I am building a drupal multisite, say childone and childtwo. Both have their separate databases. Now the requirement is to share some of the tables, eg. a user created in site childone must have the same access permissions in site childtwo also.
Can please anyone suggest me with the proper Stepwise solution ?
Regards
You need to use table prefixes, and settings.php explains how to accomplish this:
* You can optionally set prefixes for some or all database table names
* by using the 'prefix' setting. If a prefix is specified, the table
* name will be prepended with its value. Be sure to use valid database
* characters only, usually alphanumeric and underscore. If no prefixes
* are desired, leave it as an empty string ''.
*
* To have all database names prefixed, set 'prefix' as a string:
* #code
* 'prefix' => 'main_',
* #endcode
* To provide prefixes for specific tables, set 'prefix' as an array.
* The array's keys are the table names and the values are the prefixes.
* The 'default' element is mandatory and holds the prefix for any tables
* not specified elsewhere in the array. Example:
* #code
* 'prefix' => array(
* 'default' => 'main_',
* 'users' => 'shared_',
* 'sessions' => 'shared_',
* 'role' => 'shared_',
* 'authmap' => 'shared_',
* ),
* #endcode
So for your example, for your childone site's settings.php, you'd have something like the following:
'prefix' => array(
'default' => 'childone_',
'user' => 'shared_',
'sessions' => 'shared_',
'role' => 'shared_',
'permission' => 'shared_',
);
And for childtwo's settings.php, it's very similar:
'prefix' => array(
'default' => 'childtwo_',
'user' => 'shared_',
'sessions' => 'shared_',
'role' => 'shared_',
'permission' => 'shared_',
);
All tables will be prefixed with either childone_ or childtwo_ except the shared ones, which will be prefixed with shared_ (or whatever you want) after running the installation.
Related
I an looking to use a JOIN to select data from a table and a view in CakePHP like so :
$this->Annonces->find('all')
->where($arrFiltres)
->order($arrOrder)
->join([
'table' => 'annonces_suivis',
'alias' => 'AnnoncesSuivis',
'conditions' => [...],
]);
And would like to be able to select all the fields from the first table and som of the jointed table like so :
->select(['Annonces.*', 'AnnoncesSuivis.id']);
But this creates a faulty SQL query.
.* isn't supported by the ORM Query, it will convert this to
Annonces.* AS Annonces__*
which is invalid SQL. It would work with the lower level Database Query (Connection::newQuery()), which doesn't add aliases, however it won't return entities, so that's probably not what you want.
See Cookbook > Database Access & ORM > Database Basics > \Cake\Database\Connection::newQuery()
Pass a table object
As of CakePHP 3.1 you can pass table objects to Query::select(), which will cause all the fields of the table to be selected.
$this->Annonces
->find('all')
->select(['AnnoncesSuivis.id'])
->select($this->Annonces)
->join([
'table' => 'annonces_suivis',
'alias' => 'AnnoncesSuivis',
'conditions' => [ /* ... */ ],
])
->where($arrFiltres)
->order($arrOrder);
That way the AnnoncesSuivis.id field, and all fields of Annonces will be selected.
See Cookbook > Database Access & ORM > Query Builder > Selecting All Fields From a Table
Build the fields from the schema
That's what passing a table object will cause internally too, and it's also supported in CakePHP < 3.1.
$query = $this->Annonces->find('all');
$fields = $query->aliasFields(
$this->Annonces->schema()->columns(),
$this->Annonces->alias()
);
$query
->select(array_merge(['AnnoncesSuivis.id'], $fields))
->join([
'table' => 'annonces_suivis',
'alias' => 'AnnoncesSuivis',
'conditions' => [ /* ... */ ],
])
->where($arrFiltres)
->order($arrOrder);
This would also work for the fields option that can be passed to Table::find(), though you'd have to use a separate query object in that case, like
$fields = $this->Annonces->query()->aliasFields(
$this->Annonces->schema()->columns(),
$this->Annonces->alias()
);
$this->Annonces->find('all', [
'fields' => array_merge(['AnnoncesSuivis.id'], $fields)
// ...
]);
Use Query::autoFields()
In ealier CakePHP version, you could also make use of Query::autoFields(), which, when set to true, will automatically include the fields of the main table and possible containments.
See Cookbook > Database Access & ORM > Retrieving Data & Results Sets > Passing Conditions to Contain
Auto selecting all fields is the default behavior until you set fields via Query::select(), in that case you'll have to explicitly enable Query::autoFields().
