using fscanf to read in items - c

There is a file a.txt looks like this:
1 abc
2
3 jkl
I want to read each line of this file as an int and a string, like this:
fp = fopen("a.txt", "r");
while (1) {
int num;
char str[10];
int ret =fscanf(fp, "%d%s", &num, str);
if (EOF == ret)
break;
else if (2 != ret)
continue;
// do something with num and str
}
But there is a problem, if a line in a.txt contains just a num, no string (just like line 2), then the above code will be stuck in that line.
So any way to jump to the next line?

Do it in two steps:
Read a full line using fgets(). This assumes you can put a simple static limit on how long lines you want to support, but that's very often the case.
Use sscanf() to inspect and parse the line.
This works around the problem you ran into, and is generally the better approach for problems like these.
UPDATE: Trying to respond to your comment. The way I see it, the easiest approach is to always read the full line (as above), then parse out the two fields you consider it to consist of: the number and the string.
If you do this with sscanf(), you can use the return value to figure out how it went, like you tried with fscanf() in your code:
const int num_fields = sscanf(line, "%d %s", &num, str);
if( num_fields == 1 )
; /* we got only the number */
else if( num_fields == 2 )
; /* we got both the number and the string */
else
; /* failed to get either */
Not sure when you wouldn't "need" the string; it's either there or it isn't.

If the first character of the string is \r or\n this will be an empty string. You can use the comparison. fscanf() is not suitable if words contain spaces(or empty lines) in them .In that case better to use fgets()

How to solve "using fscanf":
After the int, look for spaces (don't save), then look for char that are not '\n'.
int num;
char str[10];
#define ScanInt "%d"
#define ScanSpacesDontSave "%*[ ]"
#define ScanUntilEOL "%9[^\n]"
int ret = fscanf(fp, ScanInt ScanSpacesDontSave ScanUntilEOL, &num, str);
if (EOF == ret) break;
else if (1 == ret) HandleNum(num);
else if (2 == ret) HandleNumStr(num, str);
else HadleMissingNum();
ret will be 2 if something was scanned into str, else ret will typically be 1. The trick to the above is not to scan in a '\n' after the int. Thus code can not use "%s" nor " " after the "%d" which both consume all (leading) white-space. The next fscanf() call will consume the '\n' as part of leading white-space consumption via "%d".
Minor note: reading the line with fgets() then parsing the buffer is usually a better approach, but coding goals may preclude that.

