I have to following array from inputs
array:9 [
"columns" => "4"
"device_id" => array:4 [
0 => "1"
1 => "2"
2 => "3"
3 => "4"
]
"hub_id" => "11"
"usage" => array:4 [
0 => "1"
1 => "2"
2 => "3"
3 => "4"
]
....
In my foreach loop i get back only one value not all
$devices = $request->all();
foreach ($devices["device_id"] as $device) {
dd($device);
}
This will return only 1 one value not all.
I have problem displaying all the value and saving them to database.
Witch would be the fast and the right way ?
The array and the behaviour you are getting is normal.
$devices = $request->all();
foreach ($devices["device_id"] as $device) {
dd($device);
}
This will indeed return 1, because your cursor is at the first value of $devices["device_id"]. If you wait for the next iteration, it'll be 2, then 3 and 4.
Remember you can also write your foreach this way:
foreach ($devices["device_id"] as $index => $device)
, where $index will be equal to the index related to the current value.
If you want all values, you can just simply dd($devices["device_id"]), it'll return you this array:
array:4 [
0 => "1"
1 => "2"
2 => "3"
3 => "4"
]
You do not save array in a database. Databases are not supposed to save multidimensional structures, since they do not support them.
You must convert your array into a format that the database is able to save, for example JSON or PHP serialize. It is actually very common to save data in this way if you do not need to search it easily at a later time.
Nevertheless, I would use a setter in your model to achieve this:
public function setAttributeNameAttribute($values)
{
$this->attributes['attribute_name'] = json_encode($values);
}
public function getAttributeNameAttribute($values)
{
return json_decode($values);
}
I have this big array that I need to break down and only display specific elements within it that match a criteria.
My array looks like this.
[
{
:id => 9789,
:name => "amazing location",
:priority => 1,
:address_id => 12697,
:disabled => false
},
{
:id => 9790,
:name => "better location",
:priority => 1,
:address_id => 12698,
:disabled => false
},
{
:id => 9791,
:name => "ok location",
:priority => 1,
:address_id => 12699,
:disabled => true
}
]
What I need is to only display the elements within this array that have disabled set to true.
However when I try this, I get the error stating no implicit conversion of Symbol into Integer
array.map do |settings, value|
p hash[:disabled][:true]
end
I'm wondering if there is another way, or if there is a way to do this. If anyone could take a look, I would greatly appreciate it.
By providing two arguments to #map on an array, you're actually getting the first hash and then nil. When in reality you just want to loop for each and select those where disabled is true. You can do that instead with Array#select which will filter all elements of the array where the block returns a truthy value:
print array.select { |hash| hash[:disabled] }
=> [{:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}]
You can try this with a short each or select.
a.each { |k,_v| puts k if k[:disabled] == true }
=> {:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}
This iterates over each element (hash) inside the array you have and checks if the value of the key disabled on each value is true, and puts the key, just for example, you can set it as you want to do.
Or shorter:
puts a.select { |k,_v| k[:disabled] }
=> {:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}
Your error shows up when you are treating an array or string as a Hash.
In PHP, array keys can be either numbers or strings, whereas in Ruby associative arrays are a separate data type, called a hash.
