i have a two tables namely; histories and users. i need to display data like:
id | Username | Lastest created Post | First created Post
the data of id and username is from users table and the last created and first created post data is from histories. i need to view all the users, their lastest created post and their first created post. please help me to make controller and view thanks
Try below.
<?php
$users = $this->User->find('all',array
(
'conditions' => array
(
//conditions goes here
),
'fields' => array
(
'User.id',
'User.username',
'History.Lastest created Post',
'History.First created Post'
)
));
?>
Assume that relation between 'User' and 'History' table is One-to-One and there's a 'user_id' column in History table, you may need to specify relation between them in History model, for example:
var $hasOne = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
Then, you need to perform joins to do this. For example, somewhere in your User model, try something like this:
class User extends AppModel {
....
function getAllUsersHistory{
$allHistories = $this->find('all', array(
'joins' => array(
'table' => 'history',
'alias' => 'HistoryJoin'
'type' => 'INNER',
'conditions' => array(
// your conditions, for example: 'History.user_id' => 'User.id'
)
),
'fields' => array(
'User.id',
'User.username',
'History.lastest_created_post',
'History.first_created_post'
)
));
return $allHistories;
}
.....
}
Related
I have three models in question: Customer, Company and User. Customer and User both belong to Company and Company has many Customers as following:
Customer:
var $belongsTo = array(
'Company' => array(
'className' => 'Company',
'foreignKey' => 'company_id',
'dependent' => false,
),
);
Company:
var $hasMany = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'company_id',
'dependent' => false
),
'Customer'=>array(
'className' => 'Customer',
'foreignKey' => 'company_id',
'dependent' => false
)
);
User:
var $belongsTo = array(
'Company' => array(
'className' => 'Company',
'foreignKey' => 'company_id',
'dependent' => false,
),
);
I have a problem when creating/editing Customer objects. Here is how to create form looks like:
echo $this->Form->input('Customer.customer_nr');
echo $this->Form->input('Customer.name');
echo $this->Form->input('Customer.phone');
echo $this->Form->input('Customer.email');
echo $this->Form->input('Customer.address');
echo $this->Form->input('Customer.post_nr');
echo $this->Form->input('Customer.city');
echo $this->Form->input('Customer.company_id', array('value' => $current_user['company_id'], 'type'=>'hidden'));
What I do in the end of the form is I take company_id from a currently logged in user and insert it as a Customer.company_id. It used to work without any problems before the new relations have been introduced. But now as I try to create/edit Customer, I receive the following SQL error:
Error: SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'name' in where clause is ambiguous
Any help is much much appreciated.
Here is the controller add function:
function add() {
if (!empty($this->data) ) {
$this->Customer->create();
if ($this->Customer->save($this->data)) {
$this->Session->setFlash(__('Customer was saved'), 'positive_notification');
$this->redirect(array('controller'=>'events', 'action' => 'dashboard'));
} else {
$this->Session->setFlash(__('Customer has been saved. Please, try again'), 'negative_notification');
}
}
}
The error is definately not being cause by redirect as it was fully tested.
the problem is somewhere else.
It's in fact related to a find() call.
Try to locate the exact code that trigger the error and post it in your question.
Probably you set some conditions like
'conditions' => array(
'name' => 'john'
)
but you better do something like
'conditions' => array(
'User.name' => 'john'
)
after you created the relationship between User and Company (it's just an example, maybe the two tabler involved are others) Cake started to join the two tables. So when you search for a particular name mysql doesn't know if you want user name or company name because you have name column in both tables.
If you look at the generated query (the one that gives you that error) you'll see the two tables joined. If you don't want that join you have to specify recursive => -1
'conditions' => array(
'name' => 'john'
),
'recursive' => -1
I am working on a cakephp 2.x .. I have two tables in my database both have the userid I am using bindModel.. my query is working fine ... I just have one problem .. I want to add the condition in where clause that
**where userid = $userid**
function getMessages($userid){
$this->bindModel(array(
'belongsTo' => array(
'Contact' => array(
'className' => 'Contact',
'foreignKey' => false,
'conditions' => array(
'Message.user_id = Contact.user_id',
'AND' =>
array(
array('OR' => array(
array('Message.mobileNo = Contact.mobileNo'),
array('Message.mobileNo = Contact.workNo'),
)),
)
),
'type' => 'LEFT',
)
)
), false);
return $this->find('all', array('conditions' => array(),
'fields' => array('Message.mobileNo'
),
'group' => 'Message.mobileNo',
'limit' => 6));
}
I am getting user id in parameter ... so I want to add the condition that get the following result where
message.userid and contact.userid = $userid ...
Just split the conditions in two lines like:
'conditions' => array(
'Contact.user_id' => $userid,
'Message.user_id = Contact.user_id',
[...]
)
But the approach that makes more sense is to leave the bind as is - after all the bind is generally between message users and contact users with the same id - and add the condition for the specific case in your find('all') with 'Message.user_id' => $userid.
how to get name of (UserTransactionType.name) with Transaction.who_pay_fee_1,2,3 fields.
'user_transaction_type_id' works well but how to get the rest of fields work :(
//Transaction Model
public $belongsTo = array(
'UserTransactionType' => array(
'className' => 'UserTransactionType',
'foreignKey' => 'user_transaction_type_id',
'conditions' => '',
'fields' => '',
'order' => ''
),
//UserTransactionType Model
public $hasMany = array(
'Transaction' => array(
'className' => 'Transaction',
'foreignKey' => 'user_transaction_type_id',
'dependent' => false,
))
This is the sample code for your controller:
$this->UserTransactionType->find('all',array(
'fields' => array('name'),
'contain' => array('Transaction')
)
);
If Models are associated you can specify in 'contain' which of them you want to get in the result.
