I am currently working on a project that uses pthreads. The project so far starts a user specified number of threads and does some work on each thread then closes. Each thread is stored in a dynamically allocated array of memory. I do this using:
threads = malloc(number_of_threads * sizeof(pthread_t));
Then I create each thread in a for-loop:
pthread_create(&(threads[i]), NULL, client_pipe_run, (void *) ¶m[i]);
What I need to do next is store the return values of these threads. My understanding is that I need to pass pthread_join the address of a pointer I want to have the return value stored in. This is where I get a little confused. I'm fine with pointers up to this point then my brain kind of has a melt down haha. This is my idea on how to acheive this but I'm not confident that this is correct:
int *return_vals = malloc(sizeof(int) * number_of_threads);
for(i = 0; i< number_of_threads; i++)
{
pthread_join(&(threads[i]),(void *) &(return_vals[i]));
}
Then to get the return value I would do something similar to:
int val = *(return_val[0]);
Any help on the this would be greatly appreciated!
Note that you are allocating memory for your threads like this:
threads = malloc(number_of_thread * sizeof(pthread_t));
but for return values you do:
int *return_vals = malloc(sizeof(int *));
i.e. number of threads should be taken in count here too:
int *return_vals = malloc(number_of_thread * sizeof(int));
Then you can either cast the return value to void*:
void *foo(void *arg) {
int i = 7;
return (void*)i;
}
int main(void) {
int i = 0;
int thread_count = 3;
pthread_t* threads = malloc(thread_count * sizeof(pthread_t));
int *return_vals = malloc(thread_count * sizeof(int));
// create threads:
for(i = 0; i < thread_count; ++i)
pthread_create(&threads[i], NULL, &foo, NULL);
// wait untill they finish their work:
for(i = 0; i < thread_count; ++i)
pthread_join(threads[i], (void**) &return_vals[i]);
// print results:
for(i = 0; i < thread_count; ++i)
printf("Thread %d returned: %d\n", i, return_vals[i]);
// clean up:
free(return_vals);
free(threads);
return 0;
}
or you can make sure that your code doesn't make any presumptions about size of the type you're returning being less or equal to sizeof(void*) and allocate the memory for the return value dynamically within the thread:
void *foo(void *arg) {
int* ret = malloc(sizeof(int));
*ret = 7;
return ret;
}
int main(void) {
int i = 0;
int thread_count = 3;
pthread_t* threads = malloc(thread_count * sizeof(pthread_t));
// array of pointers to return values of type int:
int **return_vals = calloc(thread_count, sizeof(int*));
// create threads:
for(i = 0; i < thread_count; ++i)
pthread_create(&threads[i], NULL, &foo, NULL);
// wait untill they finish their work:
for(i = 0; i < thread_count; ++i)
pthread_join(threads[i], (void**) &return_vals[i]);
// print results:
for(i = 0; i < thread_count; ++i)
printf("Thread %d returned: %d\n", i, *return_vals[i]);
// clean up:
for(i = 0; i < thread_count; ++i)
free(return_vals[i]);
free(return_vals);
free(threads);
return 0;
}
But in case you chose the latter one, be careful about possible memory leaks you might end up with.
Related
It's been a few hours and i can't seem to understand the issue. Build this program to count from 1 - 10. The goal of this program is to use multithreading and dynamically split the array depending on how many threads it requested. Problem is the first 2 threads are being skipped and the last thread is doing most of th e process. I suspect it's the for loop that creates the threads.
#include <stdlib.h>
#include <stdio.h>
#include <pthread.h>
typedef struct
{
int *array;
int batch;
int start;
int end;
} Parameter;
void *method(void *p)
{
Parameter *param = (Parameter *)p;
for (int i = param->start; i < param->end; i++)
{
printf("Start:%d\tEnd:%d\tIndex:%d\tValue:%d\n", param->start, param->end, i,param->array[i]);
}
}
int main(int argc, char **argv)
{
// Getting the user input
int array_length = atoi(argv[1]);
int batches = atoi(argv[2]);
printf("User specified Array:%d\tBatch:%d\n", array_length, batches);
// Creating an array
int *array = (int *)calloc(array_length, sizeof(int));
// Fill it up with some data
for (int i = 0; i < array_length; i++)
{
array[i] = i;
}
// Determine the Batches
int batch_size = array_length / batches;
int remainder = array_length % batches;
printf("%d\n", batch_size);
printf("%d\n", remainder);
int start = 0;
int end = 0;
int index =0;
// List of parameters
Parameter *param = (Parameter *)calloc(batches, sizeof(Parameter));
pthread_t *threads = (pthread_t *)calloc(batches, sizeof(pthread_t));
// Loop through each batch.
