I have a Tcl main program and I want to create a C thread from it.
I then would need to share information between the two threads: C thread's process frequently updated inputs/outputs.
I see two possible solutions to my problem: (1) port Tcl's Thread Shared Variable to C, but I didn't see any information about it in the TCL-C API. (2) Create Tcl-C linked Variables and use it as arguments during the C thread creation.
The latter idea doesn't seem to work. Here is the C code:
#include <tcl.h>
/*
startRoutine
*/
static void startRoutine (ClientData clientData) {
int *Var;
Var= (int *) clientData;
int locA=0;
int j;
int k;
while (1) {
if (locA=!*Var) {
// Modify Tcl-C shared variable
locA=2 * *Var;
*Var=locA;
for (j=0; j<100; j++){}
} else {
for (k=0; k<100; k++){}
}
}
}
static int
createThreadC_Cmd(
ClientData cdata,
Tcl_Interp *interp,
int objc,
Tcl_Obj *const objv[])
{
// Contains the ID of the newly created thread
Tcl_ThreadId id;
// Thread argument
ClientData limitData;
// Transfering global var argument to the created thread
limitData=cdata;
// Thread creation
id=0;
Tcl_CreateThread(&id, startRoutine, limitData, TCL_THREAD_STACK_DEFAULT, TCL_THREAD_NOFLAGS);
// Wait thread process, before returning to TCL prog
int i;
int aa;
for (i=0 ; i<10000000 ; i++){
aa=i;
}
// Return thread ID to tcl prog to allow mutex use
Tcl_SetObjResult(interp, Tcl_NewIntObj((int) id));
return TCL_OK;
}
int DLLEXPORT
Behavcextension_Init(Tcl_Interp *interp)
{
if (Tcl_InitStubs(interp, TCL_VERSION, 0) == NULL) {
return TCL_ERROR;
}
// Create global Var
int *sharedPtr;
int linkedVar=0;
sharedPtr=&linkedVar;
Tcl_LinkVar(interp, "linkedVar", (char *) sharedPtr, TCL_LINK_INT);
Tcl_CreateObjCommand(interp,
"createThreadC", createThreadC_Cmd, sharedPtr, NULL);
return TCL_OK;
}
Here is the Tcl code:
# linkedVar initial value in Tcl, will be overwritten by C Tcl_LinkVar() function
set linkedVar 98
puts "linkedVar: $linkedVar"
# Thread creation
#------------------
load [file join [pwd] libBehavCextension[info sharedlibextension]]
set threadId [createThreadC]
puts "Created thread $threadId, waiting"
# When Tcl_LinkVar() is called, initiate linkedVar at 2
puts "linkedVar: $linkedVar"
# Function inside thread should modify linkedVar into linkedVar*2
set linkedVar 98
after 5000
puts "linkedVar: $linkedVar"
The terminal output is here:
Main thread ID: tid0xb779b6c0
linkedVar: 98
Created thread -1227252928, waiting
linkedVar: 2
linkedVar: 98
The last result should be 2*98=196. LinkVar creation between Tcl and C is Ok (we get 2 after link creation), but passing LinkVar to the Thread is KO.
Any solution or explanations about why it doesn't work/what to do to solve it are welcome!
The problem remains the same as in the other question. You're allocating the storage for the variable on the C side on the C stack in a function that terminates shortly afterwards. It's Undefined Behavior to refer to that variable (which is linkedVar in Behavcextension_Init) after the termination of the function (Behavcextension_Init). What actually happens is that the actual storage is used for some other function call (doing who knows what) and so the value contained is arbitrary, and changing it can lead to “exciting” behavior.