Related

Read tab separated content line by line with last column empty string

I have a file format like this
1.9969199999999998 2.4613199999999997 130.81278270000001 AA
2.4613199999999997 2.5541999999999998 138.59131554109211 BB
2.5541999999999998 2.9953799999999995 146.83238401449094 CC
...........................
I have to read first three columns as float and the last column as char array in C. All the columns are tab separated and the there is an new line character at the end of each line. Everything works fine with fscanf(fp1, "%f\t%f\t%f\t%s\n", ...) till I have a some text at the end of each line (the char string part).
There are cases where instead of AA/BB/CC, I have an empty string in the file. How to handle that case. I have tried fscanf(fp1, "%f\t%f\t%f\t%s[^\n]\n", ...) and many other things, but I am unable to figure out the right way. Can you please help me out here?
Using float rather than double will throw away about half the digits shown. You get 6-7 decimal digits with float; you get 15+ digits with double.
As to your main question: use fgets() (or POSIX
getline()) to read lines and then sscanf() to parse the line that is read. This will avoid confusion. When the input is line-based but not regular enough, don't use fscanf() and family to read the data — the file-reading scanf() functions don't care about newlines, even when you do.
Note that sscanf() will return either 3 or 4, indicating whether there was a string at the end of a line or not (or EOF, 0, 1 or 2 if it is given an empty string, or a string which doesn't start with a number, or a string which only contains one or two numbers). Always test the return value from scanf() and friends — but do so carefully. Look for the number of values that you expect (3 or 4 in this example), rather than 'not EOF'.
This leads to roughly:
#include <stdio.h>
int main(void)
{
double d[3];
char text[20];
char line[4096];
while (fgets(line, sizeof(line), stdin) != 0)
{
int rc = sscanf(line, "%lf %lf %lf %19s", &d[0], &d[1], &d[2], &text[0]);
if (rc == 4)
printf("%13.6f %13.6f %13.6f [%s]\n", d[0], d[1], d[2], text);
else if (rc == 3)
printf("%13.6f %13.6f %13.6f -NA-\n", d[0], d[1], d[2]);
else
printf("Format error: return code %d\n", rc);
}
return 0;
}
If given this file as standard input:
1.9969199999999998 2.4613199999999997 130.81278270000001 AA
2.4613199999999997 2.5541999999999998 138.59131554109211 BB
2.5541999999999998 2.9953799999999995 146.83238401449094 CC
19.20212223242525 29.3031323334353637 3940.41424344454647
19.20212223242525 29.3031323334353637 3940.41424344454647 PolyVinyl-PolySaccharide
the output is:
1.996920 2.461320 130.812783 [AA]
2.461320 2.554200 138.591316 [BB]
2.554200 2.995380 146.832384 [CC]
19.202122 29.303132 3940.414243 -NA-
19.202122 29.303132 3940.414243 [PolyVinyl-PolySacch]
You can tweak the output format to suit yourself. Note that the %19s avoids buffer overflow even when the text is longer than 19 characters.

fscanf() how to go in the next line?

So I have a wall of text in a file and I need to recognize some words that are between the $ sign and call them as numbers then print the modified text in another file along with what the numbers correspond to.
Also lines are not defined and columns should be max 80 characters.
Ex:
I $like$ cats.
I [1] cats.
[1] --> like
That's what I did:
#include <stdio.h>
#include <stdlib.h>
#define N 80
#define MAX 9999
int main()
{
FILE *fp;
int i=0,count=0;
char matr[MAX][N];
if((fp = fopen("text.txt","r")) == NULL){
printf("Error.");
exit(EXIT_FAILURE);
}
while((fscanf(fp,"%s",matr[i])) != EOF){
printf("%s ",matr[i]);
if(matr[i] == '\0')
printf("\n");
//I was thinking maybe to find two $ but Idk how to replace the entire word
