Printing #define'd constants - c

Question

#include<stdio.h>
#define UPPER 999999
#define LOWER 11111
int main(void)
{
// Local Declarations
double price = 89.99;
char grade = 'B';
int age = 97;
// Statements
printf("Homework 2:\n\nUsing printf\n");
printf(" age = %c, age\n");
printf("grade = %d, grade\n");
printf("price = %f, price\n\n");
printf("Using both printf and scanf\n");
printf("Enter a new value for age: ");
scanf("%d", &age);
printf("Enter a new value for grade: ");
scanf("%c", &grade);
printf("Enter a new value for price: ");
scanf("%lf", &price);
printf("Print the new values\n");
printf(" age = %d \n", age);
printf("grade = %c\n", grade);
printf("price = %lf\n\n", price);
print("\n\nPrinting two defined constants: "UPPER" and "LOWER"\n");
print("UPPER = %08d\n", UPPER);
print("LOWER = %08d\n", LOWER);
return 0;
} // end of main
Above is my programme and im supposed to fix it. I've been at it for almost 3 hours now still can figure out the problem. I've got a error and a few warnings.
warning: too few arguments for format
Several warnings for the statements in the mid body
error: expected ')' before numeric constant
this error is for printing two constants.

Answer 1

print("\n\nPrinting two defined constants: "UPPER_S" and "LOWER_S"\n");
would only work if UPPER_S and LOWER_S were #defined as:
#define UPPER_S "999999"
#define LOWER_S "11111"
Alternatively you could use the two following macros to "stringify" the numerical #defines:
#define _STRINGIFY(s) #s
#define STRINGIFY(s) _STRINGIFY(s)
and then do:
#define UPPER 999999
#define LOWER 11111
fputs("\n\nPrinting two defined constants: "STRINGIFY(UPPER)" and "STRINGIFY(LOWER)"\n", stdout);

Answer 2

I came here looking for the answer to this question and it seems most people just got hung up on syntax errors rather than caring what the actual question is. You can use printf with #defined values as though they are normal variables. However you must pay close attention to the type.
#define HEXNUM 0xA8
#define NUMBER 129
#define STRING "somestring"
#include <stdio.h>
int main(void) {
printf("hex number: %x\n", HEXNUM);
printf("number: %d\n", NUMBER);
printf("string: %s", STRING);
return 0;
}

Answer 3

Things like
printf("grade = %d, grade\n");
expect an argument for '%d'. It should be in the form of
printf("grade = %d\n", grade);

Answer 4

You need to put your printf args outside of quotes.
Current:
// Statements
printf("Homework 2:\n\nUsing printf\n");
printf(" age = %c, age\n");
printf("grade = %d, grade\n");
printf("price = %f, price\n\n");
Should be:
// Statements
printf("Homework 2:\n\nUsing printf\n");
printf(" age = %c\n", age);
printf("grade = %d\n", grade);
printf("price = %f\n\n", price);

Answer 5

One method is to assign the constant defined variable value to a local variable value. This way it will be useful in printf("%d", X); method.
However, you could use const int EXAMPLE=12, and then EXAMPLE could be used in the standard printf method, e.g. printf("%d\n", EXAMPLE);