You're looking to have a variable that exists after Behavcextension_Init finishes, so it must not be allocated in the stack of that function. The simplest method is this:
int DLLEXPORT
Behavcextension_Init(Tcl_Interp *interp)
{
int *sharedPtr;
if (Tcl_InitStubs(interp, TCL_VERSION, 0) == NULL) {
return TCL_ERROR;
}
sharedPtr = (int *) Tcl_Alloc(sizeof(int)); // Allocate
*sharedPtr = 0; // Initialize
Tcl_LinkVar(interp, "linkedVar", (char *) sharedPtr, TCL_LINK_INT);
Tcl_CreateObjCommand(interp,
"createThreadC", createThreadC_Cmd, sharedPtr, NULL);
return TCL_OK;
}
Caveats
This leaks memory, as there is no matching Tcl_Free for that Tcl_Alloc. For memory allocated once per process, that's not much of a problem. After all, it's only a few bytes and the OS will reclaim it at exit.
This is unsafe when reading the variable from a different thread than the one where it was written; there's simply no guarantee that it will work. It will probably work as it is just an integer, but you're depending on the hardware to be cooperative. The right thing to do is to allocate a structure containing both the variable and a suitable mutex, and protect the accesses to the variable (whether reads or writes) with the mutex. That in turn requires that you do not use Tcl_LinkVar — it knows nothing about mutex-protected memory — but Tcl_LinkVar is just a wrapper round Tcl_TraceVar that provides a callback that does the coupling between Tcl's variable (see Tcl_GetVar and Tcl_SetVar) and the C variable; writing your own that knows how to do mutex-protection handling as well is not hard. (If you're interested, get the source to Tcl_LinkVar and adapt it yourself; it doesn't use any private API calls.)
Related
I'm creating a multi-thread program in C and I've some troubles.
There you have the function which create the threads :
void create_thread(t_game_data *game_data)
{
size_t i;
t_args *args = malloc(sizeof(t_args));
i = 0;
args->game = game_data;
while (i < 10)
{
args->initialized = 0;
args->id = i;
printf("%zu CREATION\n", i);//TODO: Debug
pthread_create(&game_data->object[i]->thread_id, NULL, &do_action, args);
i++;
while (args->initialized == 0)
continue;
}
}
Here you have my args struct :
typedef struct s_args
{
t_game_data *object;
size_t id;
int initialized;
}args;
And finally, the function which handle the created threads
void *do_action(void *v_args)
{
t_args *args;
t_game_data *game;
size_t id;
args = v_args;
game = args->game;
id = args->id;
args->initialized = 1;
[...]
return (NULL);
}
The problem is :
The main thread will create new thread faster than the new thread can init his variables :
args = v_args;
game = args->game;
id = args->id;
So, sometime, 2 different threads will get same id from args->id.
To solve that, I use an variable initialized as a bool so make "sleep" the main thread during the new thread's initialization.
But I think that is really sinful.
Maybe there is a way to do that with a mutex? But I heard it wasn't "legal" to unlock a mutex which does not belong his thread.
Thanks for your answers!
The easiest solution to this problem would be to pass a different t_args object to each new thread. To do that, move the allocation inside the loop, and make each thread responsible for freeing its own argument struct:
void create_thread(t_game_data *game_data) {
for (size_t i = 0; i < 10; i++) {
t_args *args = malloc(sizeof(t_args));
if (!args) {
/* ... handle allocation error ... */
} else {
args->game = game_data;
args->id = i;
printf("%zu CREATION\n", i);//TODO: Debug
if (pthread_create(&game_data->object[i]->thread_id, NULL,
&do_action, args) != 0) {
// thread creation failed
free(args);
// ...
}
}
}
}
// ...
void *do_action(void *v_args) {
t_args *args = v_args;
t_game_data *game = args->game;
size_t id = args->id;
free(v_args);
args = v_args = NULL;
// ...
return (NULL);
}
But you also write:
To solve that, I use an variable initialized as a bool so make "sleep"
the main thread during the new thread's initialization.
But I think that is really sinful. Maybe there is a way to do that
with a mutex? But I heard it wasn't "legal" to unlock a mutex which
does not belong his thread.
If you nevertheless wanted one thread to wait for another thread to modify some data, as your original strategy requires, then you must employ either atomic data or some kind of synchronization object. Your code otherwise contains a data race, and therefore has undefined behavior. In practice, you cannot assume in your original code that the main thread will ever see the new thread's write to args->initialized. "Sinful" is an unusual way to describe that, but maybe appropriate if you belong to the Church of the Holy C.
