Memory leak when using curl_easy_setopt - c

Question

I have the following code:
CURL *curl;
void http_init()
{
curl = curl_easy_init();
if (!curl) return -1;
}
void http_send_message(char *msg_out, char **msg_in)
{
CURLcode res;
curl_easy_setopt(curl, CURLOPT_URL, "http://192.168.1.133:8080/tawtaw");
curl_easy_setopt(curl, CURLOPT_USERNAME, "tawtaw");
curl_easy_setopt(curl, CURLOPT_PASSWORD, "tawtaw");
curl_easy_setopt(curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC|CURLAUTH_DIGEST);
.
.
.
curl_easy_reset(curl);
}
void http_exit()
{
curl_easy_cleanup(curl);
}
int main()
{
char *msgin=NULL;
http_init();
http_send_message("message number 1", &msg_in);
free(msgin);msgin=NULL;
http_send_message("message number 2", &msg_in);
free(msgin);msgin=NULL;
http_exit();
}
If I call
curl_easy_setopt(curl, CURLOPT_URL, "http://192.168.1.133:8080/tawtaw");
and then
curl_easy_reset(curl)
and then
curl_easy_setopt(curl, CURLOPT_URL, "http://192.168.1.133:8080/tawtaw");
again, does the allocated memory in the first curl_easy_setopt get freed by curl_easy_reset(curl) or by the second call of curl_easy_setopt?
Or the memory is not freed and there is a memory leak?

Answer 1

Does the allocated memory in the first curl_easy_setopt() get freed by curl_easy_reset(curl) or by the second call to curl_easy_setopt()?
The thing is that:
It's an implementation detail.
Arising from the preceding fact, it does not/should not matter. Either one is true, proper memory management is possible in both cases.