In a batch file, I have this line that runs an antivirus program. I'd like to ensure that it finishes its job before the batch moves on the following lines. From what I understand, START/WAIT is the wait to go. Unfortunately, START/WAIT breaks the line of code.
Here is the code that runs:
"C:\Program Files (x86)\Anti-Virus\" d:\files\%1\ProcessFiles\%2-proc\*.*
This code does not run:
START/WAIT "C:\Program Files (x86)\Anti-Virus\fsav" d:\files\%1\ProcessFiles\%2-proc\*.*
When this line runs, I get an error saying:
"Windows cannot find 'd:\files\abc\ProcessFiles\abc-proc\*.*'.
Make sure you typed the name correctly, and then try again."
While that error prompt is open, if I navigate to that folder, there ARE files in there.
Thanks in advance for any help.
using hint from SS64,
Always include a TITLE this can be a simple string like "My Script" or just a pair of empty quotes ""
According to the Microsoft documentation, the title is optional, but you may will have problems if it is omitted.
START "" /WAIT "C:\Your Anti-Virus\antivir" "d:\files\%1\ProcessFiles\%2-proc\*.*
START/WAIT is not a single word, it's two seperated by a space.
Also, putting double-quotes around the file-specs will help if any have spaces in their names.
Try This:
START /WAIT "C:\Program Files (x86)\Anti-Virus\fsav" "d:\files\%1\ProcessFiles\%2-proc\*.*"
Related
I'm writing a .bat file to launch two programs, not having success so far. I've followed the guide here.
#echo off
cd "D:\CRCR 0.4.0\"
start "" "D:\CRCR 0.4.0\Chernobyl Relay Chat Rebirth.exe"
cd "D:\MO2\"
start "" "D:\MO2\ModOrganizer.exe moshortcut://:Anomaly Launcher"
exit
Whenever I try to launch the batch file, it tells me "Windows cannot find 'D:\MO2\ModOrganizer.exe "moshortcut://:Anomaly Launcher'. Make sure you've typed the name correctly, then try again."
I've tried removing 'start' from those lines, removing quotations from the cd lines, etc. How can I get this working?
You probably want to pass moshortcut://:Anomaly Launcher as a parameter.
In that case you should also separate the string:
start "" "D:\MO2\ModOrganizer.exe" "moshortcut://:Anomaly Launcher"
Otherwise Windows will interpret the path as D:\MO2\ModOrganizer.exe moshortcut://:Anomaly Launcher not D:\MO2\ModOrganizer.exe and assume that the entire string is part of the path.
I'm a first-day user of IrfanView and have a question. I have a bunch of multi-page tiff files and I want to split all of them individually. So I write a batch file with the command like this:
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename2.tif /extract=(D:\newdirectory,tif)
...and so on...
I put the batch file on D drive, let's say in folder "batchfolder". But it can't do the job, this message shows up for each unsuccessful case (all of them were unsuccessful):
D:\batchfolder>C:\Program Files\IrfanView D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif) 1>i_view64.exe
'C:\Program' is not recognized as an internal or external command, operable program or batch file.
I guess that has something to do with the batch file location, so I bring it to C drive. But still it can't run properly, this time a different message shows up:
C:\>C:\Program Files\IrfanView D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif) 1>i_view64.exe
Access is denied.
This C:\>C:\ makes me think maybe the C:\ part on the batch file was redundant. So I take it out to make it look like this:
Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
...
But it doesn't work, either with the batch file on D or C drive.
I then try to type it directly in the CMD window and it works normally, like this:
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
Can you tell where my batch file goes wrong?
This is another question. Typing (or copy and paste) the batch file contents into the CMD works OK. But upon successful splitting, the original, multi-image file automatically opens. How can I deactivate this feature?
Note: Cross-post here: https://irfanview-forum.de/showthread.php?t=11150&p=47111#post47111. Hope it doesn't violate policy.
enclose paths/filenames with spaces into quotes to tell the interpreter, it's not two words, but one string (or even better: get used to always enclose path/filenames):
"C:\Program Files\IrfanView\i_view64.exe" "D:\originaldirectory\filename1.tif" /extract=("D:\newdirectory",tif)`
Before you build a batchfile with dozends or hundreds of nearly identical lines, use a for loop to process all .tif files in the folder:
#echo off
for %%a in ("D:\originaldirectory\*.tif") do (
"C:\Program Files\IrfanView\i_view64.exe" "%%~fa" /extract=("D:\newdirectory",tif)
)
see for /? for more information.
