Add tables to custom query in cakephp - cakephp

Question

Im trying to replicate the following query in cakephp:
SELECT *
FROM uploads, proposals
WHERE proposals.id = uploads.proposal_id AND proposals.tender_id = 10
Im using the find method in the Upload model with the following conditions:
$conditions = array(
'Proposal.id' => $id,
'AND' => array(
'Upload.proposal_id' => 'Proposal.id'
)
);
return($this->find('list', array('conditions' => $conditions)));
but im getting this query instead
SELECT `Upload`.`id`, `Upload`.`title`
FROM `kumalabs_lic`.`uploads` AS `Upload`
WHERE `Proposal`.`id` = 10 AND `Upload`.`proposal_id` = 'Proposal.id'
as you can see, the proposals table is missing, can somebody explain me how can i make this query?
Thanks :)

Answer 1

I would recommend you use the linkable behaviour for this. It is much easier than the default way of doing joins in CakePHP. It works with the latest version of CakePHP, as well as 1.3.
CakePHP Linkable Behavior
You would then modify your find to look like this:
return($this->find('list', array(
'link' => array('Proposal'),
'conditions' => array(
'Proposal.id' => $id,
),
'fields' => array(
'Upload.*',
'Proposal.*',
),
)));
CakePHP will automatically join on your primary / foreign key, so no need to have the
'Upload.proposal_id' => 'Proposal.id'
condition.
Though you don't need that condition, I also want to point out that you are doing your AND wrong. This is how you do AND and OR in CakePHP
'conditions' => array(
'and' => array(
'field1' => 'value1', // Both of these conditions must be true
'field2' => 'value2'
),
'or' => array(
'field1' => 'value1', // One of these conditions must be true
'field2' => 'value2'
),
),

Answer 2

If the model have association, CakePHP automatically join the table by 'contain' keyword. Try code bellow:
public function getProposalsFromTender($id){
$data = $this->find('all', array(
'conditions' => array('Proposal.id' => $id),
'fields' => array('Upload.*', 'Proposal.*'),
'contain' => array('Proposal')
));
return($data);
}
Note:
CakePHP use explicit join instead of implicit join like ...from proposals, uploads...

Answer 3

I'm not familiar with that JOIN syntax but I believe it equals this:
SELECT *
FROM uploads
INNER JOIN proposals ON proposals.id = uploads.proposal_id
WHERE proposals.tender_id = 10
... so you need something similar to this:
// Untested
$conditions = array(
'Proposal.id' => $id,
'joins' => array(
array(
'alias' => 'Proposal',
'table' => 'proposals',
'type' => 'INNER',
'conditions' => 'Proposal.id = Upload.proposal_id',
),
),
);
Of course, this is a direct translation of your JOIN. If your models are properly related, it should all happen automatically.