/*
if(matr[i] == '$')
count++;
if(count == 2){
...code...
}
*/
i++;
}
fclose(fp);
return 0;
}
My problem is that fscanf doesn't recognize '\0' so it doesn't go in the next line when I print the array..also I don't know how to replace $word$ with a number.
Not only will fscanf("%s") read one whitespace-delimited string at a time, it will also eat all whitespace between those strings, including line terminators. If you want to reproduce the input whitespace in the output, as your example suggests you do, then you need a different approach.
Also lines are not defined and columns should be max 80 characters.
I take that to mean the number of lines is not known in advance, and that it is acceptable to assume that no line will contain more than 80 characters (not counting any line terminator).
When you say
My problem is that fscanf doesn't recognize '\0' so it doesn't go in the next line when I print the array
I suppose you're talking about this code:
char matr[MAX][N];
/* ... */
if(matr[i] == '\0')
Given that declaration for matr, the given condition will always evaluate to false, regardless of any other consideration. fscanf() does not factor in at all. The type of matr[i] is char[N], an array of N elements of type char. That evaluates to a pointer to the first element of the array, which pointer will never be NULL. It looks like you're trying to determine when to write a newline, but nothing remotely resembling this approach can do that.
I suggest you start by taking #Barmar's advice to read line-by-line via fgets(). That might look like so:
char line[N+2]; /* N + 2 leaves space for both newline and string terminator */
if (fgets(line, sizeof(line), fp) != NULL) {
/* one line read; handle it ... */
} else {
/* handle end-of-file or I/O error */
}
Then for each line you read, parse out the "$word$" tokens by whatever means you like, and output the needed results (everything but the $-delimited tokens verbatim; the bracket substitution number for each token). Of course, you'll need to memorialize the substitution tokens for later output. Remember to make copies of those, as the buffer will be overwritten on each read (if done as I suggest above).
fscanf() does recognize '\0', under select circumstances, but that is not the issue here.
Code needs to detect '\n'. fscanf(fp,"%s"... will not do that. The first thing "%s" directs is to consume (and not save) any leading white-space including '\n'. Read a line of text with fgets().
Simple read 1 line at a time. Then march down the buffer looking for words.
Following uses "%n" to track how far in the buffer scanning stopped.
// more room for \n \0
#define BUF_SIZE (N + 1 + 1)
char buffer[BUF_SIZE];
while (fgets(buffer, sizeof buffer, stdin) != NULL) {
char *p = buffer;
char word[sizeof buffer];
int n;
while (sscanf(p, "%s%n", word, &n) == 1) {
// do something with word
if (strcmp(word, "$zero$") == 0) fputs("0", stdout);
else if (strcmp(word, "$one$") == 0) fputs("1", stdout);
else fputs(word, stdout);
fputc(' ', stdout);
p += n;
}
fputc('\n', stdout);
}
Use fread() to read the file contents to a char[] buffer. Then iterate through this buffer and whenever you find a $ you perform a strncmp to detect with which value to replace it (keep in mind, that there is a 2nd $ at the end of the word). To replace $word$ with a number you need to either shrink or extend the buffer at the position of the word - this depends on the string size of the number in ascii format (look solutions up on google, normally you should be able to use memmove). Then you can write the number to the cave, that arose from extending the buffer (just overwrite the $word$ aswell).
Then write the buffer to the file, overwriting all its previous contents.

