Count tabs and check line lengths - c

I'm learning c by myself and I'm actually trying to code a program which count the numbers of TAb in a file and if a line has a tab, I want to print the whole line and the numbers of tabs in this line. And if it is not muhch more difficult, I want you to help me to do that also if a line has more than 80 characters, print this line and the numbers of characters
I have this main function:
include <stdio.h> /* printf */
/* Prototype from tablen.c */
void tablen(const char *filename);
int main(int argc, char **argv)
{
if (argc < 2)
{
printf("Usage: tablen filename\n");
printf("where: filename - file to process.\n");
return -1;
}
tablen(argv[1]);
return 0;
}
This main function is very basic so I hope there is no error there.
And this function too:
include <stdio.h> /* FILE, fopen, feof, fgets, fclose */
include <string.h> /* strlen */
void tablen(const char *filename)
{
/*Variables*/
int i; /*loop controller */
int tabs = 0; /*number of tabs*/
int line = 0; /*current line*/
int size_string; /*size of the string*/
File *file; /* open and read the file */
file = fopen(filename, "rt"); /*open the file for read text*/
size_string = strlen(filename);
/*if we can read the file*/
if(file)
{
/*while we don't reach the end of file, we still reading*/
while (!feof(file))
{
for(i = 0; i < size_string; i++)
{
if(filename[i] == 9) /*ASCII value of TAB is 9 or '\'*/
{
tabs++;
}
if(tabs > 0)
{
printf("# %i: (tabs: %i) |", line, tabs);
}
if(filename[i] == '\n')
{
line++;
tabs = 0;
}
}
}
}
}
I've write this pseudo-code, I think it is correct
For counting tabs:
First open a file for read/text
while there are more line in the file(and reading one by one) we count the number of tabs
if we found a line with tabs, print the line and the count of tabs
Of course we close the file
For checking line lengths
First open a file for read/text and hile there are more lines in the file, we heck the length of each line.
If the line is longer than 80 characters we print that line with length information
I don't know if I am in the correct way because is the first time I try to deal with files

For counting number of tabs in a line at a time, it is better to use getline() function.
getline() reads a line from file stream and returns number of characters in read line. Read manual page of getline() for more information.
You can take a look at below code for the solution to your problem
#include <stdio.h>
#include <stdlib.h>
int main(int argc,char *argv[])
{
FILE * fp;
char * line = NULL;
size_t len = 0;
ssize_t read;
int tabs=0,totaltabs=0,i;
fp = fopen(argv[1], "r");
if (fp == NULL)
exit(EXIT_FAILURE);
while ((read = getline(&line, &len, fp)) != -1) {
printf("Retrieved line of length %d\n", read);
for(i=0;i<read;i++){
if(line[i] == '\t')
tabs++;
}
if(tabs){
printf("line = %s\nNumber of tabs = %d\n",line,tabs);
totaltabs = totaltabs+tabs;
tabs=0;
}
if(read >=80)
printf("%s\n",line);
}
if (line)
free(line);
exit(EXIT_SUCCESS);
}