for (int i = 0; i < batches; i++)
{
printf("\n\nBatch number -> %d\n", i);
end = start + batch_size;
if (remainder > 0)
{
remainder --;
end ++;
}
// Fill the parameters
param[i].array = array;
param[i].end = end;
param[i].start = start;
param[i].batch = i;
// Call the thread.
pthread_create(threads + index, NULL, method, (void *)¶m[i]);
index++;
start = end;
}
for (int i = 0; i < batches; i++)
{
pthread_join(threads[i], NULL);
}
free(param);
free(threads);
free(array);
return 0;
}
Been playing with the index of the for loop(line 57) as i'm certain it's the cause of the issue. been getting some results but the main problem still persisted.
Code Works as intended. I'm a dumbas who didn't put the printf in the void function. like so:
void *method(void *p) {
Parameter *param = (Parameter *)p;
printf("\n\nBatch number -> %d\n", param->batch); //<-- moved from main method
for (int i = param->start; i < param->end; i++)
{
printf("Start:%d\tEnd:%d\tIndex:%d\tValue:%d\n", param->start, param->end, i,param->array[i]);
} }
Thanks for pointing it out that the program works
I am trying to sum up 1000 elements integer array(where each element is 1) with pthread library by splitting the array in to segments of size 10. So effectively, 100 threads are being used to do that. The results of this parallel operation is as expected (1000). But interestingly, the sequential sum which I calculated before creating the threads is being set to zero after my first call to pthread_join(). Not sure if I am missing something here. Can someone spot the bug here?
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#define SEGMENT_SIZE 10
#define NUM_THREADS 100
int *array = NULL;
void* segment_sum(void *args)
{
int index = (int)args;
int sum = 0;
for (int i = index * SEGMENT_SIZE; i < (index + 1) * SEGMENT_SIZE; i++) {
sum += array[i];
}
return (void *)sum;
}
int main()
{
pthread_t thread[NUM_THREADS];
int res = 0;
int seq_res = 0;
int par_res = 0;
array = calloc(1, sizeof(int) * NUM_THREADS * SEGMENT_SIZE);
for (int i = 0; i < NUM_THREADS * SEGMENT_SIZE; i++) {
array[i] = 1;
seq_res += 1;
}
for (int i = 0; i < NUM_THREADS; i++) {
res = pthread_create(&thread[i], NULL, segment_sum, (void *)i);
if (res != 0) {
printf("\nError creating new thread");
}
}
printf("\nindex = %d", seq_res); // the sequential sum here is 1000
for (int i = 0; i < NUM_THREADS; i++) {
int sum = 0;
res = pthread_join(thread[i], (void **)&sum);
if (res != 0) {
printf("\nError creating new thread");
}
printf("\nindex = %d", seq_res); // Here it is becoming zero!!!
par_res += sum;
}
printf("\nmultithreaded sum: %d single threaded sum: %d\n", par_res, seq_res);
}
When you compile your program, try as much as possible to eliminate
the warnings as they often point out non portable behaviors or hidden
errors. Here the compilation points out the following:
pte.c: In function 'segment_sum':
pte.c:11:21: warning: cast from pointer to integer of different size [-Wpointer-to-int-cast]
11 | int index = (int)args;
| ^
pte.c:18:16: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
18 | return (void *)sum;
| ^
pte.c: In function 'main':
pte.c:36:69: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
36 | res = pthread_create(&thread[i], NULL, segment_sum, (void *)i);
| ^
The parameter passed to the threads is a cast of a pointer into an "int". It is
advised to pass the address of an "int". Hence, you can define a per-thread
context:
struct thd_ctx {
pthread_t thread;
int index;
int sum;
};
pthread_join() is passed the address of a pointer which will get the address
of the memory location into which the thread stored its result. The thread must
return the address of this memory location, not the value stored into it.