Here’s a cheatsheet for various foreach variants, translated into idiomatic Ruby:
Looping over a numeric array (PHP) :
<?php
$items = array( 'orange', 'pear', 'banana' );
# without indexes
foreach ( $items as $item ) {
echo $item;
}
# with indexes
foreach ( $items as $i => $item ) {
echo $i, $item;
}
Looping over an array (Ruby) :
items = ['orange', 'pear', 'banana']
# without indexes
items.each do |item|
puts item
end
# with indexes
items.each_with_index do |item, i|
puts i, item
end
Looping over an associative array (PHP) :
<?php
$continents = array(
'africa' => 'Africa',
'europe' => 'Europe',
'north-america' => 'North America'
);
# without keys
foreach ( $continents as $continent ) {
echo $continent;
}
# with keys
foreach ( $continents as $slug => $title ) {
echo $slug, $title;
}
Looping over a hash (Ruby):
continents = {
'africa' => 'Africa',
'europe' => 'Europe',
'north-america' => 'North America'
}
# without keys
continents.each_value do |continent|
puts continent
end
# with keys
continents.each do |slug, title|
puts slug, title
end
In Ruby 1.9 hashes were improved so that they preserved their internal order. In Ruby 1.8, the order in which you inserted items into a hash would have no correlation to the order in which they were stored, and when you iterated over a hash, the results could appear totally random. Now hashes preserve the order of insertion, which is clearly useful when you are using them for keyword arguments in method definitions. (thanks steenslag for correcting me on this)
Hi I have the following query:
$inc_quotes = DB::table('inc_quotes')->where('session_id', '=', $session_id)->get();
And it returns an array of arrays I believe like below:
array:36 [▼
0 => {#232 ▼
+"id": "5"
+"session_id": "1ee0556134d377c05673fce16f719b3e1077c797"
+"brand": "Acer"
+"drive": "Full Size Laptop"
+"screen": "Less than 2 Years old"
+"processor": "AMD A6"
+"condition": "No"
+"faults": "Light Damage,Heavy Damage"
+"price": "16.37"
+"name": "Alex"
+"lastname": "C"
+"email": "test#hotmail.com"
+"mobile": "12344567"
+"created_at": "2016-02-20 09:05:51"
+"updated_at": "2016-02-20 09:05:51"
}
1 => {#233 ▶}
2 => {#234 ▶}
Now I would like to extract from each array(row) for example the name and do a for each on the view to show the names for each row.
How can I extract the values?
I tried this
foreach($inc_quotes as $quote){
$quote_name = $quote->name;
}
But only returns the last value.
Any help much appreciated.
$quote_name = [];
foreach($inc_quotes as $key => $quote){
$quote_name[$key] = $quote->name;
}
EDITED
pass this to view like this.
return view('whateverYourView',compact('quote_name'));
and in view you access it with
#foreach($quote_name as $name)
{{ $name }}
#endforeach
Your $quote_name must be an array or an collection to receive all data that is comming from the array that you are iterating.
The $quote_name will be subscribed in every loop, that's why the method it will show only the last result.
I have a problem with referencing a hash in an array to another array.
I have an array #result which looks like this:
#result = (
{ "type" => "variable",
"s" => "NGDP",
"variable" => "NGDP" },
{"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP" },
{ "type" => "colon",
"s" => ",",
"colon" => "," },
{ "type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP" },
{ "type" => "operator",
"s" => "+",
"operator => "+" },
{"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP" },
);
I want to divide this array into colons and push elements of the #result array to another array, so i wrote the script:
for ($i = 0; $i <= $#result; $i++) {
if (defined $result[$i]{subject} or $result[$i]{operator} and not defined $result[$i]{colon}) {
push #part_col, \%{$result[$i]};
}
elsif ($i == $#result) {
push #part_col_all, \#part_col;
}
elsif (defined $result[$i]{colon}) {
push #part_col_all, \#part_col;
my #part_col;
}
}
So what I need is that if I print out $part_col_all[0][0]{subject} the result will be "USA",
and for $part_col_all[1][0]{subject} will be "JPN",
and for $part_col_all[1][1]{operator} will be "+" etc.
My result for $part_col_all[0][0]{subject} is "USA"
and for $part_col_all[0][1]{subject} is "JPN" which should be in $part_col_all[1][0]{subject}.
The result for $part_col_all[0][3]{subject} is "CHN", while it should be in $part_col_all[1][2]{subject}.
I'm making an application which is creating graphs from economical data based on a certain economical input. The #result array is my preprocessed input where I know to which country which variable belongs. If I get an input like GDP USA CAN, JPN+CHN I need to split this input to GDP USA CAN and JPN+CHN. That's why I made a condition, if colon is found, push everything in #part_col to the first element of #part_col_all, and then if it's on the end of the input, push JPN+CHN to the second element of #push_col_all.