You could solve that problem with a mutex by protecting just the test of args->initialized in your loop -- not the whole loop -- with a mutex, and protecting the threads' write to that object with the same mutex, but that's nasty and ugly. It would be far better to wait for the new thread to increment a semaphore (not a busy wait, and the initialized variable is replaced by the semaphore), or to set up and wait on a condition variable (again not a busy wait, but the initialized variable or an equivalent is still needed).
The problem is that in create_thread you are passing the same t_args structure to each thread. In reality, you probably want to create your own t_args structure for each thread.
What's happening is your 1st thread is starting up with the args passed to it. Before that thread can run do_action the loop is modifying the args structure. Since thread2 and thread1 will both be pointing to the same args structure, when they run do_action they will have the same id.
Oh, and don't forget to not leak your memory
Your solution should work in theory except for a couple of major problems.
The main thread will sit spinning in the while loop that checks the flag using CPU cycles (this is the least bad problem and can be OK if you know it won't have to wait long)
Compiler optimisers can get trigger happy with respect to empty loops. They are also often unaware that a variable may get modified by other threads and can make bad decisions on that basis.
On multi core systems, the main thread may never see the change to args->initiialzed or at least not until much later if the change is in the cache of another core that hasn't been flushed back to main memory yet.
You can use John Bollinger's solution that mallocs a new set of args for each thread and it is fine. The only down side is a malloc/free pair for each thread creation. The alternative is to use "proper" synchronisation functions like Santosh suggests. I would probably consider this except I would use a semaphore as being a bit simpler than a condition variable.
A semaphore is an atomic counter with two operations: wait and signal. The wait operation decrements the semaphore if its value is greater than zero, otherwise it puts the thread into a wait state. The signal operation increments the semaphore, unless there are threads waiting on it. If there are, it wakes one of the threads up.
The solution is therefore to create a semaphore with an initial value of 0, start the thread and wait on the semaphore. The thread then signals the semaphore when it is finished with the initialisation.
#include <semaphore.h>
// other stuff
sem_t semaphore;
void create_thread(t_game_data *game_data)
{
size_t i;
t_args args;
i = 0;
if (sem_init(&semaphore, 0, 0) == -1) // third arg is initial value
{
// error
}
args.game = game_data;
while (i < 10)
{
args.id = i;
printf("%zu CREATION\n", i);//TODO: Debug
pthread_create(&game_data->object[i]->thread_id, NULL, &do_action, args);
sem_wait(&semaphore);
i++;
}
sem_destroy(&semaphore);
}
void *do_action(void *v_args) {
t_args *args = v_args;
t_game_data *game = args->game;
size_t id = args->id;
sem_post(&semaphore);
// Rest of the thread work
return NULL;
}
Because of the synchronisation, I can reuse the args struct safely, in fact, I don't even need to malloc it - it's small so I declare it local to the function.
Having said all that, I still think John Bollinger's solution is better for this use-case but it's useful to be aware of semaphores generally.
You should consider using condition variable for this. You can find an example here http://maxim.int.ru/bookshelf/PthreadsProgram/htm/r_28.html.
Basically wait in the main thread and signal in your other threads.
I am trying to create a thread library and my thread is a struct type. Have to follow a certain interface and in that I need to pass the thread by value. For ex: to join on a thread my code is as follows:
int thread_join(thread_t thread, void **status1)
{
printf("Joining thread\n");
long int thId = thread.id;
printf("Thread id: %ld\n", thId);
gtthread_t * thrd = getThreadFromID(thId);
while(thrd->status != EXIT)
{
}
status1 = &(thrd->ret_value);
return 0;
}
And I an passing a struct of type thread_t to this function. My problem is when I see the thread's ID in the calling function, its displayed properly but when I check it in the thread_join function its displayed as 0. The caller function is as follows:
void* caller(void* arg)
{
thread_t th;
thread_create(&th, some_function, NULL);
thread_join(th, NULL);
while(1);
}
Thread create initializes the ID of the thread to a non-zero value and starts the function associated with it.