Related

opening and closing a text file many times and read from the continuation

I have a text file, and I open it and read one line of it, and close the text file. I'm calling my function under a for loop, but each time this function reads the first line of a text file, how can I fix it to read from the continuation
You can use fseek to reposition yourself in the file after closing and reopening, but it is very unusual to do so. So unusual, in fact, that I would suggest it is completely wrong. Here's some sample code that demonstrates how to do that, as well as a more typical loop. Each loop here reads the first 2 lines of the file, assuming each line is sufficiently small; handling long lines is beyond the scope of this question.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
FILE * xfopen(const char *path, const char *mode);
void xfseek(FILE *stream, long offset, int whence, const char *);
long xftell(FILE *stream, const char *);
void xfclose(FILE *stream, const char *);
int
main(int argc, char *argv[])
{
const char *path = argc > 1 ? argv[1] : "input";
/* Read the first two lines of the file, closing the file on each
* iteration. This is ** not ** the usual way to do this, and is
* included here for demonstration
* purposes only. DO NOT DO THIS.
* It is very unusual to close and re-open the file on each iteration.
*/
long position = 0;
for( int line = 1; line < 3; line++ ){
FILE *ifp = xfopen(path, "r");
char buf[1024];
xfseek(ifp, position, SEEK_SET, path);
fgets(buf, sizeof buf, ifp); /* (1) */
printf("line %d: %s", line, buf);
position = xftell(ifp, path);
xfclose(ifp, path); /* !! */
}
/* The more usual way to read each line of a file is to simply
* read it with repeated calls to the appropriate read method
* (fgets, fread, fgetc, etc.) Each subsequent read starts
* where the previous read finished.
*/
FILE *ifp = xfopen(path, "r");
for( int line = 1; line < 3; line++ ){
char buf[1024];
fgets(buf, sizeof buf, ifp); /* (1) */
printf("line %d: %s", line, buf);
}
xfclose(ifp, path);
return 0;
}
FILE *
xfopen(const char *path, const char *mode)
{
FILE *fp = path[0] != '-' || path[1] != '\0' ? fopen(path, mode) :
*mode == 'r' ? stdin : stdout;
if( fp == NULL ){
perror(path);
exit(EXIT_FAILURE);
}
return fp;
}
void
xfseek(FILE *stream, long offset, int whence, const char *name)
{
if( fseek(stream, offset, whence) == -1){
perror(name);
exit(EXIT_FAILURE);
}
}
long
xftell(FILE *stream, const char *name)
{
long ret = ftell(stream);
if( ret == -1 ){
perror(name);
exit(EXIT_FAILURE);
}
return ret;
}
void
xfclose(FILE *stream, const char *name)
{
if( fclose(stream) ){
perror(name);
exit(EXIT_FAILURE);
}
}
Notes: (1) It is left as an exercise for the reader how best to handle short reads (eg, when fgets returns NULL) or long lines (eg, when fgets completely fills the buffer but fails to read an entire line). Perhaps it is a bit of a cop-out to leave that as an exercise, but the annoyance of dealing with those issues points strongly towards reasons for using the standard idiom. If you want to print the first two lines of the file, use some variation of for( int count = 0; (c = fgetc(fp)) != NULL && count < 2; ) { if( c == '\n' ) count += 1; putchar(c); }. Putting the read function as a condition of the loop is (almost) always the best choice.
The comments have already made suggestions on other alternatives for what you are attempting. But regardless whether it is the right approach or not, it seems pretty clear that your stated ask is clear about wanting to use fseek() et. al to view successive lines when opening and closing a file.
To open and close a file, and each time access and display a successive line, you must first know where each of the locations to be viewed are located within that file. Indeed, as you have tagged, fseek(), (as well as ftell()) can be used to do this. The following pseudo code steps illustrate one possibility:
//store file pointer locations of each line in file:
FILE *fp = fopen(fn, "r");
if(fp)
{
for(int i = 0; i < l_cnt; i++)
{
pos[i] = ftell(fp);
fgets(line, sizeof line, fp);
}
}
fclose(fp);
Then...
//alternately open and close file to view successive lines at stored positions
for(int i = 0; i < line_cnt; i++)
{
FILE *fp = fopen(fn, "r");
if(fp)
{
fseek(fp, pos[i], 0);
fgets(line, sizeof line, fp);
printf("line %d: %s\n", i, line);
fclose(fp);
}
}
There is a more complete source and run-time example here

C program to print given number of lines from beginning of text file. File name and number of lines from command line argument

