Display image from resources by binding -WPF - wpf

Question

I have an icon on resources that it key is: xxx
I want to bind it to an image in xaml..
1:
<Image Source="{x:Static p:Resources.xxx}"></Image>
2:
<Image>
<Image.Source>
<BitmapImage UriSource="{Binding x:Static p:Resources.xxx}"/>
</Image.Source>
</Image>
3:
<Image Source=" {Binding x:Static p:Resources.xxx,Converter={StaticResource IconToBitmap_Converter}}"></Image>
4:
<Image>
<Image.Source>
<BitmapImage UriSource="{Binding x:Static p:Resources.xxx,Converter={StaticResource IconToBitmap_Converter}}"/>
</Image.Source>
</Image>
The above ways does not work, how am I supposed to do that?

Answer 1

First you must add your Image into a Resource File in the Solution Explorer. Next you must set the Build Action of your Image to Resource and then you can use it in the XAML Code like this:
<UserControl>
<UserControl.Resources>
<ResourceDictionary>
<BitmapImage x:Key="name" UriSource="Resources/yourimage.bmp" />
</ResourceDictionary>
</UserControl.Resources>
<Grid>
<Image Source="{StaticResource name}"/>
</Grid>
</UserControl>

Answer 2

First:
Add resources rsx
then:
add images as images to the resource file and set the image build action to Resource.
Now you can access the images like this:
<Image Source="pack://application:,,,/Resources/image.png"/>

Answer 3

You may implement your own Markup extension and use it as follows:
<Image Source="{ex:ImageSource {x:Static p:Resources.xxx}}"></Image>
The MarkupExtension ImageSource may look like this:
public class ImageSource : MarkupExtension
{
private readonly object source;
public ImageSource(object source) => this.source = source;
public override object ProvideValue(IServiceProvider serviceProvider)
{
Binding sourceBinding = source is Binding binding ? binding : new Binding() { Source = source };
MultiBinding converterBinding = new MultiBinding() { Converter = new SourceConverter() };
converterBinding.Bindings.Add(sourceBinding);
return converterBinding.ProvideValue(serviceProvider);
}
private class SourceConverter : IMultiValueConverter
{
public object Convert(object[] value, Type targetType, object parameter, CultureInfo culture) => BitmapToSource(value[0] as Bitmap);
public object[] ConvertBack(object value, Type[] targetType, object parameter, CultureInfo culture) => throw new NotSupportedException();
private BitmapImage BitmapToSource(Bitmap bitmap)
{
using (MemoryStream memory = new MemoryStream())
{
bitmap.Save(memory, System.Drawing.Imaging.ImageFormat.Bmp);
memory.Position = 0;
BitmapImage bitmapimage = new BitmapImage();
bitmapimage.BeginInit();
bitmapimage.StreamSource = memory;
bitmapimage.CacheOption = BitmapCacheOption.OnLoad;
bitmapimage.EndInit();
return bitmapimage;
}
}
}
}