My thread structure (and other relevant structure is):
typedef enum
{
RUNNING,
WAITING,
CANCEL,
EXIT
} stat;
//Thread
typedef struct
{
ucontext_t t_ctxt;
long int id;
stat status;
void * ret_value;
int isMain;
} thread_t;
int thread_create(thread_t *thread, void *(*start_routine)(void *), void *arg)
{
thread = (thread_t *)malloc(sizeof(thread_t));
thread->id = ++count;
thread->status = RUNNING;
thread->ret_value = NULL;
thread->isMain = 0;
if(getcontext(&(thread->t_ctxt)) == -1)
handle_error("getcontext");
thread->t_ctxt.uc_stack.ss_sp = malloc(SIGSTKSZ);
thread->t_ctxt.uc_stack.ss_size = SIGSTKSZ;
thread->t_ctxt.uc_link = &sched_ctxt;
makecontext(&thread->t_ctxt, (void (*)(void))wrap_func, 2, (void (*)(void))start_routine, arg);
enqueue(gQ, thread);
printf("Thread id: %ld\n", thread->id);
swapcontext(&(curr_thread->t_ctxt),&sched_ctxt);
return 0;
}
Why does this happen? After all, I am passing by value and this should create a copy of the thread with the same values. Thanks.
EDIT:
Basically I am having a queue of threads and there is a scheduler which round-robins. I can post that code here too but I'm sure that's needless and that code works fine.
EDIT2:
I am making a header file from this code and including that header in another file to test it. All my thread_t variables are static. The caller is a function which includes my header file.
What is this line:
thread = (thread_t *)malloc(sizeof(thread_t));
for?
You pass in to thread_create() an address which referrs to a struct thread_t defined in caller() as auto variable.
Doing as you do, you allocate memory to the pointer passed in to thread_create() initialise it and forget the address on return.
The code never writes to the memory being referenced by the address passed in! Besides this it is a memory leak.
To fix this simply remove the line of code quoted above.
You have no mutex guard on thread id getter. Presumably, there is no guard on setter. What can be happening is that the variable is not visible in the other thread yet. And, without a critical section, it may never become visible.
Each variable which is accessed for both read and write from different threads has to be accessed in a critical section (pthread_mutex_lock / unlock).
Another possibility is that you are setting the thread id inside the running thread and you are accessing the variable even before it is set. If you attempt to join immediately after starting a thread it is possible, that the other thread hasn't been run at all yet and the variable is not set.
side note: do yourself a favor and use calloc:)
In caller function,
thread_create(&th, some_function, NULL);
should be
gtthread_create(&th, some_function, NULL);
I have written a C program that uses two threads for reading and writing. I have declared the variable which are accessed by both the threads as Global. How to avoid the use of global variables in this case.
Please look into following methods of pthread library in C for having exclusive access of Shared Global variables in C:
int pthread_mutex_init(pthread_mutex_t *restrict mutex, const pthread_mutexattr_t *restrict attr);
int pthread_mutex_lock(pthread_mutex_t *mutex);
int pthread_mutex_unlock(pthread_mutex_t *mutex);
int pthread_mutex_destroy(pthread_mutex_t *mutex);
Similarly, you can look into Semaphores for synchronizing the use of global variables in C threads.
HOw to avoid the use of global variables in this case.
There is no need to avoid global variables. Only thing you have to consider is valid data by some lock mechanism.
Putting all global variables in to a struct is for readability and code control when your project grows.
I suggest you to use mutex lock.. Here is an modified sample code.
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
typedef struct
{
double *a;
double *b;
double sum;
int veclen;
} DOTDATA;
/* Define globally accessible variables and a mutex */
#define NUMTHRDS 4
#define VECLEN 100
DOTDATA dotstr;
pthread_t callThd[NUMTHRDS];
pthread_mutex_t mutexsum;
void *dotprod(void *arg)
{
/* Define and use local variables for convenience */
int i, start, end, len ;
long offset;
double mysum, *x, *y;
offset = (long)arg;
len = dotstr.veclen;
start = offset*len;
end = start + len;
x = dotstr.a;
y = dotstr.b;
/*
Perform the dot product and assign result
to the appropriate variable in the structure.
