I have thousands of files to move.
I have already used a batch file to create the directories I need.
My file names look like this:
6711_05_12.pdf
10504_06_15.pdf
559_07_11.pdf
The first characters up to the "_" are the directory the files need to go into. Started the batch file - but don't know how to identify the file name.
#echo off
setlocal EnableDelayedExpansion
for %%I in (*.pdf) do (
xcopy ???
)
Is there a manual for batch files?
You don't even need a batch file. The following one line command will do the trick.
for %I in (*.pdf) do #for /f "eol=_ delims=_" %A in ("%I") do #copy "%I" "%A"
Simply double up the percents if you want to put the command in a batch file.
Related
I have ~10,000 files in one folder. I want to copy specific files to specific folders based on a text file. Is it possible to use a semicolon delimited text file where the first part of each line is the source path & file name and the second part is the destination path?
C:\Files\File1.txt;C:\Folder1
C:\Files\File2.txt;C:\Folder2
C:\Files\File3.txt;C:\FolderN\
What would the code look like? Is there a better way to achieve the same result?
I have an existing bat file I use to copy all of the files listed in a text file to one specific folder location (below) but in this case I need to send different files to different folders and I would rather not run my bat file 50 times, changing the destination path in the bat file each time...
for /f %%f in (%1) do (
copy %%f G:\Files\PutFilesHere
)
It looks like this:
#echo off
setlocal enableextensions enabledelayedexpansion
for /f "usebackq delims=; tokens=1,2" %%I in (`type filelist.txt`) do (
copy /y %%I %%J
)
goto :eof
The for loop is told to use the result of a command (usebackq, for command type filelist.txt), to split at each ;, and to take elements #1 and #2. The fist is named as the variable (%%I, take care, case sensitive), and the second is the next letter, so %%J.
Then, the copy is trivial.
for /f "tokens=1,2delims=;" %%f in (%1) do ( copy "%%f" "%%g" )
see for /? from the prompt for documentation
I would like to append my folder name to all the available .txt files inside a subfolder. Below is the file/directory structure. I need to achieve this in Windows BATCH script.
C:\Source\Source1\1\a.txt C:\Source\Source1\1\b.txt
C:\Source\Source1\2\a.txt C:\Source\Source1\2\b.txt
C:\Source\Source2\3\a.txt C:\Source\Source2\3\b.txt
The above files should be renamed like below:
C:\Source\Source1\1\1_a.txt C:\Source\Source1\1\1_b.txt
C:\Source\Source1\2\2_a.txt C:\Source\Source1\2\2_b.txt
C:\Source\Source2\3\3_a.txt C:\Source\Source2\3\3_b.txt
Similary, I have Source1...Source30 and under each source directory, I will have multiple folders with different numbers. I need to rename all the files under these directories and append the number(directory name) to the file name.
So far below is what I wrote:
for %%* in (.) do set CurrDirName=%%~nx*
echo %CurrDirName%
for /r %%x in (*.txt) do ren "%%x" "%CurrDirName%_%%x"
With this, I am able to achieve it in a single directory. I couldn't make it recursive. Could you guys please help me with this.
#echo OFF
SETLOCAL EnableExtensions
for /F "delims=" %%G in ('dir /B /S "C:\Source\*.txt"') do (
for %%g in ("%%~dpG.") do ECHO rename "%%~fG" "%%~nxg_%%~nxG"
)
pause
where the FOR loops are:
outer %%G loop creates a static list of .txt files (recursively), and
inner %%g loop gets the parent folder of every particular file.
The rename command is merely displayed using ECHO for debugging purposes. To make it operational, remove word ECHO (no sooner than debugged).