So #part_col_all should looks like this:
#part_col_all = (
(
{"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP" },
{"type" => "subject",
"s" => "CAN",
"subject" => "CAN",
"variable" => "NGDP" },
),
(
{ "type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP" },
{ "type" => "operator",
"s" => "+",
"operator" => "+" },
{"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP" },
)
);
I dont know what I'm doing wrong. Sorry if there are any basic mistakes, im a beginner. Thanks a lot.
First, you're missing a quote:
{ "type" => "operator",
"s" => "+",
"operator" => "+" },
^ missing
As for printing, you can do the following:
foreach my $part (#part_col){
print $part->{operator}."\n";
}
Or do whatever you want in the print cycle with the values
You should read the Perl Reference Tutorial to help you.
There's no sin in dereferencing to simplify your code:
my #part_col;
my #part_col_all;
for $i ( 0..$#array ) {
my %hash = ${ $result[$i] }; # Make it easy on yourself. Dereference
if ( defined $hash{subject} or defined $hash{operator} and not defined $hash{colon} ) {
push #part_col, \%hash; # or push, #par_col, $result[$i]
}
}
Notice I changed the for from the three part setup you had to a cleaner and easier to understand way of stating it.
Looking closer at your data structure, I notice that $hash{type} will tell you whether or not $hash{operator}, $hash{subject}, or $hash{colon} is defined. Let's just use $hash{type} and simplify that if:
my #part_col;
my #part_col_all;
for my $i ( 0..$#array ) {
my %hash = ${ $result[$i] }; # Make it easy on yourself. Dereference
if ( $hash{type} eq "subject" or $hash{type} eq "operator" ) {
push #part_col, \%hash; # or push, #par_col, $result[$i]
}
}
In fact, since #array is just an array, I'll treat it like one. I'll use a simple for structure to go through each element of my array. Each element is a hash_reference, so:
for my $hash_ref ( #array ) {
my %hash = %{ %hash_ref };
if ( $hash{type} eq "subject" or $hash{type} eq "operator" ) {
push #part_col, \%hash;
}
}
And further simplification, I can dereference and talk about a particular element of my hash all at once by using the -> syntax:
for my $hash_ref ( #array ) {
if ( $hash_ref->{type} eq "subject" or $hash_ref->{type} eq "operator" ) {
push #part_col, $hash_ref;
}
}
I'm trying to understand the rest of your code:
elsif ($i == $#result) {
push #part_col_all, \#part_col;
}
elsif (defined $hash_ref->{colon}) {
push #part_col_all, \#part_col;
my #part_col;
}
}
These pushes of #part_col onto #part_col_all confuse me. Exactly what are you trying to store in #part_col_all? Remember that \#part_col is the location in memory where you're storing #part_col. You're pushing that same memory location over and over onto that hash, so you're storing the same reference over and over again. Is that really what you want? I doubt it.
You need to do is to decide exactly what your data structure really represents. A data structure should have a solid definition. What does the data structure #part_col_all represent? What does the data structure $part_col_all[$i] represent? What does the data structure $part_col_all[$i]->[$j] represent? Without knowing this, it's very hard to answer the rest of your question.
Are you storing elements where the type is colon in one array and everything else in another array? Or are you storing everything in one array, and in another array, storing everything that's not a type colon?
Once I understand this, I can answer the rest of your question.
Addendum
Thank you for your reply, I will try that way and write my results. It is realy helpful. I updated my question with more information about data structure of #part_col_all. I hope that you understand what I'm trying to explain, if not I'll try it again.
If I understand what you're doing, someone enters in NGDP USA , JPN+CNA and that means you're comparing the NGDP between the United States vs. Japan and China combined.
It seems to me that you would want three separate variables:
$parameter - What you are measuring. (GDP, etc.)
#countries_set_1 - The first set of countries
#countries_set_2 - The second set of countries which you're comparing against the first set.
And, what you call the colon (which we would call a comma in the U.S.) as a separator between the first set of countries vs. the second set. Then, you'd simply go through a loop. It could be that the two arrays are merely two elements of the same array, and the sets of countries are array references. I imagine something like this:
#input = qw(GDP USA, JPN CHN); # Compare the GDP of the USA with Japan and China together
my $parameter = shift #input; # Remove what you're measuring
my #country_sets; # An array of arrays
my $set = 0 # Which set you're on
for my $value ( #input ) {
if ( $value eq "," ) {
$set += 1; # Next Set
next;
}
push #{ $country_sets[$set] }, $input;
}
This would create a data structure like this:
#country_sets = (
(
USA,
),
(
JPN,
CHN,
),
)
No need for the complex #results since you're only going to have a single operation (GDP, etc.) for all involved.
