I am trying to do a search, using pagination for posts which have a specific tag or tags (for example, if a user was to select two tags, then posts containing either tag would be returned).
I have the relationship defined in my Posts table
public $hasAndBelongsToMany = array('Tags' => array(
'className' => 'Tags',
'joinTable' => 'posts_tags',
'foreignKey' => 'post_id',
'associationForeignKey' => 'tag_id',
'unique' => 'keepExisting'));
How do I use Find to retrieve rows with a given tag (name or ID would be fine)
Trying:
// other pagination settings goes here
$this->paginate['conditions']['Tags.id'] = 13;
gives me an error that the relationship does not exist.
Looking at the debug info it appears that the tables are not joining the Posts_Tags and Tags table, however, when I debug the data making it to the view, the Posts objects contain the tags data.
Most of the documentation I can find for this seems to revolve around earlier versions of CakePHP, any help would be appreciated.
Could not find a satisfying solution myself.
I created a behavior to take care of this.
Create a file called HabtmBehavior.php and put it in your app/Model/Behavior folder.
Put the block of code in there and save file.
Add the behavior to your model: eg public $actsAs = array('Habtm');
Here is a usage example with find.
<?php $this->Entry->find('all', array('habtm'=>array('Tag'=>array('Tag.title'=>'value to find'))) ?>
Paginate would look something like this:
$this->paginate['Entry']['habtm']['Tag'] = array('Tag.title'=>'value to find');
You are free to add as many relations as you want by adding additional Model Names in the habtm array.
(Just be careful not to make it to complex since this could start slowing down your find results.)
<?php
class HabtmBehavior extends ModelBehavior {
public function beforeFind(Model $model, $options) {
if (!isset($options['joins'])) {
$options['joins'] = array();
}
if (!isset($options['habtm'])) {
return $options;
}
$habtm = $options['habtm'];
unset($options['habtm']);
foreach($habtm as $m => $scope){
$assoc = $model->hasAndBelongsToMany[$m];
$bind = "{$assoc['with']}.{$assoc['foreignKey']} = {$model->alias}.{$model->primaryKey}";
$options['joins'][] = array(
'table' => $assoc['joinTable'],
'alias' => $assoc['with'],
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array($bind)
);
$bind = $m.'.'.$model->{$m}->primaryKey.' = ';
$bind .= "{$assoc['with']}.{$assoc['associationForeignKey']}";
$options['joins'][] = array(
'table' => $model->{$m}->table,
'alias' => $m,
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array($bind) + (array)$scope,
);
}
return $options;
}
}
Hope this helps.
Happy baking.
I think the best solution is apply find function on join table Model. I try this before and it's work fine.
in your PostTag model :
/**
* #see Model::$actsAs
*/
public $actsAs = array(
'Containable',
);
/**
* #see Model::$belongsTo
*/
public $belongsTo = array(
'Post' => array(
'className' => 'Post',
'foreignKey' => 'post_id',
),
'Tags' => array(
'className' => 'Tag',
'foreignKey' => 'tag_id',
),
);
in your controller :
// $tagsId = tags ids
$posts = $this->PostTag->find('all', array('conditions' => array('PostTag.tag_id' => $tagsId),'contain' => array('Post')));
also is better follow cake naming convention, if you have tags(plural), post_tags(first singular second plural),posts(plural) tables you must have Tag,PostTag,Post Models.
Related
I have problem with HABTM models. When I try to fetch any related model f.e. like this:
$this->Tagi->find('first');
I dont get any results for associated model. Result looks like this:
array(
'Tagi' => array(
'id' => '1',
'nazwa' => 'sth'
),
'Instytucje' => array()
)
I am sure that there should be result, I've double checked it, even
$this->Tagi->getDataSource()->getLog(false, false)
shows correct query, that fetches right results.
If you have any idea whats wrong plz give me a hint.
Tagi model:
public $hasAndBelongsToMany = array(
'Instytucje' =>
array(
'className' => 'Instytucje.Instytucje',
'joinTable' => 'instytucje-tagi',
'foreignKey' => 'tag_id',
'associationForeignKey' => 'instytucja_id',
'unique'=> true
)
);
Instytucje model:
public $hasAndBelongsToMany = array(
'Tagi' =>
array(
'className' => 'Instytucje.Tagi',
'joinTable' => 'instytucje-tagi',
'foreignKey' => 'instytucja_id',
'associationForeignKey' => 'tag_id',
'unique'=> true
)
);
EDIT:
Main problem is that HABTM refers to AppModel causing error:
Error: Table app_models for model AppModel was not found in datasource prod.
Which can be bypassed by adding $useTable in AppModel, which results in prior problem.
SOLVED
When using naming convention far beyond this Cake use, you have use third model with $useTable pointed on reference table.
Moreover its important to correctly point Cake to classes inside plugins.