If you want to have only some fields of related Model, you can determine them after 'Transaction' in 'contain' just like in the regular find() query:
'contain' => array('Transaction' => array('fields' => array('field_1',
'field_2') ))
But in your case, you don't need to specify fields, because by default you get all fields.
So no matter if you define or not fields "who_pay_fee_1,2,3" because if you use 'contain' by default you will get foreing_key - user_transaction_type_id.
I hope it's helpful
For people they like CakePhp :)
in Controller ->
get the list of 'UserTransactionType'
in View ->
after looping trough all the transactions; in Transaction Status column simply load the 'UserTransactionType'array and assign the number of array to $userTransactionTypes.
$userTransactionTypes[$transaction['Who_pay_fee_1']];
To be honest it was straight forward but needed a bit concentration :)
HI,
why not work "order" function?
$this->paginate = array(
'limit' => 5,
'order' => array(
'User.name' => 'desc'
),
'fields' => array('Post.id', 'Post.title', 'User.name AS aut_name'),
'joins' => array(
array(
'table' =>'users',
'alias' =>'User',
'type' =>'LEFT',
'conditions' => array(
'Post.user_id = User.user_id'
)
)
)
);
$posts = $this->paginate();
$this->set(compact('posts'));
DB structure:
posts:
id, title,body, created, updated, user_id
users:
user_id, name
Looking quickly your code... Does field user_id exist in User table?
'conditions' => array(
'Post.user_id = User.id'
)
Because you're specifying User.name As aut_name in your fields, you won't be able to order by User.name unless you also have User.name in your fields list. Alternatively use:
'order' => array(
'aut_name' => 'desc'
),
NOTE: This is for the initial query only, to sort by aut_name from the View you'll need to use a Virtual Field in the User model.
Also, as #Min said, are your conditions correct?
Adding a solution on the same problem:
This work for cakePHP 2.3.4
CakePHP Paginate conditions on Join Table
I'm trying to use on the fly associations to trim down the data I retrieve, but the model I'm using is associated to other models with a re-named field because I have 2 of the same models associated with it.
So, here's the model, say 'test', that has two 'user' fields, both related to the User model.
In the model:
var $belongsTo = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id'
),
'User_Watched' => array(
'className' => 'User',
'foreignKey' => 'user_id_watched'
)
);
When I retrieve data related to 'test', I want to only retrieve particular data linked to the 'User' and 'User_Watched' fields without any other nested information.
But when I do:
$this->User->unbindModel(array('hasMany' => array('something1', 'something2')), false);
then something1 and something2 data does not show up for the 'User' field of model 'test', but is still retrieved for the 'User_watched' field.
Can I not retrieve unwanted data for the 'User_watched' field?
Hope this makes sense... :)
KcYxA,
Containable behavior might help a lot in this case, as benjamin mentioned, your "find" queries would look like:
$this->User->find('first', array(
'conditions' => array('User.id' => $id),
'contain' => array('UserWatched')
));
In this case, you won't have to use unbindModel method. In this example, you'll get User and UserWatched data.
If you need only User data from "find", then tell Cake to "$this->User->contain();" so it won't go further then User model.
to use on the fly associations to trim
down the data I retrieve
Good idea.
'foreignKey' => 'user_id_watched'
should possibly be:
'foreignKey' => 'user_watched_id'.
Edit 1: At least this would make sense according to my current understanding. If user_id is a correct foreign key(FK), which cakephp uses to unbind the relations, but user_id_watched isn't, than your described behavior is explained.
Edit 2: The Containable behavior gives you another tool for controlling associated models.
Change $primaryKey in fly, run controller
Sample:
// Models
//....
class PreProductoDescripcion extends AppModel {
/**
* Primary key field
*
* #var string
*/
public $primaryKey = 'id_producto_descripcion';
//....
//....
}
class SenasaPedidosDetalles extends AppModel {
/**
* Display field
*
* #var string
*/
public $displayField = 'cod_tango';
public $belongsTo = array(
'SenasaPedidos' => array(
'className' => 'SenasaPedidos',
'foreignKey' => 'senasa_pedidos_id',
'conditions' => '',
'fields' => '',
'order' => ''
),
'PreProductoDescripcion' => array(
'className' => 'PreProductoDescripcion',
'foreignKey' => 'cod_tango',
//'conditions' => array('SenasaPedidosDetalles.cod_tango' => 'PreProductoDescripcion.codigo'),
'fields' => '',
'order' => ''
)
);
//....
#
// Controller Fly
//...
$this->SenasaPedidos->Behaviors->load('Containable');
$this->SenasaPedidos->SenasaPedidosDetalles->PreProductoDescripcion->primaryKey = 'codigo';
$datos = $this->SenasaPedidos->find(
'first', array(
'fields' => array( 'SenasaPedidos.*' ),
'conditions' => array( 'SenasaPedidos.id' => $id ),
'contain' => array(
'Usuarios' => array(
'fields' => array( 'Usuarios.apellido_nombre' )
),
'Clientes' => array(
'fields' => array( 'Clientes.razon_social' )
),
'Provincias' => array(
'fields' => array( 'Provincias.nombre' )
),
'Transportes' => array(
'fields' => array( 'Transportes.razon_social' )
),
'SenasaPedidosDetalles' => array(
'fields' => array( 'SenasaPedidosDetalles.*' ),
'PreProductoDescripcion' => array(
'fields' => array(
'PreProductoDescripcion.id_producto_descripcion',
'PreProductoDescripcion.descripcion'
)
)
),
)
));
//...