How to use switch and case for strings - c

Question

Based on an answer of the following question: How do I transform an IF statement with 2 variables onto a switch function using C?
I want to develop SWITCH and CASE macros to use it (like switch and case) for strings.
Some thing like that:
char buf[256];
SWITCH (buf) {
CASE ("abcdef"):
printf ("A1!\n");
BREAK;
CASE ("ghijkl"):
printf ("B1!\n");
BREAK;
DEFAULT:
printf ("D1!\n");
BREAK;
}
what could be SWITCH and CASE and BREAK and DEFAULT here ?

Answer 1

If you really want it, well, here it is:
#include <string.h>
#include <stdio.h>
const char *kludge;
#define evilmacro(line) label##line
#define fakelabel(line) evilmacro(line)
#define SWITCH(str) while((kludge = (str)))
#define CASE(str) if(strcmp(kludge, str) == 0) { fakelabel(__LINE__)
#define BREAK break; /* out of while loop */ }
#define DEFAULT if(1) { fakelabel(__LINE__)
int main(int argc, char *argv[]) {
SWITCH (argv[1]) {
CASE ("abcdef"):
printf ("A1!\n");
BREAK;
CASE ("ghijkl"):
printf ("B1!\n");
BREAK;
DEFAULT:
printf ("D1!\n");
BREAK;
}
return 0;
}
Getting rid of the unused labels is left as an exercise for the reader :)
EDIT: fwiw, what I would really do is table driven code.

Answer 2

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SWITCH(S) char *_S = S; if (0)
#define CASE(S) } else if (strcmp(_S, S) == 0) {switch(1) { case 1
#define BREAK }
#define DEFAULT } else {switch(1) { case 1
int main()
{
char buf[256];
printf("\nString - Enter your string: ");
scanf ("%s", buf);
SWITCH (buf) {
CASE ("abcdef"):
printf ("B1!\n");
BREAK;
CASE ("ghijkl"):
printf ("C1!\n");
BREAK;
DEFAULT:
printf ("D1!\n");
BREAK;
}
}