scanf and printf just skips after 1st time - c

Question

what is the problem here? scanf doesnt seems to working in while loop. i was trying to find out vowel & consonent until user wants.
Here's the code:
#include <stdio.h>
main()
{
char x,c;
do
{
printf("enter\n");
scanf("%c",&x);
if(x=='a'||x=='e'||x=='i'||x=='o'||x=='u')
printf("vowel\n");
else
printf("consonent\n");
printf("do u want to continue ?(y/n)\n");
scanf("%d",&c);
if(c=='n')
printf("thnks\n");
} while(c=='y');
return 0;
}

Answer 1

You are trying to read a character using %d which is wrong. Use %c instead.

Answer 2

Change code to scanf("%c",&c) your original code is getting the y/n entries as digits not characters
Edit:
Probably you are getting the carage return instead of the character try using getc or fgets instead and get the first character.

Answer 3

I think the problem might be here:
scanf("%d",&c);
It should be:
scanf("%c",&c);

Answer 4

Here is the Correct code:
#include <stdio.h>
int main()
{
char x,c;
do
{
printf("enter\n");
scanf("%c",&x);
getchar(); //to remove the \n from the buffer
if(x=='a'||x=='e'||x=='i'||x=='o'||x=='u')
printf("vowel\n");
else
printf("consonent\n");
printf("do u want to continue ?(y/n)\n");
scanf("%c",&c); //Here you were using %d instead of %c
getchar(); //to remove the \n from the buffer
if(c=='n')
printf("thnks\n");
}while(c=='y');
return 0;
}

Answer 5

Both scanfs should be changed like this:
scanf(" %c",&x);
...
scanf(" %c",&c);
Note the space before the %, it's important: it consumes leading whitespace, which includes the endline characters left over in stdin after processing the input.

Answer 6

Please try with this code to run the loop multiple times.
EDIT: Different solution without fflush(stdin). Please define a string of 8 characters as
char str[8];
and modify the code in the loop as
fgets(str, 8, stdin); // To read the newline character
printf("do u want to continue ?(y/n)\n");
scanf("%c",&c);
fgets(str, 8, stdin); // To read the newline character