I'm writing a program said in this post title. I take reference at this webpage.
https://www.includehelp.com/c-programs/c-program-to-print-given-number-of-lines-of-a-file-like-head-command-in-linux.aspx
Here are the codes from that webpage.
#include <stdio.h>
int main(int argc, char * argv[])
{
FILE *fp; // file pointer
char *line = NULL;
int len = 0;
int cnt = 0;
if( argc < 3)
{
printf("Insufficient Arguments!!!\n");
printf("Please use \"program-name file-name N\" format.\n");
return -1;
}
// open file
fp = fopen(argv[1],"r");
// checking for file is exist or not
if( fp == NULL )
{
printf("\n%s file can not be opened !!!\n",argv[1]);
return 1;
}
// read lines from file one by one
while (getline(&line, &len, fp) != -1)
{
cnt++;
if ( cnt > atoi(argv[2]) )
break;
printf("%s",line); fflush(stdout);
}
// close file
fclose(fp);
return 0;
}
My problem is the getline function. Since I'm not using Linux that function's giving error in my compiler. I tried to change it to fgets function. This is my revised codes.
I got two errors in the line ' while (fgets(&line, bufferLength, fp) != -1)'.
Error: passing argument 1 of 'fgets' from incompatible pointer type.
Error: comparison between pointer and integer.
My question is - how can I modify the program using fgets? Many thanks to anyone who can work this out.
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char *argv[])
{
FILE *fp; // file pointer
char *line = NULL;
int bufferLength = 255;
int cnt = 0;
if( argc < 3)
{
printf("Insufficient Arguments!!!\n");
printf("Please use \"program-name file-name N\" format.\n");
return -1;
}
// open file
fp = fopen(argv[1],"r");
// checking for file is exist or not
if( fp == NULL )
{
printf("\n%s file can not be opened !!!\n",argv[1]);
return 1;
}
// read lines from file one by one
while (fgets(&line, bufferLength, fp) != -1)
{
cnt++;
if ( cnt > atoi(argv[2]) )
break;
printf("%s",line);
fflush(stdout);
}
// close file
fclose(fp);
return 0;
}
Your program should compile and run correctly follows:
//c program to print given number of lines from beginning of a file
//file name and number of lines must be supply as command line argument
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char * argv[])
{
FILE* fp; // file pointer
char* line = malloc(255);
int bufferLength = 255;
int cnt = 0;
if( argc < 3)
{
printf("Insufficient Arguments!!!\n");
printf("Please use \"program-name file-name N\" format.\n");
return -1;
}
// open file
fp = fopen(argv[1],"r");
// checking for file is exist or not
if( fp == NULL )
{
printf("\n%s file can not be opened !!!\n",argv[1]);
return 1;
}
// read lines from file one by one
while (fgets(line,bufferLength, fp))
{
cnt++;
if ( cnt > atoi(argv[2]) )
break;
printf("%s",line);
fflush(stdout);
}
// close file
fclose(fp);
free(line);
return 0;
}
we have two main problems, first
char * line = NULL;
line is a line of characters, a string if you want to call it that, so we must reserve enough memory to accommodate a complete line, and we do this with the malloc function, as seen in the program, the other problem we have with fgets, this function returns a pointer therefore we cannot compare the value returned by fgets with an integer, the declaration
while (fgets (line, bufferLength, fp))
is equivalent to running the loop while fgets is other than NULL. Finally we must use line instead of &line, the latter asks for the address of the line pointer, and not the address it points to.
There's no need to keep track of more than a single character. Reading full lines is overkill. Just do:
#include <stdio.h>
#include <stdlib.h>
FILE *
xfopen(const char *path, const char *mode)
{
FILE *fp = fopen(path, mode);
if( fp == NULL ) {
perror(path);
exit(EXIT_FAILURE);
}
return fp;
}
int
main(int argc, char **argv)
{
int count = argc > 1 ? strtol(argv[1], NULL, 10) : 1;
FILE *in = argc > 2 ? xfopen(argv[2], "r") : stdin;
int line = 0;
int c;
while( line < count && ( c = fgetc(in)) != EOF ) {
putchar(c);
if( c == '\n' ) {
line += 1;
}
}
}
Note that I've reversed the order of the arguments, so that stdin is read if only a count is given.

print 5 lines from input file

currently, I am writing code in c program for printing small portion of contents from the input file. Actually, in my code I can able to print just one single line. but, i have to print next 5 lines after that one line.
I am new to programming, please help to solve this problem**
code is given below
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int lineNumber = 2;
int main()
{
FILE *file;
char line[100];
int count = 0;
///Open LS-dyna file to read
file = fopen("P:\\tut_c\\read\\df-read\\in.txt", "r");
if (file == NULL)
{
perror("fopen");
exit(EXIT_FAILURE);
}
else if ( file != NULL )
{
char line[256];
while (fgets(line, sizeof line, file) != NULL)
{
if (count == lineNumber)
{
printf("\n str %s ", line);
fclose(file);
return 0;
}
else
{
count++;
}
}
fclose(file);
}
return 0;
}
The first logical error occurs in your while loop, first iteration, when you close the file and return 0.
Next, there is no reason to have a counter for your lines, since there are many c functions that can handle finding the end of file (eof).
Instead:
Use a while loop for iteration through the file.
Use a standard library c function for file reading.
Check if file has reached the end.
If the line is still valid, then print the line.
Here is some code to reiterate:
int main()
{
FILE *file;
file = fopen("file.txt", "r");
if (!file){ // check if file exists
perror("fopen");
exit(EXIT_FAILURE);
}
else { // if file exists, then...
char line[256];
while(fgets(line, sizeof line, file)){
printf("\n str %s ", line);
}
fclose(file);
}
return 0;
}// end main

