the objects must mandatorily be in the bottom of the <select> comboBox, how could I achieve this result? I used ng-options with orderBy, but, I can't figure out how to put this particular object into the bottom.
The easiest way is to sort in the controller, when you get the data from the server:
find the "special" object that should go to the bottom and remove it from the array
sort the array, using $filter('orderBy')(array, 'name')
push the "special" object to the sorted array
expose the sorted array on the scope and use that array in ng-options
The question is quite simple but I can't find the answer.
I'm using j2me.
I have an integer array of 9 elements.
After all the computations now I want to print it or show it in a form.
It is something like Integer.toString(); for use with an array?
I know I can use a loop but I want to know if it's a faster way.
Use a loop but don't use the String + operator. Use StringBuffer.append().