Moreover, I'd consider checking whether a particular file is already renamed…
I have a batch file that lists the full file directories (including filename at the end) onto a csv file. I need it to produce this, but also just the filename in a separate column. I would like it so that the format is Filename in first column (including extension) and full file directory in second column. The batch file I currently have is:
dir C:\Users\Administrator\Desktop\test\Files\*.tif /b /s >>
C:\Users\Administrator\Desktop\test\Output.csv
EDIT: I forgot to mention the 'Files' folder contains many subfolders so I need it to process all files from all these subfolders.
Thanks in advance.
You just need to do this:
#echo off
setlocal
set "in=C:\Users\Administrator\Desktop\test\Files\*.tif"
set "out=C:\Users\Administrator\Desktop\test\Output.csv"
if not exist "%out%" type nul>"%out%"
for /f "delims=" %%a in ('dir /b/s %in%') do (
>>%out% echo "%%~nxa","%%a"
)
Iterate and write (help for for info on the %~ variable modifiers):
#echo off
cd C:\Users\Administrator\Desktop\test\Files
for %%f in (*.tif) do echo "%%~nxf","%%~dpf" >> Output.csv
I have a case where I have to move over 15,000 files. There are many duplicates, so I parsed them by MD5 and now I have a list of file names in an input file (files.txt).
I want to read from it, then copy the listed files to a new directory.
I pulled an old batch that someone had written as a two-part simple script and modified it.
It works for files without spaces. How can I get this to cover all file names?
Also, can't I put all of this into one file?
Cstart.bat:
for /f %%x in (files.txt) do call copyfiles.bat
copyfiles.bat:
set filename=%1
copy "C:\temp\%filename%" "C:\temp\pruned files\"
Your current code doesn't even pass the filename to copyfiles.bat, so it's not working with or without spaces. (If you need to confirm that, add echo %1 %filename & pause before the copy line in copyfiles.bat and run cstart.bat.)
With that being said, you can do it all in one file easily:
for /f %%x "tokens=1 delims=*" in (files.txt) do copy "C:\Temp\%%x" "C:\Temp\pruned files\%%x"
To make sure it works, just replace the copy in the line above with echo and run it from a command prompt.
I tested this with a text file named test.txt that contained the following:
One.txt
Two.txt
Three.txt
And Four.txt
with a batch file named testcopy.bat containing this:
#echo off
for /f "tokens=1 delims=*" %%x in (test.txt) do echo "C:\Temp\%%x" "C:\Temp\test this\%%x"
The above test showed this output:
e:\TempFiles>testcopy
"C:\Temp\One.txt" "C:\Temp\test this\One.txt"
"C:\Temp\Two.txt" "C:\Temp\test this\Two.txt"
"C:\Temp\Three.txt" "C:\Temp\test this\Three.txt"
"C:\Temp\And Four.txt" "C:\Temp\test this\And Four.txt"
for /f "usebackqdelims=" %%x in ("my file list.txt") do copy "C:\temp\%%~x" "C:\temp\pruned files"
I have a batch script which unzip and renames each file.
Unfortunately I now need to keep the filename of the zip file it came from.
Example Jazz1.zip now unzips and the outcoming text file becomes 1.Jazz1.zip.txt.
So I want %%F to become %%F - 4- characters.
Unfortunately I want it to be Jazz1.txt.
::Setup the stage...
SETLOCAL ENABLEDELAYEDEXPANSION
SET folder=C:\P\DataSource2_W
SET count=1
::Action
CD "%folder%"
FOR %%F IN ("*.zip") DO (
"C:\Program Files (x86)\WinZip\wzunzip" %%F
MOVE *.txt "C:\P\DataSource2_W\TextFiles\!count!%%F.txt"
SET /a count=!count!+1
)
ENDLOCAL
I do not understand what you are trying to do with the COUNT variable, nor do I understand how you are handling a ZIP file with multiple .TXT files.
But I do understand that you want the base name of each ZIP file, (name without the extension). That is easy - simply use the ~n modifier (type HELP FOR from the command prompt for more info).
So if %%F = Jazz1.zip, then %%~nF yields Jazz1