I think you're problem relates to the fact that you are not using CakePHP's naming conventions. From the look of the query being generated Cake doesn't know how to correctly alias the join table, hence getting an AppModel alias in your query. I suspect that this is causing issues when Cake tries to build the results array from the query.
This might not work, but try creating a model for the joins table called InstytucjeTagi; then update your associations to use this using the with key:-
Tagi model:
public $hasAndBelongsToMany = array(
'Instytucje' =>
array(
'className' => 'Instytucje.Instytucje',
'joinTable' => 'instytucje-tagi',
'with' => 'InstytucjeTagi',
'foreignKey' => 'tag_id',
'associationForeignKey' => 'instytucja_id',
'unique'=> true
)
);
Instytucje model:
public $hasAndBelongsToMany = array(
'Tagi' =>
array(
'className' => 'Instytucje.Tagi',
'joinTable' => 'instytucje-tagi',
'with' => 'InstytucjeTagi',
'foreignKey' => 'instytucja_id',
'associationForeignKey' => 'tag_id',
'unique'=> true
)
);
If this doesn't fix it try using the afterFind() callback in the Tagi model to check what Cake is returning:-
afterFind($results, $primary = false) {
parent::afterFind($results, $primary);
// Print out the $results to check what Cake is returning.
debug($results);
return $results;
}
I have 3 models (User, Message and Tag) with the following relations:
User hasMany Message
Message belongsto User
Message HABTM Tag
Tag HABTM Message
If a User is logged in he might want to see all Message tagged with something.
$messages = $this->Message->find('all', array(
'conditions' => array("Message.user_id" => $this->uid),
'contain' => array(
'Tag' => array(
'conditions' => array(
'Tag.id' => $activetag['Tag']['id']
)
)
));
However, this find will return ALL messages of that user. (Containable behaviour is included in both models)
Containable on child (tag) does not perform filter on the parent (message), that's why all the messages are returned. The containable only place condition on the tag itself, in your case, messages not matching $activeTag would still get returned but with empty tag array attached, while messages matching would return with an array containing only one tag, the $activeTag, but all messages would get returned.
For your purpose CakepHP recommend using join function for filtering with HABTM, it joins hasOne or belongsTo for you automatically but when it comes to HABTM you may need to perform the join yourself if needed.
assuming tables are named conventionally:
$this->Message->recursive = -1;
$options['joins'] = array(
array('table' => 'messages_tags',
'alias' => 'MessageTag',
'type' => 'INNER',
'conditions' => array(
'Message.id = MessageTag.message_id',
)
) );
$options['conditions'] = array(
'MessageTag.tag_id' => $activetag['Tag']['id'],
'Message.user_id' => $this->uid );
$message = $this->Message->find('all', $options);
more info here:
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#joining-tables
In your Model Message add
**
* #see Model::$actsAs
*/
public $actsAs = array(
'Containable',
);
/**
* #see Model::$belongsTo
*/
public $belongsTo = array(
'Message' => array(
'className' => 'Message',
'foreignKey' => 'message_id',
),
'Tags' => array(
'className' => 'Tag',
'foreignKey' => 'tag_id',
),
);
in your controller :
// $tagsId = tags ids
$message = $this->MessageTag->find('all', array('conditions' => array('MessageTag.tag_id' => $tagsId),'contain' => array('Message')));
also is better follow cake naming convention, if you have tags(plural), message_tags(first singular second plural),messages(plural) tables you must have Tag,MessageTag,Message Models.
I have question in cakephp model,
I want to add dynamic condition in var $hasMany keyword
I want to add condition like current user_id, i got user Id after my login.
var $hasMany = array(
"AskComment"=>array('limit'=>3),
'AskStatistic',
'AskContactsLink',
'AskStatistic',
'AskObject',
'AskLikes'
);
If you want to add dynamic condition in your model, then you might have to bind the model association-ship dynamically into your controller's code. Write the following code into your controller's method for which you want to impose some new condition on the existing/new associated models.
$this->PrimaryModel->bindModel(array('hasMany' => array(
'AskComment' => array(
'className' => 'AskComment',
'foreignKey' => 'primary_id',
'conditions' => array('AskComment.user_id' => $user_id)
)
)
));
Take a look at this link: Creating and destroying associations on the fly. This will surely help you to achieve the same.
I think its better to put your association in the construct function of your Model.
like this:
/**
* #see Model::__construct
*/
public function __construct($id = false, $table = null, $ds = null) {
public $hasMany = array(
'AskComment' => array(
'className' => 'AskComment',
'foreignKey' => 'primary_id',
'conditions' => array(
'AskComment.user_id' => $user_id,
),
),
);
}
For some reason i'm really having a hard time wrapping my head around HABTM associations. I learn best by watching someone do something and explaining why. Anyways, I have 2 tables I want associated, Drugs, and SideEffects. I've created the intermediate table drugs_side_effects(has no data right now). Does cake put the data in that automatically or do I need to do something? The 3.7.6.5 hasAndBelongsToMany (HABTM) from the book didn't specify.