*/
mysum = 0;
for (i=start; i<end ; i++)
{
mysum += (x[i] * y[i]);
}
/*
Lock a mutex prior to updating the value in the shared
structure, and unlock it upon updating.
*/
pthread_mutex_lock (&mutexsum);
dotstr.sum += mysum;
pthread_mutex_unlock (&mutexsum);
pthread_exit((void*) 0);
}
/*
The main program creates threads which do all the work and then
print out result upon completion. Before creating the threads,
the input data is created. Since all threads update a shared structure,
we need a mutex for mutual exclusion. The main thread needs to wait for
all threads to complete, it waits for each one of the threads. We specify
a thread attribute value that allow the main thread to join with the
threads it creates. Note also that we free up handles when they are
no longer needed.
*/
int main (int argc, char *argv[])
{
long i;
double *a, *b;
void *status;
/* Assign storage and initialize values */
a = (double*) malloc (NUMTHRDS*VECLEN*sizeof(double));
b = (double*) malloc (NUMTHRDS*VECLEN*sizeof(double));
for (i=0; i<VECLEN*NUMTHRDS; i++)
{
a[i]=1.0;
b[i]=a[i];
}
dotstr.veclen = VECLEN;
dotstr.a = a;
dotstr.b = b;
dotstr.sum=0;
pthread_mutex_init(&mutexsum, NULL);
for(i=0; i<NUMTHRDS; i++)
{
/*
Each thread works on a different set of data.
The offset is specified by 'i'. The size of
the data for each thread is indicated by VECLEN.
*/
pthread_create(&callThd[i], NULL, dotprod, (void *)i);
}
/* Wait on the other threads */
for(i=0; i<NUMTHRDS; i++)
{
pthread_join(callThd[i], &status);
}
/* After joining, print out the results and cleanup */
printf ("Sum = %f \n", dotstr.sum);
free (a);
free (b);
pthread_mutex_destroy(&mutexsum);
pthread_exit(NULL);
}
Do you truly need a shared variable, or do you actually need 2 copies of the same data for each thread? If so, instead of declaring it global, pass it as an argument to the thread at creation.
If it truly needs to be shared, it will need to be protected by a mutex. You can still also do away with the global variable if you bundle the shared variable into a struct along with the mutex and pass it along to the threads as an argument at creation.
I think you're asking how to avoid having your threads accessing globals by passing them their work-data during startup.
Please see the last parameter to pthread_create, which allows you to define a user-defined custom pointer that can be anything you want. Use that to pass data (such as a struct address or even by-value so long as the value can fit in the platform's size of a void pointer.
For example, a parent can send a child thread data by doing such:
Data data;
pthread_create(&thrd, NULL, threadProc, &data);
The child proc would reference this by:
void *threadProc(void *pv)
{
Data *pData = (Data*)pv;
.. use data here...
pthread_exit(NULL);
}
I hope this makes sense, and hope it helps you understand how to pass data to a thread proc, which was what I think your question is.
If you want each thread to have a separate copy of the variable, declare the variables as thread local.
You can make structs. I usually to use a struct called globalArgs where I put all there global variables.
Something like this:
static typedef struct {
int foo;
int baa;
} globalargs;
Or, you can pass all values as parameters to functions that needs of.
i'm working on gcc ,
i'm wondering if this is possible:
I have a function (NOTmain but aLocalFn) and I declare a local variable in it. Then I pass this local argument as a thread argument. is it doable? or there is the chance (depending on what is run first) that the aLocalVar will be lost before threadFunction is run and the reference idxPtr will be pointing to senselessness??
int *threadFunction(void *idxPtr){
int rec_idx=(int) *idxPtr;
//work in the thread with this variabel rec_idx
}
int aLocalFn(){
int aLocalVar=returnsRecordIndex();
pthread_create(&thread_id,&attr_detached,threadFunction, &aLocalVar)!=0)
return 0;
}
thank you for your help
This code is incorrect. The function aLocalFn may return before the thread function starts executing. And so by the time the thread function reads the local variable, the scope of that variable may have ended.