Check if user input into an array is too long?

I am getting the user to input 4 numbers. They can be input: 1 2 3 4 or 1234 or 1 2 34 , etc. I am currently using
int array[4];
scanf("%1x%1x%1x%1x", &array[0], &array[1], &array[2], &array[3]);
However, I want to display an error if the user inputs too many numbers: 12345 or 1 2 3 4 5 or 1 2 345 , etc.
How can I do this?
I am very new to C, so please explain as much as possible.
//
Thanks for your help.
What I have now tried to do is:
char line[101];
printf("Please input);
fgets(line, 101, stdin);
if (strlen(line)>5)
{
printf("Input is too large");
}
else
{
array[0]=line[0]-'0'; array[1]=line[1]-'0'; array[2]=line[2]-'0'; array[3]=line[3]-'0';
printf("%d%d%d%d", array[0], array[1], array[2], array[3]);
}
Is this a sensible and acceptable way? It compiles and appears to work on Visual Studios. Will it compile and run on C?
OP is on the right track, but needs adjust to deal with errors.
The current approach, using scanf() can be used to detect problems, but not well recover. Instead, use a fgets()/sscanf() combination.
char line[101];
if (fgets(line, sizeof line, stdin) == NULL) HandleEOForIOError();
unsigned arr[4];
int ch;
int cnt = sscanf(line, "%1x%1x%1x%1x %c", &arr[0], &arr[1], &arr[2],&arr[3],&ch);
if (cnt == 4) JustRight();
if (cnt < 4) Handle_TooFew();
if (cnt > 4) Handle_TooMany(); // cnt == 5
ch catches any lurking non-whitespace char after the 4 numbers.
Use %1u if looking for 1 decimal digit into an unsigned.
Use %1d if looking for 1 decimal digit into an int.
OP 2nd approach array[0]=line[0]-'0'; ..., is not bad, but has some shortcomings. It does not perform good error checking (non-numeric) nor handles hexadecimal numbers like the first. Further, it does not allow for leading or interspersed spaces.
Your question might be operating system specific. I am assuming it could be Linux.
You could first read an entire line with getline(3) (or readline(3), or even fgets(3) if you accept to set an upper limit to your input line size) then parse that line (e.g. with sscanf(3) and use the %n format specifier). Don't forget to test the result of sscanf (the number of read items).
So perhaps something like
int a=0,b=0,c=0,d=0;
char* line=NULL;
size_t linesize=0;
int lastpos= -1;
ssize_t linelen=getline(&line,&linesize,stdin);
if (linelen<0) { perror("getline"); exit(EXIT_FAILURE); };
int nbscanned=sscanf(line," %1d%1d%1d%1d %n", &a,&b,&c,&d,&lastpos);
if (nbscanned>=4 && lastpos==linelen) {
// be happy
do_something_with(a,b,c,d);
}
else {
// be unhappy
fprintf(stderr, "wrong input line %s\n", line);
exit(EXIT_FAILURE);
}
free(line); line=NULL;
And once you have the entire line, you could parse it by other means like successive calls of strtol(3).
Then, the issue is what happens if the stdin has more than one line. I cannot guess what you want in that case. Maybe feof(3) is relevant.
I believe that my solution might not be Linux specific, but I don't know. It probably should work on Posix 2008 compliant operating systems.
Be careful about the result of sscanf when having a %n conversion specification. The man page tells that standards might be contradictory on that corner case.
If your operating system is not Posix compliant (e.g. Windows) then you should find another way. If you accept to limit line size to e.g. 128 you might code
char line[128];
memset (line, 0, sizeof(line));
fgets(line, sizeof(line), stdin);
ssize_t linelen = strlen(line);
then you do append the sscanf and following code from the previous (i.e. first) code chunk (but without the last line calling free(line)).
What you are trying to get is 4 digits with or without spaces between them. For that, you can take a string as input and then check that string character by character and count the number of digits(and spaces and other characters) in the string and perform the desired action/ display the required message.
You can't do that with scanf. Problem is, there are ways to make scanf search for something after the 4 numbers, but all of them will just sit there and wait for more user input if the user does NOT enter more. So you'd need to use gets() or fgets() and parse the string to do that.
It would probably be easier for you to change your program, so that you ask for one number at a time - then you ask 4 times, and you're done with it, so something along these lines, in pseudo code:
i = 0
while i < 4
ask for number
scanf number and save in array at index i
E.g
#include <stdio.h>
int main(void){
int array[4], ch;
size_t i, size = sizeof(array)/sizeof(*array);//4
i = 0;
while(i < size){
if(1!=scanf("%1x", &array[i])){
//printf("invalid input");
scanf("%*[^0123456789abcdefABCDEF]");//or "%*[^0-9A-Fa-f]"
} else {
++i;
}
}
if('\n' != (ch = getchar())){
printf("Extra input !\n");
scanf("%*[^\n]");//remove extra input
}
for(i=0;i<size;++i){
printf("%x", array[i]);
}
printf("\n");
return 0;
}

