To retrieve groups belonging to all users I am using following filter:
(&(objectclass=*)(member:1.2.840.113556.1.4.1941:=cn=sam,DC=aaaldap,DC=com))
And, i am able to retrieve multiple DN entries like:
1. GOT ENTRY: DN => CN=group1,CN=Users,DC=aaaldap,DC=com
LDAP: Attribute Length Valueldap_get_dn
1d21h: LDAP: cn 6 group1
2. LDAP: GOT ENTRY: DN => CN=group2,CN=Users,DC=aaaldap,DC=com
LDAP: Attribute Length Valueldap_get_dn
1d21h: LDAP: cn 6 group2
All i am interested is in group membership, so i want to parse the attribute CN received in the entry and would like to assume this as a group.
Can someone suggest if this will be a valid assumption of parsing CN attribute and mark its value as "group" membership to which it belongs to?
You should specify a real objectClass instead of just *, to limit the search to whatever object class you are using for groups. Then anything you get back must be a group. The search may also run faster.
Related
I'm trying to search active directory users whose manager's username is given in the search request, but I always get 0 records regardless of the manager's username I pass.
To achieve this, I executed the following LDAP query:
(manager=sAMAccountName=Administrator)
I also tried by manager's common name like this:
(manager=cn=John Smith)
Can anyone write me an LDAP query that returns all users whose manager's sAMAccountName=administrator ?
manager has distinguished name syntax, therefore, if manager is used in an assertion, the full DN must be used as the value. Neither of the examples you gave meet this criteria. You must correct the filter to use a distinguished name.
The syntax of manager:
attributeTypes: ( 0.9.2342.19200300.100.1.10 NAME 'manager'
EQUALITY distinguishedNameMatch SYNTAX 1.3.6.1.4.1.1466.115.121.1.12
X-ORIGIN 'RFC 4524' )
To determine the syntax, use the LDAP Parameters Assignment page. On that page, search for the OID following the SYNTAX keyword (1.3.6.1.4.1.1466.115.121.1.12). That shows that it's DN syntax. Also, the EQUALITY matching rule is distinguishedNameMatch.
An example of an assertion in a filter using the correct syntax:
manager=cn=Manager Number One,ou=managers,ou=people,dc=example,dc=com
All attributes values used in an assertion must have the syntax defined for that attribute type in the schema.
Update
Verify the entries exist with a known good tool such as ldapsearch to ensure that the correct parameters are known for the search request. For example:
$ ldapsearch -h hostname -p port -b 'dc=sahara,dc=local' \
-D [your-bind-dn] -w [your-bind-dn-password] \
-s sub \
'(manager=cn=Izzeddeen Alkarajeh,ou=managers,ou=people,dc=sahara,dc=local)' \
1.1
If this search returns no entries, check with the LDAP administrators to ensure that the BIND DN in use has permission o read those entries.
see also
LDAP: Mastering Search Filters
LDAP: Search best practices
LDAP: Programming practices
I know this is old but I figured out a way to do this in C# that I have yet to find on stackoverflow.
using (var pc = new PrincipalContext(ContextType.Domain, "yourdomain.com"))
using (var user = UserPrincipal.FindByIdentity(pc, IdentityType.SamAccountName, "samAccountName"))
{
DirectoryEntry de = (DirectoryEntry)user.GetUnderlyingObject();
if (de.Properties["directReports"].Count != 0)
managedFound = de.Properties["directReports"];
}
This will give you a list of strings that you can then parse out the CN using this:
managedUserName = Regex.Match(managedFound.ToString(), #"CN[=].*?[,]").Value.Replace("CN=", "").Replace(",", "");
Then, the following to get the User properties:
UserPrincipal managedUser = UserPrincipal.FindByIdentity(pc, IdentityType.Name, managedUserName);
I am working with a customers Active Directory which has a lot of cruft in it. There are hundreds of Users with empty givenName and sn attributes. I would like to filter any records that have an empty sn or an empty givenName from my query results as those records cannot be processed by my application.
This works as per my requirements but I believe there must be a better way to do it:
(&(objectClass=User)(|(!(!(sn=*))))(!(!(givenName=*)))))
Is there a more clear and concise way to accomplish this with an ldap query?
sn and givenName have as their superior the name attribute, which is of DirectoryString syntax, that is, the syntax is 1.3.6.1.4.1.1466.115.121.1.15. Attributes which are of syntax DirectoryString are not allowed to be null, that is, a DirectoryString is required to have at least one character.
The filter sn=* is a present filter (not a substring or regular expression), meaning that the entry would be filtered out of the possible search results if the sn attribute is not present (if it is present, it must have at least one character). Same for givenName=*.
A simpler filter might be '(&)', where the search request contains the following in its list of attributes to be returned: #User, which will return all attributes in the User objectClass for each entry that matches the filter, then have the application extract the sn and givenName attributes from each entry that is returned. If the number of entries returned is large, use the Simple Paged Results Request Control to throttle the number of entries returned to a more manageable value.
Or ... it might be that Active Directory is not LDAP compliant and does not support the inetOrgPerson objectClass and syntaxes of attributes therein correctly and does allow empty or null attributes values for DirectoryString attributes, though I can't imagine Microsoft would deliver a product that is not LDAP compliant.
see also
LDAP Programming Practices
RFC 4519
(!(!(givenName=*))) = (!givenName=*)
https://technet.microsoft.com/en-us/library/ee198810.aspx
I would like to write a search filter which would help me retrieve all groups which a user is part of.