Moreover, the thread should not return the address of an automatic variable
(i.e. in its stack) as it is unspecified. The result must be the address
of a global variable (or "something" visible from the joining thread) returned either directly or through pthread_exit(). In this enhancement of the program, we use the address of the "sum" field in the thread's context:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <errno.h>
#define SEGMENT_SIZE 10
#define NUM_THREADS 100
int *array = NULL;
struct thd_ctx {
pthread_t thread;
int index;
int sum;
};
void *segment_sum(void *args)
{
int i;
struct thd_ctx *ctx = (struct thd_ctx *)args;
ctx->sum = 0;
for (i = ctx->index * SEGMENT_SIZE; i < (ctx->index + 1) * SEGMENT_SIZE; i++) {
ctx->sum += array[i];
}
return (void *)&(ctx->sum);
}
int main(void)
{
struct thd_ctx thd_ctx[NUM_THREADS];
int res = 0;
int seq_res = 0;
int par_res = 0;
int i;
array = calloc(1, sizeof(int) * NUM_THREADS * SEGMENT_SIZE);
if (!array) {
fprintf(stderr, "calloc(): error %d\n", errno);
return 1;
}
for (i = 0; i < NUM_THREADS * SEGMENT_SIZE; i++) {
array[i] = 1;
seq_res += 1;
}
for (i = 0; i < NUM_THREADS; i++) {
thd_ctx[i].index = i;
res = pthread_create(&(thd_ctx[i].thread), NULL, segment_sum, (void *)&(thd_ctx[i]));
if (res != 0) {
fprintf(stderr, "Error %d creating new thread#%d\n", res, i);
free(array);
return 1;
}
}
printf("Index = %d\n", seq_res); // the sequential sum here is 1000
for (i = 0; i < NUM_THREADS; i++) {
int *sum = 0;
res = pthread_join(thd_ctx[i].thread, (void **)&(sum));
if (res != 0) {
printf("Error %d joining thread#%d", res, i);
free(array);
return 1;
}
par_res += *sum;
printf("sum = %d\n", par_res);
}
printf("\nMultithreaded sum: %d single threaded sum: %d\n", par_res, seq_res);
free(array);
return 0;
}
I am trying to multiply two matrices using a different thread for each member of the resultant matrix. I have this code:
struct data{
int p;
int linie[20];
int coloana[20];
};
void *func(void *args){
struct data *st = (struct data *) args;
int c = 0;
for(int k = 0; k < st->p; k++){
c += st->linie[k] * st->coloana[k];
}
char *rez = (char*) malloc(5);
sprintf(rez, "%d", c);
return rez;
}
int main(int argc, char *argv[]){
int n = 2;
int m = 2;
int A[2][2] = {{1, 2},
{4, 5}};
int B[2][2] = {{7, 3},
{7, 5}};
int C[n][m];
char *res[n * m];
char *rez[n * m];
pthread_t threads[n * m];
int count = 0;
for(int i = 0; i < n; i++){
for(int j = 0; j < m; j++){
struct data st;
st.p = 2;
for(int x = 0; x < st.p; x++){
st.linie[x] = A[i][x];
st.coloana[x] = B[x][j];
}
pthread_create(&threads[count], NULL, func, &st);
count++;
}
}
for(int i = 0; i < n * m; i++){
pthread_join(threads[i], (void**) &rez[i]);
printf("%d ", atoi(rez[i]));
}
return 0;
}
But the correct result is never put into rez[i]. For example I get output "63 37 37 37".
The code works perfectly if I don't choose to wait for every thread to finish, i.e. I put that pthread_join right after pthread_create in the nested for loop. What should I do?
Thanks for reading!
Your first threading problem is here:
for(int i = 0; i < n; i++){
for(int j = 0; j < m; j++){
struct data st;
st.p = 2;
for(int x = 0; x < st.p; x++){
st.linie[x] = A[i][x];
st.coloana[x] = B[x][j];
}
pthread_create(&threads[count], NULL, func, &st);
count++;
}
}
All the threads get passed a pointer to the same variable, &st, which goes out of scope after each call to pthread_create(). You need to ensure that each thread gets its own variable, and that the variable lasts until the thread exits.