Compare each line from two different files and print the lines that are different in C

Supposing that I have two files like this:
file1.txt
john
is
the new
guy
file2.txt
man
the old
is
rick
cat
dog
I'd like to compare first line from file1 with all the lines from file2 and verify if it exist. If not, go two the second line from file1 and compare it with all the lines from file2.. and so on until eof is reached by file1.
The output that I expect is:
john
the new
guy
How I thought this should be done:
read file1 and file2
create a function which returns the line number of each of them
take the first line from file1 and compare it to all the lines from file2
do this until all the lines from file1 are wasted
Now, I don't know what I'm doing wrong, but I don't get the result that I expect:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int countlines(char *filename)
{
int ch = 0, lines = 0;
FILE *fp = fopen(filename, "r");
if (fp == NULL)
return 0;
do {
ch = fgetc(fp);
if (ch == '\n')
lines++;
} while (ch != EOF);
if (ch != '\n' && lines != 0)
lines++;
fclose(fp);
return lines;
}
int main(int argc, char *argv[])
{
FILE *template_file = fopen(argv[1], "r");
FILE *data_file = fopen(argv[2], "r");
char buffer_line_template_file[100];
char buffer_line_data_file[100];
if (argc != 3)
{
perror("You didn't insert all the arguments!\n\n");
exit(EXIT_FAILURE);
}
if (template_file == NULL || data_file == NULL)
{
perror("Error while opening the file!\n\n");
exit(EXIT_FAILURE);
}
int counter = 0;
for (int i = 0; i < countlines(argv[1]); i++)
{
fgets(buffer_line_template_file, 100, template_file);
for (int j = 0; j < countlines(argv[2]); j++)
{
fgets(buffer_line_data_file, 100, data_file);
if (strcmp(buffer_line_template_file, buffer_line_data_file) != 0)
{
counter++;
printf("%d", counter);
}
}
}
printf("\n\n");
return 0;
}
Could someone please point me into the right direction ? For testing purposes I created a counter at the end which was a part of a small debug. There should be the print() function
As per #chux answer I got the following simplified code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
FILE *template_file = fopen(argv[1], "r");
FILE *data_file = fopen(argv[2], "r");
char buffer_line_template_file[100];
char buffer_line_data_file[100];
if (argc != 3)
{
perror("You didn't insert all the arguments!\n\n");
exit(EXIT_FAILURE);
}
if (template_file == NULL || data_file == NULL)
{
perror("Error while opening the file!\n\n");
exit(EXIT_FAILURE);
}
while(fgets(buffer_line_template_file, 100, template_file))
{
buffer_line_template_file[strcspn(buffer_line_template_file, "\n")] = '\0';
rewind(data_file);
while (fgets(buffer_line_data_file, 100, data_file))
{
buffer_line_data_file[strcspn(buffer_line_data_file, "\n")] = '\0';
if (strcmp(buffer_line_template_file, buffer_line_data_file) != 0)
{
printf("%s\n", buffer_line_template_file);
}
}
}
printf("\n\n");
return 0;
}
The above code is giving me the following output, which is not what is expected:
john
john
john
john
john
john
is
is
is
is
is
the new
the new
the new
the new
the new
the new
guy
guy
guy
guy
guy
guy
Problems with OP's code
Imprecise definition of line.
Excessive recalculation
Fuzzy determination of the number of lines in a file.
Unlike string, which has a precise definition in C, reading a line is not so well defined. The primary specificity issue: does a line contain the trailing '\n'. If the first answer is Yes, then does the last text in a file after a '\n' constitute a line? (Excessively long lines are another issue, but let us not deal with that today.)
Thus possibly some lines end with '\n' and others do not, fooling strcmp("dog", "dog\n").
The easiest solution is to read a line until either 1) a '\n' is encountered, 2) EOF occurs or 3) line buffer is full. Then after getting a line, lop off the potential trailing '\n'.
Now all lines code subsequently works with have no '\n'.
fgets(buffer_line_template_file, 100, template_file);
buffer_line_template_file[strcspn(buffer_line_template_file, "\n")] = '\0';
OP's loop is incredible wasteful. Consider a file with 1000 lines. Code will loop, calling 1000 times countlines() (each countlines() call reads 1000 lines) times when one countlines() call would suffice.
// for (int j = 0; j < countlines(argv[2]); j++)
