I am trying to display records which have their date (I have a column Date in table) 30 days back from today's date. And once it gets displayed I need to make a new record by adding details with Date= today's date..
I tried this:
select * from
paymenthist
where
Date = CONVERT(datetime, CONVERT(varchar, DATEADD(day, -30, GETDATE()), 101))
But all records are getting displayed..
Ok, I admit the way I suggested may be inefficient, but if one is a datetime and the other is a date then I believe this will be more efficient than the >= <= approach because SQL is often not great at utilising indexes for queries like this, and under the covers a datetime is actually a floating point, so for pure efficiency, try this:
CREATE TABLE ##PaymentHistory
(
ID INT IDENTITY,
[Date] DATETIME,
Col1 INT,
Col2 INT
)
INSERT INTO ##PaymentHistory([Date],Col1,Col2)
VALUES(FLOOR(CAST(GETDATE() -29 AS FLOAT) ) ,1,1)
, (FLOOR(CAST(GETDATE() -30 AS FLOAT) ) ,2,2)
, (FLOOR(CAST(GETDATE() -31 AS FLOAT) ) ,3,3)
SET IDENTITY_INSERT ##PaymentHistory ON
INSERT INTO ##PaymentHistory(ID, [Date], Col1, Col2)
SELECT ID, GETDATE(), Col1, Col2
FROM ##PaymentHistory
WHERE CAST(Date AS FLOAT) = FLOOR(CAST(GETDATE() -30 AS FLOAT) )
SET IDENTITY_INSERT ##PaymentHistory OFF
It depends somewhat on the datatype of the date column, but try this.
select * from paymenthist where cast(Date as date) = cast(DATEADD(day, -30, GETDATE()) as date)
Related
I wrote a query that should select the last record of each month in a year. I'd like to create a View based on this select, that I could run later in my project, but unfortunately I can't use any while loops or variables in a view command. Is there a way to select all these records - last days of a month in a View that I can use later?
My desired effect of the view:
The query that I'm trying to implement in a view:
DECLARE #var_day01 DATETIME;
DECLARE #month int;
SET #month = 1;
DROP TABLE IF EXISTS #TempTable2;
CREATE TABLE #TempTable2 (ID int, date datetime, INP2D float, INP3D float, ID_device varchar(max));
WHILE #month < 13
BEGIN
SELECT #var_day01 = CONVERT(nvarchar, date) FROM (SELECT TOP 1 * FROM data
WHERE DATEPART(MINUTE, CONVERT(nvarchar, date)) = '59'
AND
MONTH(CONVERT(nvarchar, date)) = (CONVERT(nvarchar, #month))
ORDER BY date DESC
) results
ORDER BY date DESC;
INSERT INTO #TempTable2 (ID, date, INP2D,INP3D,ID_device)
SELECT * FROM data
WHERE DATEPART(MINUTE, CONVERT(nvarchar, date)) = '59'
AND
MONTH(CONVERT(nvarchar, date)) = (CONVERT(nvarchar, #month))
AND
DAY(CONVERT(nvarchar, date)) = CONVERT(datetime, DATEPART(DAY, #var_day01))
ORDER BY date DESC
PRINT #var_day01
SET #month = #month +1;
END
SELECT * FROM #TempTable2;
If you are actually just after the single most recent row for each month, there is no need for a while loop to achieve this. You just need to identify the max date value for each month and then filter your source data for those for those rows.