To fix this, for example, you could try:
struct data st[n * m];
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
st[count].p = 2;
for (int x = 0; x < st[count].p; x++)
{
st[count].linie[x] = A[i][x];
st[count].coloana[x] = B[x][j];
}
int rc = pthread_create(&threads[count], NULL, func, &st[count]);
if (rc != 0)
…report pthread creation error…
count++;
}
}
This gives each thread its own struct data to work on, and the structure outlasts the pthread_join() loop.
I'm not completely that it is a good scheme to make one copy of the relevant parts of the two arrays for each thread. It's not too painful at size 2x2, but at 20x20, it begins to be painful. The threads should be told which row and column to process, and should be given pointers to the source matrices, and so on. As long as no thread modifies the source matrices, there isn't a problem reading the data.
Updated answer which replaces the previous invalid code related to pthread_join() (as noted by oftigus in a comment) with this working code. There's a reason I normally test before I post!
On the whole, casts like (void **) should be avoided in the pthread_join() loop. One correct working way to handle this is:
for (int i = 0; i < n * m; i++)
{
void *vp;
int rc = pthread_join(threads[i], &vp);
if (rc == 0 && vp != NULL)
{
rez[i] = vp;
printf("(%s) %d ", rez[i], atoi(rez[i]));
free(rez[i]);
}
}
putchar('\n');
This passes a pointer to a void * variable to pthread_join(). If it finds the information for the requested thread, then pthread_join() makes that void * variable hold the value returned by the thread function. This can then be used as shown — note the error handling (though I note that the example in the POSIX specification for pthread_join()ignores the return value from pthread_join() with a (void) cast on the result).
I don't see where you use res or C.
The result I get is:
(21) 21 (13) 13 (63) 63 (37) 37
where the value in parentheses is a string and the value outside is converted by atoi(). That looks like the correct answer for multiplying A by B (in that order).
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
struct data
{
int p;
int linie[20];
int coloana[20];
};
static void *func(void *args)
{
struct data *st = (struct data *)args;
int c = 0;
for (int k = 0; k < st->p; k++)
{
c += st->linie[k] * st->coloana[k];
}
char *rez = (char *)malloc(5);
sprintf(rez, "%d", c);
return rez;
}
int main(void)
{
int n = 2;
int m = 2;
int A[2][2] = {{1, 2}, {4, 5}};
int B[2][2] = {{7, 3}, {7, 5}};
char *rez[n * m];
pthread_t threads[n * m];
int count = 0;
struct data st[n * m];
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
st[count].p = 2;
for (int x = 0; x < st[count].p; x++)
{
st[count].linie[x] = A[i][x];
st[count].coloana[x] = B[x][j];
}
int rc = pthread_create(&threads[count], NULL, func, &st[count]);
if (rc != 0)
{
fprintf(stderr, "Failed to create thread %d for cell C[%d][%d]\n", count, i, j);
exit(1);
}
count++;
}
}
for (int i = 0; i < n * m; i++)
{
void *vp;
int rc = pthread_join(threads[i], &vp);
if (rc == 0 && vp != NULL)
{
rez[i] = vp;
printf("(%s) %d ", rez[i], atoi(rez[i]));
free(rez[i]);
}
}
putchar('\n');
return 0;
}
I want to read as input a table A and B from a user , and make an inner product space from them (a1b1+a2b2+……+anbn) and save it in a local_sum and then share it to an total_sum variable. I am doing the bellow code , but there is a segment fault. For some reason table A & B can't pass to function MUL. Any help would be great, thank you!
#include <stdio.h>
#include <pthread.h>
#include <stdlib.h>
#define N 2
int p;
int A[N],B[N];
int local_sum;
void *mul(void *arg)
{
int lines, start, end, i, j;
int id = *(int*)arg;
lines = N / p;
start = id * lines;
end = start + lines;
for (i = start; i < end; i++)
local_sum = A[i] * B[i] + local_sum;
return NULL;
}
int main (int argc, char *argv[])
{
int i;
pthread_t *tid;
if (argc != 2)
{
printf("Provide number of threads.\n");
exit(1);
}
p = atoi(argv[1]);
tid = (pthread_t *)malloc(p * sizeof(pthread_t));
if (tid == NULL)
{
printf("Could not allocate memory.\n");
exit(1);
}
printf("Give Table A\n");
for (int i = 0; i < N; i++)
{
scanf("%d", &A[i]);
}
printf("Give Table B\n");
for (int i = 0; i < N; i++)
{
scanf("%d", &B[i]);
}
for (i = 0; i < p; i++)
{
int *a;
a = malloc(sizeof(int));
*a = 0;
pthread_create(&tid[i], NULL, mul, a);
}
for (i = 0; i < p; i++)
pthread_join(tid[i], NULL);
printf("%d", local_sum);
return 0;
}
Let's see:
You want to have p threads, working on the vectors A and B.