int j_limit = countlines(argv[2]);
for (int j = 0; j < j_limit; j++)
There really is no need to count the line anyways, just continue until EOF (fgets() returns NULL). So no need to fix its fuzzy definition. (fuzzy-ness concerns same issues as #1)
int counter = 0;
for (fgets(buffer_line_template_file, 100, template_file)) {
buffer_line_template_file[strcspn(buffer_line_template_file, "\n")] = '\0';
rewind(data_file);
while ((fgets(buffer_line_data_file, 100, data_file)) {
buffer_line_data_file[strcspn(buffer_line_data_file, "\n")] = '\0';
if (strcmp(buffer_line_template_file, buffer_line_data_file) != 0) {
counter++;
printf("%d", counter);
}
}
}
Other simplifications possible - for another day.
FWIW, following counts lines of text allowing the last line in the file to optionally end with a '\n'.
unsigned long long FileLineCount(FILE *istream) {
unsigned long long LineCount = 0;
rewind(istream);
int previous = '\n';
int ch;
while ((ch = fgetc(inf)) != EOF) {
if (previous == '\n') LineCount++;
previous = ch;
}
return LineCount;
}
Note that this function may get a different result that fgets() calls. Consider a file of one line of 150 characters. fgets(..., 100,...) will report 2 lines. FileLineCount() reports 1.
[Edit] Updated code to conform to OP functionality.
int found = 0;
while (fgets(buffer_line_data_file, 100, data_file))
{
buffer_line_data_file[strcspn(buffer_line_data_file, "\n")] = '\0';
if (strcmp(buffer_line_template_file, buffer_line_data_file) == 0)
{
found = 1;
break;
}
}
if (!found) printf("%s\n", buffer_line_template_file);
This program prints the diff of two files file1.txt and file2.txt.
#include<stdio.h>
#include <stdlib.h>
#include <memory.h>
int main() {
FILE *fp1, *fp2;
int ch1, ch2;
char fname1[40], fname2[40];
char *line = NULL;
size_t len = 0;
ssize_t read;
char *line2 = NULL;
size_t len2 = 0;
ssize_t read2;
fp1 = fopen("file1.txt", "r");
fp2 = fopen("file2.txt", "r");
if (fp1 == NULL) {
printf("Cannot open %s for reading ", fname1);
exit(1);
} else if (fp2 == NULL) {
printf("Cannot open %s for reading ", fname2);
exit(1);
} else {
while ((read = getline(&line, &len, fp1)) != -1 && (read2 = getline(&line2, &len2, fp2)) != -1) {
if (!strcmp(line, line2)) {
printf("Retrieved diff on line %zu :\n", read);
printf("%s", line);
}
}
if (ch1 == ch2)
printf("Files are identical \n");
else if (ch1 != ch2)
printf("Files are Not identical \n");
fclose(fp1);
fclose(fp2);
}
return (0);
}
You already have a very good answer (and always will from chux), but here is a slightly different approach to the problem. It uses automatic storage to reading file2 into an array of strings and then compares each line in file1 against every line in file2 to determine whether it is unique. You can easily convert the code to dynamically allocate memory, but for sake of complexity that was omitted:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
enum { MAXC = 256, MAXL = 512 };
void file1infile2 (FILE *fp2, FILE *fp1, size_t *n2, size_t *n1);
int main (int argc, char **argv) {
FILE *fp1 = fopen (argc > 1 ? argv[1] : "file1.txt", "r");
FILE *fp2 = fopen (argc > 2 ? argv[2] : "file2.txt", "r");
size_t n1 = 0, n2 = 0;
if (!fp1 || !fp2) {
fprintf (stderr, "error: file open failed.\n");
return 1;
}
printf ("\nunique words in file1, not in file 2.\n\n");
file1infile2 (fp2, fp1, &n2, &n1);
printf ("\nanalyzed %zu lines in file1 against %zu lines in file2.\n\n",
n1, n2);
return 0;
}
void file1infile2 (FILE *fp2, FILE *fp1, size_t *n2, size_t *n1)
{
char buf[MAXC] = "";
char f2buf[MAXL][MAXC] = { "" };
size_t i;
*n1 = *n2 = 0;
while (*n2 < MAXL && fgets (buf, MAXC, fp2)) {
char *np = 0;
if (!(np = strchr (buf, '\n'))) {
fprintf (stderr, "error: line exceeds MAXC chars.\n");
exit (EXIT_FAILURE);
}
*np = 0;
strcpy (f2buf[(*n2)++], buf);
}
while (*n1 < MAXL && fgets (buf, MAXC, fp1)) {
char *np = 0;
if (!(np = strchr (buf, '\n'))) {
fprintf (stderr, "error: line exceeds MAXC chars.\n");
exit (EXIT_FAILURE);
}
*np = 0, (*n1)++;
for (i = 0; i < *n2; i++)
if (!(strcmp (f2buf[i], buf)))
goto matched;
printf (" %s\n", buf);
matched:;
}
}
Look over the code and let me know if you have any questions.
Example Use/Output
$ ./bin/f1inf2 dat/f1 dat/f2
unique words in file1, not in file 2.
john
the new
guy
analyzed 4 lines in file1 against 6 lines in file2.

