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I am getting an error saying: Thread stopped.....access violation at 0x6:read of address 0x6.
However my code doesn't have such address.
#include<stdio.h>
#include<conio.h>
void main ()
{
int i,j,A[4][5],c=0;
for(j=0;j<5;j++)
for(i=0;j<4;i++)
{
A[i][j]=c;
c++;
}
for(i=0;i<4;i++)
{
for(j=0;j<5;j++)
printf("%d\t",A[i][j]);
printf("\n");
}
getch();
}
I was asked to enter a double array column by column instead of row by row, and I want to verify my method so I tried to print it out but had no luck doing so.
for(i=0;j<4;i++)
^^
Shouldn't this be:
for(i=0;i<4;i++)
j<4 is always true once it enters inner the loop for the first time and is the reason for memory access violation.
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This code prints the array elements, but I can't understand how does k[x-1] gives the array elements.
#include<stdio.h>
int main()
{
int x[]={2,4,6,8,10},k=1;
while (k<=5)
{
printf ("%3d",k[x-1]);
k++;
}
return 0;
}
Array indexes start at 0 in C. An array like int x[]={2,4,6,8,10} will have a value x[0]=2 and so forth. Typically, when iterating through an array, a convention like this is used:
for (int i = 0; i < length; i++)
printf("%3d",x[i]);
Since the code you provided begins the indexing at 1, you have to subtract one to fetch the proper element.
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copy all characters from one character array to another without using strcpy function.
char s1[80],s2[80];
int i;
printf("input s2");
scanf("%s",&s2);
for(i=0;i<=strlen(s2);i++)
s1[i]=s2[i];
printf("s1:%s",s1);
Instead of scanf, using gets function for getting input with spaces.
#include<stdio.h>
int main()
{
char s1[80],s2[80];
int i;
printf("input s2");
// scanf("%c",&s2);
gets(s2);
printf("%d",strlen(s2));
for(i=0;i<strlen(s2);i++)
{
s1[i]=s2[i];
}
printf("s1:%s",s1);
}
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How can I call a function that has printf in it - in printf BUT without it printing the value entered twice?
in the code written below is how it is now, it prints the inserted value.
can I just use the function without printing the value again?
can I use printf(roll(num))
#include<stdio.h>
int roll(int);
int main()
{
int num;
printf("%d",roll(num));
return 0;
}
int roll(int a)
{
printf("Enter a number between 1-6:\n");
scanf("%d",&a);
while(a<1 || a>6)
{
printf("Wrong input! please enter a number between 1-6:\n");
scanf("%d",&a);
}
return a;
}
Just call the function without printf.
roll(num);
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#include <stdio.h>
int main()
{
int var=0;
for(; var++; printf("%d",var));
printf("%d", var);
}
Please explain to me this C code. How is the output 1?
You might be confused because of the wrong code indentation. Your code is:
for(; var++; printf("%d",var))
;
printf("%d", var);
So you always get the output of the second printf. As var is initialized to 0 and var++ (the for-condition) is always executed, you end up with var==1.
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Following is the code to obtain matrix like 11 12 13 etc... I am not getting desired results since long. Help me with the solution.
#include<stdio.h>
int main() {
int i,j;
for(i=1;i<5;i++){
for(j=1;j<5;j++){
printf("%d %d",i,j);
}
printf("\n");
}
fgetc(stdin);
}
Probably because you have a space between the digits:
printf("%d %d",i,j);
Shouldn't it be:
printf("%d%d ",i,j);
for your desired output?
Shouldn't printf("%d %d",i,j); actually be printf("%d%d ",i,j);?