You must be aware of that threads share the same memory, and might be interrupted at any time.
You've got p threads, all trying to write to one shared variable local_sum. This leads to unpredictable results since one thread overwrites the value another thread has written there before.
You can bypass this problem by ensuring exclusive access of one single thread to this variable by using a mutex or the like, or you could have one variable per thread, have each thread produce an intermediate result and after joining all threads, collapse all your intermediate results into the final one.
To do this, your main should look something like (assuming your compiler supports a recent C standard):
#include <stdio.h>
#include <pthread.h>
#include <stdlib.h>
#define N 2
/* these are variables shared amongst all threads */
int p;
int A[N], B[N];
/* array with one slot per thread to receive the partial result of each thread */
int* partial_sum;
/* prototype of thread function, just to be independent of the place mul will be placed in the source file... */
void *mul(void *arg);
int main (int argc, char** argv)
{
pthread_t* tid;
p = atoi(argv[1]);
const size_t n_by_p = N/p;
if(n_by_p * p != N)
{
fprintf(stderr, "Number of threads must be an integral factor of N\n");
exit(EXIT_FAILURE) ;
}
tid = calloc(p, sizeof(pthread_t));
partial_sum = calloc(p, sizeof(int)) ;
printf("Give Table A\n");
for(size_t i = 0; i < N; ++i)
{
scanf("%d",&A[i]);
}
printf("Give Table B\n");
for(size_t i = 0; i < N; ++i)
{
scanf("%d",&B[i]);
}
for (size_t i =0; i < p; ++i)
{
/* clumsy way to pass a thread it's slot number, but works as a starter... */
int *a;
a = malloc(sizeof(int));
*a = i;
pthread_create(&tid[i], 0, mul, a);
}
for (size_t i = 0; i < p; ++i)
{
pthread_join(tid[i], 0);
}
free(tid);
tid = 0;
int total_sum = 0;
for (size_t i = 0; i < p; ++i)
{
total_sum += partial_sum[i] ;
}
free(partial_sum);
partial_sum = 0;
printf("%d",total_sum);
return EXIT_SUCCESS;
}
Your threaded method mul should now write to its particular partial_sum slot only :
void *mul(void *arg)
{
int slot_num = *(int*)arg;
free(arg);
arg = 0;
const size_t lines = N/p;
const size_t start = slot_num * lines;
const size_t end = start + lines;
partial_sum[slot_num] = 0;
for(size_t i = start; i < end; ++i)
{
partial_sum[slot_num] += A[i]*B[i];
}
return 0;
}
Beware: This code runs smoothly, only if N is some integral multiple of p.
If this condition is not met, due to truncation in N/p, not all elements of the vectors will be processed.
However, fixing these cases is not the core of this question IMHO.
I spared all kinds of error-checking, which you should add, should this code become part of some operational setup...
if (tid=NULL)
-->
if (tid==NULL)
and
for (i=start;i<end;i++)
I suppose we need
for (i=0;i<end-start;i++)
I'm pretty new to threads and would like some insight. I'm trying to get the percentage each thread has completed for its calculation. Each thread will report its percentage to a different element of the same array. I have this working with pthread_join immediately after pthread_create and a separate thread for reading all the values of the array and printing the percentage but when I have all threads running after each other without waiting for the previous one to finish I get some weird behavior. This is how I'm accessing the shared (global) array.
//global
int *currentProgress;
//main
currentProgress = malloc(sizeof(int)*threads);
for(i=0; i<threads; i++)
currentProgress[i] = 0;
//child threads
currentProgress[myId] = (int)percent; //myId is unique
//progress thread
for(i=0; i<threads; i++)
progressTotal += currentProgress[i];
progressTotal /= threads;
printf("Percent: %d", progressTotal);
This is essentially the code I think is not being used correctly for multi-threads. When I print out the state of the shared array, I notice that as soon as another thread starts accessing the array (different element though), the previous element immediately goes to some random number... -2147483648 and when the latter element finishes the prior element continues like normal. Should I be using semaphores for this? I thought I could access different elements of an array at the same time and I thought reading them wasn't an issue.
