I have HABTM associations between two models but can only get find to return one level. I can return several levels with other associations but think I must be missing something with HABTM.
Controller/SchedulesController.php
$this->Schedule->find('first', array(
'contain' => array(
'Association' => array(
'Schedule'
)
)
));
Model/Schedule.php
public $actsAs = array('Containable');
public $hasAndBelongToMany = array(
'Association'
);
Model/Association.php
public $actsAs = array('Containable');
public $hasAndBelongsToMany = array(
'Schedule'
);
At the moment I only get...
array(
'Schedule' => array(
...
),
'Association' => array(
(int) 0 => array(
...
'AssociationsSchedule' => array(
...
)
)
)
...but I would like Schedule -> Association -> Schedule
While contain() should work, the other option is to use the recursive option before the find like this:
$this->Schedule->recursive = 3; //2 might work, but I think you need 3 levels
$this->Schedule->find('first');
Its also worth mentioning that a similar question was asked here.
Related
I have problem with HABTM models. When I try to fetch any related model f.e. like this:
$this->Tagi->find('first');
I dont get any results for associated model. Result looks like this:
array(
'Tagi' => array(
'id' => '1',
'nazwa' => 'sth'
),
'Instytucje' => array()
)
I am sure that there should be result, I've double checked it, even
$this->Tagi->getDataSource()->getLog(false, false)
shows correct query, that fetches right results.
If you have any idea whats wrong plz give me a hint.
Tagi model:
public $hasAndBelongsToMany = array(
'Instytucje' =>
array(
'className' => 'Instytucje.Instytucje',
'joinTable' => 'instytucje-tagi',
'foreignKey' => 'tag_id',
'associationForeignKey' => 'instytucja_id',
'unique'=> true
)
);
Instytucje model:
public $hasAndBelongsToMany = array(
'Tagi' =>
array(
'className' => 'Instytucje.Tagi',
'joinTable' => 'instytucje-tagi',
'foreignKey' => 'instytucja_id',
'associationForeignKey' => 'tag_id',
'unique'=> true
)
);
EDIT:
Main problem is that HABTM refers to AppModel causing error:
Error: Table app_models for model AppModel was not found in datasource prod.
Which can be bypassed by adding $useTable in AppModel, which results in prior problem.
SOLVED
When using naming convention far beyond this Cake use, you have use third model with $useTable pointed on reference table.
Moreover its important to correctly point Cake to classes inside plugins.
I think you're problem relates to the fact that you are not using CakePHP's naming conventions. From the look of the query being generated Cake doesn't know how to correctly alias the join table, hence getting an AppModel alias in your query. I suspect that this is causing issues when Cake tries to build the results array from the query.
This might not work, but try creating a model for the joins table called InstytucjeTagi; then update your associations to use this using the with key:-
Tagi model:
public $hasAndBelongsToMany = array(
'Instytucje' =>
array(
'className' => 'Instytucje.Instytucje',
'joinTable' => 'instytucje-tagi',
'with' => 'InstytucjeTagi',
'foreignKey' => 'tag_id',
'associationForeignKey' => 'instytucja_id',
'unique'=> true
)
);
Instytucje model:
public $hasAndBelongsToMany = array(
'Tagi' =>
array(
'className' => 'Instytucje.Tagi',
'joinTable' => 'instytucje-tagi',
'with' => 'InstytucjeTagi',
'foreignKey' => 'instytucja_id',
'associationForeignKey' => 'tag_id',
'unique'=> true
)
);
If this doesn't fix it try using the afterFind() callback in the Tagi model to check what Cake is returning:-
afterFind($results, $primary = false) {
parent::afterFind($results, $primary);
// Print out the $results to check what Cake is returning.
debug($results);
return $results;
}
I'm having no luck trying to bend CakePHP to do what I need.
I have 2 Models, Listing & ListingService.
ListingService's fields are as follow: id, title, listing_id, service_type_id
(So in a way it is like a has and belongs to many relationship with Listing)
When I do a find right now. (Using belongsTo in Listing.php)
public $belongsTo = array(
'ListingService' => array(
'className' => 'ListingService',
'foreignKey' => 'id'
)
);
$this->paginate = array('type' => 'all', 'recursive' => 0,
'fields' => array('Listing.id', 'Listing.title',
'ListingService.service_type_id','ListingService.title'),
'limit' => 10
);
This is the query that is showing
SELECT `Listing`.`id`, `Listing`.`title`, `ListingService`.`service_type_id`, `ListingService`.`title` FROM `listings` AS `Listing` LEFT JOIN `listing_services` AS `ListingService` ON (`Listing`.`id` = `ListingService`.`id`) LIMIT 10
This is almost what I need, except that I would like the LEFT JOIN to be ON (Listing.id = ListingService.listing_id) instead of ON (Listing.id = ListingService.id)
If I use "hasMany" it doesn't even do the LEFT JOIN.
