I am having problem with importing external function to a main c file.
Here is my minimal code:
/* main.c */
#include<stdio.h>
extern int func()
int main(){
extern int func();
}
/*external file with one function that I want to
import*/
#include<stdio.h>
int func(){
printf("Hello World Again\n");
}
I compile and run like this - gcc main.c and then ./a.out but nothing is happening.
Any idea ?
You have to compile the file containing func also
gcc -Wall main.c external_file.c
(Note that the -Wall in the compiler command isn't absolutely necessary but is very good practice)
As noted by others, you also need to fix your code to call func rather than just re-declaring it.
Because you only declared the function, You never called it!
extern int func();
Declares a function. To call it you must have:
int main()
{
func();
}
You are just declaring again in main function..
you need to call the function to work..#include
extern int func()
int main(){
func();
}
/*external file with one function that I want to
import*/
#include<stdio.h>
int func(){
printf("Hello World Again\n");
}
Edits: question has changed.
extern is only used for external variables. You just need a prototype for the function.
#include <stdio.h>
void func(void); /* <-- prototype */
int main(int argc, char * argv[])
{
func();
return 0;
}
void func(void){
printf("Hello World Again\n");
}
Notice a few things. A prototype of int func() means no parameter checking in C - this is different to C++. Also, you are not returning anything from the function, so I replace it with void func(void)
Related
Say I have a library I am making and I want to call a function rename or puts, how can I keep the original rename and puts from stdlib or stdio or whatever, and yet have my own function be puts?
#include <stdio.h>
alias puts original_puts;
void
puts(char *c) {
original_puts(c);
}
How can I accomplish something to this effect?
You can't alias library functions, but you can alias your own using preprocessor directives.
For example:
mylib.h:
#include <stdio.h>
void my_puts(char *c);
#define puts(arg) my_puts(arg)
mylib.c:
void my_puts(char *c)
{
(puts)(c);
}
Now, anytime someone calls puts, it substitutes a call to my_puts instead. Also, when you want to call the "real" function in your wrapper, you can put the function name in quotes. Because the macro that does the substitution is a function-like macro, the parenthesis prevent the substitution from happening.
If compiling with gcc or clang, you can wrap the symbol with -Wl,--wrap:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
int __real_puts(const char *c);
int __wrap_puts(const char *c) {
__real_puts("Hello");
__real_puts(c);
return 0;
}
int main(int argc, char const *argv[]) {
puts("world");
}
$ gcc src.c -Wl,--wrap=puts && ./a.out
Hello
world
I'm a beginner into Linking, lets say I have two .c files
file1.c is
#include <stdio.h>
#include "file2.c"
int main(int argc, char *argv[])
{
int a = function2();
printf("%d",a);
return 0;
}
and file2.c is
int function2()
{
return 2018;
}
when I compiled, there is a linker error which is multiple definition of function2, but I only define function once in file2.c?
You should create a header file, "file2.h", with:
int function2(void);
and a file "file2.c" with the function: "file2.h" with:
#include "file2.h"
int function2(void)
{
return 2018;
...
}
Then in your main you have to include the header with:
#include "file2.h"
Keep care that all those files should be in the same folder to avoid any link problem
Try something like this:
#include <stdio.h>
#include "file2.h"
int main(int argc, char *argv[])
{
int a = function2();
printf("%d",a);
return 0;
}
file2.h:
extern int function2(void);
and file2.c is
#include "file2.h"
int function2(void)
{
return 2018;
}
And then link it together.
The statement #include "file2.c" effectively incorporates the contents of file2.c into file1.c. Then file1.c is compiled as if it contains:
int function2()
{
return 2018;
}
Those lines define function2; they tell the compiler “Here is function2, create code for it.” Because those lines effectively appear in both file1.c and file2.c, your program has two copies of function2.
Instead, you should create file2.h that contains:
int function2();
That line tells the compiler “There exists a function called function2, but its definition is somewhere else.”
Then, in file1.c, use #include "file2.h" instead of #include "file2.c". This will tell the compiler, while file1.c is being compiled, what it needs to know to compile a call to function2. The compiler will have the declaration it needs, but it will not have the definition, which is not needed in file1.c.
Also, in file2.c, insert #include "file2.h". Then file2.c will contain both a declaration of function2 (from file2.h) and a definition of function2 (from the actual lines in file2.c). The purpose of this is so the compiler can see both the declaration and the definition while it is compiling file2.c, so it can warn you if there is a typographical error that makes them incompatible.
Additionally, in C, you should use int function2(void) rather than int function2(). For historic reasons, the latter leaves the parameters unspecified. Using (void) tells the compiler there are no parameters.