I've set up the models correctly(I think) and am not sure how to proceed at this point. It seems pretty simple. I need to display side_effect from the SideEffects table in a Drug view. I think in the edit_french controller function i'll need something like
$side_effect = $this->Drug->SideEffect->read(
array('SideEffect.id','SideEffect.side_effect'), $id);
$this->set('side_effect',$side_effect);
but I feel like that won't work as expected. Or maybe there's a more efficient way? Any advice or help is appreciated.
Drug Model:
var $hasAndBelongsToMany = array(
'SideEffect' => array(
'className' => 'SideEffect',
'joinTable' => 'drug_side_effects',
'foreignKey' => 'drug_id',
'associationForeignKey' => 'side_effect_id'
)
);
}
?>
SideEffect Model:
var $hasAndBelongsToMany = array(
'Drug' => array(
'className' => 'Drug',
'joinTable' => 'drug_side_effects',
'foreignKey' => 'side_effect_id',
'associationForeignKey' => 'drug_id'
)
);
}
?>
Drugs Controller:
<?php
class DrugsController extends AppController {
var $name = 'Drugs';
var $helpers = array('Html','Form','Paginator');
var $paginate = array(
//'contain' => array('SideEffect'),
//'fields' => array('Drug.id', 'Drug.generic'),
'fields' => array('Drug.id', 'Drug.generic','Drug.date_altered'),
'limit' => 50,
'order' => array(
'Drug.generic' => 'asc'
)
);
function index() {
$data = $this->paginate('Drug');
$alldrugs = $this->set('drugs', $this->Drug->find('all'));
$this->set('drugs', $data);
$this->set('alldrugs', $data);
//$this->set('lessdrugs', $this->paginate());
$this->set('title_for_layout','List of all current drugs');
}
function edit_french($id = null) {
$this->Drug->id = $id;
$drug = $this->Drug->read(
array(
'Drug.id','Drug.generic','Drug.ahl','Drug.aap','Drug.rid','Drug.oral','Drug.mw','Drug.clinical_recommendations'
),
$id
);
$this->set('title_for_layout', 'Translate clinical recommendations - ' . $drug['Drug']['generic']);
$this->set('drug',$drug);
if (empty($this->data)) {
$this->data = $this->Drug->read();
} else {
if ($this->Drug->save($this->data)) {
$this->Session->setFlash('The drug has been updated.');
$this->redirect(array('action' => 'index'));
}
}
}
}
?>
You can pull the related data using ContainableBehavior. To do so, simply run a find on the Drug model and tell it to contain the associated SideEffect data.
$drug = $this->Drug->find('first', array(
'conditions' => array(
'Drug.id' => $id
),
'contain' => array(
'SideEffect'
)
));
You can also set the contain before using read() if you prefer.
$this->Drug->contain(array('SideEffect'));
$drug = $this->Drug->read(null, $id);
Using Containable allows you to gather all associated data in a single find() request.
In my CakePHP app I have models for Matches and Teams. Each Match has a home_team_id and an away_team_id, both of which reference a different Team.
In my team.php file, I am able to form the relationship for a Team's home matches:
var $hasMany = array(
'HomeMatch' => array('className' => 'Match', 'foreignKey' => 'home_team_id'),
'AwayMatch' => array('className' => 'Match', 'foreignKey' => 'away_team_id')
);
My problem is that I cannot automatically retrieve a Team's home and away Matches in a single array. That is, the retrieved Matches are returned in separate HomeMatch and AwayMatch arrays, which causes sorting difficulties.
I have tried the following:
var $hasMany = array(
'Match' => array('foreignKey' => array('home_team_id', 'away_team_id'))
);
...with no luck.
Any ideas on how to combine these two foreign keys into a single relationship?
Thanks, Ben
A custom finderQuery should do the trick:
public $hasMany = array(
'Match' => array(
'className' => 'Match',
'foreignKey' => false,
'finderQuery' => 'SELECT *
FROM `matches` as `Match`
WHERE `Match`.`home_team_id` = {$__cakeID__$}
OR `Match`.`away_team_id` = {$__cakeID__$}'
)
);
I was having a similar issue and instead of creating a finderQuery I used the conditions operator and it worked great!
public $hasMany = array(
'Match' => array(
'className' => 'Match',
'foreignKey' => false,
'conditions' => array(
'OR' => array(
array('Match.home_team_id' => '{$__cakeID__$}'),
array('Match.away_team_id' => '{$__cakeID__$}')
)
),
)
);
They are returned in seperate array's because the sort of represent different models (in this particular case the model is the same).
You should probably build a helper method to go over the retrieved data (in the model object or in a separate helper class) and "flatten" it. then you'd be able to sort it.
Ken.