However, I think I see what you want. We'll go with an array of arrays. Here's what I had before:
for my $hash_ref ( #array ) {
if ( $hash_ref->{type} eq "subject" or $hash_ref->{type} eq "operator" ) {
push #part_col, $hash_ref;
}
}
We'll combine that and the code I offered right above which splits the countries into two sets:
my #country_sets; # An array of arrays
my $set = 0 # Which set you're on
for my $country_ref ( #array ) {
next if $country_ref->{type} eq "variable"; # We don't want variables
if ( $country_ref{type} eq "colon" ) { # Switch to the other country set
set += 1;
next;
}
push #{ $country_sets[$set] }, $country_ref;
}
The first few entries will go into $country_sets[0] which will be an array reference. After the colon (which won't be input into the set), the second set of countries will go into $country_sets[1] which will be an other array_ref to a reference of hashes:
#country_sets - Contains the input information into two sets
#country_sets[$x] - A particular set of countries (and possibly operator)
#country_sets[$x]->[$y] - A Particular country or operator
#country_sets[$x]->[$y]->{$key} - A particular value from a particular country
Where $x goes from 0 to 1. This will give you something like this:
$country_sets[0] = (
{
"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP",
},
)
$country_sets[1] = (
{
"type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP",
},
{
"type" => "operator",
"s" => "+",
"operator => "+",
},
{
"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP",
},
);
This array was passed by $this->load->var($data) with some global variables. I need to extract the array below from the associative array that var has instantiated for me. That array currently looks like this: Notice the multidimensional array below.
Dump => array(1) {
[9] => array(1) {
[0] => object(stdClass)#21 (8) {
["day"] => string(2) "09"
["eventContent"] => string(14) "slug ok"
["eventTitle"] => string(4) "Slug"
["id"] => string(1) "4"
["user"] => string(3) "CZL"
["user_id"] => string(1) "1"
["slug"] => string(4) "Slug"
["eventDate"] => string(10) "2013-07-09"
}
}
}
I need to convert it to look like this:
Notice the single dimension array below.
Dump => array(1) {
[0] => object(stdClass)#21 (7) {
["day"] => string(2) "09"
["eventContent"] => string(14) "slug ok"
["eventTitle"] => string(4) "Slug"
["id"] => string(1) "4"
["user"] => string(3) "CZL"
["user_id"] => string(1) "1"
["slug"] => string(4) "Slug"
["eventDate"] => string(10) "2013-07-09"
}
}
Besides converting the multi to a single, is there a way I could call the singular array from the multidimensional one?
I am using a foreach on the multidimensional array, but it's outputting incorrectly. Here is what I'm using. calendars is the array above that i am passing to it.
foreach ($calendars as $calendar) {
$url = calendar_link($calendar);
$string .= '<li>';
$string .= '<h3>' . anchor($url, e($calendar->eventTitle)) . ' ›</h3>';
$string .= '<p class="pubdate">' . e($calendar->eventDate) . '</p>';
$string .= '</li>';
}
function calendar_link($calendar){
return 'calendar/event/' . intval($calendar->id) . '/' . e($calendar->slug);
}
If the multidimensional array really looks exactly like your dump, then you should be able to do somthing like:
$calendar_single = $calendars[9]; // I dont know why you get 9 as array key here?
Then you should have an array with one object.
If you want to reach the object directly, try this:
$calendar_object = $calendars[9][0];
And then you foreach should work:
foreach ($calendar_object as $calendar) { ...
Not the nicest solution and it wont work if your array key (9) will change..
You could also try a more general solution that could work regardless of array key indexes:
foreach($multi as $single){
foreach($single as $object){
foreach($object as $calendar){
// YOUR CODE HERE
calendar_link($calendar); // ETC…
}
}
}