One way to achieve this is via a row_number window function:
declare #t table(id int,dt datetime2);
insert into #t values(1,getdate()-40),(2,getdate()-35),(3,getdate()-25),(4,getdate()-10),(5,getdate());
select id
,id_device
,dt
from(select id
,id_device
,dt
,row_number() over (partition by id_device, year(dt), month(dt) order by dt desc) as rn
from #t
) as d
where rn = 1;
You can add a simple where to your select statement, in where clause you will add one day to the date field and then select the day from the resultant date. If the result date is 1 then only you will select that record
the where clause for your query will be : Where Day(DATEADD(d,1,[date])) = 1
I have query which returns hourly data. But I want to get daily data from this query, so all the hourly data per day would be averaged to daily data.
declare #Days int
set #Days = -1
select
dateadd(hour,datepart(hour,Timestamp),cast(CAST((Timestamp) as date) as datetime)) as [Time]
,[value]
from [Employee]
where dateadd(hour,datepart(hour,Timestamp),cast(CAST((Timestamp) as date) as datetime)) >= CONVERT(date, DATEADD(DAY, #Days, GETDATE()))
Assuming you have additional columns you want to average and group by date, you can try something like:
DECLARE #Days int = -1;
SELECT
CAST(Timestamp AS date) AS date
, AVG(Value) AS Value
FROM [Employee]
WHERE Timestamp >= DATEADD(day, #Days, CAST(GETDATE() AS date))
GROUP BY CAST(Timestamp AS date)
ORDER BY date;
Note the refactored WHERE clause that avoids applying a function to the column value. This will allow an index on Timestamp to be used efficiently (sargable expression).
I have CreatedDate as datetime column in my database table. I want to fetch the rows where CreatedDate and current time difference is more than 1 hour
Select * from TableName where (DateDiff(hh,CreatedDate,GetDate())>1
Answer by #Amit Singh works if you only care about the hour value itself, versus any 60 minute period.
The problem with using DATEDIFF(hh) that way is that times of 13:01 and 14:59 are only one "hour" apart.
Like:
select datediff(hh,'1/1/2001 13:59','1/1/2001 14:01')
I think doing this would address that issue:
declare #cd datetime='9/12/2013 03:10';
declare #t table(id int,CreatedDate datetime);
insert #t select 1,'9/12/2013 02:50';
insert #t select 2,'9/12/2013 02:05';
select * from #t where #cd>(DateAdd(hh,1,CreatedDate))
Dan Bellandi raises a valid point, but if it really matters if the dates should be 60 minutes apart, then just check if they are 60 minutes apart:
SELECT * FROM TableName WHERE DATEDIFF(MINUTE, DateColumnName, GETDATE()) >= 60
If you don't expect any rows created in the future...
where CreatedDate < dateadd(hour, -1, getdate())
CREATE TABLE trialforDate
(
id INT NULL,
NAME VARCHAR(20) NULL,
addeddate DATETIME NULL
)
INSERT INTO trialforDate VALUES (1,'xxxx',GETDATE())
INSERT INTO trialforDate VALUES (2,'yyyy',GETDATE())
INSERT INTO trialforDate VALUES (1,'zzzz','2013-09-12 11:20:40.533')
SELECT *
FROM trialforDate
WHERE GETDATE() > DATEADD(HOUR, 1, addeddate)
C# Code
DateTime param1= System.DateTime.Now;
DateTime param2= System.DateTime.Now.AddHours(1);
SQL Query:
SELECT * FROM TableName WHERE CreatedDate = param1 AND CreatedDate =param2;
I would like to compare datetime datatype, like "20/12/2011 00:00:00", with compound string date format (I mean that it is composed of string of date, string of month and string of year).
For example, coloumn entime is datatime datatype which is stored "20/12/2011 00:00:00" data and other three column(date,month,year respectively) are string. so I want to compare between entime column with the date,month and year composed together, How I can write SQL Command to suppurt the above requirement ?
Hope you can help me ?
The best option is to convert the datetime to string and then make the needed comparisons.
You can see here how to make the conversion.
There is also the DATEPART function as an alternative.