For instance:
Say I am retrieving entries for user A (which is part of group A). And group A may be part of group B and group D which in turn may be part of group E.
Now, my search filter should return me MemberOf attribute as all possible groups which user A is part of (in this specific case it is Group A, B, D, E).
Any pointers on how the search filter can look like?
This should do what you are asking about. It will return the FDN of each group the user is a memberOf, however, this queries the group, not the user.
As an example, to find all the groups that "CN=John Smith,DC=MyDomain,DC=NET" is a member of, set the base to the groups container DN; for example (OU=groupsOU,DC=MyDomain,DC=NET) and the scope to subtree, and use the following filter.
(member:1.2.840.113556.1.4.1941:=(CN=John Smith,DC=MyDomain,DC=NET))
-jim
There is an attribute called tokenGroups in user object. It's a constructed attributes calculated by Active Directory on the runtime. It includes all the groups the user object belong to.
Make sure your domain has a Global Catalog and make sure the account that you are using Pre-Windows 2000 Compatible Access group. Then, make sure tokenGroups is specified as one of the returned property. Do a base scope search on the user object.
You can use adfind.exe (joeware) to sort out this issue and to utilize standard ldap filters that are described here. For example:
http://social.technet.microsoft.com/wiki/contents/articles/5392.active-directory-ldap-syntax-filters.aspx
Group nesting is specified to be like this:
(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)
and if you use adfind, then it would look like this:
adfind -f "(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)" samaccountname -list
If you want to have output other than samaccountname, for example displayname, or mail attribute, just add to the list. Also if you want to search multiple users, then you might want to have inputfile containing all users and some script to extract each lines to adfind for example.
I have a scheme that looks like this:
Users exist like UserA, UserB, UserC.
Groups exist like OverGroup, SubGroup.
OverGroup automatically adds new users like UserA, UserB, etc. to its membership.
SubGroup I created myself. I have set OverGroup to be a member of SubGroup.
I want to be able to one-line query SubGroup and retrieve not OverGroup, i.e.:
Values:
CN=OverGroup,OU=Groups,DC=example,DC=com
but the full enumeration of the actual Users (User A, B, C) within OverGroup, i.e.:
Values:
CN=UserA,OU=OtherOU,DC=example,DC=com
CN=UserB,OU=OtherOU,DC=example,DC=com
CN=UserC,OU=OtherOU,DC=example,DC=com
Is there a one-liner LDAP filter that could retrieve this? (It will be put into the ExternalAuth configuration 'ldap' section in a Request Tracker instance. Pretty sure I can only do this with one query the ExternalAuth module can understand.)
Everything I try does not work, and from my reading, it does not seem possible to enumerate a list of users within a group that is a member of another group with any one-line query. Thoughts?
Active Directory has a special search filter option that allows it to filter through chained objects, like nested groups. The capability is described here.
Here is an example of how to retrieve all users in a group, including nested groups:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:={0}))
where {0} is the DN of the parent group.
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=MPV_BedPlacement,OU=Security Groups,OU=Groups,OU=CCHCS,DC=CCHCS,DC=LDAP))
You have to add the full DN for the group and no curly braces.
How do I filter an Active Directory LDAP query to groups containing the authenticated/bound user (or any user at all)? This works fine:
(&(objectClass=group)(member=*))
>>> lots of results
But I can't go any more detail:
(&(objectClass=group)(member=*S*))
>>> nothing
The MSDN mentions using a filter like this:
(member:1.2.840.113556.1.4.1941:=(cn=user1,cn=users,DC=x))
But even ignoring the crazy hyper magic number involved in that, I always get 0 results when I try to filter with that (even replacing cn=user1,cn=users,DC=x with my own distinguishedName, even replacing it with *).
You need the full DN of the user i.e
(&(member=CN=Your Name,OU=Your OU,DC=company,DC=com)(objectClass=group))
take note you cannot use * in this one
So the crazy hyper magic number involved in recursive search is explained in Search Filter Syntax.
To find in one search (recursively) all the groups that "user1" is a member of:
Set the base to the groups container DN; for example root DN (dc=dom,dc=fr)
Set the scope to subtree
Use the following filter: (member:1.2.840.113556.1.4.1941:=cn=user1,cn=users,DC=x)
explicited using LDIFDE.EXE the command line tool included in Windows Server it gives:
ldifde -f user1Grps.ldf -d "dc=societe,dc=local" -r "(member:1.2.840.113556.1.4.1941:=cn=user1,ou=Monou,dc=societe,dc=local)"
If you are running that on a W2K8 or W2K8 R2 server be careful to run as administrator.
If you are programming in C# you can use:
/* Retreiving a principal context
*/
Console.WriteLine("Retreiving a principal context");
PrincipalContext domainContext = new PrincipalContext(ContextType.Domain, "WM2008R2ENT:389", "dc=dom,dc=fr", "jpb", "PWD");
/* Look for all the groups a user belongs to
*/
UserPrincipal aUser = UserPrincipal.FindByIdentity(domainContext, "user1");
PrincipalSearchResult<Principal> a = aUser.GetAuthorizationGroups();
foreach (GroupPrincipal gTmp in a)
{
Console.WriteLine(gTmp.Name);
}