$this->Annonces
->find('all')
->select(['AnnoncesSuivis.id'])
->autoFields(true)
->join([
'table' => 'annonces_suivis',
'alias' => 'AnnoncesSuivis',
'conditions' => [ /* ... */ ],
])
->where($arrFiltres)
->order($arrOrder);
This should give you the desired query, however as mentioned this will only work for the main table and containments, if you'd wanted to include all fields of a manually joined table, then you'd have to specify them one by one.
You also can create virtual field in Entity:
namespace App\Model\Entity;
use Cake\ORM\Entity;
class User extends Entity {
protected function _getFullName() {
return $this->_properties['first_name'] . ' ' . $this->_properties['last_name'];
}
}
echo $entity->full_name;
I've a legacy SQLite 2 database I need to work with. Does Doctrine 2.4 support SQLite 2? I've tried to open a test.sqlite database; listing all tables doesn't work:
$conn = Doctrine\DBAL\DriverManager::getConnection(
array(
'driver' => 'pdo_sqlite',
'user' => null,
'password' => null,
'path' => '/path/to/test.sqlite'
),
new Doctrine\DBAL\Configuration()
);
$sm = $conn->getSchemaManager();
var_dump($sm->listTableNames()); // Empty array
No errors, just an empty array.
I want to copy 4 tables, deep associated:
Test->Scale->Question->Option
into
TestResult->ScaleResult->QuestionResult->OptionResult
In TestResult and OptionResult I want to add some new columns and also I need to have id of each 'has many' table to put it into each of 'belongs to' table.
So when I use find() I want to add aliases to result returned by Cake.
Yes, that is possible. You can provide the alias in the $hasMany, $belongsTo, etc.
public $hasMany = array(
'ImagesAlias' => array(
'className' => 'Image',
'foreignKey' => 'car_id'
)
);
You can read everything about it in the documentation
Project hasMany Comments
Payment (id, project_id, value, date)
I want to include in my index view a column equal to the sum of payments per project. I want to be able to sort by this field.
I've found some similiar problems here but neither of them concerns pagination.
My current (wrong) solution:
$this->paginate = array('Project' => array(
'conditions' => array('Project.archived =' => $archive),
'order' => 'Project.start_date DESC',
'contain' => array(
'Payment' => array(
'fields' => array('SUM(Payment.value) as Project__value_sum'),
'group' => array('Payment.project_id'),
)
)
));
$data = $this->paginate('Project');
$this->set('projects', $data);
$this->set('archive', $archive);
Seems like you'll probably want to do an afterSave on the Payment model.
Within the afterSave function, you run some MySQL that totals the payments (using MySQL SUM()) for the related Project, and store it in Project.payment_total.
Then, you can easily sort by that field, and it keeps you from having to run complex MySQL on every page, since it will only run when necessary (ie when there's a new or changed payment)
I am trying to 'tag' multiple 'points' with multiple tags. I'm tagging my single points successfully. Unfortunately, when i try and use a tag, such as 'test2' on another point as a tag it is either giving me a duplicate entry error if i have my 'unique' set to false or if 'unique' is set to true, it will del my tag for all other points for 'test2' and create a single new one.
Here is what i have for my post data:
Array
(
[Tag] => Array
(
[id] => 4b7af6d7-787c-4f10-aa49-2502c0a80001
[name] => Test2
)
[Point] => Array
(
[id] => 4b47c66f-a130-4d12-8ccd-60824051e4b0
)
)
In my tag model i have this:
public $hasAndBelongsToMany = array(
'Point' => array(
'className' => 'Point',
'joinTable' => 'points_tags',
'foreignKey' => 'tag_id',
'associationForeignKey' => 'point_id',
'unique' => false)
);
I have tried this with 'unique' set as true, too. Unfortunately, this will delete any other instances of 'Test2' in the join table ('points_tags').
I have tried this using both save() and saveAll(). Both are giving me this error:
Warning (512): SQL Error: 1062: Duplicate entry '4b7af6d7-787c-4f10-aa49-2502c0a80001-4b47c66f-a130-4d12-8ccd-608' for key 'MAN_ADD' [CORE/cake/libs/model/datasources/dbo_source.php, line 527]
Query: INSERT INTO points_tags (tag_id,point_id,id) VALUES ('4b7af6d7-787c-4f10-aa49-2502c0a80001','4b47c66f-a130-4d12-8ccd-60824051e4b0','4b7b39f3-46f8-4744-ac53-3973c0a80001')
Thoughts????
Suggestions????
Where does the id come from? I'm guessing its a primary key of the table, and from what I understand from your post (please write more clearly, help us help you) the problem isn't with points or tags, but with the id in the points_tags table.
When you use the save method, are you doing it inside of a loop? Remember, best practice is to call model::create() whenever you're saving in a loop.
I frequently find that when I have issues with the HABTM saving behavior, it's because I didn't call model::create.