Reading from two columns into variables

I'm writing a C program that takes an input file and stores it. The input file has two columns, with an integer in the first and a string in the second, like so:
12 apple
17 frog
20 grass
I've tried using fgets to take an entire line as a string then break it apart using scanf but I'm getting lots of issues. I have searched quite a lot but haven't found anything that answers my question, but sorry if I missed something obvious.
This is the code that I've been trying:
while(fgets(line, sizeof(line), fp))
{
scanf(line, "%d\t%s", &key, value);
insert(key, value, newdict);
}
Let's have a quick go at doing with strtok since someone mentioned it. Let's imagine your file is called file.txt and has the following contents:
10 aaa
20 bbb
30 ccc
This is how we can parse it:
#include <stdio.h>
#include <string.h>
#define MAX_NUMBER_OF_LINES 10 // parse a maximum of 10 lines
#define MAX_LINE_SIZE 50 // parse a maximum of 50 chars per line
int main ()
{
FILE* fh = fopen("file.txt", "r"); // open the file
char temp[MAX_LINE_SIZE]; // some buffer storage for each line
// storage for MAX_NUMBER_OF_LINES integers
int d_out[MAX_NUMBER_OF_LINES];
// storage for MAX_NUMBER_OF_LINES strings each MAX_LINE_SIZE chars long
char s_out[MAX_NUMBER_OF_LINES][MAX_LINE_SIZE];
// i is a special variable that tells us if we're parsing a number or a string (0 for num, 1 for string)
// di and si are indices to keep track of which line we're currently handling
int i = 0, di = 0, si = 0;
while (fgets(temp, MAX_LINE_SIZE, fh) && di < MAX_NUMBER_OF_LINES) // read the input file and parse the string
{
temp[strlen(temp) -1] = '\0'; // get rid of the newline in the buffer
char* c = strtok(temp, " "); // set the delimiters
while(c != NULL)
{
if (i == 0) // i equal to 0 means we're parsing a number
{
i = 1; // next we'll parse a string, let's indicate that
sscanf(c, "%d", &d_out[di++]);
}
else // i must be 1 parsing a string
{
i = 0; // next we'll parse a number
sprintf(s_out[si++], "%s", c);
}
c = strtok(NULL, " ");
}
printf("%d %s\n", d_out[di -1], s_out[si - 1]); // print what we've extracted
}
fclose(fh);
return 0;
}
This will extract the contents from the file and store them in respective arrays, we then print them and get back our original contents:
$ ./a.out
10 aaa
20 bbb
30 ccc
Use:
fgets (name, 100, stdin);
100 is the max length of the buffer. You should adjust it as per your need.
Use:
scanf ("%[^\n]%*c", name);
The [] is the scanset character. [^\n] tells that while the input is not a newline ('\n') take input. Then with the %*c it reads the newline character from the input buffer (which is not read), and the * indicates that this read in input is discarded (assignment suppression), as you do not need it, and this newline in the buffer does not create any problem for next inputs that you might take.
The problem here seems to be that you are reading from the file twice. First with fgets and then with scanf. You will probably not get an errors from the compiler in your use of scanf, but should be getting warnings as you use line for the format string and the other arguments does not match the format. It would also be pretty obvious if you checked the return value from scanf, as it returns the number of successfully scanned items. Your call would most likely return zero (or minus one when you have hit end of file).
You should be using sscanf instead to parse the line you read with fgets.
See e.g. this reference for the different scanf variants.
Your problem can be solved by using sscanf (with the support of getline) like below:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
FILE *fp;
char *line = NULL;
size_t len = 0;
ssize_t read;
/* tokens bags */
char tok_str[255];
int tok_int;
fp = fopen("./file.txt", "r");
if (fp == NULL)
exit(EXIT_FAILURE);
/* Reads the line from the stream. */
while ((read = getline(&line, &len, fp)) != -1) {
/* Scans the character string pointed by line, according to given format. */
sscanf(line, "%d\t%s", &tok_int, tok_str);
printf("%d-%s\n", tok_int, tok_str);
}
if (line)
free(line);
exit(EXIT_SUCCESS);
}
Or, even simpler. You could use fscanf (with the support of feof) and replace the while loop shown above (along with some other redundant code cleanups) with the following one:
/* Tests the end-of-file indicator for the stream. */
while (!feof(fp)) {
/* Scans input from the file stream pointer. */
fscanf(fp,"%d\t%s\n",&tok_int, tok_str);
printf("%d-%s\n", tok_int, tok_str);
}
Assuming that your file contains following lines (where single line format is number[tab]string[newline]):
12 apple
17 frog
20 grass
the output will be:
12-apple
17-frog
20-grass

In C how to strcmp just the beginning 2 characters and then concatenate? [duplicate]