SELECT *
FROM DateTable
WHERE
DATEPART(YEAR, [DATECOLUMN]) = #YearString
AND DATEPART(MONTH, [DATECOLUMN]) = #MonthString
AND DATEPART(DAY, [DATECOLUMN]) = #DayString
You can go below way, would you please try it out, thanks
SET DATEFORMAT DMY
SELECT CAST(CONVERT(VARCHAR(15), GETDATE(), 105) AS DATETIME)
SELECT CAST(('20'+'-'+'12'+'-'+'2011') AS DATETIME)
As an example:
SET DATEFORMAT DMY
SELECT CAST(CONVERT(VARCHAR(15), yourDateColumn, 105) AS DATETIME) FROM TableName
SELECT CAST((dayColumn+'-'+monthColumn+'-'+yearColumn) AS DATETIME)
FROM anotherTable
Finally the comparison:
SELECT t1.* FROM tableName t1, anotherTable t2
WHERE CAST(CONVERT(VARCHAR(15), t1.DateColumnName, 105) AS DATETIME)
= CAST((t2.dayColumn+'-'+t2.monthColumn+'-'+t2.yearColumn) AS DATETIME)
Is this your requirement ?
DECLARE #tblTemp TABLE
(
DAY VARCHAR(10)
,Month VARCHAR(10)
,Year VARCHAR(10)
)
DECLARE #dtDateTime VARCHAR(10) = '20/12/2011 00:00:00'
INSERT INTO #tblTemp VALUES
('01','01','2011'),
('01','02','2011'),
('01','03','2011'),
('01','04','2012');
select * from #tblTemp where CONVERT(DATE,Year +Month+DAY ,103) < CONVERT(DATE,#dtDateTime,103)
In SQL Server I have a DATETIME column which includes a time element.
Example:
'14 AUG 2008 14:23:019'
What is the best method to only select the records for a particular day, ignoring the time part?
Example: (Not safe, as it does not match the time part and returns no rows)
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_datetime = #p_date
Note: Given this site is also about jotting down notes and techniques you pick up and then forget, I'm going to post my own answer to this question as DATETIME stuff in MSSQL is probably the topic I lookup most in SQLBOL.
Update Clarified example to be more specific.
Edit Sorry, But I've had to down-mod WRONG answers (answers that return wrong results).
#Jorrit: WHERE (date>'20080813' AND date<'20080815') will return the 13th and the 14th.
#wearejimbo: Close, but no cigar! badge awarded to you. You missed out records written at 14/08/2008 23:59:001 to 23:59:999 (i.e. Less than 1 second before midnight.)
Technique 1:
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_datetime >= #p_date
AND column_datetime < DATEADD(d, 1, #p_date)
The advantage of this is that it will use any index on 'column_datetime' if it exists.
In SQL Server 2008, you could use the new DATE datatype
DECLARE #pDate DATE='2008-08-14'
SELECT colA, colB
FROM table1
WHERE convert(date, colDateTime) = #pDate
#Guy. I think you will find that this solution scales just fine. Have a look at the query execution plan of your original query.
And for mine:
Just compare the year, month and day values.
Declare #DateToSearch DateTime
Set #DateToSearch = '14 AUG 2008'
SELECT *
FROM table1
WHERE Year(column_datetime) = Year(#DateToSearch)
AND Month(column_datetime) = Month(#DateToSearch)
AND Day(column_datetime) = Day(#DateToSearch)
Something like this?
SELECT *
FROM table1
WHERE convert(varchar, column_datetime, 111) = '2008/08/14'
Technique 2:
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE DATEDIFF( d, column_datetime, #p_date ) = 0
If the column_datetime field is not indexed, and is unlikely to be (or the index is unlikely to be used) then using DATEDIFF() is shorter.
Good point about the index in the answer you accepted.
Still, if you really search only on specific DATE or DATE ranges often, then the best solution I found is to add another persisted computed column to your table which would only contain the DATE, and add index on this column:
ALTER TABLE "table1"
ADD "column_date" AS CONVERT(DATE, "column_datetime") PERSISTED
Add index on that column:
CREATE NONCLUSTERED INDEX "table1_column_date_nu_nci"
ON "table1" ( "column_date" ASC )
GO
Then your search will be even faster:
DECLARE #p_date DATE
SET #p_date = CONVERT( DATE, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_date = #p_date
I normally convert date-time to date and compare them, like these:
SELECT 'Same Date' WHERE CAST(getDate() as date) = cast('2/24/2012 2:23 PM' as date)
or
SELECT 'Same Date' WHERE DATEDIFF(dd, cast(getDate() as date), cast('2/24/2012 2:23 PM' as date)) = 0
This function Cast(Floor(Cast(GetDate() As Float)) As DateTime) returns a datetime datatype with the time portion removed and could be used as so.