Why wont the program read from the 2 argument file?

So the assignment is to implement a substring search program using an input file to be searched from and an input to be searched. I created the following code:
#include <stdio.h>
#include <string.h>
int main(int argc,char *argv[])
{
FILE *fp;
fp = fopen(argv[1],"r");
if (fp == NULL)
{
printf("Error");
return 0;
}
char* tmpp[100];
int count = 0;
char* nexts = argv[2];
char* tmp = fgets(tmpp,100,fp);
while(tmp = strstr(tmp,nexts))
{
count++;
tmp++;
}
printf("%d\n\n",count);
fclose(fp);
return 0;
}
The program compiles but when i go to implement it in the ubuntu terminal as:
echo "aabb" >beta
./a.out beta a
1
Why isnt the program using the first argument (argv[1]) as beta and the second argument (argv[2]) as a correctly?
You should open a file and then read bytes from that file into temporary buffer:
FILE *file = fopen("file", "r");
while (1) {
char buffer[BUFSIZ+1];
size_t nread = fread(buffer, 1, sizeof(buffer)-1, file);
if (nread == 0) break; // read error or EOF
buffer[nread] = 0;
// chunk with BUFSIZ amount of bytes is available via buffer (and is zero-terminated)
}
If you want to search for string/pattern in a file, be aware that looked pattern in file may cross your chunk-size boundary, for example: you look for "hello", and BUFSIZ is 512. File contains "hello" at byte 510. Obviously, if you read by 512, you will get the first chunk ending with "he", and the second chunk starting with "llo". Probability of this situation is nonzero for all chunk sizes (except SIZE_MAX, but that buffer size is impossible by other reasons). Dealing with borders may be very complicated.
Close...but this is closer:
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
if (argc != 3)
{
fprintf(stderr, "Usage: %s file pattern\n", argv[0]);
return 1;
}
FILE *fp = fopen(argv[1], "r");
if (fp == NULL)
{
fprintf(stderr, "Error: failed to open file %s for reading\n", argv[1]);
return 1;
}
char tmpp[1000];
int count = 0;
char* nexts = argv[2];
while (fgets(tmpp, sizeof(tmpp), fp) != 0)
{
char *tmp = tmpp;
while ((tmp = strstr(tmp, nexts)) != 0)
{
count++;
tmp++;
}
}
printf("%d\n", count);
fclose(fp);
return 0;
}
The main difference is that this loops reading multiple lines from the input file. Yours would only work on files with a single line of input.

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