You need to call the executable with quotes in the batch. Also, the > in the path will not work either. Also consider using a for loop instead of creating single batch lines.
Please try this:
"C:\Program Files\IrfanView\i_view64.exe" "D:\originaldirectory\filename1.tif" /extract=("D:\newdirectory",tif)
I want to create a batch file to launch my executable file after it has made some changes to itself.
My batch file is:
START /D "C:\Users\me\AppData\Roaming\Test\Test.exe"
When I run it though I just get a brief console flash and Test.exe doesn't start up.
I've verified the EXE is there in the directory.
I've launched the exe manually to verify it is working as well.
My batch file resides in
C:\Users\admin\AppData\Roaming\run.bat"
There are two issues:
The /D option solely defines the starting or working directory, but not the program to execute.
The start command considers the first quoted argument as the title of the new window. To avoid confusion with other arguments, always provide a window title (that may also be empty).
There are two solutions, which are actually not exactly equivalent:
Remove the /D option, so the current working directory is used:
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Keep the /D option and explicitly provide the new working directory to be used:
start "" /D "C:\Users\me\AppData\Roaming\Test" "Test.exe"
try changing to this
start /d "C:\Users\me\AppData\Roaming\Test" Test.exe
You will see the console flash and your program should startup.
Update
Thanks for #SomethingDark 's suggestion to use the following code.
start "" C:\Users\me\AppData\Roaming\Test\Test.exe
However, the above code will not work if your filename contains space.
Try with the following command.Add it to your batch script.Notice that you have to add double quotes after start keyword if there is/are whitespaces in the path string.
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Enclose any directory names which are longer than one-word into quotation marks. So the following path:
start C:\Program Files\MySQL\MySQL Workbench 8.0 CE\MySQL.exe
Should become something like this:
start C:\"Program Files"\MySQL\"MySQL Workbench 8.0 CE"\MySQL.exe
OK so having trouble with my batch script. Basically it wont run a program if the program is more than one word, even though I've put " " around the word, if anyone can offer some advice to a novice it would be appreciated:
cd "C:\Program Files (x86)\Claro Software\ClaroRead Plus"
start "ClaroRead Plus.exe"
This doesn't work however, the below does work:
cd "C:\Program Files (x86)\Claro Software\ClaroRead Plus"
start ClaroUp.exe
To make things even more strange this also doesn't work:
cd "C:\Program Files (x86)\Claro Software\ClaroRead Plus"
start "ClaroUp.exe"
Am I being totally stupid here and missing the most obvious of points or is there something else I should be doing. Thanks
The first quoted string for the start command is assumed to be a console window title. If you're not starting a console application, you can write:
start "" "ClaroRead Plus.exe"
I have tried prefixing lines with semicolons, 'REM', etc.. but no matter what when I run my batch file I keep getting "unknown command REM whatever"
"REM test" It is not recognized, and it is windows vista. I simply get "rem" output back to my console.
That's entirely normal behavior. Batch files are simply sequences of commands that are run one after another. So every line will get output to the console as if it were typed there.
H:\>echo rem test > test.cmd
H:\>test
yields the output
H:\>rem test
as if I typed rem test directly to the console.
You can suppress this by either prefixing the line with #:
#rem test
or by including echo off in the batch file:
#echo off
rem test
If I put ":: test" and execute it I get back "Test".
Can't reproduce here.
If I put "; test" it recursively executes itself
A semicolon at the start of the line seemingly gets ignored.
If you're talking about cmd.exe batch files under Windows, you can use:
rem this method or
:: this method.
For bash and a lot of other UNIX-type shells, you use:
# this method.
I'm pretty certain you're not using cmd.exe since that would give you an error like:
'rem' is not recognized as an internal or external command,
operable program or batch file.
rather then:
Unknown command ...
If you are using a UNIX-type shell, the # character is almost certainly what you're after. If you let us know exactly the shell you're using, we can probably help out further.
you probably created an UNICODE file. These files contain 2 bytes header named BOM
which is not shown by any editor but cmd attempts to execute them and fails.
To make sure this is indeed an issue: type any other command at the very beginning
of your file and see it throws the same error - for example #echo test
To fix it, just create a new plain text file and copy content of the original file there.
then remove the original file and replace it by the newly created one.
In my case the problems are line endings. Somehow Maven or the Jenkins pipeline running on a Linux machine changed the line endings from Windows style (CR LF) to Unix style (LF). Changing them back solves the issue for me.