What can confuse matters is that this code may very well appear to work, at least some of the time. However, it is incorrect and you should use heap allocated memory instead.
your code has a life-time issue with "aLocalVar"
if you just want to pass an integer, here is a non-portable way to do it.
it does not work on some platforms, but you are not likely to encounter those.
void threadFunction ( void * idxptr ) {
int rec_idx = (int) idxptr;
....
}
int rec_idx = returnsRecordIndex();
pthread_create (&thread1, &attr_detached, (void *) &threadFunction, (void *)rec_idx);
It's doable, but it's not done in the code in your question. You will have to add a signal variable to indicate when the new thread is done using the variable. Then your outer function can return.
static pthread_mutex_t lock = PTHREAD_MUTEX_INITIALIZER;
static pthread_cond_t signal = PTHREAD_COND_INITIALIZER;
int done;
int *threadFunction(void *idxPtr){
int rec_idx=(int) *idxPtr;
pthread_mutex_lock(&lock);
done = 1;
pthread_cond_signal(&signal);
pthread_mutex_unlock(&lock);
//work in the thread with this variabel rec_idx
}
int aLocalFn(){
int aLocalVar=returnsRecordIndex();
done = 0;
pthread_create(&thread_id,&attr_detached,threadFunction, &aLocalVar)!=0)
pthread_mutex_lock(&lock);
while (!done)
pthread_cond_wait(&signal, &lock);
pthread_mutex_unlock(&lock);
return 0;
}
Note that this example code is itself not thread safe (if multiple threads call aLocalFn).
This does complicate the code, and locking is expensive. So in most cases you're probably better off storing the data in the heap and letting the new thread or pthread_join code free it.
#pizza's answer is what I'd do. Another way for you to do it would be to use malloc/free as #David hinted at. I would certainly do this over the wait loop proposed in other answers here.
int *threadFunction(void *idxPtr){
int rec_idx = *(int *)idxPtr;
// free up our int buffer
free(idxPtr);
...
}
int aLocalFn(){
int aLocalVar = returnsRecordIndex();
// allocate some space for our int
int *intBuf = (int *)malloc(sizeof(int));
*intBuf = aLocalVar;
pthread_create(&thread_id,&attr_detached,threadFunction, intBuf)!=0)
return 0;
}
Whenever you are passing variables to a thread function, it is your job to ensure that the variable remains alive and valid till the thread function is done using it.
In your case aLocalFn() continues to execute simultaneously with the new thread and may even finish execution before the thread, that leaves you with an dangling pointer(pointer pointing to data that may not exist) in thread function since the local variable aLocalVar in the function ceases to exist after function returns.
I'm trying to use threads (for the first time!) in a GCC C application which works fine in non-threaded mode. When I run it some threads give results which are all zero instead of the required answers (which I know for checking purposes), but the threads giving zeroes are not the same each time I run it. The ones which give non-zero answers are correct, so the code appears to run ok as such. I wonder if anyone can point out areas where I might have something which is not thread-safe.
My own thoughts are it may be due to how I collect results or maybe memory allocation - I use malloc and free but elsewhere in StackOverflow I see that GCC malloc is considered thread-safe if linked with -lpthread (which I am doing). Nothing uses global/static variables - everything is passed as function arguments.
In order to pass results back to main, my threaded routine uses an array of structures. Each thread writes to a distinct element of this array, so they are not trying to write to the same memory. Maybe I need to use some form of locking when writing results even though they don't go to the same element of the structure array?