I don't have a ListingService.php model currently.
Please enlight.
Thank you,
Tee
Found a solution.
I need to first do this.
$this->Listing->ListingService->primaryKey = 'listing_id';
Is this a hack? If yes, is there a better way to do it?
I think your belongsTo should be like this
public $belongsTo = array(
'ListingService' => array(
'className' => 'ListingService',
'foreignKey' => 'listing_id'
)
);
I'm building a CakePHP powered website, where users can refer each other, i was thinking about a "Has and Belongs to many" relationship (A user can have multiple referrals, but can be referred only by one)
is this the right way or it's better with another association / road ?
Thanks in advance!
If I'm correct in assuming that a User can refer many, but may only be referred by one, then something like this should suffice for what you're doing:
//User model
$belongsTo = array(
'Referrer' => array(
'className' => 'User',
'foreignKey' = > 'referrer_id'
)
);
$hasMany = array(
'Referree' => array(
'className' => 'User',
'foreignKey' => 'referrer_id'
)
);
Details about Multiple relations to the same model.
An example of how to retrieve the data:
//User model
public $actsAs = array('Containable');
public $recursive = -1; //better to set in AppModel IMO
public function getUser($userId = null) {
if(empty($userId)) return false;
return $this->find('first', array(
'conditions' => array(
$this->alias . '.' . $this->primaryKey => $userId
),
'contain' => array(
'Referrer',
'Referee'
)
));
}
I have question in cakephp model,
I want to add dynamic condition in var $hasMany keyword
I want to add condition like current user_id, i got user Id after my login.
var $hasMany = array(
"AskComment"=>array('limit'=>3),
'AskStatistic',
'AskContactsLink',
'AskStatistic',
'AskObject',
'AskLikes'
);
If you want to add dynamic condition in your model, then you might have to bind the model association-ship dynamically into your controller's code. Write the following code into your controller's method for which you want to impose some new condition on the existing/new associated models.
$this->PrimaryModel->bindModel(array('hasMany' => array(
'AskComment' => array(
'className' => 'AskComment',
'foreignKey' => 'primary_id',
'conditions' => array('AskComment.user_id' => $user_id)
)
)
));
Take a look at this link: Creating and destroying associations on the fly. This will surely help you to achieve the same.
I think its better to put your association in the construct function of your Model.
like this:
/**
* #see Model::__construct
*/
public function __construct($id = false, $table = null, $ds = null) {
public $hasMany = array(
'AskComment' => array(
'className' => 'AskComment',
'foreignKey' => 'primary_id',
'conditions' => array(
'AskComment.user_id' => $user_id,
),
),
);
}
I know the solutions is simple and might have something to do with the Containable behavior but I can't get it working. Without all the tries
This is the case. I'd like to display the Event details of an Event (eg. a conference). Each event takes place in a EventVenue and each EventVenue is located in a Country.
So in the Country Model the following is present:
public $hasMany = array(
'EventVenue' => array(
'className' => 'EventVenue',
'foreignKey' => 'country_id'
))
In the EventVenue model a BelongsTo association is made
public $belongsTo = array(
'Country' => array(
'className' => 'Country',
'foreignKey' => 'country_id'
))
And in the Event model a hasOne association is made
public $hasOne = array(
'EventVenue' => array(
'className' => 'EventVenue',
'foreignKey' => 'event_id',
))
What I want is to display the country name on the page that is renderd in the EventsController. I do get all the Event and EventVenue data but the associated Country for the venue is not retrieved.
The data is retrieved in the following way
$item = $this->Event->findBySlug($slug);
How can I also get the country name (eg. Netherlands) retrieved from the database? I tried something like this but that did not work:
$item = $this->Event->findBySlug($slug,array(
'contain' => array(
'Event' => array(
'EventVenue' => array(
'Country'
)
)
)
)
Try this:
$item = $this->Event->findBySlug($slug,array(
'contain' => array(
'EventVenue' => array(
'Country'
)
)
);
Update
Turns out findBy does not support Containable. You could use this to get the desired result:
$item = $this->Event->find('first',array(
'conditions' => array(
'Event.slug' => $slug
),
'contain' => array(
'EventVenue' => array(
'Country'
)
)
);
Oh and make sure you have this in the model: public $actsAs = array('Containable');
try this method:
$this->Event->recusive = 2;
$item = $this->Event->findBySlug($slug);
You need to set the recursive to 2 before you make the find, something like this
$this->Event->recursive = 2;
with this, you'll get the Event, the EventVenue and the Country on one shot
Hope it helps