This question already has answers here:
How to check if a string starts with another string in C?
(10 answers)
Closed 7 years ago.
In C how do I strcmp just the beginning 2 characters? Then concatenate with another string? Something like this:
char s[10];
scanf("%s",s);
/* if i input "cs332" or "cs234", anything start with cs */
if (strcmp("cs",???)==0)
strcat(s,"by professor");
You are looking for the strncmp function which is functionally identical to strcmp but limits the number of characters checked. So you would use it with a length of two and the comparison string of "cs". But, you have a few other problems here.
First, your buffer is not big enough. There is no string that will fit into a ten-character buffer when you append the text "by professor" to it.
Secondly, robust code will never use scanf with an unbounded-string format specifier: that's asking for a buffer overflow problem. The scanf family is meant for formatted input and there is little more unformatted than user input :-)
If you want a robust input solution, see one of my previous answers.
Thirdly, you should always assume that concatenating a string may overflow your buffer, and introduce code to prevent this. You need to add up:
the current length of the string, input by the user.
the length of the appending string ("by professor").
one more for the null terminator.
and ensure the buffer is big enough.
The method I would use would be to have a (for example) 200-byte buffer, use getLine() from the linked answer (reproduced below to make this answer self-contained) with a sufficiently smaller size (say 100), then you can be assured that appending "by professor" will not overflow the buffer.
Function:
#include <stdio.h>
#include <string.h>
#define OK 0
#define NO_INPUT 1
#define TOO_LONG 2
static int getLine (char *prmpt, char *buff, size_t sz) {
int ch, extra;
// Get line with buffer overrun protection.
if (prmpt != NULL) {
printf ("%s", prmpt);
fflush (stdout);
}
if (fgets (buff, sz, stdin) == NULL)
return NO_INPUT;
// If it was too long, there'll be no newline. In that case, we flush
// to end of line so that excess doesn't affect the next call.
if (buff[strlen(buff)-1] != '\n') {
extra = 0;
while (((ch = getchar()) != '\n') && (ch != EOF))
extra = 1;
return (extra == 1) ? TOO_LONG : OK;
}
// Otherwise remove newline and give string back to caller.
buff[strlen(buff)-1] = '\0';
return OK;
}
Test code:
// Test program for getLine().
int main (void) {
int rc;
char buff[10];
rc = getLine ("Enter string> ", buff, sizeof(buff));
if (rc == NO_INPUT) {
// Extra NL since my system doesn't output that on EOF.
printf ("\nNo input\n");
return 1;
}
if (rc == TOO_LONG) {
printf ("Input too long [%s]\n", buff);
return 1;
}
printf ("OK [%s]\n", buff);
return 0;
}
why not directly comparing characters rather than calling strcmp?
E.g.
if(s[0]=='c' && s[1]=='s'){
...
}
if (strncmp("cs",???, 2)==0) strcat(s,"by professor");
Use strncmp
Several ways to do this.
String comparison:
if ( s[0] == 'c' && s[1] == 's' )
Is the naive way, as you can't expand this easily to slightly longer codes (say 3/4 characters in length).
I guess you've gathered you should be using strncmp() right?
String Concaternation
Don't use strcat. Really. If you concatenate two strings whose length is greater than the size of s (the destination) you're in trouble. Consider using snprint() instead, like this:
char str[80];
snprintf(str, 80, "%s by professor", s);
Or, you could use strncat() as Heath points out:
char s[80];
strncat(s, " by professor", 80);
You can use strncmp.
Edit:
strcat(s,"by professor");
// s is an array of 10 characters. You need to make sure s is big enough
// to hold the string that needs to be concatenated + to have a terminating
// character '\0'.
Yes, as said, strcmp is the preferred method. Here's just a different way to do the same.
#define CS 29539
char s[80];
scanf("%60s", s);
if( *(short *)s == CS )
if( strlcat(s, " by professor", sizeof(s)) >= sizeof(s) )
fprintf(stderr, "WARNING: truncation detected: %s", s);

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