I followed the recipe for threaded code here:
https://computing.llnl.gov/tutorials/pthreads/#Abstract
I attach (simplified) code extracts in case this gives any clues (I may have omitted/modified something incorrectly but I am not asking for anyone to spot bugs, just the general methodology).
typedef struct p_struct { /* used for communicating results back to main */
int given[CELLS];
int type;
int status;
/*... etc */
} puzstru;
typedef struct params_struct { /* used for calling generate function using threads */
long seed;
char *text;
puzzle *puzzp;
bool unique;
int required;
} paramstru;
/* ========================================================================================== */
void *myfunc(void *spv) /* calling routine for use by threads */
{
paramstru *sp=(paramstru *)spv;
generate(sp->seed, sp->text, sp->puzzp, sp->unique, sp->required);
pthread_exit((void*) spv);
}
/* ========================================================================================== */
int generate(long seed, char *text, puzstru *puzzp, bool unique, int required)
{
/* working code , also uses malloc and free,
puts results in the element of a structure array pointed to by "puzzp",
which is different for each thread
(see calling routine below : params->puzzp=puz+thr; )
extract as follows: */
puzzp->given[ix]=calcgiven[ix];
puzzp->type=1;
puzzp->status=1;
/* ... etc */
}
/* ========================================================================================== */
int main(int argc, char* argv[])
{
pthread_t thread[NUM_THREADS];
pthread_attr_t threadattr;
int thr,threadretcode;
void *threadstatus;
paramstru params[1];
/* ....... ETC */
/* set up params structure for function calling parameters */
params->text=mytext;
params->unique=TRUE;
params->required=1;
/* Initialize and set thread detached attribute */
pthread_attr_init(&threadattr);
pthread_attr_setdetachstate(&threadattr, PTHREAD_CREATE_JOINABLE);
for(thr=0; thr<NUM_THREADS; thr++)
{
printf("Main: creating thread %d\n", thr);
params->seed=ran_arr_next(startingseeds);
params->puzzp=puz+thr;
threadretcode = pthread_create(&thread[thr], &threadattr, myfunc, (void *)params);
if (threadretcode)
{
printf("ERROR; return code from pthread_create() is %d\n", threadretcode);
exit(-1);
}
}
/* Free thread attribute and wait for the other threads */
pthread_attr_destroy(&threadattr);
for(thr=0; thr<NUM_THREADS; thr++)
{
threadretcode = pthread_join(thread[thr], &threadstatus);
if (threadretcode)
{
printf("ERROR; return code from pthread_join() is %d\n", threadretcode);
exit(-1);
}
printf("Main: completed join with thread %d having a status of %ld\n",thr,(long)threadstatus);
}
/* non-threaded code, print results etc ............. */
free(startingseeds);
free(puz);
printf("Main: program completed. Exiting.\n");
pthread_exit(NULL);
}
For the benefit of others reading this - all the answers were correct, and the answer to the question in the heading is YES, threads can write safely to different elements of the same array of structures, my problem was in the calling routine - the following is the amended code snippet (now works fine):
paramstru params[NUM_THREADS];
for(thr=0; thr<NUM_THREADS; thr++)
{
printf("Main: creating thread %d\n", thr);
/* set up params structure for function calling parameters */
params[thr].text=mytext;
params[thr].unique=TRUE;
params[thr].required=1;
params[thr].seed=ran_arr_next(startingseeds);
params[thr].puzzp=puz+thr;
threadretcode = pthread_create(&thread[thr], &threadattr, myfunc, (void *)¶ms[thr]);
if (threadretcode)
{
printf("ERROR; return code from pthread_create() is %d\n", threadretcode);
exit(-1);
}
}
To answer your question, it is perfectly fine to write to different elements of the same array from different threads without locking. There will only ever be a data race if two threads write to the same byte without synchronizing (e.g., locking).
As other answers point out, the reason your code as-written breaks is because you pass a pointer to the same params object to each of your threads, an then you modify that object. You probably want to create a new param for each thread.
paramstru params[1];
The code is passing the same structure to all threads. Just the thread initialization loop is overwriting the data that a thread should work on:
for(thr=0; thr<NUM_THREADS; thr++)
{
printf("Main: creating thread %d\n", thr);
params->seed=ran_arr_next(startingseeds); /* OVERWRITE */
params->puzzp=puz+thr; /* OVERWRITE */
The reason the non-threaded code works is because each call to myfunc() terminates before the params structure is changed.
You only created one copy of your parameter structure and are overwriting it and passing the same address to each thread. Dont' you want paramstru params[NUM_THREADS];?