Select
*
Table1
Where
Cast(Floor(Cast(Column_DateTime As Float)) As DateTime) = '14-AUG-2008'
or
DECLARE #p_date DATETIME
SET #p_date = Cast('14 AUG 2008' as DateTime)
SELECT *
FROM table1
WHERE Cast(Floor(Cast(column_datetime As Float)) As DateTime) = #p_date
How to get the DATE portion of a DATETIME field in MS SQL Server:
One of the quickest and neatest ways to do this is using
DATEADD(dd, DATEDIFF( dd, 0, #DAY ), 0)
It avoids the CPU busting "convert the date into a string without the time and then converting it back again" logic.
It also does not expose the internal implementation that the "time portion is expressed as a fraction" of the date.
Get the date of the first day of the month
DATEADD(dd, DATEDIFF( dd, -1, GetDate() - DAY(GetDate()) ), 0)
Get the date rfom 1 year ago
DATEADD(m,-12,DATEADD(dd, DATEDIFF( dd, -1, GetDate() - DAY(GetDate()) ), 0))
I know this isn't exactly how you want to do this, but it could be a start:
SELECT *
FROM (SELECT *, DATEPART(yy, column_dateTime) as Year,
DATEPART(mm, column_dateTime) as Month,
DATEPART(dd, column_dateTime) as Day
FROM table1)
WHERE Year = '2008'
AND Month = '8'
AND Day = '14'
SELECT *
FROM table1
WHERE CONVERT(varchar(10),columnDatetime,121) =
CONVERT(varchar(10),CONVERT('14 AUG 2008' ,smalldatetime),121)
This will convert the datatime and the string into varchars of the format "YYYY-MM-DD".
This is very ugly, but should work
Date can be compared in sqlserver using string comparision:
e.g.
DECLARE #strDate VARCHAR(15)
SET #strDate ='07-12-2010'
SELECT * FROM table
WHERE CONVERT(VARCHAR(15),dtInvoice, 112)>= CONVERT(VARCHAR(15),#strDate , 112)
DECLARE #Dat
SELECT *
FROM Jai
WHERE
CONVERT(VARCHAR(2),DATEPART("dd",Date)) +'/'+
CONVERT(VARCHAR(2),DATEPART("mm",Date)) +'/'+
CONVERT(VARCHAR(4), DATEPART("yy",Date)) = #Dat
The best way is to simply extract the date part using the SQL DATE() Function:
SELECT *
FROM table1
WHERE DATE(column_datetime) = #p_date;
SELECT * FROM tablename
WHERE CAST(FLOOR(CAST(column_datetime AS FLOAT))AS DATETIME) = '30 jan 2012'
SELECT CONVERT(VARCHAR(2),DATEPART("dd",doj)) +
'/' + CONVERT(VARCHAR(2),DATEPART("mm",doj)) +
'/' + CONVERT(VARCHAR(4),DATEPART("yy",doj)) FROM emp
There are many formats for date in SQL which are being specified. Refer https://msdn.microsoft.com/en-in/library/ms187928.aspx
Converting and comparing varchar column with selected dates.
Syntax:
SELECT * FROM tablename where CONVERT(datetime,columnname,103)
between '2016-03-01' and '2016-03-03'
In CONVERT(DATETIME,COLUMNNAME,103) "103" SPECIFIES THE DATE FORMAT as dd/mm/yyyy
In sqlserver
DECLARE #p_date DATE
SELECT *
FROM table1
WHERE column_dateTime=#p_date
In C#
Pass the short string of date value using ToShortDateString() function.
sample:
DateVariable.ToShortDateString();