Why must malloc be used? - c

Question

From what I understand, the malloc function takes a variable and allocates memory as asked. In this case, it will ask the compiler to prepare memory in order to fit the equivalence of twenty double variables. Is my way of understanding it correctly, and why must it be used?
double *q;
q=(double *)malloc(20*sizeof(double));
for (i=0;i<20; i++)
{
*(q+i)= (double) rand();
}

Answer 1

You don't have to use malloc() when:
The size is known at compile time, as in your example.
You are using C99 or C2011 with VLA (variable length array) support.
Note that malloc() allocates memory at runtime, not at compile time. The compiler is only involved to the extent that it ensures the correct function is called; it is malloc() that does the allocation.
Your example mentions 'equivalence of ten integers'. It is very seldom that 20 double occupy the same space as 10 int. Usually, 10 double will occupy the same space as 20 int (when sizeof(int) == 4 and sizeof(double) == 8, which is a very commonly found setting).

Answer 2

It's used to allocate memory at run-time rather than compile-time. So if your data arrays are based on some sort of input from the user, database, file, etc. then malloc must be used once the desired size is known.
The variable q is a pointer, meaning it stores an address in memory. malloc is asking the system to create a section of memory and return the address of that section of memory, which is stored in q. So q points to the starting location of the memory you requested.
Care must be taken not to alter q unintentionally. For instance, if you did:
q = (double *)malloc(20*sizeof(double));
q = (double *)malloc(10*sizeof(double));
you will lose access to the first section of 20 double's and introduce a memory leak.

Answer 3

When you use malloc you are asking the system "Hey, I want this many bytes of memory" and then he will either say "Sorry, I'm all out" or "Ok! Here is an address to the memory you wanted. Don't lose it".
It's generally a good idea to put big datasets in the heap (where malloc gets your memory from) and a pointer to that memory on the stack (where code execution takes place). This becomes more important on embedded platforms where you have limited memory. You have to decide how you want to divvy up the physical memory between the stack and heap. Too much stack and you can't dynamically allocate much memory. Too little stack and you can function call your way right out of it (also known as a stack overflow :P)

Answer 4

As the others said, malloc is used to allocate memory. It is important to note that malloc will allocate memory from the heap, and thus the memory is persistent until it is free'd. Otherwise, without malloc, declaring something like double vals[20] will allocate memory on the stack. When you exit the function, that memory is popped off of the stack.
So for example, say you are in a function and you don't care about the persistence of values. Then the following would be suitable:
void some_function() {
double vals[20];
for(int i = 0; i < 20; i++) {
vals[i] = (double)rand();
}
}
Now if you have some global structure or something that stores data, that has a lifetime longer than that of just the function, then using malloc to allocate that memory from the heap is required (alternatively, you can declare it as a global variable, and the memory will be preallocated for you).

Answer 5

In you example, you could have declared double q[20]; without the malloc and it would work.
malloc is a standard way to get dynamically allocated memory (malloc is often built above low-level memory acquisition primitives like mmap on Linux).
You want to get dynamically allocated memory resources, notably when the size of the allocated thing (here, your q pointer) depends upon runtime parameters (e.g. depends upon input). The bad alternative would be to allocate all statically, but then the static size of your data is a strong built-in limitation, and you don't like that.
Dynamic resource allocation enables you to run the same program on a cheap tablet (with half a gigabyte of RAM) and an expensive super-computer (with terabytes of RAM). You can allocate different size of data.
Don't forget to test the result of malloc; it can fail by returning NULL. At the very least, code:
int* q = malloc (10*sizeof(int));
if (!q) {
perror("q allocation failed");
exit(EXIT_FAILURE);
};
and always initialize malloc-ed memory (you could prefer using calloc which zeroes the allocated memory).
Don't forget to later free the malloc-ed memory. On Linux, learn about using valgrind. Be scared of memory leaks and dangling pointers. Recognize that the liveness of some data is a non-modular property of the entire program. Read about garbage collection!, and consider perhaps using Boehm's conservative garbage collector (by calling GC_malloc instead of malloc).

Answer 6

You use malloc() to allocate memory dynamically in C. (Allocate the memory at the run time)
You use it because sometimes you don't know how much memory you'll use when you write your program.
You don't have to use it when you know thow many elements the array will hold at compile time.
Another important thing to notice that if you want to return an array from a function, you will want to return an array which was not defined inside the function on the stack. Instead, you'll want to dynamically allocate an array (on the heap) and return a pointer to this block:
int *returnArray(int n)
{
int i;
int *arr = (int *)malloc(sizeof(int) * n);
if (arr == NULL)
{
return NULL;
}
//...
//fill the array or manipulate it
//...
return arr; //return the pointer
}