Hello folks out there,
this is my code:
main.c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "sqlite3.h"
#include "db_typedefs.h"
#include "operations.h"
int main(){
printf("Text\n");
int f = 3;
void add_mini(3);
}
operations.h
#ifndef ADD_OPERATIONS_H_INCLUDED
#define ADD_OPERATIONS_H_INCLUDED
void add_mini(int flag);
#endif // ADD_OPERATIONS_H_INCLUDED
operations.c
void add_mini(int flag)
{
int rc;
rc = flag;
printf("%i\n", rc);
}
Operations.c has also libraries included similar to main.c.
Compiler Error
error: expected declaration specifiers or '...' before numeric constant
regarding to void add_mini(3)
It seems like I'm unable to pass a simple integer value. While debugging it's even skipping the add_mini line.
Do you have any idea what's going on?
The whole code is embedded in a larger query to determine typed orders but this works fine. I just can't pass this simple integer value.
Thanks in advance.
When you use
void add_mini(3);
the compiler thinks it is a function declaration, not a function call. The argument 3 is not valid for a function declaration. Hence, the compiler complains.
Remove the void part to call the function.
int main(){
printf("Text\n");
int f = 3;
add_mini(3);
}
or, since you have initialized f to 3,
int main(){
printf("Text\n");
int f = 3;
add_mini(f);
}
Call the function like so: add_mini(3); rather than void add_mini(3);
Remove the word void for calling add_mini from main.c :
add_mini(3);
Or
(void)add_mini(3);
Why we don't use extern when using function from one .c file in another .c file , but we must do extern for variables case? Is it related to linker?
Functions are extern qualified by default (unless you change it to internal with static). For example,
int func(void) {
}
extern int func2(void) {
}
Both func and func2 are external. The extern keyword is optional for external functions.
Actually, function names act just like variable names, but function prototypes are extern by default.
From cpprerefence:
If a function declaration appears outside of any function, the identifier it introduces has file scope and external linkage, unless static is used or an earlier static declaration is visible.
you can create a .hfile,declare functions you want to use in the other .c files and #include the .hfile in the other .c files.
Demo program,
one.c
#include "one.h"
void func1() //defination
{
//code
}
one.h
void func1(); //declaration
main.c
#include <stdio.h>
#include "one.h"
int main()
{
func1();
}
Then compile program in Gcc Linux : gcc main.c one.c
Yes, Let consider you have one .c file as process.c and you declared it in process.h . Now if you want to use the function from process.c to suppose tools.c then simply #include "process.h" in tools.c and use ther function. The process.h and process.c file should be in your project.
process.c file
#include<stdio.h>
#include<conio.h>
#include "process.h"
unsigned int function_addition(unsigned int a, unsigned int b)
{
unsigned int c = 0;
c = a + b;
return c;
}
process.h:
<bla bla bla >
unsigned int function_addition(unsigned int a, unsigned int b);
<bla bla bla >
tools.c file:
#include<stdio.h>
#include<conio.h>
#include "process.h"
my_tools()
{
unsigned int X = 1, Y = 9, C = 0;
C = function_addition(X,Y);
}
All these files are in one project.
I have two C files. I want to declare a variable in one, then be able to access it from another C file. My definition of the example string might not be perfect, but you get the idea.
//file1.c
char *hello="hello";
//file2.c
printf("%s",hello);
// file1.h
#ifndef FILE1_H
#define FILE1_H
extern char* hello;
#endif
// file1.c
// as before
// file2.c
#include "file1.h"
// the rest as before
*hello in file1.c must be declarated global and extern in file2.c must be global too (not inside function)
//file2.c
extern char *hello;
... function()
{
printf(...)
}
What you have would work. What you want to research is "linkage" in C. Basically objects not within a function or marked as static are extern (think global). What you need to do in this case is notify the compiler that there is in fact a variable called hello defined elsewhere. You do this by adding the following line to file2.c
extern char* hello;
this works
t.c
#include <stdio.h>
int main(void)
{
extern int d;
printf("%d" "\n", d);
return 0;
}
h.c
int d = 1;
output
[guest#localhost tests]$ .ansi t.c h.c -o t
[guest#localhost tests]$ ./t
1
[guest#localhost ~]$ alias .ansi
alias .ansi='cc -ansi -pedantic -Wall'
[guest#localhost ~]$
file1.c
int temp1=25;
int main()
{
.
.
}
file2.c
extern int temp1;
func1();
func2(temp1);
temp1 is defined in file1.c .when you want to use it in file2.c you must write
extern int temp1;
you must do it in each file which you want to use this variable
file_2.c
#include<stdio.h>
int count;
void extern_function();
void main()
{
count = 5;
extern_function();
}
file_3.c
#include<stdio.h>
void extern_function()
{
extern int count;
printf("the value from the external file is %d",count);
}
Now run the code
$gcc file_2.c file_3.c -o test
$./test
It works!!