This is the entire code:
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
#include <stdint.h>
#include <pthread.h>
#include <string.h>
#define STDIN 0
int counter = 0;
uint64_t *factors;
void *getFactors(void *arg);
void *deleteThreads(void *arg);
void *displayProgressThread(void *arg);
int *currentProgress;
struct data
{
uint64_t num;
uint64_t incrS;
uint64_t incrF;
int threads;
int member;
} *args;
int main(int argc, char *argv[])
{
if(argc < 3) {printf("not enough arguments"); exit(1);}
int i;
int threads = atoi(argv[2]);
pthread_t thread_id[threads];
pthread_t dThread;
currentProgress = malloc(sizeof(int)*threads);
for(i=0; i<threads; i++)
currentProgress[i] = 0;
args = (struct data*)malloc(sizeof(struct data));
args->num = atoll(argv[1]);
args->threads = threads;
uint64_t increment = (uint64_t)sqrt((uint64_t)args->num)/threads;
factors = (uint64_t*)malloc(sizeof(uint64_t)*increment*threads);
pthread_create(&dThread, NULL, displayProgressThread, (void*)args);
//for the id of each thread
args->member = 0;
for(i=0; i<threads; i++)
{
args->incrS = (i)*increment +1;
args->incrF = (i+1)*increment +1;
pthread_create(&thread_id[i], NULL, getFactors, (void*)args);
usleep(5);
}
for(i=0; i<threads; i++)
{
pthread_join(thread_id[i], NULL);
}
sleep(1);
printf("done\n");
for (i=0; i<counter; i++)
printf("\n%llu : %llu", factors[++i], factors[i]);
return 0;
}
void *getFactors(void *arg)
{
uint64_t count;
int myId;
int tempCounter = 0, i;
struct data *temp = (struct data *) arg;
uint64_t number = temp->num;
float total = temp->incrF - temp->incrS, percent;
myId = temp->member++;
pthread_setcancelstate(PTHREAD_CANCEL_ENABLE, NULL);
pthread_setcanceltype(PTHREAD_CANCEL_ASYNCHRONOUS, NULL);
for(count=temp->incrS; count<=temp->incrF; count++)
{
percent = (float)(count-temp->incrS)/total*100;
currentProgress[myId] = (int)percent;
if (number%count == 0)
{
factors[counter++] = count;
factors[counter++] = number/count;
}
usleep(1);
}
usleep(1);
pthread_exit(NULL);
}
void *displayProgressThread(void *arg)
{
struct data *temp = (struct data *) arg;
int toDelete = 0;
while(1)
{
int i;
int progressTotal = 0;
char *percent = malloc(sizeof(char)*20);
for(i=0; i<toDelete; i++)
printf("\b \b");
for(i=0; i<temp->threads; i++){
progressTotal += currentProgress[i];
}
progressTotal /= temp->threads;
printf("|");
for(i=0; i<50; i++)
if(i<progressTotal/2)
printf("#");
else
printf("_");
printf("| ");
sprintf(percent, "Percent: %d", progressTotal);
printf("%s", percent);
toDelete = 53 + strlen(percent);
usleep(1000);
fflush(stdout);
if(progressTotal >= 100)
pthread_exit(NULL);
}
}
There are some non synchronized pieces of code that are accessed by the threads which cause this problem.
One first place to be synchronized is:
myId = temp->member++;
But more importantly is that, the main thread is doing:
args->incrS = (i)*increment +1;
args->incrF = (i+1)*increment +1;
while at the same time in the threads:
for(count=temp->incrS; count<= temp->incrF; count++)
{
percent = (float)(count-temp->incrS)/total*100;
currentProgress[myId] = (int)percent;
if (number%count == 0)
{
factors[counter++] = count;
factors[counter++] = number/count;
}
usleep(1);
}
The unsynchronized accesses mentioned above affect the calculation of percent value which results in such abnormal happenings. You have to do synchronization in all these places in order to get the kind of behavior you would expect.